Group of and outer joins

Similar Questions

• Count (*) with Group of and a join

  I have the tables below:
  
  Tables:

  EMPLOYEE 
  EMP_ID         LNAME             FNAME
  1000                 SLITT              JOHN
  1001                 SLITHER              STEVE
  1002                 JACOB              MARLYN
  1003                 STUFFEY     NOSE
  1004                 SLIPPY              MOUTH

  -----

  ACCESS_TYPE
  ACCESS_TYPE_ID     ACCESS_DESCRIPTION
  1                         EMPLOYEE
  2                         EMPLOYEE_ADMIN
  3                         CONTRACTOR

  -----

  EMPLOYEE_ACCESS
  ACCESS_ID      ACCESS_TYPE_ID     EMP_ID     ACCESS_EFF_DATE     
  1               1               1000              01-JAN-13
  2               1               1001              10-FEB-13
  3               1               1002              18-FEB-13
  4               2               1003              10-OCT-12
  5               3               1004              10-MAR-08

  -----
  I'm trying to appear on the behalf of the Group of employees by their type and whose name does not begin with SL
  I wrote the following query and I get a missing Expression 00936. What I am doing wrong? Thank you
  
  SELECT EA. COUNT (*), ACCESS_TYPE_ID
  OF EMPLOYEE_ACCESS EA, USED E
  WHERE ACCESS_EFF_DATE > = 31 December 12 ' AND E.LNAME NOT LIKE '% SL.
  ACCESS_TYPE_ID GROUP;
  
  Published by: parsar on March 25, 2013 15:54

  >
  FAM COUNT (*)
  >
  You have a column named "COUNT" in your table? NOT! You probably intend to use the COUNT function: ditch the prefix aliases, functions use a prefix.
  >
  WHERE ACCESS_EFF_DATE > = 31 DECEMBER 12 '
  >
  Don't use strings to DATE values. Use the dates and the TO_DATE function if you need to convert a string to a date literal.

  This Cartesian join between the tables is unlikely to be what you want to do.

• outer join and OR condition

  Hello world
  
  I have a query that is not working properly. I'm trying to join two tables and I or condition and outer join
  I get the error message

   ORA-01719: outer join operator (+) not allowed in operand of OR or IN
  
  my query is as follow
  
  SELECT l.* FROM table1 l, table2 map
  WHERE (NVL(l.id, '-99') = NVL(map.id(+), NVL(l.id, '-99'))
          AND  l.TYPE = 'TKE')
        ) OR 
      (NVL(l.id, '-99') = NVL(map.id(+), NVL(l.id, '-99'))
  AND NVL(l.type, '-99') = NVL(map.type(+), NVL(l.type, '-99'))
  AND NVL(l.pos_22, '-99') = NVL(map.pos_22(+),NVL(l.pos_22, '-99'))
  AND NVL(l.pos_27, '-99') = NVL(map.pos_27(+),NVL(l.pos_27, '-99'))
  AND NVL(l.pos_17, '-99') = NVL(map.pos_17(+),NVL(l.pos_17, '-99'))
  AND NVL(l.pos_18, '-99') = NVL(map.pos_18(+),NVL(l.pos_18, '-99'))
  AND NVL(l.pos_12, '-99') = NVL(map.pos_12(+),NVL(l.pos_12, '-99'))
  AND NVL(l.pos_16, '-99') = NVL(map.pos_16(+),NVL(l.pos_16, '-99'))
  AND NVL(l.pos_34, '-99') = NVL(map.pos_34(+),NVL(l.pos_34, '-99'))
  AND NVL(l.pos_43, '-99') = NVL(map.pos_43(+),NVL(l.pos_43, '-99'))
  AND NVL(l.pos_14, '-99') = NVL(map.pos_14(+),NVL(l.pos_14, '-99'))
  AND NVL(l.status_cd, '-99') = NVL(map.status(+),NVL(l.status_cd, '-99'))
  AND NVL(l.action_cd,'-99') = NVL(map.action_cd(+), NVL(l.action_cd,'-99'))
  AND NVL(l.sys,'-99') = NVL(map.sys(+), NVL(l.sys,'-99'))
  AND NVL(l.ind,'-99') = NVL(map.ind(+), NVL(l.ind,'-99'))
    )

  So, basically in the above query I say that if the type = "TKE" do not join on all columns of pos. If type is not TKE then do all the joints on all columns POS etc.
  How do I rewrite query so that I can use OR and the outer JOIN in the same query?

