Have the help of the clause
Oracle version 8i (we will migrate the db to 12 c in the next few months)
This is defination and data table:
create table sales
(
prod_id varchar2 (10),
PROD_NAME varchar2 (30),
salesman_id varchar2 (10),
salesman_name varchar2 (30),
commission_per varchar2 (10),
commission_amt varchar2 (10)
)
/
Insert in the value of sales ('prd1',' 1 ', ' 1', 'sm1' ", '10');
Insert in the value of sales ('prd1',' 1 ', ' 2', 'sm2' ", '10');
Insert in the value of sales ('prd1',' 1 ', ' 3', 'sm3' ", '10');
Insert in the value of sales ('2 ', 'prd2', '1', 'sm1', '10.00' ");
Insert in the value of sales ('2 ', 'prd2', '2', 'sm2', '10.00' ");
Insert in the value of sales ('3 ', 'prd3', '2', 'sm2', '10.00' ");
Insert in the value of sales ('3 ', 'prd3', '1', 'sm1', '15,00' ");
Insert in the value of sales ('3 ', 'prd3', '3', 'sm3', '10.00' ");
Insert in the value of sales ('4 ', 'prd4', '1', 'sm1', '10.00' ");
Insert in the value of sales ('4', 'prd4', ' 2 ', 'sm2' ", '15');
Insert in the value of sales ('5', 'prd5', ' 1 ', 'sm1' ", '15');
Insert in the value of sales ('6', 'prd6', ' 1 ', 'sm1' ", '15');
Insert in the value of sales ('6', 'prd6', ' 2 ', 'sm2' ", '15');
Insert in the value of sales ('6', 'prd6', ' 3 ',' sm3 ', 15', ");
Insert in the value of sales ('6', 'prd6', ' 4 ',' sm4 ', 15', ");
Insert in the value of sales ('7', 'prd7', ' 1 ', 'sm1' ", '15');
Insert in the value of sales ('7', 'prd7', ' 2 ', 'sm2' ", '15');
Insert in the value of sales ('7', 'prd7', ' 3 ', 'sm3' ", '15');
Insert in the value of sales ('7', 'prd7', ' 4 ', 'sm4' ", '15');
Insert in the value of sales ('7', 'prd7', ' 7 ', 'sm7' ", '15');
Insert in the value of sales ('7', 'prd7', ' 5 ', 'sm1' ", '10');
Insert in the value of sales ('7', 'prd7', ' 6 ', 'sm6' ", '15');
Dress uniform please:
Unique Commision Amount/Commission Percentage: PROD_ID PROD_NAME SALESMAN_I SALESMAN_NAME COMMISSION COMMISSION ---------- ------------------------------ ---------- ------------------------------ ---------- ---------- 1 prd1 1 sm1 10 2 prd2 1 sm1 10.00 5 prd5 1 sm1 15
Means, we must identify the product ID for the business that gives the same percentage of commission sales amount or commission. Percentage of different Commission amount and the Commission:
Different Commision Amount/Commission Percentage: PROD_ID PROD_NAME SALESMAN_I SALESMAN_NAME COMMISSION COMMISSION ---------- ------------------------------ ---------- ------------------------------ ---------- ---------- 3 prd3 2 sm2 10.00 3 prd3 1 sm1 15.00 3 prd3 3 sm3 10.00 4 prd4 1 sm1 10.00 4 prd4 2 sm2 15 6 prd6 1 sm1 15 6 prd6 2 sm2 15 6 prd6 3 sm3 15 6 prd6 4 sm4 15 7 prd7 1 sm1 15 7 prd7 2 sm2 15 7 prd7 3 sm3 15 7 prd7 4 sm4 15 7 prd7 7 sm7 15 7 prd7 5 sm1 10 7 prd7 6 sm6 15
Means, for the highest of the product ID, assigned amount/percentage of different sales commission to sellers; that is for a product id, there is same amount/percentage of commission which would come at the first exit, if these lines of product codes should be in the second output. Kindly help me, since we use very old version, so I think that we cannot use analytics or new SQL functions. So, please help me in a simple sql. Thank you.
I hope that this works in version 8i.
SQL > select prod_id
2, prod_name
3, salesman_id
4, salesman_name
5, commission_per
6, commission_amt
7 of)
8. Select s.*
9, mod (nvl (sum (commission_per) on (prod_id partition), 0), count (*) on (prod_id partition)) +.
