Oracle: Use LEFT OUTER JOIN, but convert the data to an external list

Hello, all,.

I know it can be done; I just don't remember how I got it done, oh there are so many years.

Assumes that the tables exist for groups and individuals.  People can belong to several groups.

SELECT g.groupName, p.lastName || ', ' || p.firstName as fullName
FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON gpa.groupID = g.groupID
              LEFT OUTER JOIN person p ON p.personID = gpa.personID
ORDER BY g.groupName, fullName

This gives us:

Group One          Alpha, Daniel
Group One          Bravo, Charles
Group One          Charlie, Chuck
Group Two          Beta, Alpha
Group Two          Delta, Bonnie
Group Three        Echo, Bunny
Group Three        Golf, Samuel
Group Three        November, Stan

How word the SQL to get the data as:

Group One          Alpha, Daniel | Bravo, Charles | Charlie, Chuck
Group Two          Beta, Alpha | Delta, Bonnie
Group Three        Echo, Bunny | Golf, Samuel | November, Stan

V/r,

^_^

I finally thought to it.  I was using incorrect keywords on Google.

SELECT g.groupName, LISTAGG(p.lastName || ', ' || p.firstName,' | ') WITHIN GROUP (ORDER BY g.groupName) "fullName"
FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON ggpa.groupID = g.groupID
              LEFT OUTER JOIN person p ON p.personID = gpa.personID
GROUP BY g.groupName
ORDER BY g.groupName, fullName  

Just in case someone else is going through this same desire.

HTH,

^_^

Tags: ColdFusion

Similar Questions

  • Using Left Outer Join with reference

    I have three tables.
    Table 1: BOOK_DETAILS
    Fields: BOOK_ID, BOOK_NAME

    Table 2: BOOK_ISSUE_RECORD
    Fields: BOOK_ID, USER_NAME

    Table 3: BOOK_AUTHOR
    Fields: BOOK_ID, AUTHOR_NAME

    I must link table 1 and table 2 with a left outer join, because even if the book is not the questions to anyone, his name should come.
    I have once again display the name of the author of books for each book.
    I am able to create a query with the left outer join between table 1 and table 2. However, I am not able to give a reference to Table 3.
    Can someone help me with this please.

    Concerning
    Hawker
    select  d.book_name,
            a.book_author,
            i.user_name
      from       book_details d
            join
                 book_author a
              on (d.book_id = a.book_id)
            left join
                 book_issue_recors i
              on (d.book_id = i.book_id)
    /
    

    SY.

  • outer join while selecting the date max

    Hello
    Oracle 11g R2.

    I want to build a query that joins outside between 2 related tables, but selects only the date max if more than 1 record returned for a given customer. Here are the tables I and some records.

    create table customer (NumCli number, name varchar2 (100))
    create table orders (ordnum number, NumCli number, date orddate)

    insert into customers values (1, 'ABC')
    insert into customer values (2, 'DEF')
    insert into customer values (3, 'ABC')
    insert into customer values (4, 'DEF')

    insert into orders values (1, 1, sysdate)
    insert into orders values (2, 1, sysdate + 1)
    insert into orders values (3, 2, sysdate + 2)

    I created the following query, but it returns the two dates for NumCli = 1. I want to display the name of the client no matter if he has a prescription. But if there is more order, I want display the folder with the date max.

    Select a.custnum, b.SID, b.orddate
    client a, b of orders
    where a.custnum = b.custnum (+)
    and b.orddate (+) < = sysdate + 10 - additional criteria as part of the edition

    It is a simplified example of a more complex query, that I am trying to solve. If possible, could you please suggestion a request without the use of analytical functions or inline views?
    Thank you!!

    Published by: arizona9952 on April 4, 2013 22:05

    arizona9952 wrote:
    Thanks Jac. Any way to do this without a group of?

    Is there a particular reason not to use MAX?