  Hello

  It is one of several good reasons to use the ANSI join syntax. Move all the join conditions in the clause on, not the WHERE clause, and you do not use the sign +.

  SELECT  l.*
  FROM           table1 l
  LEFT OUTER JOIN  table2 map  ON   (    NVL(l.id, '-99') = COALESCE (map.id, l.id, '-99')
                                      AND  l.TYPE = 'TKE'
                        )
                               OR  (     NVL (l.id, '-99') = COALESCE (map.id, l.id, '-99')
                            AND   NVL (l.type, '-99') = COALESCE (map.type), l.type, '-99')
                       ...
  

  Instead of nesting the NVL statements, use COALESCE, as illustrated above. It is independent of the issue of the join.

• Oracle: Use LEFT OUTER JOIN, but convert the data to an external list

  Hello, all,.

  I know it can be done; I just don't remember how I got it done, oh there are so many years.

  Assumes that the tables exist for groups and individuals.  People can belong to several groups.

  SELECT g.groupName, p.lastName || ', ' || p.firstName as fullName
  FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON gpa.groupID = g.groupID
                LEFT OUTER JOIN person p ON p.personID = gpa.personID
  ORDER BY g.groupName, fullName
  

  This gives us:

  Group One          Alpha, Daniel
  Group One          Bravo, Charles
  Group One          Charlie, Chuck
  Group Two          Beta, Alpha
  Group Two          Delta, Bonnie
  Group Three        Echo, Bunny
  Group Three        Golf, Samuel
  Group Three        November, Stan
  

  How word the SQL to get the data as:

  Group One          Alpha, Daniel | Bravo, Charles | Charlie, Chuck
  Group Two          Beta, Alpha | Delta, Bonnie
  Group Three        Echo, Bunny | Golf, Samuel | November, Stan
  

  V/r,

  ^_^

  I finally thought to it.  I was using incorrect keywords on Google.

  SELECT g.groupName, LISTAGG(p.lastName || ', ' || p.firstName,' | ') WITHIN GROUP (ORDER BY g.groupName) "fullName"
  FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON ggpa.groupID = g.groupID
                LEFT OUTER JOIN person p ON p.personID = gpa.personID
  GROUP BY g.groupName
  ORDER BY g.groupName, fullName  
  

  Just in case someone else is going through this same desire.

  HTH,

  ^_^

• outer join on the aggregate query

  This is probably a relatively simple matter, as long as I explain it well enough:

  I have two tables:

  categorycodes and properties

  categorycodes is a lookup table.

  both tables have a catcode field which is a char (1) that contains matching data (only the numbers 1 to 6)

  CREATE

  TABLE CATEGORYCODES

  (

  CATCODE CHAR (1 BYTE) NOT NULL,

  DESCRIPTION VARCHAR2 (25 BYTE) NOT NULL,

  CONSTRAINT CATEGORYCODES_PK PRIMARY KEY (CATCODE) ALLOW

  )

  catCode

  1

  2

  3

  4

  5

  6

  The properties table has approximately 600 000 records. The properties table also has a field named parcelno which is a tank (9).  It contains a string of figures and numbers only.

  What I would like is:

  catCode, count (*)

  1 580

  2 300

  3 3000

  4 235

  5 0

  6 80

  I limited the results of the query to make sure it was a game that would not all catcodes in it.  I have trouble to get the one with zero to display.  I know that this has to do with how I do the join, but I don't know what.

  It is a sample of what I've tried:

  Select i.

  Of

  (select catcode, count (*)

  property p

  where substr (parcelno, 1, 3) = ' 871 "

  Catcode group) i

  outer join right categorycodes cc

  We i.catcode = cc.catcode;

  I'm not worried about the situations where catcode is null in the properties.  Parcelno cannot be null.

