Function @Allocate

Similar Questions

• leak memory in the dll with a function imaq

  Hello

  I'm writing a dll that uses the imaqImageToArray function.

  Of course this function allocates new memory whenever it converts an image, and as I convert 180 photos per second and shopuld program run for hours is quite a problem for me.

  The solution must of course be the free function (void * MyPointer). If I use malloc to allocate some random memory, instead of the imaqImageToArray, it works perfectly.

  However, when I call free() to free the memory allocated by the imaqImageToArray function, the LabView/dll-program crash.

  So I wonder what function the imaq functions allows you to allocate the memory and how I can get rid of him again. Is there another imaq-function?

  Thank you already!

  Greetings

  Sorry everyone for disturb you.

  I was just stupid... the answer is of course imaqDispose(void *object)

  Sorry again

  Thanks for the help

• NIReport_FreeMemory incomplete cleaning

  In the function NIReport_GetPrinters function helps online panel, there is an example of code as shown below:

  void GetAndFreePrinters (void){  char **allPrinters;  char **printer;  NIReport_GetPrinters (NULL, &allPrinters);  printer = allPrinters;    while (*printer != NULL) NIReport_FreeMemory (*printer++);  NIReport_FreeMemory (allPrinters);}
  

  I used this code in my project and I started getting errors of execution during other as free memory deallocation functions, Ini_Dispose.

  To study, I used the ResourceTracking utility to see the State of the memory.

  I discovered that after the last call to NIReport_FreeMemory in the above code, a block of memory of 80 bytes remains unfreed (I have 3 printers installed, NIReport_GetPrinters function allocates 5 blocks of memory in my PC).

  Probably this else block confuses memory allocation operations and causes some other memory irrelevant free operations to fail.

  When I say run, I mean the recoverable error "attempt to release the pointer to the memory not allocated by malloc or calloc.

  It seems that this problem is solved also in this thread many years ago, but apparently remain unresolved.

  Can you reproduce the behaviour of your PC? (I'm working on an XP SP3 and problem is observed in 8.5.1 and 9.0)

  Hello ebalci-

  I was able to reproduce this on my machine.  It turns out that we have a bit of a leak memory in the application of NIReport_GetPrinters.

  I created a bug for this issue (ID 197427) report.

  As long as this (NIReport_GetPrinters) function is not called repeatedly, the leak must be of little consequence (the leak occurs once by calling the function and the size of the leak depends on how many printers you have installed).  I am inclined to think that the leak is not the source of the errors that you receive, but I'd be happy to take a look at a code with you if things continue to look otherwise.

  NickB

  National Instruments

• error 1097 after the call dll function that allocates memory inside

  Hello!

  When a one call my duties in my dll of LabView, I get an error 1097. My function takes a few arguments, and then allocates memory for the measure.

  He doesn't have pointers to this memory area, it's just allocates this memory for himself. I don't know what could be the problem, no doubt, I'm missing something.

  Could you please help?

  Best regards

  Tamas

  
  

• allocate memory and call the dll function that writes to the pointer

  Hello!

  I have a DLL that has a function as in the following example, I need to call from labview. In C, I need to allocate memory for data and of course the struct. I add the pointer and the length of the data to the struct and call the function with the struct. The function itself inserts values of the struct and affected memory. Someone at - it a working solution how this can be done with Labview?

  typedef struct Thestruct
  {
  UINT16 val1;
  UINT8 val2;
  UINT8 val3;
  DataLength UINT16;
  UINT8 * data;
  } T_Thestruct;

  MY_API status MY_API_CALL udaReceive (handle, T_Thestruct * args);

  I tried in labview (see photo), but I only got values inside the structure as well as the 1097 error, reserved memory included values as before.

  OK, I found the soluton to my own problem. Alignment on the struct must be corrected in Labview. There must be a value between dataLength 2Bytes dummy and the pointer.

• Multi-function generation creates code that calls releases the memory it has no allocate

  Generation of a panel based on our ActiveX component generates the code below.