    It will be difficult to find a maximum date without a group of... If it's ok for you to have everything available, you can use the correlated sub query...

    select a.custnum, a.name,
             (
               select b.orddate
               from   orders b
               where b.custnum = a.custnum
               and b.orddate <= sysdate + 10
               and rownum = 1 ) ordddate
    from customer a
    
  • Left Outer Join DR.

    Hi Experts,

    I have a requirement that says - see the chart for the past 10 days, regardless the presence data table in fact.
    Lets consider an example - Time_dim product, are my dimension tables, Purchase_Order is my fact table.

    I did it for external Purchase_Order in left RPD with TIME_DIM and inner join with the PRODUCT table.  and execution of query of exit-
    Select T.Date, P.item, count (distinct PO.order_no)
    TIME_DIM t, PRODUCT P, PURCHASE_ORDER PO
    where T.date_key = PO.date_key
    and P.item = in. agenda
    and P.item = 'laptop ';

    The query generated by OBIEE left outer join, but when the condition P.item = "Notebook" included in the query, and if there are no orders for this product in one of the date, that date will not come in the result set.

    the query to be generated by the OBIEE is-


    Select T.Date, PO.item, count (distinct PO.order_no)
    TIME_DIM t,.
    (SELECT P.ITEM, IN. ORDER_NO
    PRODUCT P, PO PURCHASE_ORDER
    WHERE P.item = in. agenda
    and P.item = 'Laptop') IN.
    WHERE T.date_key = PO.date_key (+);

    How to design the RPD to achieve this. All pray to advise on this. Thanks in advance.

    Thank you
    Chantal

    Hello

    You are on 11.1.1.7?

    I would say that your condition can be made without using external and maintenance of product and the standard between the FACT dimension, time inner join join.

    If you enable your property analysis OBIEE "Include Null values" will automatically return all the elements of time and product matching your filter (so you'll need to add a filter on 'Date' to limit it to the last 10 days or you will have a unique day of your time dimension).

    If you filter then on "Laptop", even if there is not a single value in order for "Laptop" in the last 10 days, he will be there on the screen.

    Easy, clean and you keep your inner join between the facts and Dimensions.

    Take a look at this example, I just did on SampleApp 406:

    Selection of 12 months (year 2010) and a customer (id = 89) and income. The model has only an inner join. I activate the option "Include Null values" and here is the result.

    A line with cells only empty because there is not a single revenue for customer 89 in 2010. This is exactly your condition.

    Honestly, do not touch your model using the outer join, you will have more side effects than benefits. Every single scan will do the outer join and you'll have a lot of data 'empty' return of the DB (more large data set containing just the null values) and probably you need the outer join in 15 to 25% of your analysis.

    Keep things simple, it will be faster and easier to maintain.

  • Left outer join without data in a table

    I have two tables defined (see below). Emp table has given, and there is still no data in the table of Emp_Type! Now it is empty.

    I want to write a query that returns the data from the tables, even if there is no data in the Emp_type table. I use a left outer join but it return nothing. Can anyone help?
    create table EMP
    (
      EMPID   NUMBER(10,2),
      EMPNAME VARCHAR2(100)
    );
    
    INSERT INTO emp (empid,empname) values (1, 'Mark');
    INSERT INTO emp (empid,empname) values (2, 'Jason');
    INSERT INTO emp (empid,empname) values (3, 'Kevin');
    INSERT INTO emp (empid,empname) values (4, 'Drew');
    INSERT INTO emp (empid,empname) values (5, 'Jessica');
    INSERT INTO emp (empid,empname) values (6, 'Pena');
    INSERT INTO emp (empid,empname) values (7, 'Roxanne');
    
    create table EMP_Type
    (
      ID          NUMBER(10,2),
      EMPID       NUMBER(10,2),
      TYPE_ID     NUMBER(10,2),
      END_DATE    DATE
    );
    
    No data
    
    select *
      from emp e
      left outer join emp_Type t
        on e.empid = t.empid
     WHERE t.type_id = 1
       and t.end_date is null;

    WHERE t.type_id = 1

    will be ever true when table has no rows (or t.type_id is NULL?)