  Hello

  Looks like your query should work; except that you won't COUNT (*); That would make each issue at least 1.  COUNT (*) means that count the total number of lines, no matter what is on them, so he'll see the line with just the catcode of the lookup table that matches nothing and which count as 1.  You want to count the number of rows in the table of properties, so expect a column of the properties that cannot be NULL.

  Here is a slightly different way

  SELECT c.catcode

  EARL of (p.catcode) AS cnt

  OF categorycodes c

  P ON p.catcode = c.catcode LEFT OUTER JOIN properties

  AND SUBSTR (p.parcelno

  1

  3

  ) = ' 871 "

  ;

  If the condition about 871' ' part of the join condition, then you don't need a subquery.

  .

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  Point where the above statement is erroneous results, and explain, using specific examples, how you get the right result of data provided in these places.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002

• My Confusion of outer join

  Oracle 10g
  
  I have three below queries that use the outer join syntax.
  
  All three queries return exactly the same results
  
  
  (a)

  SELECT TA.ID TA
       , TB.ID TB
    FROM TA
       , TB
   WHERE TA.ID = TB.ID(+);

  (b)

  SELECT TA.ID TA
       , TB.ID TB
    FROM TA
       , TB
   WHERE TB.ID(+) = TA.ID;

  (c)

  SELECT TA.ID TA
       , TB.ID TB
    FROM TA
    LEFT OUTER JOIN TB ON TA.ID = TB.ID;

  I have the right call outer join query because the (+) sign is located on the right and outer join query (b) left because the (+) sign is on the left?
  
  Or is the left join or right determined by the join columns specified in the order select it?
  
  
  
  Create the Script

  CREATE TABLE TA
    (
      "ID" NUMBER
    );
  
  CREATE TABLE TB
    (
      "ID" NUMBER
    );
  
  INSERT INTO TA (ID) VALUES ('1');
  INSERT INTO TA (ID) VALUES ('2');
  INSERT INTO TA (ID) VALUES ('3');
  
  INSERT INTO TB (ID) VALUES ('1');
  INSERT INTO TB (ID) VALUES ('2');
  INSERT INTO TB (ID) VALUES ('4');

  Ben
  
  Published by: benton on August 15, 2012 08:16

  Hi, Ben.

  Benton says:
  ... So is it correct to say that the left or right refers to which side the null values will be displayed?

  Lol it is incorrect to say that the old syntax outer join (using the sign +) is either a left - or a right outer join.

  ... So I need to have the order of the columns in the correct SELECTION so that there is no likelihood of confusion over which side will display NULL values. If I place the columns A and B in the wrong order, that is to say B then a I'll lend to confusion about what will be returned with respect whether left or right.

  No, do not hesitate to organize columns in the select in any way will help your users the most. What is happening in the FROM and WHERE clause, in particular the order in which the tables happens to appear, may not have something to do with the order of the columns in the output.
  Many readers are more comfotable with having NULL columns at the end of a line of output, or at least not at the beginning, so maybe it's one of the reasons for ta.id first in your example. Rearrange the columns in the game any way more than makes sense for people who will look at them.

• using (+) or left outer join

  Dear Expert;
  
  I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.
  
  Thank you.

  Hello

  user13328581 wrote:
  Dear Expert;

  I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.

  They all have two outer joins. The + rating was the original way to do it in Oracle. LEFT, RIGHT, and FULL OUTER JOIN introduced in Oracle 9, but the old way is still supported.

  There are some situations (such as an outer join complete and outer-join a table to two different tables) that are better with the ANSI syntax (it's LEFT OUTER JOIN). It is possible to get the same results using +, but it must be combersome and/or inefficient workarounds. I suggest that you use always LEFT OUTER JOIN (or FULL OUTER JOIN, or, on occasions RIGHT OUTER JOIN). I think that you will find it easier and less error-prone.

• Oracle 8i outer join

  The following query is supposed to return all the rows in kpi_reports where the conditions are met and its values corresponding to kpi_master and kpi_report_requests, where the values exist. However, it only returns the lines containing the values kpi_report_request, doing so as an inner join.
  
