Help please SQL
Hi allPlease help me with this query:
I have data from a table like:
ID | emp_id | salary
1. 100. 200
2. 200 | 400
3. 300. 450
and I need to write a Sql to get the following result:
ID | emp_id | salary | C_Salary
1. 100. 200 | 200
2. 200 | 400. 600
3. 300. 450. 1050
Examples of data include:
with t as
(select 1 i_d, empi_d 100, 200 double sal)
UNION ALL
Select i_d 2, empi_d 200, 400 sal double
UNION ALL
Select 3 i_d, empi_d 300, 450 double sal)
Select * from t
Concerning
Rahul
Hello
Try like this
with t as
(select 1 i_d, empi_d 100, 200 double sal)
UNION ALL
Select i_d 2, empi_d 200, 400 sal double
UNION ALL
Select 3 i_d, empi_d 300, 450 double sal)
Select t.*, sum (sal) over (order by I_D) t C_Sal
Thank you & best regards
Srikkanth.M
Tags: Database
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I want to write a query that will have the departments table department_id and print the corresponding employee_id, last_name, manager_id in this Department into the employees table and print a message--no employee no existence for this Department in the employees table, whose employees do not exist in the employees table... I get this message in all the outputs. Help, please...
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200, Whalen, 101
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/
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message below
AIX 5300-12-04-1119 + Oracle 11.2.0.2
# Journal of primary database alerts. #########
******************************************************************
LGWR: Definition of 'active' from archive to destination LOG_ARCHIVE_DEST_2
******************************************************************
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------------------------ ------------- ----------- ---------- --- ----------------------------- ------------------------------------------------------------
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Hello
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Previous thread (RE: help please - issue of calculation of execution time) mode lock, therefore open new thread.
Karthick_Arp thanks for your great help with the merge code.
I modified my code with Merge statement instead of loops and internal loops.
PFB code and output. But still I am negitive values over time of execution because end_time < start_time is coming. Please suggest me how to solve this problem.
1 CREATE OR REPLACE PROCEDURE my_proc
2 EAST
3 sql_string VARCHAR2 (4000);
4 v_start_time TIMESTAMP;
5 v_end_time TIMESTAMP;
6 v_rowcnt NUMBER;
7. START
8 FOR c1 IN (SELECT ROWNUM tab_no, tablename, TYPE
9 FROM stored_ddl_policies by tablename) / * mourning tablename order * /.
10 LOOP
11 sql_string: = q']
12 merge into #tablename # b
13 using (select empkey, id, dt
14de emp_base) on (a.empkey = b.empkey)
15when matched then update set b.id = a.id, b.dt = a.dt] ";
16 sql_string: = REPLACE (sql_string, "#tablename #", c1.tablename);
17 v_start_time: = SYSTIMESTAMP;
18
19 sql_string EXECUTE IMMEDIATE.
20
21 v_end_time: = SYSTIMESTAMP;
22 v_rowcnt: = SQL % ROWCOUNT;
