Get the difference in days between 2 dates in Essbase 9.3.1

Similar Questions

• find the difference in days between two dates

  Hello world
  
  I'm trying to find out the difference in days between two dates and the execution of the query that I'm passing
  
  SELECT TO_char(sysdate, 'dd/mm/yyyy') - TO_char('15/11/2011', 'dd/mm/yyyy') DAYS FROM DUAL
  
  the error I get is
  
  ORA-01722: invalid number
  01722 00000 - "invalid number."
  * Cause:
  * Action:
  
  Could someone please help.
  
  Thanks in advance

  user10636796 wrote:
  Hello world

  Thanks a lot for all the replies. I am trying to apply it in a statement to my table like this

  SELECT trunc (sysdate) - TO_char (date_last_recommended, ' dd/mm/yyyy') DAYS OF recommendation;

  SELECT trunc (sysdate) - TRUNC (date_last_recommended) DAYS OF recommendation;

• Calculate the difference in days between two Dates

  Hello

  I'm trying to understand how to calculate the difference in days between two dates using JavaScript in LiveCycle. (Minimum = JavaScript knowledge)

  Where 'Start_Date' and 'Current_Date' are the names of the two dates in the palette of the hierarchy. (the two Date/time field)

  * Current date is using the object > value > execution property > current Date/time

  I need a text or number field showing the difference in days. (Difference_in_Days)

  I noticed the following code is pretty standard among other responses:

  var

  Start_date = new Date (Start_Date);

  var

  Current_Date = new Date (Current_Date);

  var

  nAgeMilliseconds = Current_Date.getTime) - Start_date.getTime ();

  var

  nMilliSecondsPerYear = 365 * 24 * 60 * 60 * 1000 ;

  I know there is lack of code and code above are may not be not correct.

  Please notify.

  OK, that's because of the way that javascript and works of the calculate event.  The field will be filled with whatever the script resolves at the end of execution. Technically, your script does not have a value because the last thing you do is an assignment to a variable.  Change the last line as follows:

  Math.ABS ((firstDate.getTime)

  ((- secondDate.getTime (()) / (oneDay));

  (eliminate the variable assignment) and get rid of the app.alert.  Your script will "return" (have) regardless of the value of calculation from the East and which will be stored in the field.

• Calculation of the difference in days between two Dates

  Hi all
  I have two text fields with dates in them (P2_CURRENT_TIME_POINT_TEST_START_DATE, P2_ORGINAL_TEST_START_DATE). I would like to assign another text field (P3_TIME_FROM_INITIAL_TEST), the difference between the two days. I use a calculation page and tried suptracting them right or a date function diff, I found online, but nothing seems to work. Could someone lend me a hand on this one?
  
  Thank you.

  Ben,

  Sorry, please try the following:

  :P3_TIME_FROM_INITIAL_TEST := TO_DATE(:P2_CURRENT_TIME_POINT_TEST_START_DATE, 'DD-MON-YYYY') - TO_DATE(:P2_ORGINAL_TEST_START_DATE, 'DD-MON-YYYY');
  

  Remember to substitute the correct format string MON-DD-YYYY.

  Kind regards
  Dan

  http://danielmcghan.us
  http://sourceforge.NET/projects/tapigen

  You can reward this answer by marking as being useful or correct ;-)

• Validate the difference in days between the dates in a table

  Greetings,
  
  I have a tabular form and date on each line. When the user saves the form, I want to sort the rows by chronological order of these dates, then go get the first and last date, calculate the difference between them and validate it.
  
  Does anyone know how to do?
  