  My problem is that it is free memory that it does not allocate - a bad programming practice. The user must allocate a buffer for testFilePath, but this method releases.

  Problem is known by a side effect of this:

  http://digital.NI.com/public.nsf/allkb/205CA72511BC735C862570F80019660A?OpenDocument

  John Barton

  ----------------------------------

  HRESULT CVIFUNC XJIntegrationOCX__XJIntegrationSetTestSystem (CAObjHandle objectHandle,
  ERRORINFO * errorInfo.
                                                                char * testFilePath,.
  VBOOL * arg2)
  {
  __Result HRESULT = S_OK;
  XJIntegrationOCX__XJIntegration_Interface * __vtblIFacePtr = 0;
  int __didAddRef;
  int __errorInfoPresent = 0;
  BSTR testFilePath__AutoType = 0;
  VBOOL arg2__Temp;

  __caErrChk (CA_CStringToBSTR (* testFilePath, & testFilePath__AutoType));

  __caErrChk (CA_GetInterfaceFromObjHandle (objectHandle,
  & XJIntegrationOCX_IID__XJIntegration,
  0, & __vtblIFacePtr, & __didAddRef));
  __caErrChk (__vtblIFacePtr-> lpVtbl-> SetTestSystem_ (__vtblIFacePtr,
  & testFilePath__AutoType,
  (& arg2__Temp));

  If (testFilePath)
  {
          CA_FreeMemory (* testFilePath);
  * testFilePath = 0;
  }
  If (testFilePath)
  __caErrChk (CA_BSTRGetCString (testFilePath__AutoType, testFilePath));
  If (arg2)
  {
  * arg2 = arg2__Temp;
  }

  Error:
  CA_FreeBSTR (testFilePath__AutoType);
  If (__vtblIFacePtr & __didAddRef)
  __vtblIFacePtr-> lpVtbl-> Release (__vtblIFacePtr);
  If (FAILED (__result))
  {
  If (testFilePath)
  {
  CA_FreeMemory (* testFilePath);
  * testFilePath = 0;
  }
  }
  CA_FillErrorInfoEx (objectHandle, & XJIntegrationOCX_IID__XJIntegration,
  __result, errorInfo, & __errorInfoPresent);
  If (__errorInfoPresent)
  __result = DISP_E_EXCEPTION;
  Return __result;
  }

  Hi John,.

  This parameter is supposed to be an output parameter? If so, so that the code looks right to me. The function expects a string to pass, and then returns a different string via the same parameter. In this case, by the rules of the ActiveX, the method releases the original string after using it, and then allocates a new string. The only difference between a typical ActiveX interface and this wrapper CVI is that with a typical ActiveX interface it would operate the BStr strings instead of the C strings.

  Because the function redistributes the buffer after the release of whatever you spend, you should not change this buffer memory management in client code. The hope is that you allocate memory initially, then call this function and then free the memory some time after the return of this function. The fact that this function of reallocation of memory at the same time should not affect this process.

  If you use invalid free question, a couple of things to watch are that: 1) when you allocate memory initially, you do not use a different allocater, such as malloc in the C library, for example. If you need to allocate explicit memory, you must use CA_AllocMemory, which is what the ActiveX library and 2) that you don't have multiple references to this pointer that could potentially be released several times.

  Luis

• Function of @Allocate can't seem to get the right syntax

  Hi friends,
  
  I need to make a linear distribution (all equal amounts) of value has prompted at least (for a given combination of year-round version scenario entity etc.)
  
  I'm yeartotal-quarters and months.
  
  I can't use the usual period of spread I need produce whole numbers and the standard distribution introduced decimal numbers.
  
  I thought I'd be able to use @allocate to do something like that, but I'm having trouble him to validate both calcmgr and eas with what I thought was a pretty simple attempt, that is, difficulty on the account will be allocated and relevant narrowing and then assign a value to the range of months using propagation and rounding and applying the difference to the higher member or the first in the range:
  
  DIFFICULTY (' 21 ',' e080201 ', 'HSP_InputValue', 'FY11","Local","Run business', 'Mensualización 1', "YearTotal")
  @ALLOCATE (12000, @levelmbrs(Period,0), Monto, spread, SKIPNONE, roundAmt,-3, errorsToHigh);
  ENDFIX;
  .
  