23 DBMS_OUTPUT.put_line (c1.tablename); / * added for display * /.
24 DBMS_OUTPUT.put_line (v_start_time);
25 DBMS_OUTPUT.put_line (v_end_time);
26 INSERT INTO exec_time (TABLE_NAME, START_TIME, END_TIME, EXCUTION_TIME, NO_OF_RECORDS_PROCESSED)
27 VALUES (c1.tab_no |) ' ' || C1. TableName, v_start_time, v_end_time, v_end_time - v_start_time, v_rowcnt);
28 END LOOP;
29
30 COMMIT;
31EXCEPTION
32 THEN THAN OTHERS
33 THEN
34 DBMS_OUTPUT.put_line (SQLERRM);
35END;
16 m
OUTPUT:
select * from exec_time by start_time desc
TABLE_NAME START_TIME, END_TIME EXCUTION_TIME NO_OF_RECORDS_PROCESSED
6 TAB6 31/05/2013 3:07:00.282065 AM 31/05/2013 3:06:47.103731 AM - 00 33 00:00:13.178334
23 TAB23 31/05/2013 3:06:56.159271 AM 31/05/2013 3:06:56.342313 AM + 00 00:00:00.183042 1013
20 TAB20 31/05/2013 3:06:47.104115 AM 31/05/2013 AM + 00 00:00:09.054770 158169 3:06:56.158885
13 TAB13 31/05/2013 3:06:41.668578 AM 31/05/2013 3:06:31.690199 AM - 00 28 00:00:09.978379
7 TAB7 31/05/2013 3:06:41.624134 AM 31/05/2013 3:06:41.668468 AM + 00 00:00:00.044334 0
12 TAB12 31/05/2013 3:06:31.690582 AM 31/05/2013 3:07:00.281522 AM + 00 00:00:28.590940 240715
3 TAB 3 31/05/2013 3:06:24.669461 AM 31/05/2013 3:06:41.623421 AM + 00 00:00:16.953960 47426
2 TAB2 31/05/2013 3:06:24.182326 AM 31/05/2013 AM + 00 00:00:00.486723 5242 3:06:24.669049
8 RAB8 31/05/2013 3:06:21.416823 AM 31/05/2013 3:06:24.181956 AM + 00 00:00:02.765133 28636
1 TAB1 31/05/2013 3:06:16.320679 AM 31/05/2013 AM + 00 00:00:05.095731 132633 3:06:21.416410
16 TAB16 31/05/2013 3:06:07.446056 AM 31/05/2013 AM + 00 00:00:08.874227 421215 3:06:16.320283
11 TAB11 31/05/2013 3:06:07.442987 AM 31/05/2013 3:05:55.361263 AM - 00:00:12.081724-00 60273
19 TAB19 31/05/2013 3:06:03.683463 AM 31/05/2013 3:06:07.445630 AM + 00 00:00:03.762167 77549
15 TAB15 31/05/2013 3:06:00.291696 AM 31/05/2013 3:06:03.683017 AM + 00 00:00:03.391321 77117
10 TAB10 31/05/2013 3:05:57.787733 AM 31/05/2013 AM + 00 00:00:09.654601 517960 3:06:07.442334
18 TAB18 31/05/2013 3:05:56.742873 AM 31/05/2013 3:06:00.291274 AM + 00 00:00:03.548401 105630
24 TAB24 31/05/2013 3:05:55.361707 AM 31/05/2013 3:05:56.742506 AM + 00 00:00:01.380799 15115
4 TAB4 31/05/2013 3:05:18.873303 AM 31/05/2013 3:05:06.966972 AM - 00:00:11.906331-00 49078
21 TAB21 31/05/2013 3:05:13.609759 AM 31/05/2013 3:05:18.872878 AM + 00 00:00:05.263119 56525
22 TAB22 31/05/2013 3:05:09.070048 AM 31/05/2013 AM + 00 00:00:48.717139 451439 3:05:57.787187
5 TAB5 31/05/2013 3:05:06.967411 AM 31/05/2013 3:05:09.069642 AM + 00 00:00:02.102231 773
25 TAB25 31/05/2013 3:05:05.198282 AM 31/05/2013 AM + 00 00:00:08.410911 308670 3:05:13.609193
14 TAB14 31/05/2013 3:04:59.575951 AM 31/05/2013 3:05:05.197701 AM + 00 00:00:05.621750 12118
17 TAB17 31/05/2013 3:04:43.740910 AM 31/05/2013 3:04:59.575503 AM + 00 00:00:15.834593 529
9 TAB9 31/05/2013 3:04:38.286041 AM 31/05/2013 3:04:59.011404 AM + 00 00:00:20.725363 65921
Thanks in advance.
Published by: 1008545 on May 31, 2013 01:40
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The creation of sequence error. Help, please
I use following script to create the sequence but in error
Error report:
SQL error: ORA-01722: invalid number
01722 00000 - "invalid number."
CREATE SEQUENCES BL_BTN_MASTER_SEQ
MINVALUE 1
MAXVALUE 999999999999999999
INCREMENT BY 1
START WITH (SELECT MAX (BULLETIN_MASTER_ID) + 1
OF BL_BTN_MASTER)
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FYI... The bulletin_master_id column data type is NUMBER (22.0)
Help, please.
