Why do I get 2 different results of these identical derivatives screws?

Similar Questions

• Why can I get two different results from the same coefficients?

  I get two different results of the evaluation of the polynomial function.

  For the first, I get the coefficients of a polynomial function to adapt.  I feed the coefficients of the function made the function Eval Poly and get the correct 12.8582 result when I evaluate 49940.

  For the second, I create constant array of values that have been returned by the polynomial Fit function (I typed in).  However, I get an incorrect result of - 120.7913 when I feed the constant table the function Eval Poly when I evauate 49940.

  How this can happen when I use the same values in table?

  A picture of what I explained is attached.

  Hi Altran,

  are you sure about using the 'same '?

  You compare them? Do you have (at least) set them to 17 digits display properties?

  Please attach a VI instead of an image...

• Why do I get different results of these

  I use the HR diagram and study the nested instructions. When I run these two SQL statistics I get a different result. Someone knows why?
  
  Select avg (salary), country_id of
  (select department_id, location_id, salary, country_id of)
  employees join natural services locations of natural join)
  Country_id group;
  
  Select avg (salary), country_id (select country_id, treatment)
  employees join departments using (department_id)
  Join the locations using (location_id))
  Country_id group;
  
  Thanks in advance.

  Natural join joins the tables on columns with the same name. If you look at HR. EMPLOYEES and human resources. Tables of DEPARTMENTS, they share two columns department_id and MANAGER_ID while your second query attached just the department_id. If you add MANAGER_ID to the second query that both return the same results:

  SQL> select  avg(salary),
    2          country_id
    3    from  (
    4           select  salary,
    5                   department_id,
    6                   location_id,
    7                   country_id
    8             from  hr.employees natural join hr.departments natural join hr.locations
    9          )
   10  group by country_id;
  
  AVG(SALARY) CO
  ----------- --
         5640 US
         6000 CA
         8500 UK
  
  SQL> select  avg(salary),
    2          country_id
    3    from  (
    4           select  salary,
    5                   country_id
    6             from  hr.employees join hr.departments using(department_id,manager_id)
    7                   join hr.locations using (location_id)
    8          )
    9  group by country_id;
  
  AVG(SALARY) CO
  ----------- --
         5640 US
         6000 CA
         8500 UK
  
  SQL> 
  

  SY.

• Why Express PSD gives a different result of amplitude as FFT PSD?

  Hello

  When I use the express VI of spectral measures to trace the power spectral density, I get a different result than when using the FFT PSD VI. The data are the same but the amplitudes are different in the PSD plot. Everyone comes through this?

  Thank you

  Donners,

  The PSD2 and graphic PSD2 are different because you are breastfeeding two extra points in the tables (t0, df). When graphic entry of data in the tables, they interpret not automatically information of t0 and df.  Actually they do not yet receive this information.  You must program the scales with nodes of property.  If you simply draw the order of magnitude, the spectra are very similar.

  

  ^ ^ ^ This confuses only the chart!

  The spectral forms differ slightly as the power spectrum of FFT and PSD.vi uses a default Hanning window.

  Lynn

• Why do I get an incorrect result for my Pl/SQL procedure?

  Hello, I just try to figure out % limpCount consists of playercount
  The result is always 100 even if limpcount and playercount are correct when it is printed.
  
  CREATE OR REPLACE PROCEDURE workoutVPIPProc
  IS
  nrplayersV_PIP NUMBER (10);
  handCount NUMBER (10);
  playercount NUMBER (10);
  limpCount NUMBER (10);
  Temp NUMBER (10);
  BEGIN
  SELECT count (nlhm_hands. NLHM_hand_number) IN handCount OF nlhm_hands;
  SELECT sum (nlhm_hands. NLHM_no_players_involved) IN nlhm_hands playercount;
  SELECT sum (nlhm_hands. NLHM_no_players_limp) IN limpCount OF nlhm_hands;
  Temp: = limpCount/playercount;
  nrplayersV_PIP: = temp * 100;
  DBMS_OUTPUT. Put_line (' the average VPIP for NLHM is: ' | nrplayersV_PIP |) "% of the sum of players limping: ' | limpCount |': ' | playercount);
  END workoutVPIPProc;
  /

  A tip:

  SQL> select  cast(123/77 as number(10)) from dual;
  
  CAST(123/77ASNUMBER(10))
  ------------------------
                         2
  
  SQL> select  cast(123/77 as number(10,5)) from dual;
  
  CAST(123/77ASNUMBER(10,5))
  --------------------------
                      1.5974
  
  SQL> 
  

  SY.

