Help please! Artist faced w / Flash Question!
I bought a Flash video tutorial online for animation and the FIRST step is to create a circle with the circle tool and the guy does online, and he is looking. I repeat its actions exactly and I get about the same result. I just get a circle. I work in CS3, I don't know what is the instructor. But someone, please help! I just want to learn, but I can't get past the first step!
Kara
When you select the circle drawing tool, look in the properties panel, and do not forget to specify the fill and the colors of the race. And perhaps, in order to ensure, select a fill color that is not the same as the background color.
If you still see only a draft, then there is a chance that you have the outline mode turned on, or to the layer of the file. If this is the layer, then you'll see that is indicated by the rectangle next to the layer not having domain name does not a fill - click on the rectangle to cancel it. If it's the file, then you will see outlines selected if you choose View-> Preview Mode... Choose another mode of preview, if this is the case.
Tags: Adobe Animate
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Use: Oracle 11.2.0.1 on Windows XP
create table tab40 (bno varchar2 (1), pno varchar2 (7), the number (3) weight, lineno number (3));
insert into tab40 values ('1', '1115027', 36, 1);
insert into tab40 values ('2', the '1115100', 25, 2);
insert into tab40 values ('3', the '1115200', 50, 3);
insert into tab40 values ('1', the '1112510', 60, 4);
insert into tab40 values ('+', '1112610', 6, 5)
insert into tab40 values ('+', '1112710', 4, 6);
insert into tab40 values ('+', '1110710', 1, 7)
insert into tab40 values ('2', '1117014', 79, 8);
insert into tab40 values ('+', '1117000', 9, 9)
insert into tab40 values ('+', '1117001', 2, 10);
insert into tab40 values ('1', '1317001', 200, 11);
insert into tab40 values ('1', '1697001', 20, 12);
insert into tab40 values ('2', '2997001', 40, 13);
insert into tab40 values ('1', '2996001', 44, 14);
create table tab41 (bno varchar2 (1), pno varchar2 (7), the number (3) weight, lineno number (3));SQL> select * from tab40; B PNO WEIGHT LINENO - ------- ---------- ---------- 1 1115027 36 1 2 1115100 25 2 3 1115200 50 3 1 1112510 60 4 + 1112610 6 5 + 1112710 4 6 + 1110710 1 7 2 1117014 79 8 + 1117000 9 9 + 1117001 2 10 1 1317001 200 11 B PNO WEIGHT LINENO - ------- ---------- ---------- 1 1697001 20 12 2 2997001 40 13 1 2996001 44 14 14 rows selected. SQL>
insert into tab41 values ('1', '1115027', 36, 1);
insert into tab41 values ('2', the '1115100', 25, 2);
insert into tab41 values ('3', the '1115200', 50, 3);
insert into tab41 values ('1', the '1112510', 60, 4);
insert into tab41 values ('+', '1112610', 6, 5)
insert into tab41 values ('+', '1110710', 1, 6);
insert into tab41 values ('2', '1117014', 79, 7);
insert into tab41 values ('+', '1117000', 9, 8)
insert into tab41 values ('1', '1317001', 200, 9);
insert into tab41 values ('1', the '1697001', 20, 10);
insert into tab41 values ('2', '2997001', 40, 11);
insert into tab41 values ('1', '2996001', 44, 12);
insert into tab41 values ('+', '1112710', 4, 13);
insert into tab41 values ('+', '3332710', 8, 14)
Power required:SQL> select * from tab41; B PNO WEIGHT LINENO - ------- ---------- ---------- 1 1115027 36 1 2 1115100 25 2 3 1115200 50 3 1 1112510 60 4 + 1112610 6 5 + 1110710 1 6 2 1117014 79 7 + 1117000 9 8 1 1317001 200 9 1 1697001 20 10 2 2997001 40 11 B PNO WEIGHT LINENO - ------- ---------- ---------- 1 2996001 44 12 + 1112710 4 13 + 3332710 8 14 14 rows selected. SQL>
Logic: The plus sign in Bno says that no. Packet was sent to the customer with the last packet (order by lineno) either signed number that is for example in tab40 there is line no. 6 whose main package number is 1112510 (from either signed lines previous PNO). So come to the power required; which shows that these signed (whose master PNO is that) packages are not according to the tab40 vs tab41 something as complete an outer join between tab40 and tab41. Example:A B C D E F G H 1 1112510 60 4 1 2996001 44 12 + 1112710 4 6 + 1112710 4 13 2 1117014 79 8 + 1117001 2 10 1 2996001 44 12 + 3332710 8 14
+ 1112710 is associated with 1112510 in tab40, in tab41, it is associated with 2996001; So that's the difference.
+ 1117001 is associated with 1117014 in tab40, while it is not in tab41.
Vice versa;
+ 3332710 is associated with 2996001 in tab41, while it is not in tab40.
I mean, if only more marked parcel number of PNO line mater is not equal to master PNO (previous no more BNO) in both the table, it should be part of the select query please. Usually this happens when our packing service gets a late delivery of prior master package, so that they send just the small package with immediately available (either) a package.
Kindly let me know; I am clear in my request, or I should elaborate more. This can be more complex, because may be bad/data from the design table, but I need the output of the select query please help me.
Full Outer Join help please
Wrongly, I posted the question here, I should post here. Keep will be remembered in the future.
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Published by: user12050217 on January 3, 2012 08:38Hello
user12050217 wrote:
HelloUse: Oracle 11.2.0.1 on Windows XP
create table tab40 (bno varchar2 (1), pno varchar2 (7), the number (3) weight, lineno number (3));
insert into tab40 values ('1', '1115027', 36, 1); ...Thanks for posting the version and CREATE TABLE and INSERT statements. It is very useful.