  But I get a syntax error: error: 1012000 syntax not v lida. None are un comando c calculation [@ALLOCATE].
  
  I'm at my wits end. Anyone know what I'm doing wrong here and if allocate work even for what I try to achieve?
  
  If not what other submissions do something like this don't you have?
  
  I need to come up with more later as well guests to make the amount a variable and the range invited as well, but for now if I pass it I'll be happy.
  
  Agnete

  Hello

  'Re missing you the 4th parameter. Also try to put a member in the left part of the equation.

  Try 'Member' = @ALLOCATE (12000, @levelmbrs(Period,0), Monto, propagation, SKIPNONE, roundAmt,-3, errorsToHigh);

  Note the comma before "propagation."

  Thank you
  JM

• An array of strings as function parameter in loop fails

  Hallo,

  I have a weird problem here and I hope someone can help me find the cause.

  I have a function where I said an array of strings (string_list). I pass the array to a function that does modifactions to the table. I am addressing Walker the array of strings to an index of all the values are stored correctly. When I loop through the array by incrementing the index automatically only the last index value are saved in all positions.

  Why is this? Or what I am doing wrong?

  It is the passage to another function, an array of strings
  
  int calling_function
  
  {
  
        char * string_list [MAX_PATHNAME_LEN];  //< store="" strings="" in="">
  
        function_called (string_list);  passing a pointer to an array of string
  
        return 0;
  
  }
  
  This is the function receives a reference to an array of strings to store data
  
  int function_called (char * output_list [])
  
  {
     int i = 0;  counter variable
  
     / * This works and good values are stored in output_list * /.
  
      output_list [0] = '02 ";
  
      output_list [1] = '12 ';
  
      output_list [2] = "22";
  
      output_list [3] = "32";
  
      output_list [4] = '42 ';
  
      output_list [5] = "52";
  
      output_list [6] = '622 ';
  
      output_list [7] = "72".
  / * This does not work and will store '31' in all places of the matrix * /.
  
      < 32="">
  
      {
  
          < %d »,="" i) ;="" incrémenter="" la="" valeur="">< br="">
          output_list [i] = sample;  < br="">
          i = i ++ ;                   < br="">
      < br="" >="">

  output_list [0] = '02 "; < br=""> output_list [1] = '12 ';< br="" >="">

  Thanks!

  Hi,.

  When you do

  output_list [i] = sample;

  all of the members of the array have the same value: sample-a char pointer. You are modifying the afterwards glad of sample purpose the previous values still point to sample.

  If you assign values to each array member like:

  you assign different values: a pointer to a string containing "02", pointing to a string contaning "12",...
  If you want to assign values in a loop you need to allocate memory for each string (output_list [i]) and copy the content of sample in them.
  Does this make sense to you?
  Constantin

• allocation of an array of 2d in labVIEW and move to the DLL function to obtain data

  Hi all!

  I searched a lot about this, but one cannot find any solution. Please find attached the vi that I try to get a unit of 32 channels data,

  100000 samples per channel with 14-bit resolution. And please also find enclosed the header for my dll file. (in the header, it is the GetBuffers function).

  There is not a lot of data, it is a little more then 6 MB in the task of LAbVIEW Manager eats about 30 MB more memory, then it should. Are there explanations why?

  Because there is much more data in a single channel (million samples or more)

  Then I will try to allocate a 2D to data array, but when I try to run my LabVIEW vi crashes.

  Could you please help?

  Best regards

  Tomzi

  Dear Tomzi!

  To allocate the data in a table in LabVIEW, you must always initialize, as in a you must have a valid entry on cell (x-, y - 1) have a size of table of (x, y). It is usually best to use the function Array initialized for this purpose.