10 mod (nvl (sum (commission_amt) on (prod_id partition), 0), count (*) on (prod_id partition)) val
11, row_number() over (partition by prod_id arrested by salesman_id) rno
12 s sale
13 )
14 where val = 0
15 and rno = 1;
PROD_ID PROD_NAME SALESMAN_I SALESMAN_NAME COMMISSION COMMISSION
---------- ------------------------------ ---------- ------------------------------ ---------- ----------
1 prd1 1 sm1 10
2 prd2 1 sm1 10.00
5 prd5 1 sm1 15
SQL > select prod_id
2, prod_name
3, salesman_id
4, salesman_name
5, commission_per
6, commission_amt
7 of)
8. Select s.*
9, mod (nvl (sum (commission_per) on (prod_id partition), 0), count (*) on (prod_id partition)) +.
10 mod (nvl (sum (commission_amt) on (prod_id partition), 0), count (*) on (prod_id partition)) val
11, row_number() over (partition by prod_id arrested by salesman_id) rno
12 s sale
13 )
14 where val! = 0 ;
PROD_ID PROD_NAME SALESMAN_I SALESMAN_NAME COMMISSION COMMISSION
---------- ------------------------------ ---------- ------------------------------ ---------- ----------
3 prd3 2 sm2 10.00
3 prd3 1 sm1 15.00
3 prd3 3 sm3 10.00
4 prd4 1 sm1 10.00
4 prd4 2 sm2 15
6 prd6 2 sm2 15
6 prd6 1 sm1 15
6 prd6 4 sm4 15
6 prd6 3 sm3 15
7 prd7 7 sm7 15
7 prd7 5 sm1 10
7 prd7 4 sm4 15
7 prd7 3 sm3 15
7 prd7 6 sm6 15
7 prd7 1 sm1 15
7 prd7 2 sm2 15
16 selected lines.
SQL >
Tags: Database
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SQL query help needed in the Clause type
Hello
I'm currently learning Clause type. How can I write in the clause type to get the result below:
I have a table like this
DEPTNO ENAME
------- ------
20 SMITH
CELINE 10
BOND 20
ALLEN 30
WARD 30
20 JONES
30 MARTIN
30 BLAKE
10 CLARK
SCOTT 20
10 KING
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20 ADAMS
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I want the output should look like this
DEPTNO ENAME
------ -----
CELINE 10, CLARK, KING, MILLER
20 JONES, ADAMS, BOND, FORD, SCOTT, SMITH
30 MARTIN, JAMES BLAKE, WARD, TURNER, ALLEN
Hear is the script I am currently working on.
with emp_group as
(
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choose 10, 'CÉLINE' from dual union all
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Select 20, "JONES' from dual union all
Select 30, 'MARTIN' from dual union all
Select 30, "BLAKE" from dual union all
choose 10, 'CLARK' from dual union all
Select 20, 'SCOTT' from dual union all
choose 10, 'KING' of the dual union all
Select 30, 'TURNER' from dual union all
Select 20, 'ADAMS' from dual union all
Select 30, 'JAMES' of the dual union all
Select 20, 'FORD' Union double all the
choose 10, 'MILLER' from dual
)
Select
DEPTNO
A1
of emp_group
model
ignore the nav
partition (deptno)
dimension (ROW_NUMBER() over (PARTITION BY deptno ORDER BY ename DESC) rn)
measures (ename, LPAD(' ', 100) A1)
rules)
A1 [rn > 0] = ename [cv ()],
A1 [0] = ename [cv ()]
)
order by deptno
;
your help is very appreciated.
Thank you in advance.
Try this.
Select
*
Of
(
with emp_group as
(
Select 20 deptno, ename 'SMITH' Union double all the
choose 10, 'CÉLINE' from dual union all
Select 20, "BOND" of all the double union
Select 30, 'ALLEN' from dual union all
Select 30, 'WARD' of all the double union
Select 20, "JONES' from dual union all
Select 30, 'MARTIN' from dual union all
Select 30, "BLAKE" from dual union all
choose 10, 'CLARK' from dual union all
Select 20, 'SCOTT' from dual union all
choose 10, 'KING' of the dual union all
Select 30, 'TURNER' from dual union all
Select 20, 'ADAMS' from dual union all
Select 30, 'JAMES' of the dual union all
Select 20, 'FORD' Union double all the
choose 10, 'MILLER' from dual
)
Select
DEPTNO
names
rn
of emp_group
model
ignore the nav
partition (deptno)
dimension of)
ROW_NUMBER() over (PARTITION BY deptno ORDER BY ename) rn
)
measures (ename, cast (null as names of varchar2 (40)))
rules
(
names [any] order by desc = ename [cv ()] rn | «, » || names [cv () + 1]
)
order by deptno
)
where rn = 1
Best regards, Andrei
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