HBA/LUN names - must be the same on hosts?

Similar Questions

• Upload a file attachment name - name must be the same as the name of the file!

  Hello
  Im trying to upload a file to my custom page of the OPS, I need to read the file that iam trying to download and need to display this name. Currently its display as 'view '.
  and I also need to disable the clear button.
  
  I went through the doc jdev, forums and I checked with a few pages standard OPS and written the following code:
  
  DataObject dataobject = pageContext.getNamedDataObject("AttachData");
  String s7 = (String) dataobject.selectValue (null, "UPLOAD_FILE_NAME") ;//
  System.out.println ("S7" + S7);
  
  Up to this point, s7 prints correctly (i, e file never name im trying to download his displays not correctly).
  
  
  When I add the line below its giving error:
  
  BlobDomain blobdomain = (BlobDomain) fileUploadData.selectValue (null, s7);
  
  Can not find the variable "fileUploadData" class...
  
  
  I also tried the below one:
  OADataBoundValueViewObject = displayNameBoundValue
  new OADataBoundValueViewObject (uploadBean, "FileName");
  uploadBean.setAttributeValue (DOWNLOAD_FILE_NAME, displayNameBoundValue);
  
  Even after the import of all needed packages, always his mistake to launch:
  Can not find "uploadBean" class...
  
  
  can anyone help me in this.
  
  Thank you
  Mahesh
  
  Published by: user8996062 on August 23, 2010 15:55

  Mahesh

  Before setting the value of the bean, you will first need to find it. You can use the following code for this.

  import oracle.apps.fnd.framework.webui.beans.message.OAMessageFileUploadBean;
  
  OAMessageFileUploadBean uploadBean = (OAMessageFileUploadBean)webBean.findChildRecursive("Id of your upload Bean");
  OADataBoundValueViewObject displayNameBoundValue =
  new OADataBoundValueViewObject(uploadBean, "FileName");
  uploadBean.setAttributeValue(DOWNLOAD_FILE_NAME,displayNameBoundValue);
  

  I hope that helps!

  Thank you
  AJ

• A file in a source path must have the same package structure ", as the definition's package?

  How I can fix this bug with my class, I get this message:
  
  "A file in a source path must have the same package structure", as the definition, "photoviewer" package. "
  
  It's my source WindowedApplication:
  
  <? XML version = "1.0" encoding = "utf-8"? >
  "" < mx:WindowedApplication xmlns:mx = ' http://www.adobe.com/2006/mxml '
  "" xmlns = "*".
  paddingBottom = paddingTop = "0" "0".
  paddingLeft paddingRight '0' = '0 = '.
  Layout = "vertical".
  pageTitle = "Photo Viewer"
  creationComplete = "init ()" viewSourceURL = "srcview/index.html" > "
  
  < mx:Script >
  <! [CDATA]
  
  Import mx.collections.ArrayCollection;
  Mx.rpc.events import. *;
  
  PhotoViewer Import. Gallery;
  PhotoViewer Import. PhotoService;
  
  [Bindable]
  private var: Gallery;
  
  [Bindable]
  private var service: PhotoService.
  
  private function init (): void
  {
  service = new PhotoService("data/galleries.xml");
  }
  []] >
  < / mx:Script >
  
  This is my Gallery class source:
  
  the photoviewer package
  {
  Import mx.collections.ICollectionView;
  Import mx.collections.ArrayCollection;
  Import mx.collections.IViewCursor;
  
  [Bindable]
  public class Gallery
  {
  public var name: String;
  public var description: String;
  public var photos: ArrayCollection collection;
  public var selected: int;
  
  private var photo: Photo;
  
  public void Gallery (gallery:Object = null)
  {
  photos = new ArrayCollection();
  If (Gallery! = null)
  {
  Fill (Gallery);
  }
  }
  
  public void fill(gallery:Object):void
  {
  myIdName = gallery.id;
  This.Description = gallery.description;
  This.Selected = 0;
  
  for (var i: int = 0; i < gallery.photo.length; i ++)
  {
  Photo = new Photo (gallery.photo );
  photos.addItem (photo);
  }
  }
  }
  }
  
  Someone knows how to fix this error?
  "A file in a source path must have the same package structure", as the definition, 'photoviewer' package. '?
  
