Get the lines between colors in Illustrator
Hello
I have a problem and I'm looking for some advice. I dropped a raster image in Illustrator (AI) and with the trace function, has turned into a vector image which looks great on my monitor. However, when I load the vector file in PDF format and then open the PDF file, I see a small, light, grey hairlines between colors.
I do a product for a customer label. He wants a photo (JPEG) for the background. Printing wants vector images to CMYK.
I am fairly new to HAVE and probably not using 'approved methods' although I took what I thought, is a logical step to achieve my goal.
I took the JPEG RGB, converted into a .tiff to CMYK. I also tried to convert the JPEG in .bmp and .esp - all in CMYK mode, before moving to HAVE. I also tried putting the JPEG directly in I.
I dropped these images in Illustrator separately and Live tracks on each. At this point, each attempt gave me excellent vector images in CMYK mode, but went wobbly when I transfer to PDF.
Curiously, when I make a hard copy of this PDF on a Hi ground digital printer (2400 dpi), the lines do not appear. However, I am still very concerned about these lines, because I send a power off to work on offset printing. I'm sure that the printer will panic if he sees these lines and I am even more worried that these lines may appear in the print process four colors.
A local graphics person I spoke with that suggested I'd find my solution to scout, but I fiddled a little this feature and could not solve the problem. Although I still wonder if maybe it's where I could find the solution, because when I hit Expand the blue path lines seem to match with the troublesome gray lines.
Someone else told me to hit Expand and then turn off the Stroke. I think that I did it correctly, but there is no difference. I also didn't see any difference when I applied to the maximum value for the race. Other attempts to find a cure included deselected Resample, then re - sample with a resolution of 300.
This is driving me crazy and I hope I can find help.
Matt
Here's a quick and easy way to get rid of these lines. Place the image raster in illustrator. Then click on copy. Then direct route on the image use, using the preset of 8 colors. This will give you a very simple version of the photo. Click on expand. Then click on paste in front to put a new copy of the raster on the top of the first image. Use the tracing once again, but this time with a screening of high resolution. Click on expand. This should solve the problem.
You see, these lines are only tiny spaces between the vector objects. By creating two vector images in the same frame, the bottom a slightly simpler from the top edge, you can get rid of these lines.
I hope this helps!
Tags: Illustrator
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How to get the average between the lines are null?
I need to get the average between the 2 positive numbers.
Then update the table with the average for the rows that have NULL value between 2 positive numbers.
The average will come (78 + 89) / 2 = 83.5. Round up to 84.
Then it will be:
04/06/13 84
05/06/13 84
06/06/13 84
Regarding the 13/06/09 and 10/06/13, these values will always be NULL.
{code}
create the dummy (date of tmestmp of the table
(, maxtemp number (4,0));
insert into dummy (tmestmp, maxtemp) values (to_date('20130601','YYYYMMDD'), 70);
insert into dummy (tmestmp, maxtemp) values (to_date('20130602','YYYYMMDD'), 81);
insert into dummy (tmestmp, maxtemp) values (to_date('20130603','YYYYMMDD'), 78);
insert into dummy (tmestmp) values (to_date('20130604','YYYYMMDD'));
insert into dummy (tmestmp) values (to_date('20130605','YYYYMMDD'));
insert into dummy (tmestmp) values (to_date('20130606','YYYYMMDD'));
insert into dummy (tmestmp, maxtemp) values (to_date('20130607','YYYYMMDD'), 89);
insert into dummy (tmestmp, maxtemp) values (to_date('20130608','YYYYMMDD'), 91);
insert into dummy (tmestmp) values (to_date('20130609','YYYYMMDD'));
insert into dummy (tmestmp) values (to_date('20130610','YYYYMMDD'));
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I need the output to look like this:
Header 1 Header 2 1 JUNE 13
2 JUNE 13
JUNE 3, 13
JUNE 4, 13
5 JUNE 13
JUNE 6, 13
JUNE 7, 13
JUNE 8, 13
JUNE 9, 13
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70
81
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84
84
84
89
91null
null
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - production
PL/SQL Release 10.2.0.4.0 - Production
"CORE 10.2.0.4.0 Production."
AMT for 32-bit Windows: release 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
Suggestions?
TIA.
Steve42
Select tmestmp,
NVL)
maxtemp,
round)
(
LAST_VALUE (maxtemp Ignore Nulls)
(order tmestmp).