Published by: user11228834 on May 29, 2013 10:22
Published by: user11228834 on May 29, 2013 10:23
Published by: user11228834 on May 29, 2013 10:25Oracle doesn't like the ' (select max (bulletin_master_id) + 1 bl_btn_master)' statement incorporated in the CREATE SEQUENCE statement because if you look at the syntax it expects an acual number.» You can use run immediately to create the sequence in this way:
{code}
declare
number of v_seq;
v_statement varchar2 (200);
Start
SELECT max (bulletin_master_id) + 1
in v_seq
of bl_btn_master;v_statement: = 'CREATE the SEQUENCE BL_BTN_MASTER_SEQ |
"MINVALUE 1' |
"MAXVALUE 999999999999999999' |
' INCREMENT OF 1' |
'START WITH ' | v_seq |
"NOCACHE";execute immediate (v_statement);
end;
{code} -
How to add 02 decimal of a number using LPAD and REPLACE... Help, please
What I'm trying to do is to have a variable to five digits with two decimal places:
I want to format 33 to 033.00 or 33.5 to 033.50
My Code:
DECLARE
v_traffic_total NUMBER (5.2): = 0;
v_traffic_total1 NUMBER (5.2): = 0;
v_code_B_total VARCHAR2 (11);
v_code_B_total1 VARCHAR2 (11);
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B00033
B00335
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Help, please
HopeIn addition:
SQL> select 'B' || ltrim(replace(to_char(33.5,'0099.00'),'.','')) from dual; 'B'||LTRIM(REPLACE(TO_CHAR(33. -------------------------------------------------------------------------------- B003350 -
Hello
Use: Oracle 11.2.0.1 on Windows XP
create table tab40 (bno varchar2 (1), pno varchar2 (7), the number (3) weight, lineno number (3));
insert into tab40 values ('1', '1115027', 36, 1);
insert into tab40 values ('2', the '1115100', 25, 2);
insert into tab40 values ('3', the '1115200', 50, 3);
insert into tab40 values ('1', the '1112510', 60, 4);
insert into tab40 values ('+', '1112610', 6, 5)
insert into tab40 values ('+', '1112710', 4, 6);
insert into tab40 values ('+', '1110710', 1, 7)
insert into tab40 values ('2', '1117014', 79, 8);
insert into tab40 values ('+', '1117000', 9, 9)
insert into tab40 values ('+', '1117001', 2, 10);
insert into tab40 values ('1', '1317001', 200, 11);
insert into tab40 values ('1', '1697001', 20, 12);
insert into tab40 values ('2', '2997001', 40, 13);
insert into tab40 values ('1', '2996001', 44, 14);
create table tab41 (bno varchar2 (1), pno varchar2 (7), the number (3) weight, lineno number (3));SQL> select * from tab40; B PNO WEIGHT LINENO - ------- ---------- ---------- 1 1115027 36 1 2 1115100 25 2 3 1115200 50 3 1 1112510 60 4 + 1112610 6 5 + 1112710 4 6 + 1110710 1 7 2 1117014 79 8 + 1117000 9 9 + 1117001 2 10 1 1317001 200 11 B PNO WEIGHT LINENO - ------- ---------- ---------- 1 1697001 20 12 2 2997001 40 13 1 2996001 44 14 14 rows selected. SQL>
insert into tab41 values ('1', '1115027', 36, 1);
insert into tab41 values ('2', the '1115100', 25, 2);
insert into tab41 values ('3', the '1115200', 50, 3);
insert into tab41 values ('1', the '1112510', 60, 4);
insert into tab41 values ('+', '1112610', 6, 5)
insert into tab41 values ('+', '1110710', 1, 6);
insert into tab41 values ('2', '1117014', 79, 7);
insert into tab41 values ('+', '1117000', 9, 8)
insert into tab41 values ('1', '1317001', 200, 9);
insert into tab41 values ('1', the '1697001', 20, 10);
insert into tab41 values ('2', '2997001', 40, 11);
insert into tab41 values ('1', '2996001', 44, 12);
insert into tab41 values ('+', '1112710', 4, 13);
insert into tab41 values ('+', '3332710', 8, 14)
Power required:SQL> select * from tab41; B PNO WEIGHT LINENO - ------- ---------- ---------- 1 1115027 36 1 2 1115100 25 2 3 1115200 50 3 1 1112510 60 4 + 1112610 6 5 + 1110710 1 6 2 1117014 79 7 + 1117000 9 8 1 1317001 200 9 1 1697001 20 10 2 2997001 40 11 B PNO WEIGHT LINENO - ------- ---------- ---------- 1 2996001 44 12 + 1112710 4 13 + 3332710 8 14 14 rows selected. SQL>
Logic: The plus sign in Bno says that no. Packet was sent to the customer with the last packet (order by lineno) either signed number that is for example in tab40 there is line no. 6 whose main package number is 1112510 (from either signed lines previous PNO). So come to the power required; which shows that these signed (whose master PNO is that) packages are not according to the tab40 vs tab41 something as complete an outer join between tab40 and tab41. Example:A B C D E F G H 1 1112510 60 4 1 2996001 44 12 + 1112710 4 6 + 1112710 4 13 2 1117014 79 8 + 1117001 2 10 1 2996001 44 12 + 3332710 8 14
+ 1112710 is associated with 1112510 in tab40, in tab41, it is associated with 2996001; So that's the difference.