  Kind regards
  EvsPeart
  

  Yes. If you want to file package photoviewer Gallery you create directory photoviewer in src and move the file there.

• your ip address of the router and the printer's address must be the same, so it can print from the computer

  IM setting upward a new router and wants to find the printer but the printer and the router are different VPI address Will this work

  Are they similar addresses, for example 192.168.1.1 for the router and 192.168.1.37 for the printer, it should work file.  If they are more than just a bit different - say for example instead of 192.168.1.37 the printer address is 192.168.0.100 or 169.54.45.21 - then is not likely.  In most home networks, the first three bytes of the IP address must be the same with the fourth byte is different for each computer or device connected to the network.

• I use a USB key to solid state. On my Win7 PC, the drive is e: on my XP PC, the drive h: I need the drive must be the same.

  How I change one of them?

  I need them to be of the same kind when I run Outlook on two computers (the .pst file is on the USB key), the path to the Outlook folders must be the same or rules Outlook fails when you try to copy a message from the Inbox to another folder in Outlook e-mail.

  You probably have one of these drives to multi format card on your XP machine who caught a lot of drive letters.  If you don't mind not reconfigure your Outlook rules one last time, I suggest assignment drive letter Z (or something else, towards the end of the alphabet) to your external drive.

  With the drive connected to one of the computers, open disk management:

  • Right click on my computer > manage > disk management
  • Right-click on the drive letter in the upper pane corresponding to the external drive and select "change drive letter and paths".
  • Click the button change
  • Select the new letter drive and OK your way out

  Repeat on the other machine

• E4200 access via a browser is low. Password and wireless keys must be the same.

  I tried to change my admin password to something I just want to know. When I did, I was told that the key and wireless admin password must be the same. What madness is this? I have to give my children the key to enter the system there. I put parental controls for device there. Now all owe it do is google this router and read and then they can understand the key and the password are the same. Log in to the router and change parental controls.

  I thought about a work around that. I would give them the key to access as a guest. It was great if they were going to use a browser to surf the Web. Guest access does not work for me on other devices such as iPods and iPads. In my tests on these types of devices applications cannot get on the Internet with guest access. That a browser can.

  Thoughts from cisco? No help from cisco on this?

  Do not use Cisco Connect and you'll be able to have the password admin and "wireless key" be different without problem.  I don't know why Cisco Connect is doing this, but if you go to http://192.168.1.1 with your web browser after using Cisco Connect and you connect to the web GUI admin here, you can manually set your admin password and the "wireless key" However desired.

• My family name is not the same thing as my husband, but my name appears on the emails under his name. How to change that?

  My name is different from my husband: for example, my name is Mary Smith and my husband is John Doe. When I send an email, the message watch is from may Doe. How can I show that it is Mary Smith? If I send a message to myself, I've send it to Mary Smith, but it is the same thing.

  This is why it is so difficult to solve a problem in the Internet especially in any detail.

  When you look at the main window you see the pane of folders on the left side of the window with your e-mail accounts listed?
  If this is not the case, press the alt key to make the call of menu bar, then select View-presentation-folder pane.

  Now follow the original instructions.

  All this assumes that you and your husband have separate accounts. If you share the same account, then forget. There is only one name associated with an e-mail account. Then the answer is get a second account in your name.

• A file in a source path must have the same package structure

  Hello

  I'm creating an application. What I did to cause this error, should separate my AS3 code to another .as file in the same folder. Since then, I get this error. I tried a couple of different things as creating a new folder under the same structure with the same name as the package I said. However, no effect, it's a gave the same error.

  I searched for information on this error, all suggest the same thing... I did. Probably I did not receive what they say...

  However, can someone explain where I'm wrong about this?

  Thanks and greetings

  H.R.

  My guess is you put in the right place, and the 'heap of various errors' that you refer to are compilation errors in your class. In its current location, Flex doesn't compile your class because he is in the wrong directory, so you will not see these errors. Put it back where it should be and if you get more errors that you don't understand, search with google, read actionscript docs or ask another question on the forum.