  From now on, I came up with this:
  
  1. a PL/SQL Page process "before the calculations and Validations' which creates a collection and inserts lines in my tabular form (p_c004 being the date field):

  begin   
    if apex_collection.collection_exists('UPDATE_DATES') then
      apex_collection.delete_collection('UPDATE_DATES');
    end if;
  
    apex_collection.create_or_truncate_collection('UPDATE_DATES');
  
    for i in 1..apex_application.g_f04.count
    loop
        apex_collection.add_member(
            p_collection_name => 'UPDATE_DATES',
            p_c002            => htmldb_application.g_f02(i),
            p_c003            => htmldb_application.g_f03(i),
            p_c004            => htmldb_application.g_f04(i),
            p_c005            => htmldb_application.g_f05(i),
            p_c006            => htmldb_application.g_f06(i),
            p_c007            => htmldb_application.g_f07(i));
    end loop;
  end;

  and
  
  2. a "PL/SQL Error: Validation

  DECLARE
    l_count NUMBER;
  BEGIN
    apex_collection.sort_members('UPDATE_DATES', 4);
    l_count := apex_collection.collection_member_count('UPDATE_DATES');
  
    SELECT
    to_date(c004(l_count),'DD/MM/YYYY') - to_date(c004(1),'DD/MM/YYYY') Difference 
  
    FROM 
    apex_collections 
  
    WHERE 
    collection_name = 'UPDATE_DATES'
    and to_date(c004(l_count),'DD/MM/YYYY') - to_date(c004(1),'DD/MM/YYYY') < 30;
  
  EXCEPTION
    WHEN NO_DATA_FOUND THEN
      raise_application_error(-20101, 'Error');
  END;

  In my understanding, the validation must sort the collection in chronological order of the dates entered, calculate the difference in days between the nearest and farthest date and return it if it's less than 30 years (the difference in days allowed). If it's more than 30 years, the SELECT statement does not return anything and my block of exceptions raises a custom error that will trigger the validation "process of refusal."
  
  But when I try this, it tells me c004 does not exist and if I drop the parentheses, it works, but of course, it does not give the desired result.
  
  Any ideas?
  
  Best regards
  Mathieu

  Assuming that your domain is c004 then I don't see the need for the sorting of the collection.

  You can write a simple SQL select that sent you the desired result.

  Maybe something like this not tested

  SELECT
    max(to_date(c004,'DD/MM/YYYY')) - min(to_date(c004,'DD/MM/YYYY') ) Difference
    FROM apex_collections
    WHERE collection_name = 'UPDATE_DATES';
  

  The test if the result is > 30 days. If that's what you want to know.

• How to find the difference "within weeks" between two date values?

  Hi all

  Jdev version 11.1.1.7.1

  I used two < af:inputDate > & a < af:inputText > < af:panelFormLayout > components. My requirement is, I want to display the difference of weeks between these two day values in the inputText component when the user clicks the shape.

  Any suggestion would be appreciated.

  Kind regards

  
  

  Novel

  You can use this method to get the number of days between the day and date, and then divided by 7 to get the number of weeks

  public static long getDifferenceDaysBetweenTwoDates (d1, d2 oracle.jbo.domain.Date oracle.jbo.domain.Date)

  {

  If (d1! = null & d2! = null)

  {

  return (d1.getValue () .getTime () - d2.getValue () .getTime ()) / (24 * 60 * 60 * 1000);

  }

  return 0;

  }

  Check - http://sameh-nassar.blogspot.in/2014/10/dealing-with-dates-in-java.html

  Ashish

• How to find the number of days between 2 date elements in the XSLT file

  Hello
  
  I need to calculate the number of days between 2 date elements (type xs: date). Can you please direct me as to how I can do the same thing.
  
  I work in 11g and using XSLT 1.0. I tried several options but yet to get a solution for this. I think that this can be done also using XSLT 2.0, but who has not worked for me.
  
  Can someone please help with this problem, thanks in advance!
  
  Thank you
  Anju

  Hello

  Have you seen this message?
  Re: Get the Date difference between 2 values of date in days

  You can do in the XSLT file since the dates are in ISO 8601 format.
  http://www.w3.org/TR/NOTE-datetime

  Here is a sample XSLT...

