Get the firstday and last month lastday

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• How to get the first and last record

  Hai All
  
  I have a table called T1 and there are more than 8 lakhs Archives and I have a column named Timestamp, so I need to get the first record value and time stampvalue and last record and time stamp value so that I can conclude that for example
  form June 13 to 15 June data are here
  
  
  Kind regards
  
  SrikkanthM

  What is the problem with:

  select min(timestamp),max(timestamp)
  from T1;
  

  ?

• get the first and last day of the year

  and razm.date > = to_date ("' 1.01 ' |: $VDATE |", ' dd.mm.yyyy ") AND razm.date < = to_date ('31.12.2010. ' || (": $VDATE |", ' dd.mm.yyyy ");
  
  but I get:
  ORA-01830: date format picture ends before converting all of the input string
  01830 00000 - "date format picture ends before converting all of the input string.
  * Cause:
  * Action:
  
  
  : $VDATE is entered as 2010 param. I need to get data from range 1.1.2001 to 31.12.2010
  
  THX

  Why don't you use:

  to_char(razm.date,'YYYY') = :VDATE
  

• Get the first and the last day of the month...

  Hi friends,
  
  I'm trying to get the first and last day of a month and wants to implement that in the following code:
  
  SELECT COALESCE (Date_A, Date_B, Date_C)
  OF the double
  
  Here Date A and B are in Format DD MM YYYY (March 14, 2008)
  and Date like MM YYYY (March 2008)
  
  How can I get the Date_C as of March 1, 2008, OR March 31, 2008 if Date A and B are NULL?
  
  Thank you!
  
  Published by: user11095386 on April 23, 2009 10:45

  Hello

  In my previous message, I thought that you were starting with strings like ' 03 12 2009"and you want to display in the form of" 12 March 2009'.» If what you have is just the opposite, then simply reverse strings format in my first message. Add a comma, if you want, in the format string.
  I think that's what you want:

  COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_C, 'fmMonth YYYY'),    'MM DD YYYY')
           )
  

  Notice how, on the 3rd line, TO_DATE is called without DD in the format string:

  TO_DATE ( Date_C, 'fmMonth YYYY')
  

  When you do so, by default the day the 1st of the month, so that's all you need to do to convert the VARCHAR2 'March 2009' at the DATE of March 1, 2009.

  If you would like the last day of the month, not the first, when Date_C is selected, then use LAST_DAY:

  COALESCE ( TO_CHAR ( TO_DATE ( Date_A, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( TO_DATE ( Date_B, 'fmMonth DD YYYY'), 'MM DD YYYY')
           , TO_CHAR ( LAST_DAY ( TO_DATE ( Date_C
                                            , 'fmMonth YYYY'
                              )
                       )
               , 'MM DD YYYY'
               )
           )
  

• I've lost the last two digits of my valid key for xp pro sp2 and notebook, how do I get the key and support? where?

  I've lost the last two digits of my valid key for xp pro sp2 and notebook, how do I get the key and support? where?

  Hi Jonathan,.

  Please go to the Microsoft Community Forums.
  After the description of the question, I understand that you have lost the last 2 digits of the product key.
  Let me go ahead and help you with the issue.
   
  Please answer these questions, which will help us to help you best.
  1. How did you get the product key?
  2. the operating system come preinstalled on the computer?
   
  I suggest you for the link and check if that helps:
  How to identify, locate, and replace a product key
  http://support.Microsoft.com/kb/811224
   
  See also:
  http://support.Microsoft.com/kb/295539
  
  I hope this helps. If you have any other queries/issues related to Windows, write us and we will be happy to help you further.

• How to get the second and third weekend of every month over a period of time?

  Hello

  No idea how to get the second and third weekend of every month on a given period without use of CLAUSE?

  Thanks in advance.

  Try it below,

  SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'SAT '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 1

  WHERE TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'Sun '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 6

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), "SAT") + 1

  END as second_weekendday,

  BOX WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'SAT '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 7

  WHERE TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'Sun '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 7

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), "SAT") + 7

  END AS third_weekendday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• Need a query to return the first and last date for a rowset.

  Hello
  
  I have a query which can be simplified to the following data, if
  Assume that it is my dataset, with THE_VALUE of
  Sign (Anum) therefore,-1, 0 or 1.
  