FIRST_VALUE (maxtemp Ignore Nulls)
(tmestmp order
lines between the 1 suite and unlimited
)
) / 2
)
) maxtemp
modeling
/
TMESTMP MAXTEMP
------------------- ----------
01/06/2013 00:00:00 70
02/06/2013 00:00:00 81
03/06/2013 00:00:00 78
04/06/2013 00:00:00 84
05/06/2013 00:00:00 84
06/06/2013 00:00:00 84
07/06/2013 00:00:00 89
08/06/2013 00:00:00 91TMESTMP MAXTEMP
------------------- ----------
09/06/2013 00:00:00
10/06/2013 00:00:0010 selected lines.
SQL >
SY.
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How can I get the lines for the date between 2 different days
Hi all,
How can I get the lines for the date between 2 different days.
Sample data:
Table name: Articles
Title start_date end_date
Heading1 08-22-2011 2011-09-11
2011-08-01-2011-09-01 Title2
Title 3 2011-08-21 08-21-2011
title4 2011-08-28 2011-09-11
Result will be:
Title start_date end_date
Heading1 08-22-2011 2011-09-11
2011-08-01-2011-09-01 Title2
title4 2011-08-28 2011-09-11
This is my example query:
SELECT * FROM items WHERE trunc (es.date_start) > = TO_DATE('2011-08-22', 'YYYY-MM-DD') AND trunc (es.date_end) < = TO_DATE ('2011-08-28', 'YYYY-MM-DD')
but I can not get the expected results. Any help would be much appreciated.
Thanks in advancenot read your question properly before...
Please try this
Select * FROM items
WHERE (TO_DATE ('2011-08-22', 'YYYY-MM-DD') between TRUNC (es.date_start))
AND TRUNC (es.date_end)) OR
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AND TRUNC (es.date_end)) -
The most elegant way to get the difference between two tables - not least!
Hello
Simplified example of what I'm trying to achieve - I have two tables ORIGINAL and REVISED.
My aim is to compare the two, such as; -
When there is data in the two tables I get the difference between the Budget column, and if there is no difference, so I don't want no lines.
When data exists in the ORIGINAL, but not in review, I want to the inverse of the current value of the Budget column.
Where the data exist in REVISED I want the REVISED value.
I can see how I can do this, see below, but is there a more elegant solution?
Data for the ORIGINAL table
Data for the REVISED tableselect '801040' entity, '2186' expense_type, 234000 budget from dual union all select '801040' entity, '3001' expense_type, 1000 budget from dual union all select '801040' entity, 'P132' expense_type, 34000 budget from dual union all select '801040' entity, 'P135' expense_type, 43000 budget from dual
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ENTITY EXPENSE_TYPE DIFFERENCE
------ ------------ ----------
801040 2186 1000
801040 3001-1000
801040 P135-43000
801040 P139 56000
5 selected lines.
Code current to achieve this, is there a better way?
Thanks a lot for your comments,.select original.entity , original.expense_type , (nvl(revised.budget,0) - original.budget) as difference from original , revised where original.entity = revised.entity(+) and original.expense_type = revised.expense_type(+) and (nvl(revised.budget,0) - original.budget) != 0 union all select revised.entity , revised.expense_type , revised.budget as difference from revised where not exists (select 'x' from original where original.entity = revised.entity and original.expense_type = revised.expense_type) and revised.budget != 0
Robert.