• Connect Reporting different results to look at a pdf file

  Through a program of training and receipt, a team of users is necessary to read a pdf file, close it, and then recognize their agreement with the terms in the pdf file. In order to show completed in the curriculum, all courses must be completed. The pdf is set up as a course and need to show as completed. I see the results of different people who consult this pdf file. Some users show over some not taken when they say they have opened the pdf file and found that it. This is a 2 page document. Of the reasons why we would get such different results? To get a complete users should consult the two pages? Other suggestions?

  When I see this problem, it usually has to do with the conversion of the PDF file to allow the display of reports. Either re - download the PDF file and update the price or convert the document to HTML and use this current version. PDF conversion is random and frequent, but will allow some users to obtain a full and some show status does not matter how much the view the PDF.

• When you try to find the IP address of my computer, I see two different results with two different numbers. Which is accurate?

  original title: a different output for ping - an IP address

  I am trying to determine the name of the computer to an IP address

  When I open a command prompt in a computer (Windows XP connected to our domain) and type ping - a [IP address], I get a result

  When I open a command prompt in another computer (Windows Server 2008 connected to the WORKING group) and type ping - a [IP address], I get a different result

  And there are other times when ping - [IP address] will display the name of the computer on a computer (usually the Windows Server 2008), but not the other

  I tried to google

  1. why this happens

  2. what result is correct

  Please specify.

  The order of DNS in Windows name resolution is as follows:

  1. Name of the local host (file Hosts Local generally in c:\windows\system32\drivers\etc\hosts)
  2. Cache Client DNS resolution
  3. DNS server
  4. Cache of NetBIOS names
  5. WINS server
  6. NetBIOS broadcasts
  7. File LMHosts (same location as the HOSTS file)

  The reason you get different results could be because machines could be on different subnets (different results for broadcast), using a different DNS server machines or are configured for different WINS servers, or the names are already cached because of prior activity.

  HTH,
  JW

• using the same search terms on ebay, getting different results on firefox exploer

  using the same words to search on ebay for internet explorer, I get results more when I use ebay on FireFox > is cutting some of the results when using Firefox

  It is always possible that eBay is to differentiate between browsers and gives different results, based on previous visits.
  You can try to delete cookies in two browsers to see if it has an impact.

  "Clear the Cache":

  • Firefox/tools > Options > advanced > network > content caching Web: 'clear now '.

  'Delete Cookies' sites causing problems:

  • Firefox/tools > Options > privacy > "Use the custom settings for history" > Cookies: "show the Cookies".

• Why do I get emails intended for person with completely different e-mail address?

  Why do I get emails intended for person with completely different e-mail address? some of the Emails are addressed to names nowhere near the same spelling to my address and I always get them

  You CAN receive email if your email is added to the BCC list [1].

  Most spammers use this medium to spam others.

  [1] http://en.wikipedia.org/wiki/Blind_carbon_copy

  See you soon!

• I have synced my LR my android mobile. Why the images in a different order from the catalogue on the PC and how can I get them in the same order?

  I have synced my LR my android mobile. Why the images in a different order from the catalogue on the PC and how can I get them in the same order?

  You can check the order of Lightroom Mobile synchronization.

  Click on the collection name and choose the last option to sort.

  It should be similar to this screenshot:

  

  Once you get to know Lightroom Mobile images sort order, you can set the same sort order on your desktop of Lightroom.

