Help in the data in the column of row data conversion

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  I tried to download a pdf and convert them into excel, but the data in excellent is always to the image format.  How can I get the pdf data into the columns and rows so that I can do the calculations?

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• passing parameters between different areas to help Navigate the column

  Hi all
  
  I know I can pass parameters between the reports through a few subjects by using Url go. However, I want to keep the functionality of the menu displayed when you use defyining multi target in the s column Navigate with drop-down feature. So the problem I encountered is the sequel
  
  (1) when I set some goals to navigate - is it possible to transfer parameters to these links point to destinations? (I tried to add them at the end of the link in the field "Target", but without success)
  
  (2) or alternatively - when you use GoUrl, can I define a < would display a href link that might point to places menu and mulitple drop down?
  
  I really appreciate your help with above
  Best regards
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  Published by: user1291979 on October 7, 2009 11:51

  -without add nothing more to this link, selected GEOGRAPHY. COUNTRIES must be passed to destination and > must complete guest there? It works that way in my environment

  If you are using navigation on the current query column properties and component the dashboard then the query current source column is analyzed on the quick dash in both have SAME_TABLE. The names of SAME_COLUMN, else parameter is not parsed.

  Target: / shared/Adecco01/_portal/01 edge/weekly table dashboard
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  He must complete only the GEOGRAPHY. COUNTRIES in the reports within the area where the source report comes from?

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  If you use GO URL, URL of the dashboard EDGE or the other, I already explained.

  Concerning
  Goran
  http://108obiee.blogspot.com

• SQL help - Need help to rotate the columns to rows

  I have a HughesNet to divide the columns into multiple lines. For example:
  
  EMP_DEPT
  
  ROWID empid1 ename1 empid2 ename2 empid2 ename2 empid4 ename4 dept4 dep3 dep2 dept1
  100001 1 'SCOTT' 10 2 'DAVE' 20 3 10 4 20 SMITH "MILLER"
  100002 1 'SCOTT' 10 2 'DAVE' 20 3 'MILLER' 20
  
  Note: EMP_DEPT do not always have information about the 4 employees settled for example in info only 3 employees rank 2 are there
  
  I need to convert and insert it into the EMPLOYEE table as follows:
  
  EMPLOYEE
  
  EmpID ename dept
  1 SCOTT 10
  2 20 DAVE
  3 MILLER 10
  4 SMITH 20
  
  1 SCOTT 10
  2 20 DAVE
  3 MILLER 20
  
  Thank you
  KeV

  Hey Kevin,

  Here's one way:

  WITH t AS (
    SELECT level i FROM dual CONNECT BY level <= 4
  )
  SELECT enty_type, enty_name, enty_id
  FROM (
    SELECT case when mod(t.i,2) = 0 then 'DEPARTMENT'
                else 'EMPLOYEE'
           end as enty_type
         , case t.i
             when 1 then emp_name1
             when 2 then dept_name1
             when 3 then emp_name2
             when 4 then dept_name2
           end as enty_name
         , case t.i
             when 1 then emp_id1
             when 2 then dept_id1
             when 3 then emp_id2
             when 4 then dept_id2
           end as enty_id
    FROM emp
         CROSS JOIN t
  )
  WHERE enty_id IS NOT NULL
  ;
  

  Another using the MODEL clause:

  SELECT *
  FROM (
    SELECT enty_id, enty_name, enty_type
    FROM emp
    MODEL
    RETURN UPDATED ROWS
    PARTITION BY (pk)
    DIMENSION BY (0 i)
    MEASURES(
       emp_id1, emp_name1
     , emp_id2, emp_name2
     , dept_id1, dept_name1
     , dept_id2, dept_name2
     , cast(null as number(10)) enty_id
     , cast(null as varchar2(200)) enty_name
     , cast(null as varchar2(30)) enty_type
    )
    RULES (
       enty_type[1] = 'EMPLOYEE' , enty_id[1] = emp_id1[0], enty_name[1] = emp_name1[0]
     , enty_type[2] = 'EMPLOYEE' , enty_id[2] = emp_id2[0], enty_name[2] = emp_name2[0]
     , enty_type[3] = 'DEPARTMENT' , enty_id[3] = dept_id1[0], enty_name[3] = dept_name1[0]
     , enty_type[4] = 'DEPARTMENT' , enty_id[4] = dept_id2[0], enty_name[4] = dept_name2[0]
    )
  )
  WHERE enty_id IS NOT NULL
  ;
  

  Published by: odie_63 on 8 Dec. 2010 21:00

• Get the name of the column of row

  All,
  
  In my Jdev 11.1.2 app I want to know the name of the attribute column that is modified. I am able to get the attribute name that currently use the getAttrbute() on the line (if you open the VO we see name |) Type of | Column, etc.). How can I get the name of the column?
  