  • using (+) or left outer join

    Dear Expert;

    I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.

    Thank you.

    Hello

    user13328581 wrote:
    Dear Expert;

    I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.

    They all have two outer joins. The + rating was the original way to do it in Oracle. LEFT, RIGHT, and FULL OUTER JOIN introduced in Oracle 9, but the old way is still supported.

    There are some situations (such as an outer join complete and outer-join a table to two different tables) that are better with the ANSI syntax (it's LEFT OUTER JOIN). It is possible to get the same results using +, but it must be combersome and/or inefficient workarounds. I suggest that you use always LEFT OUTER JOIN (or FULL OUTER JOIN, or, on occasions RIGHT OUTER JOIN). I think that you will find it easier and less error-prone.

  • Get the error invalid identifier in the left outer join

    I wrote a query and get the invalid identifier error during execution:
    the exact error is: ORA-00904: "D". "" ACCT_NO ": invalid identifier
    This query is not able to access the parent table alias in the subquery of the left outer join.

    This is the query:
    SELECT D.PROD_DESC_TX, BASE. ASSET_NUM, BASE. PROD_ID, BASE.NAME
    OF TABLE1 D
    LEFT OUTER JOIN
    (
    SELECT ASSET_NUM, PROD_ID, B.SID
    FROM TABLE2 E
    JOIN IN-HOUSE TABLE3 HAS IT E.PROD_ID = A.ROW_ID
    JOIN INTERNAL TABLE 4 C ON A.PAR_PROD_INT_ID = C.ROW_ID
    INTERNAL TABLE5 JOIN B ON C.ROW_ID = B.PAR_ROW_ID
    AND B.TYPE = 'VALUE '.
    AND B.NAME = 'VALUE '.
    WHERE E.ASSET_NUM = ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO)))
    ) BASE ON ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO))) = BASE. ASSET_NUM
    WHERE D.BANK_NO = 'VALUE '.
    AND D.APPL_CD = 'VALUE '.
    AND D.ACCT_NO = 'VALUE '.

    Edited by: user648525 13 Sep, 2011 01:21

    I can easily look at your request at this time (using my iPhone on a train).

    But trying out this line in the WHERE (the one with the invalid reference) clause in the main query.

    Who is... in the view of inline, use only the logic of the join (the clauses).

    Overflow the filtering logic (WHERE clause) to the main request. You may need to select some additional inline view columns to make these references work.

  • Modeling of the left outer join

    Hello world

    I'm tender hand to you guys for a modeling help

    I have a FACT, the customers, the Dim_Date and CUST_ADDRESS of tables to model

    Fact and the client are joined through CUST_ID

    FACT and DATE are joined through DATE_ID

    CUST_ADDRESS must be attached to the top of the model through CUST_ID, DATE_ID and this join must be Left outer because sometimes the address does not exist or is not current, which means DATE_ID could be different between Dim_Date and CUST_ADDRESS

    If it were to join internal, model would have been easy, because of the outside left that I am unable to model, it's pretty good.

    Application under
    Select D.DATE, C.CUST_NAME, CA. ADDRESS, F.AMOUNT
    Of
    F FACT
    JOIN THE
    CUSTOMER C
    ON C.CUST_ID = F.CUST_ID
    JOIN THE
    DIM_DATE D
    ON F.DATE_ID = D.DATE_ID
    LEFT OUTER JOIN
    CUST_ADDRESS CA
    ON C.CUST_ID = CA. CUST_ID AND C.DATE_ID = D.DATE_ID

    Thanks in advance

    When I add the CUSTOMER and in FACT LTS CUST_ADDRESS

    Stop it!

    Don't add CUSTOMER and CUST_ADDRESS in the FACT of LTS. Why would add you to the LTS DO?

    You design a management model: CUSTOMER is a dimension and it has its own logical table this logic table join with a logical join in the activity diagram. Ditto for CUST_ADDRESS.