  The XSLT above will result in * 4 * for the next entry...

  
  2012-01-11T00:00:00.000-05:00
  2012-01-15T00:00:00.000-05:00
  
  

  You can test this example here...
  http://xslttest.appspot.com/

  I hope this helps...

  See you soon,.
  Vlad

  It is considered good etiquette to the answerers rewards with points (as "useful" - 5 pts - or 'correct' - 10pts)
  https://forums.Oracle.com/forums/Ann.jspa?annID=893

• Dynamic calculation of the number of days between two dates in a table

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  Hi BO123,

  BO123 wrote:

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  one of the way to do this by calling ajax on change of end_date.

  See the sample code given below to fetch the resulting duration and making the field read only after calculation

  Step 1: Change your page

  under CSS-> Inline, put the code below

  .row_item_disabled {
    cursor: default;
    opacity: 0.5;
    filter: alpha(opacity=50);
    pointer-events: none;
  }
  

  Step 2: Create on demand Ajax process I say CALC_DURATION

  Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call

  Declare
    p_start_date  date;
    p_end_date    date;
    p_duration number;
  Begin
    p_start_date  := to_date(apex_application.g_x01);
    p_end_date    := to_date(apex_application.g_x02);
  
     --do your calculation and assign the output to the variable p_duration
    select p_end_date - p_start_date into p_duration
      from dual;
  
    -- return calculated duration
    sys.htp.p(p_duration);
  End;
  

  Step 3: Create the javascript function

  Change your page-> the function and the declaration of the Global Variable-> put the javascript function

  You must extract the rowid in the first place, for which you want to set the time, see line 2

  assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration

  See no line no 8 how set the value returned by the process of ajax at the duration column

  Replace your column to the respective column identifiers in the code below

  function f_calulate_duration(pThis) {
    var row_id  = pThis.id.substr(4);
    var start_date = $('#f06_'+row_id).val();
    apex.server.process ( "CALC_DURATION", {
    x01: start_date,x02: $(pThis).val()
  }, { success: function( pData ) {
  // set duration to duration column
  $('#f08_'+row_id).val(pData);
  // disable duration column
  $("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); }
  });
  }
  

  Step 4: choose the end date call the javascript function

  Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below

  onchange="javascript:f_calulate_duration(this);"
  

  
  

  hope this helps you,

  Kind regards

  Jitendra
  

• JavaScript anomaly on the number of days between two dates

  Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
  
  Here are some examples:
  
  March 10, 2013 = 69 days of December 31, 2012
  March 11, 2013 = 69 days of December 31, 2012
  March 12, 2013 = 70 days of December 31, 2012
  
  November 3, 2013 = 306 days in December 31, 2012
  November 4, 2013 = 308 days in December 31, 2012
  
  11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
  
  Change the past_date to March 10, 2013 produces the following:
  
  March 10, 2013 = 0 days of March 10, 2013
  March 11, 2013 = 0 days of March 10, 2013
  March 12, 2013 = 1 days of March 10, 2013
  
  But change the past_date to 11 March 2013, product of the correct numbers:
  
  March 11, 2013 = 0 days of March 11, 2013
  March 12, 2013 = 1 days of March 11, 2013
  March 13, 2013 = 2 days of March 11, 2013
  
  I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
  
  var w1 = ($v ("P48_PAST_DATE"));
  W1 = (w1.toString ());
  vmon var = (w1.substr (3.3));
  vyr var = (w1.substr (7));
  var r = (vyr.length);
  If (r == 2)
  vyr. = (parseFloat (vyr) + 2000);
  vday var = (w1.substr (0.2));
  var y = (vmon.concat ("", vday, ",", vyr));
  y = Date.parse (y);
  
  var w2 = ($v ("P48_CURRENT_DATE"));
  var vmon2 = (w2.substr (3.3));
  var vyr2 = (w2.substr (7));
  var vday2 = (w2.substr (0.2));
  var x = (vmon2.concat ("", vday2, ",", vyr2));
  x = Date.parse (x);
  
  var numdays = (x - y);
  numdays = (Math.floor(numdays / 86400000));
  $s ("P48_NUMBEROFDAYS", numdays);

  Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:

  This method does not work correctly if there is an advanced economies jump between the two dates.

