Help with the cluster in table for the cluster size difference, please!

Similar Questions

• Need help with the automatic backup feature - please!

  Hello

  I recently started a flash animation and the AutoSave feature is enabled.  I got a good animation, but decided to play a little with it.  After a few moments, I decided to call one night and you exit the program ensuring NOT to save my work.  When you open this file the next time, I just found out that Flash has my file saved automatically while I was playing.  Now I have an animation worthless and have to start over again.  Is it possible to go back to an earlier backup or AutoSave at this point or I am about to do a lot of work again?

  Thanks to all who can help.

  As far as I know, the auto save feature is not able to track down the previous versions of the document being saved - that calls for a specified version control system. I think that Flash saves the file only if it is requested to the. There are several ways to enable or disable auto-save:

  1. in the dialog "new Document." You can choose to activate the automatic backup.
  2. In the "Properties of the Document" dialog box, you can set the check mark.

  If these are true, it will not happen of any economy car. The problem may be, there is also a section called ASR. Backup and recovery is not the same when it comes to Flash, but people tend to consider the same. You set the AutoRecover feature in preferences under general.

  • Windows: Edit > Preferences: general > auto salvage
  • Mac OS: Flash Professional > preferences: general > auto salvage

  Both has a default value of 10 minutes and it can confuse the user. Please see the document to make sure, that you have not disconnected ASR instead of the Auto-Save. You can do this:

  1. Go to preferences (Ctrl + U on Windows, and command + U on Mac OS) and check if the automatic recovery is set.
  2. Go to the properties of documents (Ctrl + Windows and cmd + D on Mac OS) and check if the Auto-Save is set.

  The first (in preferences) is ok to have fixed. It is the second, which could have caused problems for you.

  /Ockley

• Need help with the error Code: 1002 please!

  I am trying to update my CC Id & get the error Code: 1002

  Any suggestions before I try to support?

  Thank you!

  Hello

  Please follow the steps below:

  Uninstall CC Desktop App using https://helpx.adobe.com/creative-cloud/help/uninstall-creative-cloud-desktop-app.html

  Run the tool cleaning Adobe CC from here: https://helpx.adobe.com/creative-cloud/kb/cc-cleaner-tool-installation-problems.html

  Restart your computer

  Install creative cloud app: https://www.adobe.com/creativecloud/desktop-app.html

  Let us know if it works!

• Need help with the launching track pack for forza code 4

  Bought new Forza 4 and the lancer Track Pack code does not work, how do I get a code that is generated in the form I've already paid for it. Rank of loads of numbers and sent 10 s of emails but cant seem to get help.
  
  This is the help I get when the cat to an Ambassador xbox on xbox.com
  
  Terry wrote:
  Need help with the launching track pack for forza code 4
  The Xbox Ambassador says:
  Location of Ambassador of the community...
  The Xbox Ambassador says:
  Location of Ambassador of the community...
  The Xbox Ambassador says:
  Your question will be answered by an Ambassador of the Xbox. You have been connected to the Ambassador as a user Xbox [3]
  The Xbox Ambassador says:
  Hello
  Terry wrote:
  Hello
  The Xbox Ambassador says:
  Hey
  Terry wrote:
  just to be on the phone to xbox live support and was told to come here
  The Xbox Ambassador says:
  ok\
  The Xbox Ambassador says:
  What is your problem?
  Terry wrote:
  I bought the 4 for forza ansd 360 new sealed Christmas...
  Terry wrote:
  has got 2 codes that accompanies the game but the pack track code does not work
  The Xbox Ambassador says:
  Wow good
  Terry wrote:
  whenever I put in the code it says code redeemed
  The Xbox Ambassador says:
  I think the code is used. You must return to the retailer
  Terry wrote:
  I tried to, but since I already opened the case they will not accept
  The Xbox Ambassador says:
  Oh. No,
  Terry wrote:
  the code had been used or defective as I am the only person who has touched the game once opened, tried to enter the code when it is open
  The Xbox Ambassador says:
  Maybe it was auto bought?
  Terry wrote:
  so, how do I get another code generated track Pack if defective?
  The Xbox Ambassador says:
  I do not know.
  Terry wrote:
  bought the game new, so I get the track pack
  The Xbox Ambassador says:
  Oh. It's bad.
  The Xbox Ambassador says:
  I think that if you Exchange 1 code it will buy it
  Terry wrote:
  car pack code worked, starter pack did not work
  The Xbox Ambassador says:
  Oh.
  The Xbox Ambassador says:
  It's a bad
  The Xbox Ambassador says:
  BTW you have an evolution of the tests?
  Terry wrote:
  Yes, I want to? but more anxious to get a code object generated for this pack
  The Xbox Ambassador says:
  Hey if I help can u give me this game too?
  Terry wrote:
  ?????????????????
  Terry wrote:
  So is it possible to get a code for that time?
  The Xbox Ambassador says:
  Hey
  The Xbox Ambassador says:
  Yes.
  The Xbox Ambassador says:
  you need to contact them
  The Xbox Ambassador says:
  and tell them that the code is used.
  Terry wrote:
  I was told to come here? where can I go to get the code?