    So the change, I missed earlier is CUST_ADDRESS contains no Cust_ID (ACTUALLY existing), but contains a Cust_NO, and the table to translate Cust_NO in Cust_ID is CUSTOMER?

    No problem...

    Let's start with a new alias of CUSTOMER (to keep more simple to understand at the moment), call as you want, but this new alias will be the link between the FACT and CUST_ADDRESS.

    In LTS of the dimension 'Address', you have CUST_ADDRESS initially, add an inner join on the new alias that you created in the LTS of the CUSTOMER. So now your 'Address' logical dimension contains the Cust_NO and Cust_ID and this will make the join to FACT.

    Between CUST_ADDRESS and the CLIENT, you can keep an inner join, because the target is not not for get the address of the customer, but is having the Cust_ID in the address line.

    Give it a try at that.

    But do not add these tables in the LTS, they are logical dimensions.

  • left outer join and the where clause for the table to the right

    I want to join two tables a and b, where a is a must and b is a result set in option. When I use a left outer join to a to b, I want to achieve:

    1. Select a single column, two columns of b (not the join columns)
    2 - even if theres no friendly on the join column does not return data from one.
    3. If there is a match applies when the criteria on column b (table in option)

    so, how can I avoid no_data_found in this case? When I apply where criteria for b, so it does not return the data from one, which is a must.

    Sounds like a regular outer join to me...

    select a.col1, b.col2, b.col2
    from   tableA a
           left outer join tableB b
           on (a.id = b.id and b.colX = 'X')
    
  • What is the difference between NOT IN and LEFT OUTER JOIN

    Hello

    I searched the difference between everywhere. But his powerlessness.
    Please tell me the differences.

    Thanks in advance
    KVB

    It's like comparing apples and oranges.

    NOT IN - exclude all lines matching the condition NOT IN (beware of NULL values).

    JOIN EXTERNAL - return of rows from the inner table even if there is no corresponding row in the outer table.

    SQL> -- NOT IN
    SQL> with x as
      2  (select 1 col1 from dual union all
      3   select 2 col1 from dual union all
      4   select 3 col1 from dual)
      5  ,    y as
      6  (select 1 col1 from dual)
      7  select *
      8  from   x
      9  where  col1 not in (1,2);
    
          COL1
    ----------
             3
    
    SQL> -- NOT IN (subquery)
    SQL>
    SQL> with x as
      2  (select 1 col1 from dual union all
      3   select 2 col1 from dual union all
      4   select 3 col1 from dual)
      5  ,    y as
      6  (select 1 col1 from dual)
      7  select *
      8  from   x
      9  where  col1 not in (select col1 from y);
    
          COL1
    ----------
             2
             3
    
    SQL> -- OUTER JOIN
    SQL> with x as
      2  (select 1 col1 from dual union all
      3   select 2 col1 from dual union all
      4   select 3 col1 from dual)
      5  ,    y as
      6  (select 1 col1 from dual)
      7  select *
      8  from   x
      9  left outer join
     10         y
     11  on x.col1 = y.col1;
    
          COL1       COL1
    ---------- ----------
             1          1
             3
             2
    
    SQL> -- Maybe it helps to contrast LOJ with just JOIN?
    SQL> with x as
      2  (select 1 col1 from dual union all
      3   select 2 col1 from dual union all
      4   select 3 col1 from dual)
      5  ,    y as
      6  (select 1 col1 from dual)
      7  select *
      8  from   x
      9  join   y
     10  on x.col1 = y.col1;
    
          COL1       COL1
    ---------- ----------
             1          1
    
    SQL> 
    
  • doubt left outer join

    Hi all

    I use under version

    Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0

    SQL > SELECT E.ENAME,.