Power required:
A B C D E F G H 1 1112510 60 4 1 2996001 44 12 + 1112710 4 6 + 1112710 4 13 2 1117014 79 8 + 1117001 2 10 1 2996001 44 12 + 3332710 8 14Those are the best names of columns for this work? Even if your users really insist on having the names, do not forget that people who want to help are also familiar with your application, so it would be useful that you used for the column names more descriptive as bno_40 (meaning tab40 bno), pno_40,..., lineno_41 during the validation of the problem. You can change the column alias back to a, b,..., h after the problem is resolved, if necessary.
Logic: The plus sign in Bno says that no. Packet was sent to the customer with the last packet (order by lineno) either signed number that is for example in tab40 there is line no. 6 whose main package number is 1112510 (from either signed lines previous PNO). So come to the power required; which shows that these signed (whose master PNO is that) packages are not according to the tab40 vs tab41 something as complete an outer join between tab40 and tab41. Example:
+ 1112710 is associated with 1112510 in tab40, in tab41, it is associated with 2996001; So that's the difference.
+ 1117001 is associated with 1117014 in tab40, while it is not in tab41.
Vice versa;
+ 3332710 is associated with 2996001 in tab41, while it is not in tab40.I mean, if only more marked parcel number of PNO line mater is not equal to master PNO (previous no more BNO) in both the table, it should be part of the select query please. Usually this happens when our packing service gets a late delivery of prior master package, so that they send just the small package with immediately available (either) a package.
Kindly let me know; I am clear in my request, or I should elaborate more. This can be more complex, because may be bad/data from the design table, but I need the output of the select query please help me.
Yes, it seems unnecessarily complicated, so you should be especially clear in your description.
It is always useful to describe what each line of output. In this issue, it seems that different production lines represent different things:
(1) some lines represent an incompatibility between -marked lines in tab40 and tab41 (i.e. the lines or table where bno ='' and when the ofn even in the table has a different master_pno, or it the pno even does not exist in the other table). We will call these lines 'follower '.
(2) the other lines represent lines masters of the lines do not match (1)To get the master for each line + marked row in a table, use the analytical LAST_VALUE function. That's what the two first of subqueries, got_master_pno_40 and got_master_pno_41 below.
To get the lines are not (the disciples, or the output type (1)), do an outer join complete, as you said. It's that the subquery follows, mismatched_followers.
To get the final result, a Union of the followers with their respective masters. It's that the main request below.WITH got_master_pno_40 AS ( SELECT bno, pno, weight, lineno , LAST_VALUE ( CASE WHEN bno != '+' THEN pno END IGNORE NULLS ) OVER ( ORDER BY lineno) AS master_pno FROM tab40 ) , got_master_pno_41 AS ( SELECT bno, pno, weight, lineno , LAST_VALUE ( CASE WHEN bno != '+' THEN pno END IGNORE NULLS ) OVER (ORDER BY lineno) AS master_pno FROM tab41 ) , mismatched_followers AS ( SELECT NVL (m40.pno, m41.pno) AS pno , m40.bno AS bno_40 , m40.pno AS pno_40 , m40.weight AS weight_40 , m40.lineno AS lineno_40 , m40.master_pno AS master_pno_40 , m41.bno AS bno_41 , m41.pno AS pno_41 , m41.weight AS weight_41 , m41.lineno AS lineno_41 , m41.master_pno AS master_pno_41 FROM got_master_pno_40 m40 FULL OUTER JOIN got_master_pno_41 m41 ON m40.pno = m41.pno WHERE NVL (m40.master_pno, '?') != NVL (m41.master_pno, '?') AND '+' IN (m40.bno, m41.bno) ) SELECT bno_40, pno_40, weight_40, lineno_40 , bno_41, pno_41, weight_41, lineno_41 , pno , 'F' AS master_or_follower FROM mismatched_followers -- UNION ALL -- SELECT t40.bno, t40.pno, t40.weight, t40.lineno , t41.bno, t41.pno, t41.weight, t41.lineno , f.pno , 'M' AS master_or_follower FROM mismatched_followers f LEFT OUTER JOIN tab40 t40 ON f.master_pno_40 = t40.pno LEFT OUTER JOIN tab41 t41 ON f.master_pno_41 = t41.pno -- ORDER BY pno , master_or_follower DESC ;This assumes that ofn is unique to each table and that ofn! = ' ?'.
Output:
B PNO_40 WEIGHT_40 LINENO_40 B PNO_41 WEIGHT_41 LINENO_41 PNO M - ------- ---------- ---------- - ------- ---------- ---------- ------- - 1 1112510 60 4 1 2996001 44 12 1112710 M + 1112710 4 6 + 1112710 4 13 1112710 F 2 1117014 79 8 1117001 M + 1117001 2 10 1117001 F 1 2996001 44 12 3332710 M + 3332710 8 14 3332710 FYou did not ask the last two columns, but you need to sort. If you don't want to see them, then you can make the UNION in a subquery, then, in the main query, use "ORDER BY pno, master_or_follower", as above, but do not include the columns in the SELECT clause. Your front end may have an easier way to hide these columns, so that they are still as a result set (and therefore, can be used in the ORDER byclause of a UNION) but are not displayed. In SQL * Plus, for example:
COLUMN pno NOPRINT COLUMN master_or_follower NOPRINT -
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View the tick code goes here
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