  There are ways to pass arrays 2D to DLLs, cand find you examples of both in examples > communicate with external Applications > external Code using the > integrating DLLs > DLL.vi call. Basically, LabVIEW can pass in the form of a big table 1 d 2D tables, so you'll need to spend too much table size index it. If you pass the array 2D handles it is preferable to use the typedef that LabVIEW generates for you, something along the lines of

  / * LabVIEW created typedef * /.
  
  typedef struct {}
  
  	Int32 dimSizes [2];
  
  	Double elt [1];
  
  	} TD1;
  
  typedef TD1 * TD1Hdl;

  I hope this helps.

  Best regards:

  Andrew Valko

  NOR Hungary

• How does the library function call Labview? Can I emulate using C++?

  Hi all. I recently finished writing a dll CUDA for LabView, and now I'm in the steps of optimization of code, memory management, etc. BUT since my code depends on the entries of Labview (lots of data under types of specific data as table manages and Clusters labview) I can't use the CUDA Profiler or the Profiler VC ++ on the DLL. What I intend to do runs labview and then out of all data entry for the DLL in a binary file and then add an additional function in my code that will read in the binary file, allocate and assign variables to their respective positions, and then call the specific DLL function in Labview. In the end, this miniature function will act as the library function call to my specific group of data entries.

  In any case, I started to make this purchase all my data entry of cluster and it comes out in a binary file. And then I started the initialization of the handles of labview, allocating memory and begins to write the binary data in the memory and it works for integers (ints), floats, etc., but I'm confused on how it works with table handles!

  Some examples of code:

  Sets the Handle for table 1 d for INT
  
  typedef struct {}
  
  	int length;
  
  	int val [1];
  
  		to access the value in a row-online val [Online]
  
  } Array1dInt, * Array1dIntHandle;
  
  int main()
  
  {
  
  	Array1dIntHandle x = new Array1dInt *;
  
  	(* x) = new Array1dInt;
  ifstream file ('TESTDATAIN.dat', ios: in | ios::binary);
  If (file.is_open ())
  
  	{
  
  		file ((char *) &(*x)-> length, sizeof;)
  
  		file ((char *) &(*x)-> val [0], sizeof (int) *(*x)-> length);
  LabviewSpecificFunction (x);
  
  		leader. Close();
  
  	} else
  
  	{
  
  		< "file="" did="" not="" open!"=""><>
  
  	}
  
  	return 0;
  
  }
  __declspec(dllexport) LabviewSpecificFunction (Array1dIntHandle x)
  
  {
  
  ...
  
  }

  However, my program crashes when the table is nominally big, and it is expected, because if we look at the Array1dHandle, it has allocated only enough memory to 1 item of value! YET, somehow, in its magical and mysterious labview is capable of making val [1] be val [HOWEVERMANYYOUWANT], even if C++ 101 says that val [1] is a constant pointer, and even if I dynamically allocated memory another somwhere, I would never be able to put these data in this round!

  Can you explain, or maybe even write example on how I can fool my program into thinking that the binary code comes from labview, so I can then run my program independent of allowing me to profile the functions inside labview?

  I hope that this question is clear and my sample code is also clear, but I'm happy to answer any questions that relate to this.

  Thank you all!

  I think that I thought about it.

  Array1dIntHandle x = new Array1dInt *;
  int tempsize;
  
  file ((char *) & tempsize, sizeof;)
  
  (* x) = (Array1dInt *) malloc (sizeof (int) + sizeof (int) * tempsize);
  
  (* x)-> length = tempsize;
  
  file ((char *) &(*x)-> val [0], sizeof (int) *(*x)-> length);

  Well enough, you will need to make the handle, and then make a new Array1dInt * for him, then read in the length of the array in a temporary variable. Then use this information to then malloc memoery quantity you need for the table and pass this place on the handle. Now the handle will point to the size of the memory and you will be able to access the memory in the format, you've done the handle. Badabing badaboom

• [HELP] Call library function node...