  For example: the name of the attribute is Nom_tiers, column name can be Party_Name. I am able to do Nom_tiers but not Party_Name.
  
  thnks
  
  Published by: in the line of fire on 14 December 2011 14:13

  getEntityAttrForAttribute("attribute_name_here").getColumnName)

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  The problem I have is that, if a row is deleted in the middle of the table, the lines don't re-COMP.

  For example, if the table contains rows numbered 1, 2, 3 & 4, and line 2 is deleted, I want

  the lines to be re-numbered 1, 2, & 3. Instead, what I get is lines 1, 3 and 4.

  The script I use to number the lines is:

  this.rawValue=this.parent.index+1

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  number of lines if a line is removed.

  For some reason, it does not work for me.

  All of the suggestions.

  Thank you!

  I created a sample for you... Take a look and let me know what you want.

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• display the columns as rows in the table of non-unique key

  Hi OTN/users, I hope you can help me
  
  Given a table:
  
  create table t (varchar2 (30), int b, int, date c);
  
  with these data in:
  
  insert into values t (a1, 40, to_date (December 1, 2012 '));
  insert into values t (a1, 50, to_date (December 1, 2012 '));
  insert into values t (a1, 60, to_date (December 1, 2012 '));
  insert into values t (b1, 10, to_date (December 1, 2012 '));
  insert into values t (b1, 20, to_date (December 1, 2012 '));
  insert into values t (b1, 30, to_date (December 1, 2012 '));
  insert into values t (c1, 60, to_date (December 1, 2012 '));
  insert into values t (c1, 70, to_date (December 1, 2012 '));
  insert into values t (c1, 80, to_date (December 1, 2012 '));
  
  -I want the output columns for each of the 'a' as a single line ex:
  
  A1 40 50 60 1 December 2012
  B1 10 20 30 December 1, 2012
  ...
  
  I was almost right, but "a" neck repeats 4 times for each line of output:
  
  A1 40
  50 A1
  A1 60
  A1 1 December 2012
  
  -I want to exit repeat delete the first column "a" but see the rest in a straight line.
  
  I tried various things (Pivot, Rollup, etc.), but the fact that I'm in overlay on a table with no unique lines complicated things maybe.
  Any help would be appreciated

  Hi Kim,

  Kim Berg Hansen wrote:
  Even [url http://asktom.oracle.com/pls/apex/f?p=100:11:0:P11_QUESTION_ID:5658416800346527104] Tom agrees with Nicosa ;-)

  Very honored that Tom has decided to use my solution. ;-) ;-) ;-)
  But I guess that means that the OP may not like here to mark the thread as an answer.

• How to convert the column of ROW using DBMS_REDIFINITION object type column

  Hi all
  Suppose I have the following table to convert:

  create table customer as select customer_id cid, cust_first_name name, cust_address street from customers;
  alter table customer modify cid primary key;

  I created the table based on the customers of the OE schema table, while the street column has cust_address_typ with the following attribute object type

  SQL> describe cust_address_typ
   Name                                     Null?     Type
   ----------------------------------------------------- -------- ------------------------------------
   STREET_ADDRESS                               VARCHAR2(40)
   POSTAL_CODE                                   VARCHAR2(10)
   CITY                                        VARCHAR2(30)
   STATE_PROVINCE                               VARCHAR2(10)
   COUNTRY_ID                                   CHAR(2)

  I want to convert the object attribute adresse_rue in a column of RDM. Consider the following temporary table:

  CREATE TABLE INT_CUSTOMER(
  CID NUMBER,
  NAME VARCHAR2(30),
  street varchar2(100)
  );

  First of all, I checked if the table can be redefined:

  --Verify if the table can be redefined
  BEGIN
  DBMS_REDEFINITION.CAN_REDEF_TABLE('OE','CUSTOMER',DBMS_REDEFINITION.CONS_USE_PK);
  END;
   4  /
  
  PL/SQL procedure successfully completed.