+ 1117001 is associated with 1117014 in tab40, while it is not in tab41.
Vice versa;
+ 3332710 is associated with 2996001 in tab41, while it is not in tab40.
I mean, if only more marked parcel number of PNO line mater is not equal to master PNO (previous no more BNO) in both the table, it should be part of the select query please. Usually this happens when our packing service gets a late delivery of prior master package, so that they send just the small package with immediately available (either) a package.
Kindly let me know; I am clear in my request, or I should elaborate more. This can be more complex, because may be bad/data from the design table, but I need the output of the select query please help me.
Full Outer Join help please
Wrongly, I posted the question here, I should post here. Keep will be remembered in the future.
Kindly help me.
Thank you and best regards.
Published by: user12050217 on January 3, 2012 08:38Hello
user12050217 wrote:
HelloUse: Oracle 11.2.0.1 on Windows XP
create table tab40 (bno varchar2 (1), pno varchar2 (7), the number (3) weight, lineno number (3));
insert into tab40 values ('1', '1115027', 36, 1); ...Thanks for posting the version and CREATE TABLE and INSERT statements. It is very useful.
Power required:
A B C D E F G H 1 1112510 60 4 1 2996001 44 12 + 1112710 4 6 + 1112710 4 13 2 1117014 79 8 + 1117001 2 10 1 2996001 44 12 + 3332710 8 14Those are the best names of columns for this work? Even if your users really insist on having the names, do not forget that people who want to help are also familiar with your application, so it would be useful that you used for the column names more descriptive as bno_40 (meaning tab40 bno), pno_40,..., lineno_41 during the validation of the problem. You can change the column alias back to a, b,..., h after the problem is resolved, if necessary.
Logic: The plus sign in Bno says that no. Packet was sent to the customer with the last packet (order by lineno) either signed number that is for example in tab40 there is line no. 6 whose main package number is 1112510 (from either signed lines previous PNO). So come to the power required; which shows that these signed (whose master PNO is that) packages are not according to the tab40 vs tab41 something as complete an outer join between tab40 and tab41. Example:
+ 1112710 is associated with 1112510 in tab40, in tab41, it is associated with 2996001; So that's the difference.
+ 1117001 is associated with 1117014 in tab40, while it is not in tab41.
Vice versa;
+ 3332710 is associated with 2996001 in tab41, while it is not in tab40.I mean, if only more marked parcel number of PNO line mater is not equal to master PNO (previous no more BNO) in both the table, it should be part of the select query please. Usually this happens when our packing service gets a late delivery of prior master package, so that they send just the small package with immediately available (either) a package.
Kindly let me know; I am clear in my request, or I should elaborate more. This can be more complex, because may be bad/data from the design table, but I need the output of the select query please help me.
Yes, it seems unnecessarily complicated, so you should be especially clear in your description.
It is always useful to describe what each line of output. In this issue, it seems that different production lines represent different things:
(1) some lines represent an incompatibility between -marked lines in tab40 and tab41 (i.e. the lines or table where bno ='' and when the ofn even in the table has a different master_pno, or it the pno even does not exist in the other table). We will call these lines 'follower '.
(2) the other lines represent lines masters of the lines do not match (1)To get the master for each line + marked row in a table, use the analytical LAST_VALUE function. That's what the two first of subqueries, got_master_pno_40 and got_master_pno_41 below.
To get the lines are not (the disciples, or the output type (1)), do an outer join complete, as you said. It's that the subquery follows, mismatched_followers.