  SELECT kr.report_id, kr.report_name, kr.kpi_id, km.kpi_description, krr.requested_date
  OF kpi_reports kr, kpi_master km, kpi_report_requests krr
  WHERE kr.kpi_id = km.kpi_id
  AND kr.dsp_id = 9
  AND kr.report_name IS NOT NULL
  AND kr.report_id = krr.report_id (+)
  AND krr.dealer_id = 26402
  ORDER BY kr.report_name
  
  I have reviewed a number of tutorials online brush upward on this thus shown a colleague, and I think Miss me something, maybe you can not do an inner join and outer join in the same query? Don't seem to make sense to me, but all the examples I've seen consist of two tables with an outer join.
  
  Thanks in advance!

  Something like this maybe? (Not sure about Oracle 8, but I do similar things in 9i)

  Phil

• Complex Inner Join and outer subquery where clause to join internal?

  The DDL for this post was too big and I had to put on my site:
  http://www.harbortownsolutions.com/DDLForDORTable.txt
  
  My goal is to create a report of sales data for 116 stores containing daily sales and count of comments in recent years. My challenge is that I am pulling data from the same table, but with different dates to get data from last year and the week in data from date of last year.
  
  
  The dates used for reports are:
  
  SalesDate = 06/04/2009
  SalesDateForLastYear = 2008-06-05
  SalesDateBeginningOfWeek = 01/06/2009
  SalesDateBginningOFWeekLastYear = 2008-06-02
  
  PSEUDOQUERYS:

  ---======= DOLLAR VARIANCE = You Said you have $100 worth of meat(inventory) but you only have $50 worth of meat
  SELECT 
      BUSI_DATE as BusinessDate, 
      ORACLE_KEY as StoreID,
      FIELD1  as Sales,
      FIELD2  as GuestCount,
      FIELD3  as DollarVariance,
      FIELD4  as Cars
  FROM MYDAILYTOTALS
  WHERE Busi_date = SalesDate
     AND ORACLE_KEY IN (SELECT StoreID From MyStores); 
  -======= ONLY Guest count and Sales are needed in comparisons against last year    
  ---======    Last YEar dates = corresponding dates for this year ie Tuesday of this 
  week matched to Tuesday of last year (except for leap year)
  SELECT 
      ORACLE_KEY as StoreID
      FIELD1  as SalesLastYear
      FIELD2  as GuestCountLastYear   
  FROM MYDAILYTOTALS
  WHERE Busi_date = SalesDateForLastYear 
     AND ORACLE_KEY IN (SELECT StoreID From MyStores);
         
  
  SELECT 
      ORACLE_KEY as StoreID
      SUM(FIELD1)  as WeekToDateSales
      SUM(FIELD2)  as WeekToDateGuestCount  
  FROM MYDAILYTOTALS
  WHERE Busi_date BETWEEN SalesDateBeginningOfWeek and SalesDate
     AND ORACLE_KEY IN (SELECT StoreID From MyStores) 
  GROUP BY ORACLE_KEY 
     --=======  
  SELECT 
      ORACLE_KEY as StoreID
      SUM(FIELD1)  as WeekToDateSalesLastYear
      SUM(FIELD2)  as WeekToDateGuestCountLastYear  
  FROM MYDAILYTOTALS
  WHERE Busi_date BETWEEN SalesDateBeginningOfWeekLastYear and SalesDateLastYear
     AND ORACLE_KEY IN (SELECT StoreID From MyStores) 
  GROUP BY ORACLE_KEY   

  Question: Since they all use the same store of nbrs, I specify on each request? Can't I just specify only once on outer query Where clause?
  