  I have a DLL that has a function as follows:

  int GetMessageNameNumber (char * messageName [], const int MessageNumber);
  

   

  The function is used thus:

  char * MessageName = NULL;
  
  int MessageNumber = 0;
  
  ...
  error = HL1553API_GetMessageNumberName (& MessageName, MessageNumber);
  

  MessageName will contain the name of the message as a string.

  I saw the Devils own job trying to wrap this in a Labview module.  I have a knot of library function to call the above function, but I'm not sure what to set the parameter "MessageName" also!  I tried array of integers 8 signed bits, adapted to the Type of pointer to data in the table and then passed in an array of strings.  Whatever I do translates into LabView crash.  I know HL1553API_GetMessageNumberName works, because if I call it directly in TestStand it works fine.  I need LabView well!

  Any ideas?

  C a pointer to a string or an array of strings are completely ambiguous.

  char * something = char * something [].

  You can't tell the two apart from the syntax, but only from the documentation or an example of how the function is called. A C compiler treats the equal in terms of access (but a C++ compiler will do a syntactic differentiation when code syntax checking, with the possible result compile warnings when you are prompted to use a sufficiently high level of warning).

  The example shows that it is not a string array gets allocated by the caller and passed to the function, but a string pointer that is passed by reference. So the function will allocate a pointer and return it (a very atypical C practice at least for strings). This automatically raises the question when and how this pointer will be released? The documentation for this function should document the call from Manager memory allows to allocate this pointer and also point to the function to call to release. Ideally the library (DLL) provides an exported function for this purpose.

  Assume that everything I spoke so far is clear and available you need to cheat a bit LabVIEW. You need to configer a pointer size whole that is passed by reference. Now this whole in the diagram IS actually your channel. If you only need to pass this pointer to other library functions call that you're already doing. Otherwise if you need access to the contents of this string from the diagram LabVIEW, you will need to copy the information from this string to a real string of LabVIEW pointer.

  One way to do that is to use the export of the MoveBlock() C function that LabVIEW exports itself. I have explained this several times here on this forum and the MoveBlock research will no doubt find out these positions.

  Another slightly better way is to use the LStrPrintf() function which also exports of LabVIEW. To do this, you configure a library function call as follows:

  Library name: LabVIEW

  Function name: LStrPrintf

  Calling Convention: C

  Thread: both are possible, but the function is thread safe, so just use environment

  return parameter: int32 (there is a possible LabVIEW Manager error code)

  1st parameter: handle string of LabVIEW, passed by value

  parameter 2: C string pointer

  3rd parameter: integer pointer size, passed by valu

  Wire an empty string in the first parameter constant.

  Wire a constant containing the text '%s' without the quotes on the 2nd.

  The pointer to your thread on the 3rd string

  The function will return 0 as a return value and the content of the string on the side of the exit of the 1st parameter or a zero value indicating that a mistake to return back.

• tables as input for the shared library function

  I played with the call of LV VI using matlab.

  So I built a simple VI which returns an integer as input and multiply it by 10, I then put in a shared library and named it MATLAB - well.

  Now, I tried to do the same thing with a table - I want to send a picture to the VI and multiplied it by 10, but when I build the .h file, it seems that the function expects get table of entry AND exit of table as inputs.

  so, how I can build a shared library VI who gets an array (of a constant size if this is important) and multiply it by 10?

  Thank you!

  A function in a DLL can only return a scalar value, not a table, no matter what languages are used. To return an array, instead calling it allocates the array pass a reference to the DLL and then after the function called the referenced table table contains the new data. This is why there are two parameters - the input array (actually a pointer to it) and a pointer (reference) to the output array. You must change your code in MATLAB, there is nothing you can do about it in LabVIEW. EDIT: Also note that it allows to re-use of the input as an output table, optionally passing a reference only to the table of entry and then by changing that. You can do it in LabVIEW by configuring the setting table as input and output.

• Make sure that wire you all the inputs and outputs of your node library function call?

  This document says "make sure that wire you all the inputs and outputs of your node library function call.

  http://digital.NI.com/public.nsf/WebSearch/7253D2F0D91F68058625752F005AB672?OpenDocument&submitted&&...