• Get different results even script according to what VM it hits?

  Hello.

  IM starting to Powershell and PowerCLI, so you will know at what level it is on =)

  I get different results depending on what VM my script hits (whetever they may or may not have more than one drive). I do not understand how I can fix this...

  For example, I created 4 new virtual machines.

  TestVMfirst1 have only a single drive

  TestVM02 have 2 drives

  TestVM03 have 3 discs

  TestVM04 have only a single drive

  My goal is to get a CSV with all disks included. I want the name, the data store and SizeGB, this info I get from Get-hard drive.

  When I run my script to select all 4 virtual machines:

  $VMs = get-cluster-name kluster01 : get-vm-name TestVM *

  -----------------------------------------------------------------------------

  $VMs = get-cluster-name kluster01 | Get-vm-name TestVM *.

  $Results = @)

  {foreach ($VM to $VMs)

  $Result = new-object PSObject

  $Result | Add-Member - membertype NoteProperty-name 'Name' - value $VM. Name

  $VMDiskCount = 1

  Get-$VM hard drive | {foreach}

  $disk = $_

  $Result | Add-Member-'Disc ($VMDiskCount) name' name-value $disk. Name - membertype NoteProperty

  $Result | Add-Member-name '($VMDiskCount) Datastore disk' - value $disk. Filename.Split(']') [0]. TrimStart('[') - membertype NoteProperty

  $Result | Add-Member-name 'Disk ($VMDiskCount) SizeGB' - value ([math]: round ($disk.) CapacityKB / 1 MB))-membertype NoteProperty

  $VMDiskCount ++

  }

  $Results += $Result

  }

  $Results | Select-object * | format-table

  -----------------------------------------------------------------------------

  I get the result with max 1 disc:

  Name	(1) name of disc	Disk data store (1)	SizeGB disc (1)
  ----	-----------	----------------	-------------
  TestVMfirst1	Hard drive 1	DS-201	40
  TestVM02	Hard drive 1	DS-201	40
  TestVM03	Hard drive 1	DS-201	40

  But if I run the same thing but with TestVM0 * (selects 4-2 VMs):

  $VMs = get-cluster-name kluster01 | Get-vm-name TestVM0 *.

  -----------------------------------------------------------------------------

  $VMs = get-cluster-name kluster01 | Get-vm-name TestVM0 *.

  $Results = @)

  {foreach ($VM to $VMs)

  $Result = new-object PSObject

  $Result | Add-Member - membertype NoteProperty-name 'Name' - value $VM. Name

  $VMDiskCount = 1

  Get-$VM hard drive | {foreach}

  $disk = $_

  $Result | Add-Member-'Disc ($VMDiskCount) name' name-value $disk. Name - membertype NoteProperty

  $Result | Add-Member-name '($VMDiskCount) Datastore disk' - value $disk. Filename.Split(']') [0]. TrimStart('[') - membertype NoteProperty

  $Result | Add-Member-name 'Disk ($VMDiskCount) SizeGB' - value ([math]: round ($disk.) CapacityKB / 1 MB))-membertype NoteProperty

  $VMDiskCount ++

  }

  $Results += $Result

  }

  $Results | Select-object * | format-table

  -----------------------------------------------------------------------------

  I get this result:

  Name	(1) name of disc	Disk data store (1)	(1) name of the disc SizeGB disc (2).	Disk data store (2)	SizeGB disc (2)
  ----	-----------	----------------	------------- -----------	----------------	-------------
  TestVM02	Hard drive 1	DS-201	Hard 40 2 disc	DS-201	10
  TestVM03	Hard drive 1	DS-201	Hard 40 2 disc	DS-202	10
  TestVM04	Hard drive 1	DS-201	40

  I miss all my disks on TestVM03, I seems that the first VM sets the limit on how many records can be issued in the table... A dirty solution is to create a model on the first target VM disks, but it seems the wrong way to solve my problem.

  Thanks in advance

  You're conclusion is correct, I'm afraid, the first line determines how many properties, you will see.