    2 D.DEPTNO,

    3 D.LOC

    4. TO EMP E,.

    DEPT 5 D

    6. WHERE = E.DEPTNO D.DEPTNO (+);

    ENAME, DEPTNO LOC

    ---------- ------ -------------

    DALLAS SMITH 20

    ALLEN 30 CHICAGO

    WARD 30 CHICAGO

    20 DALLAS JONES

    MARTIN 30 CHICAGO

    BLAKE 30 CHICAGO

    CLARK 10 NEW YORK

    SCOTT 20 DALLAS

    THE 10 NEW YORK KING

    TURNER 30 CHICAGO

    20 DALLAS ADAMS

    JAMES 30 CHICAGO

    FORD 20 DALLAS

    MILLER 10 NEW YORK

    40 BOSTON

    15 selected lines

    -----------------------------------------------------------------------------------------------------------------------------

    SQL > SELECT E.ENAME,.

    2 D.DEPTNO,

    3 D.LOC

    4. TO EMP E

    5 LEFT OUTER JOIN

    D 6 DEPT

    7. THE E.DEPTNO = D.DEPTNO;

    ENAME, DEPTNO LOC

    ---------- ------ -------------

    MILLER 10 NEW YORK

    THE 10 NEW YORK KING

    CLARK 10 NEW YORK

    FORD 20 DALLAS

    20 DALLAS ADAMS

    SCOTT 20 DALLAS

    20 DALLAS JONES

    DALLAS SMITH 20

    JAMES 30 CHICAGO

    TURNER 30 CHICAGO

    BLAKE 30 CHICAGO

    MARTIN 30 CHICAGO

    WARD 30 CHICAGO

    ALLEN 30 CHICAGO

    14 selected lines

    My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.

    but the results are different.

    For the first query null is coming for unmatched records in the dept table

    but in the second query, it does not come

    Thank you

    Hello

    2947022 wrote:

    Hi all

    I use under version

    Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0

    SQL > SELECT E.ENAME,.

    2 D.DEPTNO,

    3 D.LOC

    4. TO EMP E,.

    DEPT 5 D

    6. WHERE = E.DEPTNO D.DEPTNO (+);

    ENAME, DEPTNO LOC

    ---------- ------ -------------

    DALLAS SMITH 20

    ALLEN 30 CHICAGO

    WARD 30 CHICAGO

    20 DALLAS JONES

    MARTIN 30 CHICAGO

    BLAKE 30 CHICAGO

    CLARK 10 NEW YORK

    SCOTT 20 DALLAS

    THE 10 NEW YORK KING

    TURNER 30 CHICAGO

    20 DALLAS ADAMS

    JAMES 30 CHICAGO

    FORD 20 DALLAS

    MILLER 10 NEW YORK

    40 BOSTON

    15 selected lines

    -----------------------------------------------------------------------------------------------------------------------------

    SQL > SELECT E.ENAME,.

    2 D.DEPTNO,

    3 D.LOC

    4. TO EMP E

    5 LEFT OUTER JOIN

    D 6 DEPT

    7. THE E.DEPTNO = D.DEPTNO;

    ENAME, DEPTNO LOC

    ---------- ------ -------------

    MILLER 10 NEW YORK

    THE 10 NEW YORK KING

    CLARK 10 NEW YORK

    FORD 20 DALLAS

    20 DALLAS ADAMS

    SCOTT 20 DALLAS

    20 DALLAS JONES

    DALLAS SMITH 20

    JAMES 30 CHICAGO

    TURNER 30 CHICAGO

    BLAKE 30 CHICAGO

    MARTIN 30 CHICAGO

    WARD 30 CHICAGO

    ALLEN 30 CHICAGO

    14 selected lines

    My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.

    but the results are different.

    For the first query null is coming for unmatched records in the dept table

    but in the second query, it does not come

    Thank you

    In fact, these requests are not the same.

    The first is to find all the lines of the Department, with the corresponding lines of PGE (when there are).  This is equivalent to «FROM dept LEFT OUTER JOIN emp...» ».

    The second is to find all the rows in the emp of the lines of the Department (when there are any).  This is equivalent to «...» WHERE e.deptno = d.deptno (+).