  * (Sorry for crushed registration. "I can't understand this website's rich text formatting.) *
  
  THE_VALUE THE_DATE THE_MEMBER
  1 0 1 January 2007
  1 0 1 February 2007
  1 0 1 March 2007
  1. 1 April 1, 2007
  1 1 1 May 2007
  1 0 1 June 2007
  1. 1 July 1, 2007
  1. 1 August 1, 2007
  1 0 01 - sep - 2007
  2 0 1 January 2007
  2 1 February 1, 2007
  2 0 1 March 2007
  2. 1 April 1, 2007
  2 1 1 May 2007
  2 0 1 June 2007
  -2 1 1 July 2007
  2. 1 August 1, 2007
  2. 1 01-sep-2007
  3 0 1 January 2007
  3. 1 February 1, 2007
  3 0 1 March 2007
  3 0 1 April 2007
  3. 1 May 1, 2007
  3 0 1 June 2007
  3. 1 July 1, 2007
  3. 1 August 1, 2007
  3 0 01 - sep - 2007
  
  I need to get the lines with the THE_MEMBER, the values of the first and the last
  THE_DATE, where the value is - 1, and the date range is the last
  set of lines to the Member, with the same value of THE_VALUE.
  
  I tried the following to get the dates of first and last for a set
  consecutive months with the same value for the Member.
  
  SELECT the_member
  the_value
  the_date
  first_value (the_date)
  in the first_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
  last_value (the_date)
  during the last_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
  OF togola
  ORDER BY the_member
  the_date;
  
  At first, it seems to work, but then, when the return value
  an old value, FIRST_DATE will be the first of all the lines containing
  This value for the Member rather than the first of consecutive
  rows with this value for the Member. Apparently the partitioning
  occurs before the order.
  
  THE_MEMBER THE_VALUE THE_DATE FIRST DATE LAST DATE
  1 0 January 1, 2007 January 1, 2007 January 1, 2007
  1 0 1 February 2007 1 January 2007 1 February 2007
  1 0 1 March 2007 1 January 2007 March 1, 2007
  1. 1 April 1, 2007 April 1, 2007 April 1, 2007
  1. 1 May 1, 2007 April 1, 2007 may 1, 2007
  1-0 June 1, 2007 January 1, 2007 June 1, 2007
  1. 1 July 1, 2007 April 1, 2007 July 1, 2007
  1. 1 August 1, 2007 April 1, 2007 August 1, 2007
  1 0 01 - sep - 2007 1 January 2007 01-Sep-2007
  
  2 0 January 1, 2007 January 1, 2007 January 1, 2007
  2 1 1 February 2007 February 1, 2007 February 1, 2007
  2 0 1 March 2007 1 January 2007 March 1, 2007
  2. 1 April 1, 2007 February 1, 2007 April 1, 2007
  2 1 1 May 2007 February 1, 2007 may 1, 2007
  2-0 June 1, 2007 January 1, 2007 June 1, 2007
  -2 1 1 July 2007 February 1, 2007 July 1, 2007
  2. 1 August 1, 2007 February 1, 2007 August 1, 2007
  2. 1 01-sep-2007 1 February 2007 01-Sep-2007
  
  3 0 January 1, 2007 January 1, 2007 January 1, 2007
  3. 1 February 1, 2007 February 1, 2007 February 1, 2007
  3 0 1 March 2007 1 January 2007 March 1, 2007
  3 0 April 1, 2007 January 1, 2007 April 1, 2007
  3. 1 May 1, 2007 February 1, 2007 may 1, 2007
  3 0 June 1, 2007 January 1, 2007 June 1, 2007
  3. 1 July 1, 2007 February 1, 2007 July 1, 2007
  3. 1 August 1, 2007 February 1, 2007 August 1, 2007
  3 0 01 - sep - 2007 1 January 2007 01-Sep-2007
  
  That's what I need to get in the end.
  
  THE_MEMBER FIRST DAY DATE OF LAST
  July 2 1 2007-01 - Sep - 2007
  
  Any ideas would be really appreciated.
  
  Published by: user10700981 on December 17, 2008 13:57

  Hello

  We'll call the lines whose the_value =-1 'good' lines and lines with the_value! =-1 ranks of 'bad '.

  For each value of the_value, we need the first and last values of the_date where
  the last row in the group is good
  (b) the current line is good
  (c) there is a lot of lines from the current line to the end of the Group
  Condition (a) is just a special case of (c).
  Conditions (b) and (c) are similar: (b) if applied to the current line, (c) applies to all lines after him. They can easily be combined into a single test that counts the number of lines after the current line or bad.

  Which produces the results you requested of the sample data that you provided:

  WITH     count_bad     AS
  (
       SELECT     the_member
       ,     the_date
       ,     COUNT     ( CASE
                      WHEN  the_value != -1 -- assuming the_value is never NULL
                      THEN  1
                   END
                 ) OVER     ( PARTITION BY     the_member
                        ORDER BY     the_date     DESC
                      )     AS bad_cnt
       FROM     table_x
  )
  SELECT     the_member
  ,     MIN (the_date)     AS first_date
  ,     MAX (the_date)     AS last_date
  FROM     count_bad
  WHERE     bad_cnt     = 0
  GROUP BY     the_member
  ORDER BY     the_member;
  

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