  Alternatively, you can sort the lines on the number of properties in descending order.

  Something like that

  $Result | Tri-objet-property {($_ |)} Get - Member). {Count of}-descending | Format-Table

• Flatten channel gives different results on a RT system compared to a Windows system?

  When I flatten a structure moderately complex to a string in LabVIEW Windows, I get a slightly different result than when I do the same thing (interactive) Looking RT. LabVIEW to hexadecimal display produced channels, towards the tail end of the strings that I see:

  Windows: A 999, 0000. FB99 A 9999 9999 9999 9, 00
  RT: 9999 A000... FB99 9999 9999 99A 0 0000

  Shouldn't get the same value of the two systems?

  Your problem is the use of the extended data type.  I don't have a cRIO to do more thorough testing, but the only items that do not match are the two elements of smoothing.  The two values differ by about - 5.54976E - 18 (that is to say, not much - less, in fact, the value of epsilon machine).  If you use the context-sensitive help and hover on an EXT thread, you'll see a note indicating the precision varies by platform, so it must be provided.  Also documented A in aid, under the heading "digital, data types table.  Is there a reason why a double precision is not sufficient?

• CONNECT BY giving different results / duplicate records

  I have a hierarchy like this:

  UserTable-> username, treename_code

  username treename_code

  Scott TREE

  Henry TREE

  TREENAMES-> treename_code

  treename_code

  TREE

  subtree-> id, parent_id, treename_code

  ID parent_id treename_code

  1 null TREE

  2 1 TREE

  select case when connect_by_isleaf = 1 then 0
              when level = 1             then 1
              else                           -1
         end as status, 
         level, 
         subtree.id as value, 
         SYS_CONNECT_BY_PATH(subtree.id, '/') Path
    from usertable,
         treenames,
         subtree
    where upper(usertable.username)=upper(:username)
      and treenames.treename_code=usertable.treename_code
      and subtree.treename_code=treenames.treename_code
    start with subtree.parent_id is null
    connect by subtree.parent_id=prior subtree.id;
  
  

  Database version: 11.2.0.1.0

  According to the user, the order of results is different: we give values:

  1-2-2 (double on '2')

  gives another

  2 1-2 (always double on '2')

  BUT on another database, same version, it gives:

  1-2 (which is expected)

  Any idea?

  This is essentially because of the what the predicate to filter for the USER name is applied. If you are using an Inline view, you will get the desired result.

  Check this. I just simplified your query by removing just the other columns in the select list. But the CONNECT BY and are of the join of the table intact.

  SQL > select subtree.id
  2 usertable,
  3 treenames,
  subtree 4
  5 where upper (usertable.username) = upper ('scott')
  6 and treenames.treename_code = usertable.treename_code
  7 and subtree.treename_code = treenames.treename_code
  8 start
  9 with subtree.parent_id is null
  10 connect
  11 by prior subtree.id = subtree.parent_id;

  ID
  ----------
  2
  1
  2

  SQL > select * from table (dbms_xplan.display_cursor);