  But when I started the redefinition, I got an error:

  BEGIN
  DBMS_REDEFINITION.START_REDEF_TABLE(
  uname => 'OE',
  orig_table => 'CUSTOMER',
  int_table => 'INT_CUSTOMER',
  col_mapping => 'CID CID, NAME NAME, STREET CUST_ADDRESS_TYP(STREET_ADDRESS)'
  );
  END;
    9  /
  BEGIN
  *
  ERROR at line 1:
  ORA-00923: FROM keyword not found where expected
  ORA-06512: at "SYS.DBMS_REDEFINITION", line 52
  ORA-06512: at "SYS.DBMS_REDEFINITION", line 1646
  ORA-06512: at line 2

  What seemed to be the problem?
  
  Best regards
  Val
  
  Published by: Valerie good-natured October 9, 2011 21:43

  Have you tried this one:

  BEGIN
  DBMS_REDEFINITION.START_REDEF_TABLE(
  uname => 'OE',
  orig_table => 'CUSTOMER',
  int_table => 'INT_CUSTOMER',
  col_mapping => 'CID CID, NAME NAME,"CUSTOMER".STREET.STREET_ADDRESS STREET'
  );
  END;
  

  Looking at your trace file, I claim that when you use the call above to START_REDEF_TABLE, the inner workings of this procedure will create this SQL statement:

  select CID CID, NAME NAME,"CUSTOMER".STREET.STREET_ADDRESS STREET from "OE"."CUSTOMER" "CUSTOMER"
  

  (You can prove or disprove my claim by tracing it ;-)))

  And this statement has had an alias - even if the alias is the same as the name of the table...

• How to save the table column and row headings

  I have a table where I activated the column and row headings.  Once the table is loaded with data, I would like to save the contents of the table, including the column and row headings in a text file.  The crux of "value" property returns only the content of the table, not the row and column headers.  I could use "header line chains []" and '[] column header chains' property nodes as well, but I'm in the island there is an easier way.  Looks like adding the headers of lines would be difficult.  Any ideas?

  Thanks in advance.

  Here is a way. The construction with the empty constant is to provide to the left corner of the table where there is no data.

  

• Please help on the design of the table

  I have the below 3 fields of my application
  
  Category: daily or weekly (single value)
  Day: Sunday to Saturday (more than one value can be selected)
  Calendar: only once
  
  I need to store the selected value in a row. What is the best way to design the table with columns to achieve (as separated by commas for the day of the column or something else).
  Can you please guide. That I'll use as a scheduler to perform the procedures
  
  Thank you.

  Vanessa wrote:
  I have the below 3 fields of my application

  Category: daily or weekly (single value)
  Day: Sunday to Saturday (more than one value can be selected)
  Calendar: only once

  I need to store the selected value in a row. What is the best way to design the table with columns to achieve (as separated by commas for the day of the column or something else).
  Can you please guide. That I'll use as a scheduler to perform the procedures

  Thank you.

  IMO, the best way is to have 2 columns in your table:
  1 category
  2. date (this includes Date, use that can come from day and will also store component "hour").

  This will ensure you have no redundant columns in your table and it conforms to the 3rd form standardization.

  If you need to store several days, then just insert another record for the same category with different day i.e. Date with information at the same time.

  Storage of data in a single column will facilitate queries that need to be learned on a particular day. Having several columns (one for each day) you need to include those much where predicates. If you are fine with it, then it wouldn't be such a bad option.

  For example: you have the structure below:

  create table test_table
  (
    category_name     varchar2(10),
    time_info         varchar2(8),          --In 24 Hours format, a bad way to store data
    sunday            char(1),
    monday            char(1),
    tuesday            char(1),
    wednesday            char(1),
    thursday            char(1),
    friday            char(1),
    saturday            char(1)
  );
  
  insert into test_table (category_name, time_info, sunday) values ('ABC', '13:00:00', 'Y');
  insert into test_table (category_name, time_info, monday) values ('ABC', '13:00:00', 'Y');
  insert into test_table (category_name, time_info, thursday) values ('ABC', '13:00:00', 'Y');
  
