Help to update all rows in the Table with a sequence

Similar Questions

• Problem updated 16 rows, it updates all rows in the table

  I tried to update of 16 ranks with AL as the name of divion with the script as below:
  
  Update wire_center set a.wg_id = '63'
  where EXISTS (select b.div_name from wire_center, title b, area c, ns_workgroups d).
  where B.DIV_NAME =' al ' AND a.dis_id = c.dis_id and b.div_id = c.div_id and d.wg_id = a.wg_id);
  
  When I run it, it updates all rows in the table.
  
  However when I run the select subquery, it returns 16 ranks.
  
  It seems where EXISTS is the problem. If I exist, it gave me error ora-00936.
  
  How to fix? Need urgent help please. DB is 10g.
  
  Thanks in advance.

  If I understand correctly what you want, you must not include wire_center once again in the second select (in your clause).
  The second selection has no relationship to the table you're updating, so because select the second returns 16 rows, it is always set to true will. For each line. If all the rows will be updated.

  Instead of

  Update wire_center a set a.wg_id='63'
  where EXISTS (select b.div_name from wire_center a, division b, district c, ns_workgroups d
  where B.DIV_NAME='AL' AND a.dis_id=c.dis_id and b.div_id=c.div_id and d.wg_id=a.wg_id );
  

  Try this:

  Update wire_center a set a.wg_id='63'
  where EXISTS (select b.div_name from division b, district c, ns_workgroups d
  where B.DIV_NAME='AL' AND a.dis_id=c.dis_id and b.div_id=c.div_id and d.wg_id=a.wg_id );
  

  Published by: big on 29-dec-2010 14:27

• all rows in the table are not eligible for the specified partition

  SQL > Alter Table ABC
  Exchange 2 Partition P1 with Table XYZ;
  
  Modified table.
  
  SQL > Alter Table ABC
  Exchange 2 Partition P2 with Table XYZ;
  
  
  P2 Partition Exchange with XYZ Table
  *
  ERROR on line 2:
  ORA-14099: all rows in the table are not eligible for the specified partition
  
  The exchange partition works fine for the first time. However, if we try to swap the 2nd partition it gives the error.
  How to solve this error?
  How can I find the lines which are not qualified for a specific part. is there a query to find out the same thing?

  >
  Well, exchange of syntax and logic is not clearly as it should (IMHO). There is no element of syntax that tells Oracle we want to Exchange partition data in a table that is not partitioned or not partitioned into partition table data.
  >
  What? Not sure where you got that but maybe it was before you had first cup of coffee? ;)

  An "Exchange", it's just that; an Exchange. Partition data end up in the non-partitioned table and vice versa. It is meaningless and totally obsolete if "we want Exchange partition data in a table that is not partitioned or not partitioned into partition table data".
  >
  It was decided by Oracle not partitioned table control. If the non-partitioned table is empty, it means you want to Exchange data partition in a non-partitioned table. And if not partitioned table is not empty, it means you want to Exchange data in the table that is not partitioned into partition.
  >
  There is no decision to make. The segments are swapped. Oracle doesn't check, know or even care if one or the other or both segments are empty. 'Control' which is carried out (by default except if NO CONTROL is used) only consists of ensuring all the data in the segment intended for the partition belongs to this partition.

  It is what gives the example of John. This can NEVER work if table1 is empty unless p1 is empty at the beginning:
  1 Exchange p1 with table1
  2 Exchange p2 with table1

  As John explains, assuming that no other operations are trying to put the data from p1 P2 which is not possible if p1 actually contains data.

  You can save it for next April 1!

• Request from oracle to MySql using dblink read all rows in the table

  Hello
  I use the heterogeneous connectivity between oracle 10204 to the Mysql database.
  I have a database of link on the side of the oracle.
  I request a table in MySql with 10 million rows.
  
  His is not serious if I am running:
  ' Select * from ' CDR_Accounts"@mysql where 'id '= 7675405;
  or
  Select * from 'CDR_Accounts"@mysql;
  
  There is an index on the column id.
  It seems that the Mysql is feteching all rows in the table, all data is transferred to oracle on the dblink and only after the required lines are back to the client.
  