  PLAN_TABLE_OUTPUT
  -------------------------------------------------------------------------------------------------
  ----------------------------------------------------------------------------------------
  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |
  ----------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT |           |       |       |     7 (100) |          |
  |*  1 |  FILTER |           |       |       |            |          |
  |*  2 |   CONNECT BY WITH FILTERING |           |       |       |            |          |
  |*  3 |    HASH JOIN |           |     2.   102.     7 (15) | 00:00:01 |
  |   4.     THE CARTESIAN MERGE JOIN.           |     2.    90.     4 (0) | 00:00:01 |
  |*  5 |      TABLE ACCESS FULL | SUBTREE.     1.    32.     2 (0) | 00:00:01 |
  |   8 2 SORT OF BUFFER.           |     2.    26.     2 (0) | 00:00:01 |
  |   7.       TABLE ACCESS FULL | USERTABLE |     2.    26.     2 (0) | 00:00:01 |
  |   3 ×     TABLE ACCESS FULL | TREENAMES |     1.     8-2-2 (0) | 00:00:01 |
  |*  9 |    HASH JOIN |           |     1.    51.     7 (15) | 00:00:01 |
  |  10.     THE CARTESIAN MERGE JOIN.           |     1.    45.     4 (0) | 00:00:01 |
  | * 11 |      HASH JOIN |           |       |       |            |          |
  |  12.       CONNECT PUMP |           |       |       |            |          |
  |  13.       TABLE ACCESS FULL | SUBTREE.     1.    32.     2 (0) | 00:00:01 |
  |  14.      KIND OF BUFFER.           |     2.    26.     2 (0) | 00:00:01 |
  |  15.       TABLE ACCESS FULL | USERTABLE |     2.    26.     2 (0) | 00:00:01 |
  |  16.     TABLE ACCESS FULL | TREENAMES |     1.     6.     2 (0) | 00:00:01 |
  ----------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):
  ---------------------------------------------------

  1 Filter (SUPERIOR ("USERTABLE".) "USER NAME") = "SCOTT") "
  2 - access("SUBTREE".") PARENT_ID "= NULL PREREQUISITE)
  3 - access("TREENAMES".") TREENAME_CODE '=' USERTABLE '. "" TREENAME_CODE "AND
  "SUBTREE". "" TREENAME_CODE "=" TREENAMES. " ("' TREENAME_CODE")
  5 - filter("SUBTREE".") (PARENT_ID' IS NULL)
  9 - access("TREENAMES".") TREENAME_CODE '=' USERTABLE '. "" TREENAME_CODE "AND
  "SUBTREE". "" TREENAME_CODE "=" TREENAMES. " ("' TREENAME_CODE")
  11 - access("SUBTREE".") PARENT_ID "= NULL PREREQUISITE)

  If you see that the filter for the USER name is applied after that CONNECT BY runs. But if I use a view online. then check it

  SQL > select id
  2 starting at)
  3. Select subtree.id
  4, subtree.parent_id
  5 usertable,
  6 treenames,
  subtree 7
  8 where upper (usertable.username) = upper ('scott')
  9 and treenames.treename_code = usertable.treename_code
  10 and subtree.treename_code = treenames.treename_code
  11          )
  Starter 12
  13 with parent_id is null
  14 connect
  15 by parent_id = prior id;

  ID
  ----------
  1
  2

  SQL > select * from table (dbms_xplan.display_cursor);

  PLAN_TABLE_OUTPUT
  -------------------------------------------------------------------------------------------------
  ---------------------------------------------------------------------------------------
  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |
  ---------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT |           |       |       |     7 (100) |          |
  |*  1 |  CONNECT BY WITH FILTERING |           |       |       |            |          |
  |*  2 |   HASH JOIN |           |     1.    51.     7 (15) | 00:00:01 |
  |   3.    THE CARTESIAN MERGE JOIN.           |     1.    45.     4 (0) | 00:00:01 |
  |*  4 |     TABLE ACCESS FULL | USERTABLE |     1.    13.     2 (0) | 00:00:01 |
  |   5.     KIND OF BUFFER.           |     1.    32.     2 (0) | 00:00:01 |
  |*  6 |      TABLE ACCESS FULL | SUBTREE.     1.    32.     2 (0) | 00:00:01 |
  |   7.    TABLE ACCESS FULL | TREENAMES |     1.     6.     2 (0) | 00:00:01 |
  |*  8 |   HASH JOIN |           |     1.    51.     7 (15) | 00:00:01 |
  |   9.    THE CARTESIAN MERGE JOIN.           |     1.    45.     4 (0) | 00:00:01 |
  | * 10 |     HASH JOIN |           |       |       |            |          |
  |  11.      CONNECT PUMP |           |       |       |            |          |
  |  12.      TABLE ACCESS FULL | SUBTREE.     1.    32.     2 (0) | 00:00:01 |
  |  13.     KIND OF BUFFER.           |     1.    13.     2 (0) | 00:00:01 |
  | * 14 |      TABLE ACCESS FULL | USERTABLE |     1.    13.     2 (0) | 00:00:01 |
  |  15.    TABLE ACCESS FULL | TREENAMES |     1.     6.     2 (0) | 00:00:01 |
  ---------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):
  ---------------------------------------------------