  • Bad result in a left outer join in 12.1.0.2

    Hallo,

    We discovered a strange behaviour in a query. The query provides values in a column of outer join where there is no corresponding value in the table is attached to the outside.

    When you expand this request by the "ORDER BY" then this query gives the correct result.

    Example:

    SQL > desc tb_a
    Name                                Null?    Typ
    -------------------------------------------- ----------------------------
    ID NOT NULL NUMBER (19)

    SQL > desc tb_b
    Name                                Null?    Typ
    -------------------------------------------- ----------------------------
    CLOSED NOT NULL NUMBER (1)
    ID NOT NULL NUMBER (19)

    CCS_APPLICATION@icw01> select * from tb_a where id in (4148,4141,4195);

    ID
    ----------
    4148
    4141
    4195

    CCS_APPLICATION@icw01> select * from tb_b where id in (4148,4141,4195);

    INTERNAL ID
    ---------- ----------
    4148 0

    CCS_APPLICATION@icw01> SELECT
    2      b.id                            AS b_id,
    3      a.id                            AS a_id,
    4 b.closed AS b_closed
    5
    6 tb_a a
    7 LEFT OUTER JOIN tb_b b ON a.id = b.id
    8 WHERE a.id IN (4148, 4195, 4141)
    9 ORDER BY ASC a.id
    10;

    B_ID ALLOCATION A_ID B_CLOSED
    ---------- ---------- ----------
    4141
    4148 4148 0
    4195

    CCS_APPLICATION@icw01> SELECT
    2      b.id                            AS b_id,
    3      a.id                            AS a_id,
    4 b.closed AS b_closed
    5
    6 tb_a a
    7 LEFT OUTER JOIN tb_b b ON a.id = b.id
    8 WHERE a.id IN (4148, 4195, 4141)
    9 - ORDER BY ASC a.id
    10;

    B_ID ALLOCATION A_ID B_CLOSED
    ---------- ---------- ----------
    4148 4148 0
    4141 4141
    4195 4195

    instance parameter:

    VALUE OF TYPE NAME

    ------------------------------------ ----------- ------------------------------

    compatible string 12.1.0.2.0

    optimizer_features_enable string 12.1.0.2

    After ""alter system set optimizer_features_enable = ' 11.2.0.4 ';"  the query provides the correct result in both cases (ordered and unordered).

    Now the final question: is this a bug?

    1480970 wrote:

    Hallo!  Yes, I searched the Support of Oracle. I found some similar entries, but not an exact match. To fix some issues

    with 12.1.0.2.

    There is another interesting clue when look you on the execution plan:

    Note

    -----

    -the dynamic statistics used: dynamic sampling (level = 2)

    - This is an adaptation plan

    We have disabled (= FALSE) optimizer_adaptive_features and the query provides the correct values.

    This could be a solution for us.

    Looks like a pretty tight match for bug 18430870, even if it affects the two 12.1.0.1 and 12.1.0.2, which contradicts the Martin trial against 12.1.0.1.

    The description of the bug mentions disabling "_projection_pushdown" (set to false) should also be a viable solution, perhaps if you want to give that a try and see if it is a different bug or not.

    There are also a number of one-time fixes already available for download, maybe your version / platform is already covered, if the bug applies.

    Randolf

  • Help for a LEFT OUTER JOIN query

    Hello, all,.

    I'm having some trouble setting up an Oracle 11 g Server SQL query, and I could use some help.

    Let's say tableA is blogs; tableC is comments for blog entries; tableB is the associative array:

    tableA
    blogID        blogTitle       blogBody      dateEntered
    1             This is a test  More text...  2016-05-20 11:11:11
    2             More testing    Still more!   2016-05-19 10:10:10
    3             Third charm!!   Blah, blah.   2016-05-18 09:09:09
    

    tableC
    commID        userID          userText      dateEntered
    10            Bravo           I like it!    2016-05-20 11:21:31
    11            Charlie         I don't!      2016-05-20 11:31:51
    12            Alpha           Do it again!  2016-05-19 10:20:30
    13            Bravo           Still more?   2016-05-19 10:30:50
    14            Charlie         So, what?     2016-05-19 10:35:45
    15            Bravo           Blah, what?   2016-05-18 09:10:11
    16            Alpha           Magic number! 2016-05-18 09:11:13
    

    tableB
    blogID        commID
    1             10
    1             11
    1             12
    2             13
    2             14
    3             15
    3             16
    
    
    
    

    I'm trying to get blogID, blogTitle, blogBody and the number of comments for each blog entry.  But, since I'm on to_char() for date and COUNT (commID) for the total number of comments, I am not "a group by expression.