Published by: Robert Angel on January 17, 2012 03:31 to change is not equal to! = - Thanks for the heads upSQL> with original 2 as 3 ( 4 select '801040' entity, '2186' expense_type, 234000 budget 5 from dual 6 union all 7 select '801040' entity, '3001' expense_type, 1000 budget 8 from dual 9 union all 10 select '801040' entity, 'P132' expense_type, 34000 budget 11 from dual 12 union all 13 select '801040' entity, 'P135' expense_type, 43000 budget 14 from dual 15 ) 16 , revised 17 as 18 ( 19 select '801040' entity, '2186' expense_type, 235000 budget 20 from dual 21 union all 22 select '801040' entity, 'P132' expense_type, 34000 budget 23 from dual 24 union all 25 select '801040' entity, 'P139' expense_type, 56000 budget 26 from dual 27 ) 28 select * 29 from ( 30 select nvl(o.entity, r.entity) entity, 31 nvl(o.expense_type, r.expense_type) expense_type, 32 nvl(r.budget,0) - nvl(o.budget,0) budget 33 from original o 34 full join revised r 35 on o.entity = r.entity 36 and o.expense_type = r.expense_type 37 ) 38 where budget <> 0 39 / ENTITY EXPE BUDGET ------ ---- ---------- 801040 2186 1000 801040 P135 -43000 801040 3001 -1000 801040 P139 56000 SQL> -
Get the lines containing only numbers and English characters
ΗΙ,
Assume that there are the following lines:
Select 'RE89203' Union double all the
Select 'cd89203' Union double all the
Select 'cD89203' Union double all the
Select 'CZC4255463' Union double all the
Select '597CD83843KL' Union double all the
Select CD 90832 83843FE 597' a Union double all the
Select 597 CD 90832 ~ 83843FE' a Union double all the
Select 'CD9083283843FΔ' Union double all the
Select 'CD9083283843FΑ' of the double
In the list above, I want to get the lines containing at least a figure and English at least one character (in capital), but with the exception of these, any other character is not acceptable (and the line as well).
I tried the following, but the result set is not the direction you want:
with sample_data as
(
Select 'RE89203' Union double all the
Select 'cd89203' Union double all the
Select 'cD89203' Union double all the
Select 'CZC4255463' Union double all the
Select '597CD83843KL' Union double all the
Select CD 90832 83843FE 597' a Union double all the
Select 597 CD 90832 ~ 83843FE' a Union double all the
Select 'CD9083283843FΔ' Union double all the
Select 'CD9083283843FΑ' of the double
)
Select one
of sample_data
where regexp_like (, ' [A - Z] [[: digit:]] ',' it)
Explanations:
The value "cD89203" is not acceptable because it contains the character 'c' (in lowercase).
597 90832 83843FE record value CD' is not acceptable because there is a space.
597 90832 record value CD ~ 83843FE' is not acceptable because there is a character "~".
The value "CD9083283843FΔ" is not acceptable because there is a non-English (character 'Δ') character.
The value of the last record "CD9083283843FΑ" is not acceptable because there is a non-English (character 'Α') character.
Note:
I'm using OraDB 11 g v2
with sample_data as ( select 'RE89203' a from dual union all select 'cd89203' a from dual union all select 'cD89203' a from dual union all select 'CZC4255463' a from dual union all select '597CD83843KL' a from dual union all select '597CD90832 83843FE' a from dual union all select '597CD90832~83843FE' a from dual union all select 'CD9083283843F?' a from dual union all select 'CD9083283843F?' a from dual union all select 'ABCDEF' a from dual union all select '1234' a from dual ) select a from sample_data where replace(translate(translate(a, '~', '#'), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789', '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~'), '~', null) is null and regexp_like(a, '[A-Z]') and regexp_like(a, '[0-9]') /
Edit: See post of Chris Hunt for a more efficient version of the line 17.
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I have a photography teacher program Adobe and must add Adobe Illustrator for the BSc SAID curriculum I am on at the Academy of digital skills in Dublin, Ireland how I get the student discount to add Illustrator to mentoring rate?
I don't know if we can add a program, or you if have to go to a subscription 'all' education
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When I save an illustrator SVG format file, I want to get the SVG code but open Illustrator Adobe Flash Builder, I just want to open a browser, NO FLASH BUILDER, how do I do that?
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1 application ofst - sum (homepass) Select table 1
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Is it possible to display the difference as -
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I know that the above query would give syntax error, but is there a better way or something to get the above done task from a single query.
Hopefully, my question is clear.
Please get back with the answer to my query.
Concerning
You can always do something like
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Justin
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Execution Plan ---------------------------------------------------------- Plan hash value: 735384656 -------------------------------------------------------------------------------- - | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | -------------------------------------------------------------------------------- - | 0 | SELECT STATEMENT | | 1 | 4 | 2 (0)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 4 | | | |* 2 | INDEX FAST FULL SCAN| IND_IDN | 1000 | 4000 | 2 (0)| 00:00:01 | -------------------------------------------------------------------------------- - Predicate Information (identified by operation id): --------------------------------------------------- 2 - filter("ID" IS NOT NULL) Statistics information ---------------------------------------------------------- 0 recursive calls 0 db block gets 5 consistent gets >> there have 5 consistent gets 0 physical reads 0 redo size 409 bytes sent via SQL*Net to client 385 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed
What gets the relationship between the number of blocks and coherent? How to calculate become consistent?You can see that your uniform is getting down to 6 to 12, is it not? Reading of the below thread Asktom.
http://asktom.Oracle.com/pls/Apex/f?p=100:11:0:P11_QUESTION_ID:880343948514Aman...