  1 - access("SUBTREE".") PARENT_ID "= NULL PREREQUISITE)
  2 - access("TREENAMES".") TREENAME_CODE '=' USERTABLE '. "" TREENAME_CODE "AND
  "SUBTREE". "" TREENAME_CODE "=" TREENAMES. " ("' TREENAME_CODE")
  4 filter (SUPERIOR ("USERTABLE".) "USER NAME") = "SCOTT") "
  6 - filter("SUBTREE".") (PARENT_ID' IS NULL)
  8 - access("TREENAMES".") TREENAME_CODE '=' USERTABLE '. "" TREENAME_CODE "AND
  "SUBTREE". "" TREENAME_CODE "=" TREENAMES. " ("' TREENAME_CODE")
  10 - access("SUBTREE".") PARENT_ID "= NULL PREREQUISITE)
  14 filter (SUPERIOR ("USERTABLE".) "USER NAME") = "SCOTT") "

  Here, the filter is applied before CONNECT you IS executed. This is the reason why you get the unexpected result in your query. Use the online mode.

• Colors as a very different result of preview

  I just installed the latest Photoshop CC. whenever I'm in Image → adjustments → whatever it is, the result turns out to be completely different from what I see in the preview. For example, when I use Hue to colorize a photo:

  

  If I do the same using the appropriate adjustments layer, I get the same result as in the Preview on the screen, but as soon as I save the image in a non - psd format, colors are gone.

  It is impossible to work like this. You have an idea why this happens? I should note that I work in the standard RGB mode and "proof colors" option is disabled (but if I let it, the results are the same).

  I just realized what the problem was. The photos, I'm working on right now are huge woodcuts, which is what looks like a gradient of color is actually more or less dense lines in only a few shades of gray. The preview is calculated depending on the photo, we see on the screen (that is, with all the shades of gray that do not exist when we zoom). Obviously, applying the curves or color change in the image resized with new shades of gray is not the same but to apply the same adjustment to the original high-resolution photo and scaling it down.

  Funny problem, indeed. This is the first time I'm editing woodcuts; It took me a few hours to realize what could be the problem.

• List of deployed applications. Different results for different hierarchies of MBean

  Hello

  When I list deployed applications, I get different results depending on what hierarchy MBean I question:

  • serverConfig():

  wls:/MY_WEBLOGIC_DOMAIN/serverConfig> listApplications() APPLICATION_1APPLICATION_2
  

  • domainRuntime():

  wls:/MY_WEBLOGIC_DOMAIN/domainRuntime/AppRuntimeStateRuntime/AppRuntimeStateRuntime> ls()
  -r--   ApplicationIds                               java.lang.String[APPLICATION_1, APPLICATION_2, APPLICATION_3]
  

  No idea why is APPLICATION_3 in the list?

  
  

  Thanks in advance,

  Luis

  
  

  PS: if I apply directly to the managed server:

  wls:/MY_WEBLOGIC_DOMAIN/domainRuntime/ServerRuntimes/prodGAD_1> ls('ApplicationRuntimes')
  dr--   bea_wls9_async_response
  dr--   bea_wls_cluster_internal
  dr--   bea_wls_deployment_internal
  dr--   bea_wls_diagnostics
  dr--   bea_wls_internal
  dr--   APPLICATION_1
  dr--   APPLICATION_2
  

  Hi Vijaya,

  Thanks for your reply, yes you are right, my config.xml file I see this request:

    
      APPLICATION_3
      ...
      ear
      ...ear
      DDOnly
    
  

  But now that I read your response, I already rebooted the AdminServer. This new beginning has resolved the problem.

  Thank you

  Luis