Help: How do I calculate the duration between 2 dates, when these dates on 2 rows?

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  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

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  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
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• Calculate business hours between 2 dates with negative numbers

  Hi all

  I use a function to calculate the difference between 2 dates schedules. The function was taken and adapted from this thread:

  Calculate business hours between two dates in a cursor

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,
                                   p_end_date DATE
                                  )
    RETURN NUMBER
    IS
        v_return NUMBER;
    BEGIN
        with t as (
                   select  case level
                             when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                             else trunc(p_start_date) + level - 15 / 24
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(p_end_date,trunc(p_end_date) + 20 / 24)
                             else trunc(p_start_date) + level - 4 / 24
                           end end_dt
                     from  dual
                     connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                  )
        select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
        RETURN v_return;
    END;
    /

  I am running into an issue that when the p_end_date is before the p_start_date value the function returns the full time between the dates without regard for business hours. if the end_date is before the start date I get the expected result i.e. difference between the dates in business hours.

  Using example dates of start 19th October 2012 13:00:00 and end 22nd october 2012 13:21:00 the business minutes are 681. However if i reverse the dates I get -4341.

  


  Correct labour code is the following, I've annotated so that he could help someone else looking for a solution like this:

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,  --these are the 2 dates passed into the function
                                   p_end_date DATE     --these are the 2 dates passed into the function
)
RETURN NUMBER
IS
v_return NUMBER;

          l_start  DATE;

          l_end    DATE;

          l_factor NUMBER;
    BEGIN

          IF p_start_date <= p_end_date THEN            --this IF section checks which of the 2 dates is the greatest


             l_start  := p_start_date;                  -- and then assigns the earliest date to p_start_date


             l_end    := p_end_date;

             l_factor := 1;

          ELSE   -- swap the dates around, and multiply the result by -1

             l_start  := p_end_date;

             l_end    := p_start_date;

             l_factor := -1;

          END IF;


          with t as (
                   select  case level
                             when 1 then greatest(l_start,trunc(l_start) + 9 / 24)  -- this sets the start of working hours
                             else trunc(l_start) + level - 15 / 24  --if the start time is adjusted this value must also be adjusted
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(l_end,trunc(l_end) + 20 / 24)  -- this sets the end of working hours
                             else trunc(l_start) + level - 4 / 24  -- if the end time is adjusted this value must also be adjusted
                           end end_dt
                     from  dual
                     connect by level <= trunc(l_end) - trunc(l_start) + 1
                  )
        select  sum(end_dt - start_dt) * 24 * 60 work_minutes  -- this subtracts the 2 dates and then multiplies by hours and minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- this exclude weekends
        RETURN v_return * l_factor;  -- this gives the negative or positive results so you can see if it was completed before or after the required date.
    END;
    /

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

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  I have two fields that stores just the hour in 24-hour ex: 08:00 and 20:00 now I want to calculate the difference between two times
  
  Kindle help me
  
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  Hello

  diiference in hours

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