    Here is an example of pseudo-SQL of what I'm trying.

    SELECT a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS') as dateEntered, COUNT(c.commID) as total
    FROM tableA a LEFT OUTER JOIN tableB b ON b.blog_ID = a.blog_ID
                  LEFT OUTER JOIN tableC c ON c.commID = b.commID
    WHERE a.blogID = '1'
    GROUP BY blogID, blogTitle, blogBody
    ORDER BY to_date(dateEntered,'MM-DD-YYYY HH24:MI:SS') desc
    

    I'm sure it's something simple, but I just DO NOT see it.  Can you help me?

    V/r,

    ^_^

    Try:

    GROUP BY a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS')
    

    See you soon

    Eddie

  • Why left outer join with a table gives me more lines?

    Hi gurus,

    I can see "view_a" and a table 'table_a '.

    view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.

    However, I'm more than 100 lines. Is it still possible?

    Also even to analyze these situations, how can I move forward?

    Because it is very high volumn of sight and takes longer to run.

    Select count (*) view_a, view_b

    where view_a.col1 = view_b.col1 (+)

    and view_a.col2 = view_b.col2 (+);

    Thank you

    I can see "view_a" and a table 'table_a '.

    view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.

    However, I'm more than 100 lines. Is it still possible?

    Also even to analyze these situations, how can I move forward?

    Because it is very high volumn of sight and takes longer to run.

    Select count (*) view_a, view_b

    where view_a.col1 = view_b.col1 (+)

    and view_a.col2 = view_b.col2 (+);

    Which is not necessarily related to the use of an outer join.

    Just join of two tables in general will give you more rows of one table has.

    Scott DEPT table contains ONE row for deptno = 10

    The EMP table has THREE rows of deptno = 10

    The number of rows you plan if you join two tables using an equi-join?

    Three - what is MORE lines the DEPT table has for deptno = 10

    Select * from Department where deptno = 10

    DEPTNO, DNAME, LOC
    10, ACCOUNTING, NEW YORK

    Select * from emp where deptno = 10

    MGR, EMPLOYMENT ENAME, EMPNO, HIREDATE, SAL, COMM, DEPTNO
    7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
    7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
    7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

    Select dept.*, emp.*
    Department, emp
    where dept.deptno = 10
    and dept.deptno = emp.deptno

    DEPTNO, DNAME, LOC, EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO_1
    10, ACCOUNTING, NEW YORK, 7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
    10, ACCOUNTING, NEW YORK, 7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
    10, ACCOUNTING, NEW YORK, 7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

    So if these are the lines ONLY in the table EMP and DEPT the query would give you THREE lines despite the DEPT table only ONE line.

    No do you expect? You get ALL the child rows that belong to the parent company. Otherwise, how could it possibly work?

    The OUTER join includes lines where the parent row exists but there is NO child line as others have shown.

    Outer joins

    Outer join extends the result of a simple join. Outer join returns all rows that satisfy the join condition and also returns some or all rows in a table for which no line of the other meet the join condition.

    Get more lines to exist in one of the paintings is a basic necessity. It usually has NOTHING to with the question of whether you have an outside to join or not.

    See the section on the JOINTS in the Oracle documentation

    http://docs.Oracle.com/CD/B28359_01/server.111/b28286/queries006.htm

  • Problem with XMLTABLE and LEFT OUTER JOIN

    Hi all.