  The /etc/odbcinst.ini file is as follows:
  

  [odbcprd:oracle@odbc /software/oracle]$ cat /etc/odbcinst.ini
  [myodbc3]
  Description             = Mysql connector to mysql version 3.5
  Driver          = /software/oracle/MysqlOdbc/3.52/lib/libmyodbc3-3.51.25.so
  Driver64                = /usr/lib
  Setup           = /software/oracle/MysqlOdbc/3.52/lib/libmyodbc3S-3.51.25.so
  Setup64         = /usr/lib
  UsageCount              = 1
  CPTimeout               = 3600
  CPReuse         = 

  Please advice
  
  Thank you

  Initialization of gateway open tha file located in $ORACLE_HOME/hs/admin called init .ora and change HS_FDS_TRACE_LEVEL to HS_FDS_TRACE_LEVEL =WE.

  ATTENTION:
  Do not forget t turn off after all your tests.

• Cannot get rid of the gaps between the rows in the table with the basic HTML in DW cc 2015

  Hi gang

  I haven't used html in ages and doing something basic without css... but for some reason any I get these gaps between the rows in the table, no cause I do.

  what I am doing wrong?

  < ! DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 / / IN" "http://www.w3.org/TR/html4/strict.dtd" > ""

  < html >

  < head >

  < meta http-equiv = "Content-Type" content = text/html"; Charset = UTF-8 ">"

  < title > Untitled Document < /title >

  < / head >

  < body >

  < table width = "560" >

  < /table >

  < table width = "560" border = "0" align = "center" cellpadding = "0" cellspacing = "0" >

  < tbody >

  < b >

  < td colspan = "3" > < img src = "images/AAA - ADE_01.jpg" width = "560" > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_02.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_03.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_04.jpg" height = "267" / > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_05.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_06.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_07.jpg" height = "267" / > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_05.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_06.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_07.jpg" height = "267" / > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_08.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_09.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_10.jpg" height = "267" / > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_11.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_12.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_13.jpg" height = "267" / > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_14.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_15.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_16.jpg" height = "267" / > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_17.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_18.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_19.jpg" height = "267" / > < table >

  < b >

  < td width = "209" > < img src = "images/AAA - ADE_20.jpg" height = "267" / > < table >

  < td width = "158" > < img src = "images/AAA - ADE_21.jpg" height = "267" / > < table >

  < td width = "193" > < img src = "images/AAA - ADE_22.jpg" height = "267" / > < table >

  < /tr >

  < / tbody >

  < /table >

  < / body >

  < / html >

  Add this in thesection of your page

• A script to remove all rows in the table that contains a specific text

  Hello

  I tried some old scripts but cannot move to the right solution.

  I need a script that deletes all the rows in a table that contains a specific unique word text, something like "xxx".
  Someone has an idea?

  Thank you

  Hello

  To remove a line using row.remove () method.

  Iterate if table.rows and delete the matching condition.

  If we talk about condition, be more specific - what do you mean "a line contains a text:

  ==> 1st cell contains,

  ==> any cell contains.

  Content of the line whole is an array of his cells.contents, so your text from line 1 is:

  rows [0].contents.join ("") ==> string

  Jarek

• AF: displays do not all rows in the table

  Hi all

  I have an af table in my jsff and it is bound to a display object. When I run the page locally in my jdev the table af shows all lines present in the ViewObject. But when I deploy the application in our SIT weblogic break page maximum of 25 lines shows if VO has more than 25 lines.

  I put the size of the VO - 1 range. The size of range iterator is empty. I'm naïve why he works in local jdev and does not not in SIT.

  A level of the application or the server parameter influences the number of lines to display in the table.

  Thank you

  Champion

  If it worked before, something had changed on the server. Have you asked your admins if they changed something and if so what?

  They have applied a patch.

  Timo

• How to update exists column on the table with the exact number and auto increment

  Hello

  I have a table with more than 10 million rows and there is a column called 'number_zaq', I want to update this column on line frist from 2000 and + 1 for the next all ranks.

  Update your_table

  Set number_zaq = rownum + 2000-1;

• Hide or show rows in the table with AppleScript?

  I have a large table number, and I sometimes want to display the entire table and sometimes select a group of lines to hide or show, to make the display of data more convenient.

  By selecting many rows to hide is tedious (there are many, and they are not contiguous).  So I would use AppleScript to do this.  But in the numbers AppleScript dictionary, I don't see any way to apply an attribute "hidden" in rows, columns or beaches.  Y at - it a trick I'm missing?  Or it simply not exist in the current implementation?

  Thank you

  AFAIK, you can't hide a line or set a height of 0 using AppleScript, although I suggested that any time via numbers of > provide comments numbers in the menu.

  What you could do is filter the table to hide the lines, probably by adding a column filter designating the lines that you want to see (or, conversely, hide).  This filter can be turned on and off via AppleScript using the filtered table property, although it would probably be easier to do via the integrated interface.