  There are examples available to calculate the difference between two dates.

• to calculate the number of days between 2 dates

  Hi all
  
  
  I need to calculate the number of days between 2 dates.
  Y at - it no oracle built on that basis.
  
  
  
  Thanks in advance
  Kind regards
  
  Nick

  user646786 wrote:
  Hello

  Thanks a lot its really useful, but I must make a correction, I just want weekdays rather working days

  As already said, there are many examples on the forum of the calculation of the working days or the days of the week or whatever you want between certain dates of restrictions. You will need to have a go at adapting what has already been given before and then when you get stuck, come here and your postcode, and someone will take a look for you.

• To find the months and days between 2 dates

  Hello

  I want to find the months and days between 2 dates.

  For example.

  1 - Date: August 25, 2013

  2 - Date: October 23, 2013

  If we consider each month 30 days, it should give

  August 25, 2013 to August 30, 2013 = 6 days

  01-Sep-2013-30-Sep-2013 = 1 month

  October 23, 2013 to October 30, 2013 = 8 days

  Total = 1 month and 14 days.

  Kindly help as soon as possible.

  Thanks and greetings

  Suresh

  Assuming that d2 > d1,.

  where d)

  Select sysdate d1, sysdate + 56 double d2

  Union all select to_date (March 1, 2013 ',' dd-mon-yyyy "") d1, to_date (March 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (5 February 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy "") d1, to_date (March 23, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (August 2, 2013 ',' dd-mon-yyyy "") d1, to_date (29 October 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 1, 2013 ',' dd-mon-yyyy "") d1, to_date (May 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (25 August 2013 ',' dd-mon-yyyy "") d1, to_date ('03-Sep-2013', 'Mon-dd-yyyy') d2 double

  Union all select to_date (July 30, 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (August 30, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (3 August 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (3 July 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date ('31-08-2013', ' dd-mm-yyyy'), to_date('05-10-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('31-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-02-2013','dd-mm-yyyy') of the double

  )

  Select d1, d2,

  1 + 30 * trunc (months_between (d2, d1)) + LESS (extract (day of d2), 30)-LESS (excerpt (d1 day), 30)

  + CASE when extracted (d2 day)< extract(day="" from="" d1)="" then="" 30="" else="" 0="" end ="">

  d

  D1 D2 DAYSBETWEEN

  ----------- ----------- -----------

  October 10, 2013 5 December 2013 56

  March 1, 2013 30 March 31, 2013

  5 February 2013 March 31, 2013 56

  February 25, 2013 March 23, 2013 29

  February 25, 2013 March 31, 2013 36

  August 2, 2013 29 October 2013 88

  February 1, 2013 may 31, 2013 120

  August 25, 2013 03 - Sep-2013 9

  July 30, 2013 31 August 31, 2013

  July 31, 2013 August 30, 2013 31

  July 31, 2013 3 August 2013 4

  July 3, 2013 August 31, 2013 58

  31 August 2013 5 October 2013 36

  5 February 2013 March 31, 2013 56

  5 February 2013 March 5, 2013 31

  February 5, 2013 February 5, 2013 1

  In my view, which corresponds to your rules.

• Calculate the number of days between two dates

  Hello

  Can someone help please change my formcalc script to calculate the number of working days between two date fields.  My script currently calculates the total number of days between two dates, including the weekends which must be excluded from the total.

  If

  (HasValue (Start_Date1) & HasValue (End_Date1)) then

  $

  = Date2Num (End_Date1, "YYYY-MM-DD" "en_IE") - Date2Num (Start_Date1, "YYYY-MM-DD" "en_IE") + 1

  on the other

  ""

  endif

  Any help will be most appreciated.

