Generating unique random number with a Boolean signal on an RT target

Similar Questions

• Generate a random number with a decimal point

  I searched all over the internet and cannot find how to generate a random number that had a decimal.

  I'm trying to randomly generate numbers between 12.0 and 13.0.

  Here is my code... I know its bad because of Math.round and Math.random, but I can't seem to find something that deals with a decimal...

  addEventListener (Event.ENTER_FRAME, fl_EnterFrameHandler_1);

  function fl_EnterFrameHandler_1(event:Event):void
  {
  Volt.Text = Math.round (Math.random () * (1) + 12) m:System.NET.SocketAddress.ToString ();
  }

  Any suggestions?

  -Pat

  Try this,

  addEventListener(Event.ENTER_FRAME, fl_EnterFrameHandler_1);
  
  function fl_EnterFrameHandler_1(event:Event):void
  {
  
       var rndNum:Number = int(Math.random()*10)/10; // Generate random num with 1 decimal place
       var newVal:Number = newVal + 12;
       volt.text = newVal.toString();
  }
  

  If you want 2 decimal places then replace the 10 per 100.

• Random number with no repeat

  Hi, I made a new class to generate a random number with no repeat between the x and the y number. I want to share with all of this. Let me know incase of any problem. while I could change that.
  
  To call the following class, simply call the class as follows:
  var randomObj: Random = new Random();
  var newArray:Array = randomObj.getRandom ();
  Now this newArray has all the different numbers at each location to its length.
  

  Hi, I made a new class to generate a random number with no repeat between the x and the y number. I want to share with all of this. Let me know incase of any problem. while I could change that.

  To call the following class, simply call the class as follows:
  var randomObj: Random = new Random();
  var newArray:Array = randomObj.getRandom ();
  Now this newArray has all the different numbers at each location to its length.

• Generate a random number

  I have this function to generate a random number

  RandNum = genRand();

  public function genRand (): int
  {
  Return (Math.Random ());
  }

  but he seemed to generate the number is 0

  any1 have more luck with this?

  Hey,.

  According to the range of numbers you're trying to get it, you must either change the type returned or modfiy before he returned. What happens is the number that you generate is probably something like 0.9393 (example) and his cutting the comma because you return a value type int value (no decimals).

  try to modify the function to do this:

  public function genRand():int
          {
              return(Math.random() * 10);
          }
  

  and you will get a number from 0 to 10. If you want a number from 0 to 100, you can use 100 instead of ten, and so on. This will give you back not decimal numbers. If you want decimal numbers simply change the type of data returned to the number instead. hope that helps. Good luck!

• How to build a VI that generates a random number between 1 and 80... Help!

  Generate a VI that generates a random number between 1 and 80

  Divide the random number by a number specified in the front panel.

  If the number of seizures is zero, the VI program should light a LED in the face to indicate a divide by zero error.

  Hai edwardty2009,

  Welcome to the forum.

  Thanks for the congratulations.

  Your problem is solved? If so can you please mark as solution what post help better to solve your problem.

  Thank you

  Mathan

• 5 digit unique random number based on the year

  Hello
  I need 5 digit unique random number based on the year. If the new year then duplicate random number allowed.
  Thank you

  If only 5-digit numbers are needed you can extract some transformation injective (http://en.wikipedia.org/wiki/Injective_function) and you could easily check for uniqueness:
  substr (to_char (ln (sequence_value)), 10, 5)
  substr (to_char (exp(1 / sequence_value)), 20, 5)
  ...

  Concerning

  Etbin

• Generator of random numbers with Page break

  Hello

  I was wondering if it is possible to write a JavaScript script that will:

  -generating a random number

  -When a random number is generated, a specific page in the document is loaded.

  For example, when 4 is generated, from 1 to 6, you would jump to page 10, when 5 is built, you

  jump to page 20, etc.

  The idea is that when you press the key which is linked this javascript, you will automatically be

  go to a random page.

  This would be possible at all?

  Thank you!

  Kind regards

  Fabian

  It is possible, but your description is not very clear. What is the relationship between the random number and the page you jump to? Why not just generate a random number between 1 and N (N being the number of pages in the file), and then go to this number?

• generate a random number between 1 and 10

  Dear All;
  
  I have an insert... Select and in one of the columns, I would like to generate a random number from 1 to 10, how is this possible. Thank you.

  Select round (dbms_random.value (1,10)) double;

  http://download.Oracle.com/docs/CD/B28359_01/AppDev.111/b28419/d_random.htm#CDEJAHCB

• How to generate a random number within a specified tolerance and control than tolerance.