To get the final result, a Union of the followers with their respective masters. It's that the main request below.WITH got_master_pno_40 AS ( SELECT bno, pno, weight, lineno , LAST_VALUE ( CASE WHEN bno != '+' THEN pno END IGNORE NULLS ) OVER ( ORDER BY lineno) AS master_pno FROM tab40 ) , got_master_pno_41 AS ( SELECT bno, pno, weight, lineno , LAST_VALUE ( CASE WHEN bno != '+' THEN pno END IGNORE NULLS ) OVER (ORDER BY lineno) AS master_pno FROM tab41 ) , mismatched_followers AS ( SELECT NVL (m40.pno, m41.pno) AS pno , m40.bno AS bno_40 , m40.pno AS pno_40 , m40.weight AS weight_40 , m40.lineno AS lineno_40 , m40.master_pno AS master_pno_40 , m41.bno AS bno_41 , m41.pno AS pno_41 , m41.weight AS weight_41 , m41.lineno AS lineno_41 , m41.master_pno AS master_pno_41 FROM got_master_pno_40 m40 FULL OUTER JOIN got_master_pno_41 m41 ON m40.pno = m41.pno WHERE NVL (m40.master_pno, '?') != NVL (m41.master_pno, '?') AND '+' IN (m40.bno, m41.bno) ) SELECT bno_40, pno_40, weight_40, lineno_40 , bno_41, pno_41, weight_41, lineno_41 , pno , 'F' AS master_or_follower FROM mismatched_followers -- UNION ALL -- SELECT t40.bno, t40.pno, t40.weight, t40.lineno , t41.bno, t41.pno, t41.weight, t41.lineno , f.pno , 'M' AS master_or_follower FROM mismatched_followers f LEFT OUTER JOIN tab40 t40 ON f.master_pno_40 = t40.pno LEFT OUTER JOIN tab41 t41 ON f.master_pno_41 = t41.pno -- ORDER BY pno , master_or_follower DESC ;This assumes that ofn is unique to each table and that ofn! = ' ?'.
Output:
B PNO_40 WEIGHT_40 LINENO_40 B PNO_41 WEIGHT_41 LINENO_41 PNO M - ------- ---------- ---------- - ------- ---------- ---------- ------- - 1 1112510 60 4 1 2996001 44 12 1112710 M + 1112710 4 6 + 1112710 4 13 1112710 F 2 1117014 79 8 1117001 M + 1117001 2 10 1117001 F 1 2996001 44 12 3332710 M + 3332710 8 14 3332710 FYou did not ask the last two columns, but you need to sort. If you don't want to see them, then you can make the UNION in a subquery, then, in the main query, use "ORDER BY pno, master_or_follower", as above, but do not include the columns in the SELECT clause. Your front end may have an easier way to hide these columns, so that they are still as a result set (and therefore, can be used in the ORDER byclause of a UNION) but are not displayed. In SQL * Plus, for example:
COLUMN pno NOPRINT COLUMN master_or_follower NOPRINT -
Hi all
When I try to export the database, I get the following error. Help, please
C:\ > exp case/compass@prd_test file='I:\Prd_dumb222_refresh\backup_before_refresh\exp_cas_backupbeforefresh_020310.dmp' log='I:\Prd_dumb222_refresh\backup_before_refresh\exp_cas_backupbeforefresh_020310.log'
Export: Release 10.2.0.1.0 - Production Wed Feb 3 06:04:25 2010
Copyright (c) 1982, 2005, Oracle. All rights reserved.
EXP-00056: ORACLE error 6550
ORA-06550: line 1, column 41:
PLS-00302: component 'SET_NO_OUTLINES' must be declared.
ORA-06550: line 1, column 15:
PL/SQL: Statement ignored
EXP-00000: export completed unsuccessfully
The version of the db and export utility is that same as u see by below.
C:\ > sqlplus "virtue sysdba".
SQL * more: Release 10.2.0.1.0 - Production Wed Feb 3 06:06:35 2010
Copyright (c) 1982, 2005, Oracle. All rights reserved.
Connected to:
Oracle Database 10g Enterprise Edition Release 10.1.0.2.0 - Production
With partitioning, OLAP and Data Mining options
SQL >
Concerning
Arun Kumararundba wrote:
I put the oracle home as below...C:\>set ORACLE_HOME=I:\d001\oracle\10.1.0.2
But it still gives the same error...
Help, please
Kind regards
ArunNow you have 10.1.0.2 Oracle installed on the machine you run the exp?
If Yes can post you the error again you got.Concerning
Anurag -
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