  Thank you.

  Check...

  (1) you said that you put the script on the event «days1» calculate My sample imitates the variable names used in the original message, "Start_Date1" and "End_Date1". If the names of variables for the start and end dates are different, you will need to modify the script to account for these names.

  (2) the Date2Num functions in the calculation of the "totalDays" use the date format "YYYY-MM-DD". If your date habits differ from "YYYY-MM-DD" FormCalc will complain.

  Steve

• Dynamically calculate the number of days between two dates and amounts of split

  Hello
  
  I have searched for a solution for this, but had no success.
  I need to show the amounts broken down by days.
  
  I have a table that has an amount column and start and end dates.
  
  I need to write a query so that the amounts will be broken evenly based on the number of days between the start date and end date.
  
  For example, for this line.
  insert into my_test values (' 1, '' 3-mar-2010, ' 7 - mar - 2010 ", 1000);
  
  the query returns this (split $1,000 over 5 days)
  
  
  ID Date amount
  1 ' 3-mar-2010' 200,00
  1 ' 4-mar-2010' 200,00
  1 ' 5-mar-2010' 200,00
  1 ' 6-mar-2010' 200,00
  1 ' 7-mar-2010' 200,00
  
  
  
  create table my_test)
  ID number (10),
  start_date date,
  End_date date,
  amount number (10.2)
  );
  
  
  Select * from my_test
  
  insert into my_test values (' 1, '' 3-mar-2010, ' 7 - mar - 2010 ", 1000);
  insert into my_test values (2, 10-mar-2010 ", 19-mar-2010", 2000);
  insert into my_test values (3, 20-mar-2010 ',' 21-mar-2010, 5000);
  
  
  
  Thanks in advance.

  Hello

  One way is to join a Meter of Table , a table, or (more often) a set of results includes a line for eery number 1, 2, 3,... until the maximum number of times you need to divide a line.
  For example:

  WITH     cntr     AS
  (
       SELECT     LEVEL - 1     AS n
       FROM     (  SELECT  MAX (end_date - start_date)     AS max_day_cnt
               FROM        my_test
            )
       CONNECT BY     LEVEL <= 1 + max_day_cnt
  )
  SELECT       t.id
  ,       t.start_date + c.n                    AS dt
  ,       t.amount / (t.end_date + 1 - t.start_date)     AS amt
  FROM       my_test      t
  JOIN       cntr            c     ON     c.n <= t.end_date - t.start_date
  ORDER BY  id
  ,            dt
  ;
  

  This assumes that all dates have the same number of hours, minutes, and seconds, as is the case in your sample data.
  If this isn't the case, then use TRUNC (start_date) and TRUNC (end_date) instead of start_date and end_date or post some sample data and results if some lines do not represent a whole number of days.

• Dates of the fortnight of days between two dates

  Hello
  
  I want to show every fortnight dates based on the date, to date and the day of week (sunday, monday...)
  
  Input parameters
  Date: 31/05/2011
  To date: 30/06/2011
  day of week: Thursday
  
  Output
  06/02/2011
  16/06/2011
  30/06/2011
  
  
  Input parameters
  Date: 25/06/2011
  To date: 30/06/2011
  day of week: Monday
  
  Output
  27/06/2011
  
  can someone help me?
  