  I am trying to simulate data without using a data acquisition device using a random number generator and I want to be able to control the "range" the random number generated well.  On the front panel, the user can enter a nominal number, and the random number generator would generate numbers more or less disponibles.003 this number nominal.  The data would be delayed on a chart.  Someone knows how to do this?  Or if it is still possible?

  Just for the sake of information, the random number is supposed to resemble thickness measures, that's why I want to simulate more and less disponibles.003 because the data might be thinner or thicker than the nominal value.

  Thanks in advance!

  Two ways of approaching the issue.  First of all, for even distribution, you can 'Roll the dice', which is the (0,1) random number function, multiply the result by 0.06 and then add Mean - 0.03 to center around average distribution.  If you simulate a real process, my initial guess would be that the results would follow a normal distribution.  In this case, you can use the VI of white noise Gaussian of the palette of generation of signals with a standard deviation of 0.015 if you wanted 0.03 to be the point of 2 sigma, then add average results.

• Unique random number

  Hello

  Oracle 11.2.0.1

  Windows

  I have a table something like this:

  create table (ID, number of rnd) rnd;

  I need a process something like this:

  exec genrnd (200,300);

  After executing the procedure, there will be 100 lines in the table of rnd and there will be unique random numbers in the column of rnd.  OK, suppose if I run once again something like this:

  exec genrnd (173,514);

  therefore table will be truncated and (514-173) + 1 = 342 lines will be rnd table and new unique random numbers will be in the column of rnd.

  Column ID is just at the end of the order of.  There will be 1,2,3... 100 or 1,2,3,4... numbers 342.

  I get random number in this way:

  Select trunc (dbms_random.value (200,300)) rnd twice;

  Select trunc (dbms_random.value (173,514)) rnd twice;

  but number must be unique within the given range, so I don't get how this is possible, please help me.

  Thank you.

  Insert into rnd

  Select rownum, one of

  (

  Select * from

  (

  Select rownum + start_value - 1A

  Double connect rownum<= end_value="" -="" start_value="" +="">

  )

  order of dbms_random.value

  );

  This query has 4 parts

  (1) generation X Y numbers in order

  (2) randomized data generated

  (3) assign a rownum for each row of data

  (4) Insert the result in the table

  So he adapts to the requirements of the opus and don't know how

  > Order by on the insert does nothing

  available in photo with this code.

• generate a random number in a range of duplication no

  Good day people,

  I need help once again. I want to animate an image inside a movieclip with frame label animate1, animate2, animate3 and animate4.

  I managed to generate random numbers, but my concern is I want my animation not animate same image twice, here is my code.

  = main time line code =.

  function randRange(min:Number,_max:Number):Number {}
  Generate a number between and including min - max
  var randomNum:Number = Math.floor (Math.random () *(max-min)) + min;
  Return randomNum;
  }

  
  

  build table to hold the frame label names
  var frameArray:Array = new Array();
  frameArray [0] = "animate1";
  frameArray [1] = "animate2";
  frameArray [2] = "animate3";
  frameArray [3] = "animate4";
  
  Get created random number
  var n: Number = plageAleatoire (0, frameArray.length);

  
  

  trace ("n": + n);

  
  

  Stop Frame label name
  This.img_ani.gotoAndStop (frameArray [n]);

  
  

  trace ("frameArray:" + frameArray [n])

  = label code and frame inside a clip with 4 frames containing different pictures =.

  as layer: stop();

  image tag: animate1, animate2, animate3, animate4

  Any help is greatly appreciated. Thanks in advance.

  It is not a routine of brewing, integrated, but there is a pretty standard shuffle function that was happening around...

  var frameArray:Array = new Array();
  frameArray [0] = "animate1";
  frameArray [1] = "animate2";
  frameArray [2] = "animate3";
  frameArray [3] = "animate4";

  function shuffle (a) {}
  var p;
  var t;
  Ivar var;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

  trace (frameArray);  See the property before shuffle

  Use:
  Shuffle (frameArray);

  trace (frameArray);  Show after shuffle

• Need to generate unique sequence number based on category

  Hello

  I have to update the NEW_NUMBER column with a unique number, taking into account the category column.

  Here is the table structure and data.