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There you go...
http://www.libinst.com/audio%20DiffMaker.htm
Unfortunately, the above utility has been abandoned by its author. :-(
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-RFH
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Here is what I got (this is apex 4.0):
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I created a dynamic action on the page who fires on the point lose focus (above points).
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because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code
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Concerning
Patrick
-----------
My Blog: http://www.inside-oracle-apex.com
APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
Twitter: http://www.twitter.com/patrickwolfPublished by: Patrick Wolf on January 17, 2011 10:54
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the difference between photoshop and illustrator effects?
In the menu effects cs5, what is the difference between photoshop and illustrator effects? When you use the those Photoshop?
Thank you.
The effects of Photoshop are copies of similar effects from Photoshop. Therefore, they cannot be applied to the art of raster, such as modified in Photoshop. When you apply a Photoshop Illustrator art effect that you apply it is pixelated in the background and the effect is applied to the art raster version. If you expand the appearance of anything with a Photoshop top effect it will be pixelated. Other effects to retain all or part of the vector art. When you expand the effect or save a PDF file at least some of the original will vector art remain as vectors, although some effects (drop shadow, blur, feather, inner glow, etc.) to add pixelated art to the file.
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Hello world
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public void mousePressed(MouseEvent e) { if (e.getSource() == label1 || e.getSource() == label2) { drag = true; } } -
See the line between cursors on a graph
Hello
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Steve
Looks like you have a graph of intensity. Easier would be e to use the overlay "draw pictures.
A simple example is shown here.
Of course, in your situation, you get the coordinates of the cursor to set the line. For example, use an event 'move cursor' to recalculate.
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draw the line between black pixel: coordinates of the selected pixels?
Hello
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I wrote this script below (my first script...), but it's VERY slow (and my final image is VERY large), I think because I test the color for each pixel in the image.
So an alternative would be to select a black pixel with the wand, then the script record all the details of the selected pixels, then my script wil test only the pixels (less than 1% of the pixels are black in my image).
Is this possible with JavaScript?
Thank you for your answer!
Marc
function main(){ var startRulerUnits = app.preferences.rulerUnits; app.preferences.rulerUnits = Units.PIXELS; var myHeight = app.activeDocument.height; var myWidth = app.activeDocument.width; // Find black pixel for(var i=5; i<myWidth; i++) { for(var j=5; j<myHeight; j++) { activeDocument.colorSamplers.removeAll() var sampler = activeDocument.colorSamplers.add([new UnitValue (i, 'px'), new UnitValue (j, 'px')]); if (sampler.color.rgb.hexValue === "000000") { // For each black pixel, search another black pixel below left up to 5 pixels for (var m=i-5; m<i; m++) { for (var n=j+1; n<j+5; n++) { activeDocument.colorSamplers.removeAll() var test = activeDocument.colorSamplers.add([new UnitValue (m, 'px'), new UnitValue (n, 'px')]); if (test.color.rgb.hexValue === "000000") { // Then draw a black line between the two black pixels var FillColour = new SolidColor; FillColour.rgb.hexValue = '000000'; var ad=activeDocument; ad.selection.select([[m,n],[i,j],[m,n+1],[i,j+1]], SelectionType.REPLACE, 0, true); ad.selection.fill(FillColour); ad.selection.deselect() } } // For each black pixel, search another black pixel below right up to 5 pixels for (var m=i+1; m<i+5; m++) { for (var n=j; n<j+5; n++) { activeDocument.colorSamplers.removeAll() var test = activeDocument.colorSamplers.add([new UnitValue (m, 'px'), new UnitValue (n, 'px')]); if (test.color.rgb.hexValue === "000000") { // Then draw a black line between the two black pixels var FillColour = new SolidColor; FillColour.rgb.hexValue = '000000'; var ad=activeDocument; ad.selection.select([[i,j],[m,n],[m,n+1],[i,j+1]], SelectionType.REPLACE, 0, true); ad.selection.fill(FillColour); ad.selection.deselect() } } } } } } } } main();If someone wants to do the same thing, the ImageJ software works very well on very large images (1 billion pixels) by the process according to > binary > close
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