  /*
    Query to pick details of category which is available on Thursday
  */
  select *
    from test_table
   where thursday = 'Y'       --> This restricts to adapt the same query for multiple days. i.e. for each day you will have to write a seperate query
     and category_name = 'ABC';
  
  CATEGORY_NAME TIME_INFO SUNDAY MONDAY TUESDAY WEDNESDAY THURSDAY FRIDAY SATURDAY
  ------------- --------- ------ ------ ------- --------- -------- ------ --------
  ABC           13:00:00                                  Y
  
  --You may alternatively use Un-Pivot Operations to convert the Columns to Rows in a View and access the view.
  
  drop table test_table;
  
  create table test_table
  (
    category_name     varchar2(10),
    date_info         date
  );
  
  insert into test_table (category_name, date_info) values ('ABC', to_date('03-Apr-2013 13:00:00', 'DD-Mon-YYYY HH24:MI:SS'));
  insert into test_table (category_name, date_info) values ('ABC', to_date('02-Apr-2013 13:00:00', 'DD-Mon-YYYY HH24:MI:SS'));
  
  create or replace view vw_test_table as
  select category_name, trim(to_char(date_info, 'Day')) day, to_char(date_info, 'HH24:MI:SS') time_info
    from test_table;
  
  --This allows you to pass the Day information at run-time, thus increasing Code reuse.
  select *
    from vw_test_table
   where day = 'Tuesday'
     and category_name = 'ABC';
  
  CATEGORY_NAME DAY                                  TIME_INFO
  ------------- ------------------------------------ ---------
  ABC           Tuesday                              13:00:00
  

  Published by: Jen K on April 3, 2013 13:40
  Addition of demonstration.

• What is the empty string, the value null in the column, or...?

  I use Oracle 11.2, a table tb_class as follows:
  
  TB_CLASS (number (3) id, varchar2 (32) nm, seqNum number (3));
  
  1, 212
  2, "under", 12
  3, 'qq', 12
  
  Select * from TB_CLASS where id = 1 and n = null;... .no selected line
  Select nvl (nm) in the TB_CLASS where id = 1; ... 1 selected line
  
  Any know what's in the column of row id = 1 nm? I thought that it is an empty string, but why it returns no rows in the first query?
  
  Thank you!

  (1) in Oracle there is no difference between NULL and an empty string.

  (2) NULL is never equal to what whatsoever (including another NULL). NULL is never spotty what whatsoever (including another NULL). You must use the IS NULL and IS NOT NULL operators to search for NULL values

  SELECT *
    FROM tb_class
   WHERE nm IS NULL
  

  or

  SELECT *
    FROM tb_class
   WHERE nm IS NOT NULL
  

  Of course, it is also possible that you declare that the NM column contains one or more spaces or it contains one or more non-printable characters and not a NULL value. That's why we asked you what dump (nm) returns

  Justin

• SQL queries for reports help: need to reverse the data in the column in columns [O

  Hi all
  
  I'm looking for help in writing SQL, where I need to reverse the data in the columns column.
  
  My data in DB is as below.
  
  VALUE OF NAME OF MONTH
  Jan-10 M1 5
  Jan-10 M2 8
  Jan-10 M3 9
  Feb-10 M1 4
  Feb-10 M2 6
  Feb-10 M3 2
  M4 10 Feb 10
  M1 10 Mar 21
  Mar-10 M2 6
  
  Power required for the declaration will be like:
  
  
  MONTHS M1 M2 M3 M4
  Jan-10 5 8 9
  Feb-10 4 6 2 10
  21 Mar-10 6
  
  How can I do this using SQL. [ORACLE 10g]?
  
  I can make use of server Oracle BI also.
  
  Please help me on this...

  I think this is wrong forum to ask this question. You want to do it in OBIEE or at the DB level. In oBIEE you can do in a table privot view.

  Thnaks,
  Knani

• Dates are not appearing in the column start and Finsh of MS Project 2010. They become W31/4, W31/5, etc. Instead of 7/31/20113. How can I fix it?

  Dates are not appearing in the column start and Finsh of MS Project 2010. They appear rather like W31/4, W31/5, etc. When it should be like this: 7/31/20113. How can I fix it? Note: Dates listed do appear correctly.

  Hello Charlie,.