  Also, how would fit the following of HOEK script:
  See how I put 1 field based on another field value
  
  He reads a record for each store of 116 stores in the database. There are 2 situations that have been addressed by Hoeks code:
  For each of the 116 stores in the store table, there must be 1 and only
  registration of 1 stock to match the record of MyStoreTotals. However, sometimes there is no record of inventory.
  and sometimes there will be 2 (in a case where a manager of database updates)
  After daily treatment) files. If so, the record with Is_posted = 1
  is the one that should be included in the query. The following text accomplishes this:
  -chr (39) is the single quote
  

   Select StoreId, 
           DollarVariance 
    from   (select store.storeid, 
                     case
                            when inv.storeid is null then 'None'
                            when inv.is_posted = 0 then 'NP'
                            else chr(39)||inv.total_dol_var||chr(39)
                      end as DollarVariance, 
                      row_number() over (partition by store.storeid order by inv.is_posted desc) rn  
                 from  myInven inv 
                 right outer join mystores  store
                                on store.storeid = inv.fk_str_main_id
                                and inv.busi_date = to_date(SalesDate, 'dd-mon-yyyy'))
        where rn = 1;      

  Can I put this request on the place where clause of the outer to query I put on a JOIN clause?

  So I guess that's why you used the MAX.

  That is right.
  I used CASES to identify and complete the necessary columns since the first set of results (WITH).
  So then I more or less "swivels somehow" lines of this result set to the columns, each store will appear once the most.

• left and right outer join

  Hi gurus,

  Left outer join:

  -------------------

  Select * from A LEFT OUTER JOIN B on A.col = B.col;

  by definition, a left outer join brings the rows that match the join condition and lines not corresponding to table A.

  My question here is "corresponding to B and no matching rows in A" is that nothing, but... SELECT * FROM A;

  can someone pls clarity...

  Thank you.

  Imagine that you had:

  TableA

  COLUMN1 COLUMN2

  'A'                1

  'B'                2

  'C'                3

  TABLEB

  COLUMN1 COLUMN2

  'A'                 'X1'

  'A'                 'X2'

  'B'                 'Y'

  'D'                 'Z'

  SELECT * FROM TABLEA;

  A 1

  B 2

  C 3

  Now, if you want to join (first column is either in table A or B, (deuxieme from tableA, third table B)

  SELECT * FROM TABLEA A JOIN TABLEB B ON (A.COLUMN1 = B.COLUMN1)

  A 1 X 1

  A 1 X 2

  B 2 Y

  SELECT * FROM TABLE LEFT B EXTERNAL ON (A.COLUMN1 = B.COLUMN1) JOIN TABLE

  A 1 X 1

  A 1 X 2

  B 2 Y

  C 3 {null}

  SELECT * FROM TABLE A TABLE RIGHT OUTER JOIN B (A.COLUMN1 = B.COLUMN1)

  A 1 X 1

  A 1 X 2

  B 2 Y

  D {null} Z

  SELECT * FROM TABLE A TABLE FULL OUTER JOIN B (A.COLUMN1 = B.COLUMN1)

  A 1 X 1

  A 1 X 2

  B 2 Y

  C 3 {null}

  D {null} Z

  HTH

• Outer joins are equijoins and?

  Manual says Yes, but I think their only equijoins, insofar as the matched data and include other data as well. so technically should not fall outside the category of the equijoins?

  Hello

  Outer joins can be are equijoins.  In other words, some outer joins are of equijoins, others are not.

• Outer joins and null in the 'where' clause condition

  Hi people,

  Please help me on this.

  Here's my query.

  with x

  (select 'a' as a dual union all col1)

  Select 'b' as col1 of union double all the

  Select 'c' as double col1

  ),

  y as

  (

  Select 'b' as col2 from dual Union all the

  Select 'c' as col2 from dual Union all the

  Select would be "as col2 from dual Union all the"

  Select 'e' as col2 from dual

  )

  Select * x y right outer join

  on x.col1 = y.col2 and y.col2 is null

  Get all the lines of 'COL1' as null. Why like this?

  Just add the condition to the WHERE clause for example

  WITH x AS
  (SELECT 'a' AS col1 FROM dual UNION ALL
  SELECT 'b' AS col1 FROM dual UNION ALL
  SELECT 'c' AS col1 FROM dual
  ),
  y AS
  (
  SELECT 'b' AS col2 FROM dual UNION ALL
  SELECT 'c' AS col2 FROM dual UNION ALL
  SELECT 'd' AS col2 FROM dual UNION ALL
  SELECT 'e' AS col2 FROM dual
  )
  SELECT * FROM x LEFT OUTER JOIN y
  ON x.col1=y.col2                     ----want to add "and y.col2 is null " condition to get value "a"
  where y.col2 is null
  

• left outer join and the where clause for the table to the right

  I want to join two tables a and b, where a is a must and b is a result set in option. When I use a left outer join to a to b, I want to achieve:
  
  1. Select a single column, two columns of b (not the join columns)
  2 - even if theres no friendly on the join column does not return data from one.
  3. If there is a match applies when the criteria on column b (table in option)
  
  so, how can I avoid no_data_found in this case? When I apply where criteria for b, so it does not return the data from one, which is a must.

