gamepad get a different numerical value of 0 and 1

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• Validation of the numerical value of precision and scale

  Hi all
  
  IAM using ADF with EJB.
  I have an inputText field that accepts numeric values (of type java.lang.Double). Due to data constraints, I want to validate the input on its accuracy and scale value.
  I put a label of f: convertNumber under the inputText and set the MaxIntegerDigits and MaxFractionDigits properties with the values you want.
  I also set the ApplyValidation of the attribute in the file pagedef property. However, no validation has worked.
  I did the same test with af:ConvertNumber without result too.
  
  I know it's easy to put these constraints at the level of the entities with BC4J.
  
  Is there a neat way to set validation or I need to write code in the bean to support?

  How about using a regular expression validator:
  http://blogs.Oracle.com/Shay/2007/12/regular_expression_validation.html

• How do switch you between 2 numeric values using a Boolean switch?

  Hello

  I'm a newbie to labview, so it is perhaps easy to answer.

  I would like to perform a calculation which, according to the test unit, will require a different numeric value to use in the Calc.

  I tried to use a Boolean switch to choose which constant must be used during runtime mode as well for example or 0.01 or 0.02 will be selected. The idea is to labview so insert the constant selected in the calculation and spit out the answer.

  There is only one output on the Boolean toggle switch and not of entry so that I can't work out how to do it. If there were 2 inputs and 1 output it would do the job.

  Thank you

  Andy

  Try the joint.  I have provided two methods.

• How to connect the value of the input string to numeric values

  Hello

  I'm trying to figure out how to connect the value of unique user input string to numeric values. Basically I want the user to enter the name of a gas that I have a list for (I think I put the list of gases in a table >). Then I want to match numeric values 2 'a' and 'b', according to which gas, name of the user has set. These 'a' and 'b' values will be automatically matched with the name of the gas in a list that I put. For example, hydrogen gas has the value 3 for "a" and 4 for "b. when the user puts the ' hydrogen' name in a string constant, automatically 'a' and 'b' must be issued.» I have connect a and b to a formula

  Thanks for any help

  Hello

  It is perhaps not exactly what you are looking for, but perhaps you could use the enumerated data type and the array of clusters of points (a, b).

  Look at the VI I enclose.

• What is javascript customized for converting an estimate of the numerical value in equivalent term?

  
  Hello fellow Adobe users,.

  I'm trying to find a way to see the numerical value of average and presents its equivalent word.  Rather than display the number, it should show the following:

  A numeric score from 3.1 to 4 should show as pending

  A digital index of 2.1 to 3 should show meets expectations

  A numeric score from 1.5 to 2 should show as below performance

  A rating of 1 to 1.4 should show as failure

  Should what simple javascript I type the javascript custom in the text field properties?

  Looking forward to your comments.

  Thanks in advance!

  Jonathan

  You have a field that is the calculation of this average in number? Let's say you do and it's called 'average '. You can then use this code as the custom for the field "Average in the words:" calculation script

  event.value = "";
  var a = +this.getField("Average").value;
  if (a>=1 && a<=1.4) event.value = "Fail";
  else if (a>=1.5 && a<=2) event.value = "below performance";
  else if (a>=2.1 && a<=3) event.value = "Meeting Expectations";
  else if (a>=3.1 && a<=4) event.value = "Outstanding";
  

• How can I get the numeric value of a reference?

  I would like to get the numeric value of a reference.  If I look at any reference with a probe, I can see it has value, i.e. F280006B.  I would like to enter this value in a digital indicator for some troubleshooting I do. but running a Ref directly in a digital indicator introduced the code. Somehow the probe's work, it must be accessible. All advice out there?

  Type caster in U32.

  Lynn

  

• How do you get the numeric value of an image

  How do you get the numeric value of an image

  This in a small example

  var Red = ' \u00FF\u00D8\u00FF\u00E1\x05oExif\x00\x00MM\ '.

  
  

  
  

  Here is a link to a script open source that generates a string that represents the data of a file binary, especially useful to integrate a small image in a script or file patterns in a JSON structure, for example:

  Get the data from binary string

  HTH,

  Domestic-

• How to get the day as a numeric value without the date in shape?

  Hello
  to reduce the costs of a sql statement, I need to get the day of a date under the number (to compare to a numerical value) value without formatting. Each formatting causes a complete table of the table scan and the date field. Is there a function for this problem?
  
  Version of Oracle's 11g.
  
  Thank you Carsten

  You can use EXTRACT...

  SQL> select extract(day from sysdate) from dual;
  
  EXTRACT(DAYFROMSYSDATE)
  -----------------------
                        7
  
  SQL>
  

• Want to get the records of only numeric values

  I have tables sales_order, with column ATTRIBUTE_8 VARCHAR2 (50) and job_order with column NUMBER HIGH_AMOUNT.

  attribute_8 column of the sales_order table has both numerical values & character values.  For example:-32232.3764, 234283.878, YES, NOT... etc.

  I intend to load data of tabe sales_order to job_order. For all non-numeric values of ATTRIBUTE_8, I want to do as a 0.

  Please indicate an INSERT statement to achieve this.

  create or replace function clean_number(p_string in varchar2) return number is
  begin
    return to_number(p_string);
  exception when value_error then
    return 0;
  end clean_number;
  /
  with input(ATTRIBUTE_8) as (
    select '-32232.3764' from dual union all
    select '234283.878' from dual union all
    select 'YES' from dual union all
    select 'NO' from dual union all
    select '1e4' from dual
  )
  select attribute_8, clean_number(attribute_8) high_amount from input;
  

  ATTRIBUTE_8	HIGH_AMOUNT
  -32232.3764	-32232.3764
  234283.878	234283.878
  YES	0
  NO.	0
  1E4	10000

• Convert a numeric value to text

  First problem-

  Convert a numeric value to text

  Convert currency value in words.

  e.g. Rs. 10, 000 would become rupees ten thousand only

  RS 1,50,749.77 would become rupees one Lakh fifty eight thousand seven hundred forty-nine and seventy seven Paise only.