  You are welcome. It is what we are trying to do... help people! Thanks for letting me know that the problem is solved. Don't forget to mark it as your response so that we can spread the knowledge more far.

  Kind regards

  BearPup

• Display the name of the tag as the column name and the value in the tag as a row of data from the input string.

  Hi Forum members,

  I am looking for a query display the name of the tag as the column name and the value in the tag as a row of data.

  I have to print the values within the tag to a file by choosing the value of the flags. the sequence of the tags will vary each time, as the tag name will change dynamically.

  So here is the example of input data and the expected output. The string in the text column must be separated as the column names and values.

  Input data
  Select 1 as seqno,' < > 0210A 50 4f < / 4f > < 5f20 > TEST CARD 16 < / 5f20 > < 5f2a > < / 5f2a > < 82 > 1 c 00 < / 82 > ' double text

  
  Output:

  Seqno 4f 5f20 5f2a 82
  0210A 50 16 1 00 TEST CARD 1

  Please help me by providing your entries on this.

  We use the version of Oracle 11.2.

  Note: This is not the XML string

  Thank you

  Shree

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  )

  Select d.seqno, x.*

  d the data,

  XMLTable ('/ root')

  by the way xmltransform (xmltype ('': replace (replace (text,'<><>'),)))

  XmlType (q'~http://www.w3.org/1999/XSL/Transform "version ="1.0"> ")

                                                   

                                                     

                                                       

                                                     

                                                   

                                                   

                                                     

                                                       

                                                     

                                                   

  ~'

  )

  )

  path of columns '4f' varchar2 (10) "tag4f."

  path of "5f20' varchar2 (30)"tag5f20. "

  path of '5f2a' varchar2 (10) "tag5f2a."

  path of varchar2 (10) "82" "tag82.

  ) x

  
  

  SEQNO	4f	5f20	5f2a	82
  1	0210A 50	16 TEST CARD	-	1 00
  2	0210A 50	16 TEST CARD	-	1 00
  3	0210A 50	16 TEST CARD	-	1 00
  4	0210A 50	16 TEST CARD	-	1 00

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  ),

  Chopper (seqno, Key, value, String) as

  (select seqno,

  regexp_substr (text,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (Text,'>(.*?))

  regexp_substr (text,'<.+?>. *? ) (.*) $', 1, 1, null, 1). » <>'

  from the data

  Union of all the

  Select seqno,

  regexp_substr (String,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (String,'>(.*?))

  regexp_substr (String,'<.+?>. *? ) (.*) $', 1, 1, null, 1)

  Chopper

  where regexp_substr (string,'<(.*?)>', 1, 1, null, 1) is not null

  )

  Select '4f', seqno, '5f2a', '82', '5f20.

  of (seqno, lower (key) select key, value)

  Chopper

  )

  Pivot (max (value) for key in ('4f' as '4f', '5f20' as '5f20', '5f2a' as '5f2a', "82" as "82"))

  Concerning

  Etbin
  

• Disable the previous dating date picker in the column in a table

  can someone please help.

  on the date column in a table, need to disable previous dates.

  Current functionality. But when the validation page gets updated and the user is able to select earlier dates.

  
  

  
  

  To restrict the datePicker for new lines changed the URL of the button 'Add Row '.

  javascript:myAddRow();

  In the page edit, I added this to "Javascript > function and Variable global statement.

  function myAddRow()
  { apex.widget.tabular.addRow(); 
  $("td[headers='DETAIL_DATE'] input:last") 
  .datepicker("option","changeMonth",false) 
  .datepicker("option","minDate",$v("P2_MASTER_MONTH_MINDATE")) 
  
  .datepicker("option","maxDate",$v("P2_MASTER_MONTH_MAXDATE")); };
  
  https://Apex.Oracle.com
  w/u/p: nani5048/test/test
  App 92603 5 page
  Thank you
  Nani
  			 
  I created a dynamic action
  the loading of the page
  $("td [en-têtes = 'STATUS_DATE'] entrée")
  . DatePicker ("option", "minDate", $v ("P5_MASTER_MONTH_MINDATE"));
  as well as the global javascript function
  function myAddRow() {}
  apex.widget.tabular.addRow ();
  $("td [en-têtes = 'STATUS_DATE'] entrée")
  . DatePicker ("option", "minDate", $v ("P5_MASTER_MONTH_MINDATE"));
  }