  {code}

  create table (sample)

  CATEGORY VARCHAR2 (100),

  NUMBER VARCHAR2 (100),

  NEW_NUMBER VARCHAR2 (100))

  {code}

  {code}

  insert into sample values ("CAPACITOR ', ' 36858'," ");

  insert into sample values ("CAPACITOR ', ' 37858'," ");

  insert into sample values ("CAPACITOR ', ' 36958'," ");

  Insert the sample values ('RÉSISTANCE', '46858', ");

  Insert the sample values ('RÉSISTANCE', '47858', ");

  Insert the sample values ('RÉSISTANCE', '46958', ");

  {code}

  I have to update the NEW_NUMBER column with a unique number, taking into account the category column.

  Output would be like that.

  {code}

  Insert in the values('CAPACITOR','36858','270-01-0000001') sample.

  Insert in the values('CAPACITOR','37858','270-01-0000002') sample.

  Insert in the values('CAPACITOR','36958','270-01-0000003') sample.

  Insert in the values('RESISTOR','46858','370-01-0000001') sample.

  Insert in the values('RESISTOR','47858','370-01-0000002') sample.

  Insert in the values('RESISTOR','46958','370-01-0000003') sample.

  {code}

  If you can help generate for one category, I'll do it for the other categories.

  Thanks in advance.

  Thank you

  LAK

  Not sure how you came up with 270 and 370. But with the information that you never provided that that's what I came with.

  SQL > select * sample;

  CATEGORY OLD_NUMBER NEW_NUMBER
  ---------- -------------------- --------------------
  CAPACITOR 36858
  CAPACITOR 37858
  CAPACITOR 36958
  RESISTANCE 46858
  RESISTANCE 47858
  RESISTANCE OF 46958

  6 selected lines.

  SQL > fusion in a sample
  2 using the)
  3. Select category
  4, old_number
  5, decode (category, "CAPACITOR ', ' 270', 'RÉSISTANCE', '370'")
  6                 || ' '-01 -.
  7                 || LPAD
  8                    (
  9 row_number() over (partition by order of category by old_number)
  10                     , 7
  11                     , '0'
  (12) new_number
  13 for example
  (14) b
  15 on)
  a.category 16 = b.category and
  17 a.old_number = b.old_number
  18        )
  19 when matched then
  20 update set a.new_number = b.new_number;

  6 lines merged.

  SQL > select * from sample by category, old_number;

  CATEGORY OLD_NUMBER NEW_NUMBER
  ---------- -------------------- --------------------
  CAPACITOR 36858 270-01-0000001
  CAPACITOR 36958 270-01-0000002
  CAPACITOR 37858 270-01-0000003
  RESISTANCE 46858 370-01-0000001
  RESISTANCE 46958 370-01-0000002
  RESISTANCE 47858 370-01-0000003

  6 selected lines.

• generator of random numbers with conditions?

  Hiya,

  I'm pretty new to Flash so this can be a very easy fix for someone who knows what they are doing...

  Here is my code...

  the idea is that the player clicks on a button to look out the window and then a 4 options arise randomly, he'll be CHARGED 5 points of energy for the privilege.

  LOOKING OUT WINDOW - this section works fine...

  trainWINDOW.addEventListener (MouseEvent.CLICK, windowcheck);
  
  function windowcheck(event:MouseEvent):void
  {
  updateScoreENERGY();
  }
  function updateScoreENERGY (): void
  {
  If (scoreENERGY < 5) {}
  WINDOWRESULT.text = ' YOU ARE TOO TIRED to DRAG YOURELF until THE WINDOW";} m:System.NET.SocketAddress.ToString ().
  on the other

  scoreENERGY-= 5;
  randomzombieforcast();
  energycptext. Text = scoreENERGY.toString ();
  }

  the section above works fine, I don't think that the 'randomzombieforcast' function works

  
  I think the problem starts here...

  function randomzombieforcast()
  {
  var Results:Number is Math.floor (Math.random () * 4) + 1;.
  return results ;}

  {If (results == 1)
  WINDOWRESULT.text = "there are only a few zombies around (day light)"m:System.NET.SocketAddress.ToString ();
  If (results == 2)
  WINDOWRESULT.text = "there are a certain number of zombies hidden nearby (average day)"m:System.NET.SocketAddress.ToString (); ".
  If (results is 3)
  WINDOWRESULT.text = ' there are a lot of zombies LURKING in your street (day) "(heavy) m:System.NET.SocketAddress.ToString;»
  If (results is 4)
  WINDOWRESULT.text = "I wouldn't look for if I were you! (Revelation) "m:System.NET.SocketAddress.ToString (;})
  

  Any help at all would be greatly appreciated

  Thank you!