    I have a problem with XMLTABLE and LEFT OUTER JOIN, in 11g it returns the correct result, but in 10g it doesn't, it is illustrated as a INNER JOIN.
    SELECT * FROM v$version;
    
    Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
    PL/SQL Release 11.2.0.1.0 - Production
    "CORE     11.2.0.1.0     Production"
    TNS for Linux: Version 11.2.0.1.0 - Production
    NLSRTL Version 11.2.0.1.0 - Production
    
    --test for 11g
    
    CREATE TABLE XML_TEST(
         ID NUMBER(2,0),
         XML XMLTYPE
    );
    
    INSERT INTO XML_TEST
    VALUES
    (
         1,
         XMLTYPE
         ('
              <msg>
                   <data>
                        <fields>
                             <id>g1</id>
                             <dat>data1</dat>
                        </fields>
                   </data>
              </msg>
         ')
    );
    
    INSERT INTO XML_TEST
    VALUES
    (
         2,
         XMLTYPE
         ('
              <msg>
                   <data>
                        <fields>
                             <id>g2</id>
                             <dat>data2</dat>
                        </fields>
                   </data>
              </msg>
         ')
    );
    
    INSERT INTO XML_TEST
    VALUES
    (
         3,
         XMLTYPE
         ('
              <msg>
                   <data>
                        <fields>
                             <id>g3</id>
                             <dat>data3</dat>
                        </fields>
                        <fields>
                             <id>g4</id>
                             <dat>data4</dat>
                        </fields>
                        <fields>
                             <dat>data5</dat>
                        </fields>
                   </data>
              </msg>
         ')
    );
    
    SELECT
         t.id,
         x.dat,
         y.seqno,
         y.id_real
    FROM
         xml_test t,
         XMLTABLE
         (
              '/msg/data/fields'
              passing t.xml
              columns
                   dat VARCHAR2(10) path 'dat',
                   id XMLTYPE path 'id'
         )x LEFT OUTER JOIN
         XMLTABLE
         (
              'id'
              passing x.id
              columns
                   seqno FOR ORDINALITY,
                   id_real VARCHAR2(30) PATH '.'
         )y ON 1=1
    ;
    
    ID     DAT     SEQNO     ID_REAL
    --     -----     -----     -------
    1     data1     1     g1
    2     data2     1     g2
    3     data3     1     g3
    3     data4     1     g4
    3     data5          
    This is all nice, now the problem:
    Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
    PL/SQL Release 10.2.0.1.0 - Production
    "CORE     10.2.0.1.0     Production"
    TNS for HPUX: Version 10.2.0.1.0 - Production
    NLSRTL Version 10.2.0.1.0 - Production
    
    --exactly the same environment as 11g (tables and rows)
    SELECT
         t.id,
         x.dat,
         y.seqno,
         y.id_real
    FROM
         xml_test t,
         XMLTABLE
         (
              '/msg/data/fields'
              passing t.xml
              columns
                   dat VARCHAR2(10) path 'dat',
                   id XMLTYPE path 'id'
         )x LEFT OUTER JOIN
         XMLTABLE
         (
              'id'
              passing x.id
              columns
                   seqno FOR ORDINALITY,
                   id_real VARCHAR2(30) PATH '.'
         )y ON 1=1
    ;
    
    ID     DAT     SEQNO     ID_REAL
    --     -----     -----     -------
    1     data1     1     g1
    2     data2     1     g2
    3     data3     1     g3
    3     data4     1     g4
    As you can see in 10g that I don't have the last row, it seems that Oracle 10 g does not recognize the LEFT OUTER JOIN.

    Is this a bug?, Metalink says that sometimes we can have an ORA-0600, but in this case there is no error results returned, just incorrect.

    Help, please.

    Kind regards.

    What about try the original Oracle method for outer joins? Using (+) without the extra space

    XMLTABLE(...COLUMNS ... id XMLTYPE PATH ... ) x,
    XMLTABLE(... PASSING x.id ...) (+) y
    

Maybe you are looking for