• With the family to Apple music subscription, must be the same Apple that use all the devices ID?

  I want to make a family membership at Apple ID, but do not want to use the same identifier Apple on registered devices.

  your question is a bit difficult...

  each device can use their own separate Apple ID but be part of the same family.

• Partition member in source and target must be the same

  Hello gurus, I have a cube with partitions and each partition is to have about 10 dimensions.

  A dimension, I became a member and wrote a rule for this member in the partition of the source, I have to take the same Member in the score target to write the rule.

  No, you don't have to have the same set of members on both sides.

  If you have...

  A, B, C, D

  .. .in the source, and...

  A, B, C

  .. .in the target, you have two options.

  First option, live with the warnings of validation "incompatibility of cell count" and do nothing to do.  Then no data will appear in the target for had 'and had data' will be not only be pushed in any of the partition.

  Second option, card would be "one of the 'A', 'B' and 'C'."

• ORA-01790 expression must have the same type of data, matching expression

  SELECT *  from award_test
          UNPIVOT(VAL for operator in(                                                                                                                                                                                                        
  AWARD_NAME,                                                                                                                                                                                                               
  TOTAL_PROCEEDS,                                                                                                                                                                                                              
  EARNING_PROCS ,                                                                                                                                                                                                               
  TOT_PROCS_EARNINGS ,                                                                                                                                                                                                            
  GROSS_PROCS    ,                                                                                                                                                                                                                
  PROC_REF_DEF_ESCR ,                                                                                                                                                                                                         
  OTH_UNSP_PROCS ,                                                                                                                                                                                                               
  ISSUANCE_COST ,                                                                                                                                                                                                             
  WORK_CAP_EXP ))
          PIVOT(max(VAL) for award_number in  ('XIAAE' as "XIAAE",'XIBNG' as "'XIBNG"))

  Expected results

  operator   XIAAE     XIBNG     
  AWARD_NAME ab          cd                                                                                                                                                                                    
  TOTAL_PROCEEDS   0     1                                                                                                                                                                                              
  EARNING_PROCS                                                                                                                                                                                                            
  TOT_PROCS_EARNINGS                                                                                                                                                                                                          
  GROSS_PROCS                                                                                                                                                                                                                  
  PROC_REF_DEF_ESCR                                                                                                                                                                                                         
  OTH_UNSP_PROCS                                                                                                                                                                                                               
  ISSUANCE_COST                                                                                                                                                                                                            
  WORK_CAP_EXP

  the data stored will be populated as columns

  Hello

  Is this the same probllem like
  Re: ORA-56901: no constant expression is not allowed to pivot. UNPIVOT values
  ?

  You do not post again and again the same problem. One of these threads mark as "Answered" right away; and only continue in the other. In this way, you will have only to look in one place to find answers.
  I suggest marking it as 'Response', given that the other has a few examples of data.

• 2 cluster nodes does not work on the same esx host

  Hello

  I would like to know how it is possible for 2 VM (a cluster of application) cannot run on the same esx (for example: only 2 esx in a cluster and an esx crash!)

  Thank you

  Concerning

  You must configure the properties of the DRS cluster to add a new regulation anti-affinite.

  See cluster / properties / DRS

  André

• Best way to build the same ESX hosts

  Hi, I need to build 4-6 ESX hosts are configured identically. (Same groups of ports, NTP settings etc..) All hosts will use the same brand/model/hardware configuration)

  I think kickstart server and a load of scripts PowerCLI would be the best way to do this, but I don't him did not before.

  Can you recommend the best way to do that, or no matter what links?

  Thanks in advance

  PS. The customer only paid for the license of the company,(not enterprise Plus), so I can't use Host Profiles)

  Are kickstarts way to go.  However, if you have business + licenses you can use the profiles of the host.