  Sounds like a regular outer join to me...

  select a.col1, b.col2, b.col2
  from   tableA a
         left outer join tableB b
         on (a.id = b.id and b.colX = 'X')
  

• Outer Join and joining several Tables

  Hello
  
  Oracle Database 10 g Express Edition Release 10.2.0.1.0 - product
  
  I have three tables AddProject, AssociateProjectLead, AddAssociate. Now I'm generating a report who will join AddProject and AssociateProjectLead for a list of all the projects, even if it doenst have a project coordinator. I used the outer join for this. However, if I want the name of the project leader, I need to search for AddAssociate table. By joining this table also, the outer join is no longer valid. Please see the result below
  
  

  CREATE TABLE  "ADDPROJECT" 
     (     "VERSIONNO" NUMBER(*,0), 
       "PROJID" VARCHAR2(20), 
       "PROJNAME" VARCHAR2(60), 
       "PROJSTARTDATE" DATE, 
       "PROJSTATUS" VARCHAR2(20), 
       "PROJENDDATE" DATE, 
       "PROJENDTYPE" VARCHAR2(20), 
       "PROJENDREASON" VARCHAR2(1000), 
       "UCPROJECTMANAGER" VARCHAR2(20), 
       "FROMDATE" DATE, 
       "TODATE" DATE, 
       "SRCHFIELD" VARCHAR2(20), 
       "OPERATOR" VARCHAR2(20), 
       "PARENTPROJID" VARCHAR2(20), 
       "PROJHIDDENDATE" VARCHAR2(20), 
        CONSTRAINT "PK_B36" PRIMARY KEY ("PROJID", "PROJHIDDENDATE") ENABLE
     )
  
  
  CREATE TABLE  "ADDASSOCIATE" 
     (     "VERSIONNO" NUMBER(*,0), 
       "ASSOCIATEID" NUMBER(9,0) NOT NULL ENABLE, 
       "ASSOCIATENAME" VARCHAR2(100) NOT NULL ENABLE, 
       "CTOJOINDATE" DATE, 
       "STATUS" VARCHAR2(20), 
       "ENDDATE" DATE, 
       "SRCHFIELD" VARCHAR2(20), 
       "OPERATOR" VARCHAR2(20), 
       "FROMDATE" DATE, 
       "TODATE" DATE, 
        CONSTRAINT "PK_B23" PRIMARY KEY ("ASSOCIATEID") ENABLE
     )
  
  CREATE TABLE  "ASSOCIATEPROJECTLEAD" 
     (     "VERSIONNO" NUMBER(*,0), 
       "PROJLEADASSOID" NUMBER(9,0), 
       "PROJID" VARCHAR2(20), 
       "ASSOCIATEID" NUMBER(9,0), 
       "PROJLEADSTARTDATE" DATE, 
       "STATUS" VARCHAR2(20), 
       "ASSOCPROJHIDDENDATE" VARCHAR2(20), 
       "PROJHIDDENDATE" VARCHAR2(20), 
       "ENDDATE" DATE, 
        CONSTRAINT "PK_B40" PRIMARY KEY ("ASSOCIATEID", "PROJID", "ASSOCPROJHIDDENDATE") ENABLE
     )
  
  
  elect ap.projid,apl.associateid
  from addproject ap, associateprojectlead apl
  where ap.projid = apl.projid(+)
  and ap.projhiddendate = apl.projhiddendate(+)
  