  SG

• Problem updating multiple rows in the table using subquery

  Hi everyone, I can't update multiple lines with a subquery. Here is the configuration:

  create table mytable (
  col_a number primary key,
  col_b number,
  col_c number,
  col_d number);
  
  insert into mytable values (1 ,1,1,15);
  insert into mytable values (2 ,1,2,7 );
  insert into mytable values (3 ,1,3,11);
  insert into mytable values (4 ,1,4,23);
  insert into mytable values (5 ,1,5,14);
  insert into mytable values (6 ,2,1,50);
  insert into mytable values (7 ,2,2,41);
  insert into mytable values (8 ,2,3,13);
  insert into mytable values (9 ,2,4,12);
  insert into mytable values (10,2,5,19);
  insert into mytable values (11,3,1,10);
  insert into mytable values (12,3,2,92);
  insert into mytable values (13,3,3,81);
  insert into mytable values (14,3,4,17);
  insert into mytable values (15,3,5,66);
  insert into mytable values (16,4,1,54);
  insert into mytable values (17,4,2,41);
  insert into mytable values (18,4,3,22);
  insert into mytable values (19,4,4,24);
  insert into mytable values (20,4,5,17);

  For this example, by using an update statement (or merge if this is better), I mean set values for col_d where col_b = 3 equal to that of the col_d where col_b = 1 and col_c equal between them. Results should resemble the following after the update:

  col_a col_b col_c col_d
  1     1     1     15
  2     1     2     7
  3     1     3     11
  4     1     4     23
  5     1     5     14
  6     2     1     50
  7     2     2     41
  8     2     3     13
  9     2     4     12
  10    2     5     19
  11    3     1     15
  12    3     2     7
  13    3     3     11
  14    3     4     23
  15    3     5     14
  16    4     1     54
  17    4     2     41
  18    4     3     22
  19    4     4     24
  20    4     5     17

  I see her there within my reach using this query, where I want to put b_col_d = a_col_d, but miss me something, this query returns too many rows when it is used in the update statement.

  select * from (
    select col_a as a_col_a, col_b as a_col_b, col_c as a_col_c, col_d as a_col_d
    from mytable
    where col_b = 1
    ) a, (
    select col_a as b_col_a, col_b as b_col_b, col_c as b_col_c, col_d as b_col_d
    from mytable
    where col_b = 3
    ) b
  where a.a_col_c = b.b_col_c

  Update column_d set mytable = (select? where?)
  
  Can someone help me get there? I use 10 gr 2.
  
  Thank you!
  Mark

  I hope that's what you're looking for:

  SQL > UPDATE mytable myt1
    2  SET    col_d = ( SELECT myt2.col_d
    3                   FROM   mytable myt2
    4                   WHERE  myt2.col_b = 1
    5                   AND    myt1.col_c = myt2.col_c
    6                 )
    7  WHERE  col_b = 3
    8  AND    EXISTS
    9         ( SELECT NULL
   10           FROM   mytable myt2
   11           WHERE  myt2.col_c = myt1.col_c
   12         )
   13  ;
  
  5 rows updated.
  
  SQL > SELECT * FROM mytable ORDER BY col_a;
  
                 COL_A                COL_B                COL_C                COL_D
  -------------------- -------------------- -------------------- --------------------
                     1                    1                    1                   15
                     2                    1                    2                    7
                     3                    1                    3                   11
                     4                    1                    4                   23
                     5                    1                    5                   14
                     6                    2                    1                   50
                     7                    2                    2                   41
                     8                    2                    3                   13
                     9                    2                    4                   12
                    10                    2                    5                   19
                    11                    3                    1                   15
                    12                    3                    2                    7
                    13                    3                    3                   11
                    14                    3                    4                   23
                    15                    3                    5                   14
                    16                    4                    1                   54
                    17                    4                    2                   41
                    18                    4                    3                   22
                    19                    4                    4                   24
                    20                    4                    5                   17
  
  20 rows selected.
  

  Thank you very much for providing the sample data in a format that is easy to consume form, as well as the expected results.