  But all the terminals on the right side of the call library node considered "outputs" referred to in the foregoing statement?

  This same document continues to show the right way to allocate memory with this illustration and in the illustration, the right "outputs" are left without junctions.

  

  Am I right in assuming that the only terminals that count as outputs, those who use the code of the DLL (modify) as output?  If it is true, then all other terminals output associated with the values entered alone so don't really account as outputs, correct?

  In the parameter call-library configuration screen there is a "Constant" check box and the help that he wrote "indicates whether the parameter is a constant."  What is this box? for me in the setup of the DLL call

  Finally, assuming that a call from the DLL that is supposed to write in these five outputs, is it legitimate to use constants like this to book a space of memory for the output values?

  

  How about if local variables associated with the output terminals are used instead?

  

  Despite the linked document, it is necessary to connect the corresponding entry for simple scalar output parameters (for example a digital). LabVIEW automatically allocate memory for them. If you do not want the entries for all the output wire anyway, there should not be no difference between a constant and a local variable; I would use a constant to avoid useless local variables.

  For settings that are only entries, there is not need to connect the outlet side. It's a bit simplistic since all parameters are entered only and get one result (other than the return value), you pass a memory address and modify the content to this address, but LabVIEW manages this dereferencing pointer for you. If you want to really get into the details, learn more about pointers in C.

  The "Constant" check box acts as the qualifier "const" on a c function parameter. It tells the compiler that the function you are calling will not change this setting. If you call a function prototype includes a const parameter, then you must mark this as a constant parameter when you configure the call library function node. Otherwise, I wouldn't worry on this subject.

• When you call a function in a shared library, are copied locally settings?

  I have a shared library with a function which the header is:

  void __cdecl nextevent (double entry [], int32_t len);

  When it is called it sends the values in [entry] to the input control:

  

  This vi is compiled into a DLL that uses the header above.

  Now, my question is: which of these operations is good:

  1. the input control is a reference to the entry in array [], no value is copied.

  2. the values of the Input [] array are copied into the input control, the local copy is used by the vi, then the values of the local copy is deleted/trimmed.

  It seems reasonable that 1 is good, but I can't be sure, and I see no way to check.

  For this particular case, option 2 is valid. The reason is that the tables of LabVIEW are not just pointers to a memory location but the handles. And there is no legal way to create valid LabVIEW handles of a runtime C allocated memory pointer. If LabVIEW transforms the table pointer entering a handle which is basically nothing else that allocate the handle with a sufficient size to contain all the data in the table and then copy the data from the table pointer in this handle. After the call, the handle is properly released.

• How to use the node function call library for a function in the dll with the data SUB type

  Hi all

  I would ask for your kind help

  I am facing a problem with the call library node.

  I have a C++ (stdcall) function, which has Sub as data type

  XXXX error code (hwnd, lid, getValue, * Sub data1, * Sub data2)

  data1 and data2 types are constantly changing based on the value of 'getValue '.

  Mainly I can use the call library node several times and adapt each node according to the types of data data1, data2 and extract the values and use in the code. Here is no question. Real question is:

  My question:

  How can I use a node of library time call and make a case according to the 'getvalue', who will control the data1, data2 data type. Here I really seeking solutions.

  My tests:

  I used varaints as entry to the libray call node of the data1, data2 and selected parameters in the call libraby node as "Adapt to type. Here labview just crashed.

  I appreciate your suggestions to feedbackand.

  Thank you

  Karine

  You must allocate enough space for data1 and data2, and then pass a pointer to this space. An easy way to do this is the function to initialize table. Set the U8 type and size for the number of bytes required. Pass this array to the function as a pointer of table data.

  After the function call returns, you need to extract the data in the table. You can do it manually, but a simple approach is to use the array of bytes to a string. Then, in a housing structure, use Unflatten chain to convert the string to the correct data type. This method also converts the "endianness" which will be probably necessary; Be sure to only set all entries for unflatten correctly.