  Here's what I've used to help build my kickstarts

  http://blog.laspina.ca/ubiquitous/automating-vSphere-ESX4-host-installations

  http://www.VMware.com/PDF/vSphere4/r40_u1/vsp_40_u1_esx_vc_installation_guide.PDF

  ... also, everything I do not use this, it is very well implemented

  http://www.jasemccarty.com/blog/?p=571

  .. .and finally

  http://www.ivobeerens.nl/?p=509

• ORA-01790 Expression must have the same data type

  select  'sal' as A, sal as B, sal as C, sal as D
  from
  (Select sum(sal) sal from emp)
  union all
  select
    'comm', comm, comm, comm
  from
  (Select sum(comm) comm from emp)
  union all
  select rpad('-',10,'-') ,rpad('-',10,'-'),rpad('-',10,'-'),rpad('-',10,'-') from emp;

  Get the following error when you run the above query. I know it's because of the rpad('-',10,'-') what is the best way to achieve the expected results
  
  I would like to have the result with underscore. What is the best way to achieve this.
  
  Expected results:
  I am developing report.
  I need to have the following oupput.
  How can I put underscore after the recordings.

   A              B        C             D        
  sal         29025       29025     29025
  comm     2200    2200     2200
  --------------------------------------------------

  SQL> select  'sal' as A, sal as B, sal as C, sal as D
    2  from
    3  (Select sum(sal) sal from emp)
    4  union all
    5  select
    6    'comm', comm, comm, comm
    7  from
    8  (Select sum(comm) comm from emp)
    9  union all
   10  select rpad('-',10,'-') ,rpad('-',10,'-'),rpad('-',10,'-'),rpad('-',10,'-') from emp;
    'comm', comm, comm, comm
            *
  ERROR at line 6:
  ORA-01790: expression must have same datatype as corresponding expression
  
  SQL> select  'sal' as A, to_char(sal) as B, to_char(sal) as C, to_char(sal) as D
    2  from
    3  (Select sum(sal) sal from emp)
    4  union all
    5  select
    6    'comm', to_char(comm), to_char(comm), to_char(comm)
    7  from
    8  (Select sum(comm) comm from emp)
    9  union all
   10  select rpad('-',10,'-') ,rpad('-',10,'-'),rpad('-',10,'-'),rpad('-',10,'-') from emp;
  
  A          B                                        C                                        D
  ---------- ---------------------------------------- ---------------------------------------- ------------------
  sal        29025                                    29025                                    29025
  comm       2200                                     2200                                     2200
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  
  A          B                                        C                                        D
  ---------- ---------------------------------------- ---------------------------------------- ------------------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  ---------- ----------                               ----------                               ----------
  
  16 rows selected.
  
  SQL> 
  

  SY.

• 2 queries must return the same result (but they are not...)

  Hello
  I have a query:
  

  select col1,extract(year from datum) yr, COUNT(*)
  from tableA@dblink where
  DATUM between '1-jan-1985' and '31-dec-2012'
  and col2 > 100 and col2 not in ('999999')
  and TRIM(TO_CHAR(col1)) in ('0','1')
  group by col1,extract(year from DATUM);

  the query above returns the number: 143 982 for the year 1991
  However, when I put the filter directly in this year the request returns a different number: 143 917
  

  select col1,extract(year from datum) yr, COUNT(*)
  from tableA@dblink  where
  DATUM between '1-jan-1991' and '31-dec-1991'
  and col2 > 100 and col2 not in ('999999')
  and TRIM(TO_CHAR(col1)) in ('0','1')
  group by col1,extract(year from DATUM);

  Please can you help me understand why what is happening and why these 2 heads are different?
  ID appreciate any advice
  Thank you very much
  Rgds

  Try these...

  select col1,extract(year from datum) yr, COUNT(*)
  from tableA@dblink where
  trunc(DATUM) between to_date('1-jan-1985','dd-mon-yyyy') and to_date('31-dec-2012','dd-mon-yyyy')
  and col2 > 100 and col2 not in ('999999')
  and TRIM(TO_CHAR(col1)) in ('0','1')
  group by col1,extract(year from DATUM);
  

  select col1,extract(year from datum) yr, COUNT(*)
  from tableA@dblink  where
  trunc(DATUM) between to_date('1-jan-1991','dd-mon-yyyy') and to_date('31-dec-1991','dd-mon-yyyy')
  and col2 > 100 and col2 not in ('999999')
  and TRIM(TO_CHAR(col1)) in ('0','1')
  group by col1,extract(year from DATUM);