  Second problem-

  = SIERREUR (IF ($A16 > = $K$ 1, (INDEX (($L$1:$L$40), MATCH ($B16,($H$1:$H$40), 0))), IF ($A16 < = $I$ 1, (INDEX (($J$1:$J$40), MATCH ($B16,($H$1:$H$40), 0))), 0)))

  This formula works in Microsoft excel but displays error while being used in numbers (iwork).

  Number of formula considers only the first part. While giving the equation for the second part it gives the result as FALSE. And when used in number last 0 and support must be removed to get the result. If it is not removed form displays the error message.

  Concerning

  Nishat Gupta

  Hi John,.

  First question needs a lookup table for the translation. I did several years ago for AppleWorks and later Numbers ' 09. Take a look for her tonight.

  I think that neither SGIII nor Wayne Contello done one more early as well. Both were English/North American names and number formats, so a direct copy may not be sufficient.

  Second question:

  A lot of extra parentheses in there! They are not necessary for frame type Beach H1:H40 references. Won't it doesn't work, but they don't add noise when a man tries to ead the formula.

  Here is an example using the addresses in your formula, but omitting the function SIERREUR the part I wanted to see real results, including errors, if any.

  

  The formula below comes from U16. The title of the image is in U17.

  IF ($A16≥$ K$ 1, INDEX ($L$ 1: $21, MATCH($B16,$H$1:$H$21,0) $L), IF ($A16≤$ I$ 1, INDEX ($ 1 $J: $J$ 21, MATCH ($B16, $H$ 1: $H$ 21.0)), 1))

  In the selected cell (U17) tests in two IF statements returns FALSE, then the FALSE result for the second, it is what is returned.

  To add a SIERREUR function:

  SIERREUR = (formula above,0)

  Kind regards

  Barry

• Why do I get 2 different results of these identical derivatives screws?

  I wrote two calculator derived from point by point identical screws and I am at a loss about why

  I get two different results.  I don't know what I have missed/missing which is the origin of this anomaly.

  Please take a look at the downloaded screw (written in LabVIEW 8.0) and let me know what I did wrong.

  Perhaps they are not the same after all.

  Tips for troubleshooting or suggestions are welcome!

  Thank you

  noviceLabVIEWuser

  item 1 of table 1 = 0.9998899980

  item 1 of table 2 = 0.9998900000

  Change the format to display the different values

  the code is identical

• How to interpret the numerical values of SQL_ColType()?

  Hello

  After the execution of:
  ..
  Call SQL_Connect("abcDB","user","pw","") ' abcDB is an ODBC link to my Mysql 5 database
  Call SQL_ExecDirect ("SELECT id, temperature, tsdat FROM v$ _header WHERE id")< 1000")="">
  ..

  > the SQL_ColType(1..ColumnNo) variable shows me the data types of each column to a numeric value, for example:

  SQL_ColType (1) = 4
  SQL_ColType (2) = - 9
  SQL_ColType (3) = 93

  What real data types are behind the values? It would be nice to get a complete list of all possible values?

  Thank you.

  Hi ddehn,

  The SQL_... orders () are the old method for DIAdem to connect to SQL databases, using the ODBC approach.  Since the tiara 10.2 the ADO approach is the recommended method.  This is the function that I used to use to make sense of the values SQL_ColType():

  Function GetODBColTypes()
  
    Dim j, jMax, ChTypes
  
    jMax = SQL_ResultCols
  
    < 1="" then="" jmax="">
  
    ReDim ChTypes (jMax)
  
    FOR j = 1 TO jMax
  
      IF SQL_ColType (j) = 93 THEN
  
        ChTypes (j) = "DateTime".
  
      Else if SQL_ColType = - 1 OR SQL_ColType (j) (j) > 8 THEN ' STRING
  
        ChTypes (j) = "String".
  
      ON THE OTHER
  
        ChTypes (j) = 'number '.
  
      END IF ' SQL_ColType (j)
  
    NEXT ' j
  
  GetODBColTypes = ChTypes
  
  End Function ' GetODBColTypes()

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• Why can I get two different results from the same coefficients?

  I get two different results of the evaluation of the polynomial function.

  For the first, I get the coefficients of a polynomial function to adapt.  I feed the coefficients of the function made the function Eval Poly and get the correct 12.8582 result when I evaluate 49940.

  For the second, I create constant array of values that have been returned by the polynomial Fit function (I typed in).  However, I get an incorrect result of - 120.7913 when I feed the constant table the function Eval Poly when I evauate 49940.

  How this can happen when I use the same values in table?

  A picture of what I explained is attached.

  Hi Altran,

  are you sure about using the 'same '?

  You compare them? Do you have (at least) set them to 17 digits display properties?

  Please attach a VI instead of an image...

• How to place numerical values on the peak in graphs

  Hello

  Is it possible to put the numerical value on the crest of the wave as in the below image where the yellow dots on the Ridge, we put value digital pic?

  

  It needs a lot of cleanup (and there are probably still have a better way in general), but it should at least help you get started.

  

  I used the Detector.vi Peak, which requires the LV Full Development System.

• Numeric value of time zone

  Hi all

  How can I get the numeric value of the current time zone on the device

  ex: GMT = 0.0

  Cairo = + 2.0

  XXX = - 6.0

  coz the API zone get a string representation of the time zone Id, not the digital representation.

  Thank you, all

  . getRawOffset() or

  .getOffset?