• Update multiple rows in a table with one value of another multiple

  Using SQL Server

  How this can be done:

  In all the lines in the upper table PS_CA_BILL_PLAN, we want to update the field LAST_XREF_SEQ_NUM with the MAX (XREF_SEQ_NUM) + 1 of the bottom table

  Where the CONTRACT_NUM and the BILL_PLAN_ID are equal

  This SQL below (in green) works for one line only

  

  I think it's the SQL code you're looking for:

  UPDATE PS_CA_BILL_PLAN SET LAST_XREF_SEQ_NUM =

  (SELECT MAX (XREF_SEQ_NUM) + PS_CA_BP_XREF 1 B)

  WHERE B.CONTRACT_NUM = A.CONTRACT_NUM AND B.BILL_PLAN_ID = A.BILL_PLAN_ID)

• Rows in the table LT until merger of all workspaces

  Database 11.2.0.4

  In our environment, we ran a few important updates in the workspaces and then merged these live workspaces.  Up to 25% of the data has been updated in those workspaces.  When these update batch workspaces have been created, previous workspaces exist who are not yet ready for the merger.

  I noticed that the underlying tables of the LT now have about 25% more lines than the live view.  We have now discovered that dbms_wm.refreshWorkspace works really poor.  This statement is used to take seconds or minutes to the maximum, but can now take half an hour or more.

  We recorded a support with Oracle request and provided details of the plan to see if we can get some resolution/advice explaining.

  In the meantime, I have a question for the forum help my understanding of the works of the Manager of the workspace.

  In the example below, I have table "wm_test_table", "test_workspace1" and "test_workspace2".  In "test_workspace1", I update all rows in the table - the table LT now has 2 rows for each record.  I merge 'test_workspace1' live and LT still has 2 rows for each record.  The other lines are not removed until "test_workspace2" is merged and removed.

  
  

  SQL> -- Create a test table
  SQL> create table wm_test_table (
    2     id integer primary key,
    3     name varchar2(100));
  
  
  Table created.
  
  
  SQL> -- Insert 1,000 rows
  SQL> insert into wm_test_table (
    2     select rownum, 'before'
    3     from dual
    4     connect by level <= 1000);
  
  
  1000 rows created.
  
  
  SQL> commit;
  
  
  Commit complete.
  
  
  SQL> -- Version enable it
  SQL> execute dbms_wm.enableVersioning('wm_test_table');
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> -- Create two workspaces
  SQL> execute dbms_wm.createWorkspace('test_workspace1');
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> execute dbms_wm.createWorkspace('test_workspace2');
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> -- Go to test_workspace1 and update all the rows
  SQL> execute dbms_wm.goToWorkspace('test_workspace1');
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> update wm_test_table set name = 'after';
  
  
  1000 rows updated.
  
  
  SQL> commit;
  
  
  Commit complete.
  
  
  SQL> -- Check how many rows in wm_test_table_lt - we expect 2,000 as we haven't merged yet
  SQL> select count(*) from wm_test_table_lt;
  
  
    COUNT(*)
  ----------
        2000
  
  
  SQL> -- Merge and remove test_workspace1
  SQL> execute dbms_wm.goToWorkspace('LIVE');
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> execute dbms_wm.mergeWorkspace('test_workspace1', remove_workspace=>true);
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> -- Check how many rows in wm_test_table_lt
  SQL> -- I'd hope there'd only be 1,000 but there is 2,000
  SQL> select count(*) from wm_test_table_lt;
  
  
    COUNT(*)
  ----------
        2000
  
  
  SQL> -- Let's see if compressWorkspace will get rid of them
  SQL> execute dbms_wm.compressWorkspace( -
  >       workspace => 'LIVE',   -
  >       auto_commit => true,   -
  >       remove_latest_deleted_rows => true);
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> -- They're still there
  SQL> select count(*) from wm_test_table_lt;
  
  
    COUNT(*)
  ----------
        2000
  
  
  SQL> -- Now merge test_workspace2
  SQL> execute dbms_wm.mergeWorkspace('test_workspace2', remove_workspace=>true);
  
  
  PL/SQL procedure successfully completed.
  
  
  SQL> -- and the additional 1,000 rows are removed
  SQL> select count(*) from wm_test_table_lt;
  
  
    COUNT(*)
  ----------
        1000
  

  Is it possible to safely remove the extra lines in LT without waiting until we merged the workspaces that existed before the update batch has been done?  I hope that it will so improve the performance of refreshWorkspace.

  
  

  I thought that something like this can do, but it does not remove the other ranks, is:
  

  execute dbms_wm.PurgeTable(
   table_id => 'test.wm_test_table', 
   archive_table => null, 
   where_clause => 'id not in (select id from test.wm_test_table)', 
   instant=>null, 
   workspace => 'LIVE', 
   purgeAfter => false);
  

  This question is similar to

  Lines left in the table LT after removal of the direct workspace and the removal of all workspaces

  and

  How to delete soft deleted records?

  but I'm still not sure.