  Try...

  function randomzombieforcast()
  {
  var Results:Number is Math.floor (Math.random () * 4) + 1;.

  If (results == 1) {}
  WINDOWRESULT.text = "there are only a few zombies autour (day light);

  } Else if (results == 2) {}
  WINDOWRESULT.text = "there are a number of hidden nearby zombies (medium day);"
  } Else if (results == 3) {}
  WINDOWRESULT.text = ' there are a lot of zombies in your street TAPI (heavy day);
  } Else if (results == 4) {}
  WINDOWRESULT.text = "I wouldn't look for if I were you! (apocalypse) » :

  }

  }

• Need help with a JavaScript to generate random number

  Hello

  First things first. I don't know the JavaScript J.

  When I thought about a ready to use solution to generate a random number in Captivate, I found this on a forum of LinkedIn.

  (1) add a user to your project variable, called "NombrAl". Its value can be zero.

  (2) add a text caption with ' $$randomNumber$ $"inside, to check if your script works.

  (3) add a button to the slide. Give him one on success Action to run JavaScript. Clear the check box 'continue playing the Project '.

  (4) add the following text in the button Script_Window:

  var objCP = document. Captivate;

  var rand = 1 + Math.floor (Math.random () * 10);

  onButtonClick() {} function

  objCP.cpEISetValue ('NombrAl', rand);

  }

  onButtonClick();

  However, it is (as the poster in the forum warned) for 7 Captivate does not. Can someone please help?

  I am open to all other methods to achieve the same result.

  Thanks in advance,

  Anthony

  Hi Anthony,.

  During the test, make sure that you are testing from a web server where the web address starts with http or https.  When you set the captivate variable "NombrAl" try this instead:

  objCP.cpEISetValue ('m_VarHandle.randomNumber', rand);

  This will work for the SWF output.  If you want to work for the release of HTML5 and SWF, try this code:

  window.onButtonClick = function(){
            var rand = generateRandomNumber(1, 10);
            setCpVariable('randomNumber', rand);
  
  };
  
  window.generateRandomNumber = function(min, max){
            var randomNum = 0;
  
            if(!isNaN(parseFloat(min)) && !isNaN(parseFloat(max))){
                      min = Number(min);
                      max = Number(max);
                randomNum = Math.floor(Math.random() * (max - min + 1)) + min;
            }
  
            return randomNum;
  };
  
  window.setCpVariable = function (cpUserVariableName, variableValue) {
            /* Check for HTML5 vs. SWF output */
            if (typeof window.cp === 'undefined') {
                      /* We have SWF output, so Get the Captivate Object */
                      var objCp = document.getElementById('Captivate');
  
                      if (objCp && objCp.cpEISetValue) {
                                /* Set the Captivate User variable with the JavaScript variable, variableValue */
                                objCp.cpEISetValue('m_VarHandle.' + cpUserVariableName, variableValue);
                      }
            } else {
                      /* We have HTML5 output */
                      /*If variable does not exist off of the window object, then use the variables manager*/
                      if (typeof window[cpUserVariableName] === 'undefined') {
                                if (cp.vm && cp.vm.setVariableValue) {
                                          cp.vm.setVariableValue(cpUserVariableName, variableValue);
                                }
                      } else {
                                window[cpUserVariableName] = variableValue;
                      }
            }
  };
  
  window.onButtonClick();
  

  Don't forget to test this situation from a web server either local security prevents the javascript code for execution.

  Best,

  Jim Leichliter

• How to generate a single random number in a MySQL database

  I create a volunteer and also a separate request form from the seller for an air show. The volunteer and seller info is stored in separate tables in MySQL db, a line by volunteer or the seller. There will be about 100 volunteers and 50 sellers. When the request should immediately be printed by the applicant signed and mailed in. This year we had problems with some people who do not immediately print asked, so I would still give them the possibility to print immediately, but also to send them an email with a link to their specific line in the MySQL database. I have an AutoIncrement primary key for each table field, but I think to send this key to the applicant in an email would be too easy for them to guess a different id and access the information of others.

  I think I should add a column for each table containing a unique random number and then I would send this key in the e-mail to the applicant. So, can anyone suggest a simple way to do this or suggest a better way to give the applicant a way to access their own request and nobody elses not after submitting their form?

  Thank you all.

  Tony Babb

  In your code, you should:

   VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, $s)",
  

  Change the $s to %s and that should solve the problem for you.

  Let me know.  Thank you!

  Chad