  
  PROJID ASSOCIATEID 
  Proj08 75825 
  Proj09 75825 
  Proj10 75825 
  Proj11 75825 
  Proj12 259811 
  Proj01 103035 
  Proj02 103035 
  Proj03 320092 
  Proj04 320092 
  Proj05 120974 
  Proj06 367393 
  Proj07 117618 
  Proj07 224882 
  Proj07 246652 
  prj001 -  
  prj001 -  
  
  16 rows returned in 0.00 seconds
  
  
  select ap.projid,apl.associateid,aa.associatename
  from addproject ap, associateprojectlead apl,addassociate aa
  where ap.projid = apl.projid(+)
  and ap.projhiddendate = apl.projhiddendate(+)
  and apl.associateid = aa.associateid
  
  
  PROJID ASSOCIATEID ASSOCIATENAME 
  Proj11 75825 Amarendra Kumar Singh 
  Proj10 75825 Amarendra Kumar Singh 
  Proj09 75825 Amarendra Kumar Singh 
  Proj08 75825 Amarendra Kumar Singh 
  Proj02 103035 Rajesh Jayaprakash 
  Proj01 103035 Rajesh Jayaprakash 
  Proj07 117618 Chetan Malhotra 
  Proj05 120974 Perumal Rajaram 
  Proj07 224882 Dilshad Ahmad 
  Proj07 246652 Shankar Kausley 
  Proj12 259811 Arunchandar Arun Vasan 
  Proj04 320092 Venkatesh Sarangan 
  Proj03 320092 Venkatesh Sarangan 
  Proj06 367393 Venkata Ramakrishna P 
  
  14 rows returned in 0.00 seconds

  How can I select all the values in table AddProject?
  
  Published by: Pramukh on August 23, 2012 12:18

  Hello

  I could get the result with a bit of modification

  select ap.projid,
         apl.associateid,
         aa.associatename
    from addproject ap
         left outer join
         associateprojectlead apl
      on ap.projid = apl.projid
     and ap.projhiddendate = apl.projhiddendate
         left outer join
         addassociate aa
      on apl.associateid = aa.associateid
  

  As a follow-up, I have a request more. In the report form, the user can select a particular project ID and the report should be generated as a result. For example;-he wants to see the results of the only "Proj08". I get the output as below, while the result should display only the details of 'Proj08 '.

  select ap.projid,
         apl.associateid,
         aa.associatename
    from addproject ap
         left outer join
         associateprojectlead apl
      on ap.projid = apl.projid
     and ap.projhiddendate = apl.projhiddendate
     and ap.projID = 'Proj08'
         left outer join
         addassociate aa
      on apl.associateid = aa.associateid
  ORDER BY ap.projID
  
  PROJID ASSOCIATEID ASSOCIATENAME
  Proj01 -  -
  Proj02 -  -
  Proj03 -  -
  Proj04 -  -
  Proj05 -  -
  Proj06 -  -
  Proj07 -  -
  Proj08 75825 Amarendra Kumar Singh
  Proj09 -  -
  Proj10 -  -
  Proj11 -  -
  Proj12 -  -
  prj001 -  -
  prj001 -  -  
  

• What is the difference between NOT IN and LEFT OUTER JOIN

  Hello
  
  I searched the difference between everywhere. But his powerlessness.
  Please tell me the differences.
  
  Thanks in advance
  KVB

  It's like comparing apples and oranges.

  NOT IN - exclude all lines matching the condition NOT IN (beware of NULL values).

  JOIN EXTERNAL - return of rows from the inner table even if there is no corresponding row in the outer table.

  SQL> -- NOT IN
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  where  col1 not in (1,2);
  
        COL1
  ----------
           3
  
  SQL> -- NOT IN (subquery)
  SQL>
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  where  col1 not in (select col1 from y);
  
        COL1
  ----------
           2
           3
  
  SQL> -- OUTER JOIN
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  left outer join
   10         y
   11  on x.col1 = y.col1;
  
        COL1       COL1
  ---------- ----------
           1          1
           3
           2
  
  SQL> -- Maybe it helps to contrast LOJ with just JOIN?
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  join   y
   10  on x.col1 = y.col1;
  
        COL1       COL1
  ---------- ----------
           1          1
  
  SQL>