  Thank you

  John

  Hello

  This behavior is expected and it is due to the test_workspace2 workspace.  A compression operation will not allow compressed range to include a backup implicit point that is created for a child workspace.  This is done to preserve the integrity of this workspace.  The initial 1000 lines are all lines that are visible from test_workspace2.  Removal of these lines would leave test_workspace2 will 0 lines in there.  Lines 1000 updates are the lines that do not appear on LIVE.  So, given that the two sets of lines are needed, none of the lines can be deleted physically.  A compression operation will never change the view of data for any workspace.  It only removes the unnecessary records.  The two options in order to be able to compress these lines is to either delete (as you did) or refresh test_workspace2.  The refresh operation would move the implicit savepoint for the workspace to a version that isn't after all 2000 lines in the table _LT and allow the dressing to remove first half of them because they are no longer needed by any child workspace.

  With respect to the performance of RefreshWorkspace, I would need to see a trace of the transaction file.  But who should rather get through the SR you filed.

  Kind regards

  Ben

• deselect all rows in af: table in the adf.

  Dear all,
  
  I have af:table with activated single selection. When the page is initially loaded I want all rows of the table deselection... so, how can I achieve this?
  
  
  Thank you.
  Kind regards.
  
  jdev version 11.1.1.4.0

  Remove the attribute according to the definition of af: table when a display object is instance fell into the page in a table:

  selectedRowKeys = ' #{bindings. " Employees.collectionModel.selectedRow}.

  The example of table definition should look like:

  
  lines = ' #{bindings. " Employees.rangeSize}.
  emptyText = "#{bindings." Employees.Viewable? "{'No data to display.': 'Access Denied.'}".
  fetchSize = "#{bindings." Employees.rangeSize}.
  rowBandingInterval = '0 '.
  selectionListener = "#{EmpTableBean.onTableNodeSelection} '"
  rowSelection = "single" id = "t1" >

  The following code can be used to get the selected node - after the user selects a node:

  {} public void onTableNodeSelection (SelectionEvent selectionEvent)
  resolveMethodExpression ("links. Employees.collectionModel.makeCurrent} «»
  NULL, new class [] {SelectionEvent.class},
  (New Object() {selectionEvent});
  Object richeTableau = (RichTable) selectionEvent.getSource ();
  Line line = null;
  {for (object facesRowKey: {object.getSelectedRowKeys ())}
  object.setRowKey (facesRowKey);
  Object o = object.getRowData ();
  JUCtrlHierNodeBinding rowData = o (JUCtrlHierNodeBinding);
  line = rowData.getRow ();
  }
  System.out.println (Row.GetAttribute("FirstName"). ToString());
  }

  public Object resolveMethodExpression (String expression, class returnType,
  Class [] argTypes,
  Object [] argValues) {}
  FacesContext facesContext = FacesContext.getCurrentInstance ();
  Application app = facesContext.getApplication ();
  ExpressionFactory elFactory = app.getExpressionFactory ();
  ELContext elContext = facesContext.getELContext ();
  MethodExpression methodExpression =
  elFactory.createMethodExpression (elContext, expression, returnType,
  argTypes);
  Return methodExpression.invoke (elContext, argValues);
  }

  Thank you
  Nini

• Rows in the table are break on separate pages...

  I have 20 lines equipped table:

  first 3 lines are on one page, then half of the page is empty hen remaining 17 rows is on the second page.

  How can I keep table to break the lines. I want all rows in the table to succeed himself.

  Help, please. Thank you.

  Keep them with parameters are in the table > Format > Format line...

  

  Note: the first row on the second page may also have a start parameter that indicates that it is at the top of a page or column.

  The control of widows and orphans just specifies how many rows to keep together (widow is the first page; ( orphan , is the second page) when a table has over a page. The higher the number, the more lines are forced to remain together.

• I have a table of the adf, I added a column that contains a button that I created, when I click it must remove this row in the table, but it is not, please help

  I have a table of the adf, I added a column that contains a button that I created, when I click it must remove this row in the table, but it is not, please help

  I don't understand. You use vo and eo for you to use business components.

  Again, this kind of code call in trouble.

  You must post the changes to make them visible to the eo find vo. You must then run the query for the changes in the business layer strips then you must update the iterator he table is based on.

  In your code I see that happen, hooch maybe because it is more often than not formatted and undocumented.

  My advice is to do a small test case that you can manage with easy sql. Once you get it to run transfer you the results to the actual application.

  Timo