  Published by: user10594152 on May 30, 2011 22:10
  
  Published by: user10594152 on May 30, 2011 22:19

  Hello

  Here's one way:

  WITH     parameters     AS
  (
       SELECT     DATE '2011-05-31'     AS start_date
       ,     DATE '2011-06-30'     AS end_date
       ,     'Thursday'          AS day_o_week
       FROM     dual
  )
  ,     got_dt     AS
  (
       SELECT     end_date
       ,     NEXT_DAY ( start_date - 1
                  , day_o_week
                  ) + (14 * (LEVEL - 1))     AS dt
       FROM     parameters
       CONNECT BY     LEVEL     <= CEIL     ( (end_date - start_date)
                           / 14
                           )
  )
  SELECT     dt
  FROM     got_dt
  WHERE     dt     <= end_date
  ;
  

  This ID on NLS_DATE_LANGUAGE load. If you do not what it is, you can change the sub-quewry like this:

  WITH     parameters     AS
  (
       SELECT     DATE '2011-06-25'     AS start_date
       ,     DATE '2011-06-30'     AS end_date
       ,     TO_CHAR ( DATE '2011-05-30'     -- or any Monday
                 , 'Day'
                 )          AS day_o_week
       FROM     dual
  ) ...
  

  Published by: Frank Kulash, 30 May 2011 13:13
  Adding a warning about NLS_DATE_LANGUAGE

• How to get the difference in Date in years, months and days

  Select Sysdate-Birth_date from Employees;

  the query returns the number of days between two dates
  I want to convert this number in years, months and days
  Can someone help me please

  Hoek wrote:
  Try:

  SQL> with t as (
  2  select to_date('01-01-1980', 'dd-mm-yyyy') birthdate
  3  ,      to_date('05-05-2010', 'dd-mm-yyyy') today
  4  from   dual
  5  )
  6  --
  7  --
  8  --
  9  select extract(year from today)-extract(year from birthdate) years
  10  ,      extract(month from today)-extract(month from birthdate) months
  11  ,      extract(day from today)-extract(day from birthdate) days
  12  from   t;
  
  YEARS     MONTHS       DAYS
  ---------- ---------- ----------
  30          4          4
  
  1 row selected.
  

  (May need some adjustments, possibly using the LARGEST, but currently not as long)

  Indeed, a few adjustments...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (
    2    select to_date('31-01-2009', 'dd-mm-yyyy') birthdate
    3    ,      to_date('28-02-2010', 'dd-mm-yyyy') today
    4    from   dual
    5    )
    6  --
    7  --
    8  --
    9  select extract(year from today)-extract(year from birthdate) years
   10  ,      extract(month from today)-extract(month from birthdate) months
   11  ,      extract(day from today)-extract(day from birthdate) days
   12* from   t
  SQL> /
  
       YEARS     MONTHS       DAYS
  ---------- ---------- ----------
           1          1         -3
  
  SQL>
  

  Maybe something like this?

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select to_date('17-nov-2006','dd-mon-yyyy') as c_start_date, to_date('21-jan-2008','dd-mon-yyyy') as c_end_date from dual union all
    2             select to_date('21-nov-2006','dd-mon-yyyy'), to_date('17-feb-2008','dd-mon-yyyy') from dual union all
    3             select to_date('31-jan-2009','dd-mon-yyyy'), to_date('28-feb-2010','dd-mon-yyyy') from dual union all
    4             select to_date('21-jun-2006','dd-mon-yyyy'), to_date('17-jul-2008','dd-mon-yyyy') from dual
    5             )
    6  -- end of test data
    7  select c_start_date, c_end_date
    8        ,trunc(months_between(c_end_date, c_start_date) / 12) as yrs
    9        ,trunc(mod(months_between(c_end_date, c_start_date), 12)) as mnths
   10        ,trunc(c_end_date - add_months(c_start_date, trunc(months_between(c_end_date, c_start_date)))) as dys
   11* from t
  SQL> /
  
  C_START_DATE        C_END_DATE                 YRS      MNTHS        DYS
  ------------------- ------------------- ---------- ---------- ----------
  17/11/2006 00:00:00 21/01/2008 00:00:00          1          2          4
  21/11/2006 00:00:00 17/02/2008 00:00:00          1          2         27
  31/01/2009 00:00:00 28/02/2010 00:00:00          1          1          0
  21/06/2006 00:00:00 17/07/2008 00:00:00          2          0         26