  Hi Terryg76,

  ·         What version of the operating system is installed on the computer?

  I suggest you to contact the game manufacturer for more help and information.

• Need help with the IP configuration on vm ware for the installation of 11 GR 2 on linux vmware 6 on win7

  Need help with the ip configuration on/etc/hosts for the installation of 11 GR 2 on linux vmware 6 on win7.

  Let me know if you need more info... in fact I have a setting error while installation said

  -(/ etc/hosts has no correct entry for the host name)

  Host: 192.168.85.100

  Win7 ip: 192.168.1.x

  Thank you...

  (host computer)

  Win7 64 bit

  (vmware)

  Oracle Linux Server 6.3 version

  Release of Red Hat Enterprise Linux Server 6.3 (Santiago)

  Oracle Linux Server 6.3 version

  -(/ etc/hosts has no correct entry for the host name)

  Then post your/etc/hosts.

  Host: 192.168.85.100

  Win7 ip: 192.168.1.x

  Why 85? have you tried 192.168.1.100?

• What is the correct way to ask for help with the forum, rather than product, questions?

  I can't find the right way to ask a question about the forums themselves.

  PAGulley said

  I can't find the right part of the forum to ask questions about the forum itself and its features. I wonder what the right place and the way is to get help with the forum system itself. I can find the place to ask questions about specific Mozilla products very well.

  Look up where it says contributor tools and select Contributor Forums. Make sure that you scroll to the top or you'll get a bar with different links instead,

  The forum is https://support.mozilla.org/forums where you question would be better in the SUMO community discussions.

• Help with the query to select only one record from the result set in double

  Hello

  Please help with the query. Version of Oracle database we use is 10g R2.

  I have a vision that is duplicated IDS, but they are used across the different functions. See below examples of data. Please help me with a query to select only one record (based on ID regardless of the area) from the bottom of the result set of duplicate records. For what is the point of view is there unique records, given the combination of the fields ID, Org, DF, dry, Sub-Sec

  ID	Org	DF	Sec	Sub-Sec

  
  (163)CQCPDMCPDMHD(163)PCENGENGENG(163)CQASICASICIS8888TSTACTACTAC(163)TSHEHESW6789CQINFOINFOFOS6789PCSECSYSSECSYSINFO16789TSSECSYSSECSYSINFO29009PCBMSBMSBMS1

  My result set must eliminate the duplicate identifiers regardless of whoever we choose of the result set. (I mean without distinction Org, DF, s, Sub-s). My expected result set should be.

  ID	DSB

  
  DF
  SEC
  Sub-Sec
  (163)CQCPDMCPDMHD8888TSTACTACTAC6789CQINFOINFOFOS9009PCBMSBMSBMS1

  
  

  Thank you

  Orton
  

  Hello

  This sounds like a job for ROW_NUMBER:

  WITH got_r_num AS

  (

  SELECT id, DSB, df, s, sub_sec org

  ROW_NUMBER () OVER (PARTITION BY ID.

  ORDER BY org

  ) AS r_num

  OF view_x

  )

  SELECT id, DSB, df, sub_sec s,

  OF got_r_num

  WHERE r_num = 1

  ;

  He is a Top - N query example, where you choose the elements of N (N = 1 in this case) from the top of an ordered list.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and INSERT, only relevant columns instructions) to your sample data and the results desired from these data.  (I know that you said that you were a view selection.  Just for this thread, pretending it is a picture and post simple CREATE TABLE and INSERT statements to simulate your point of view).
  Point where the above query is to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in these places.  (I didn't quite understand the explanation above.  I don't know why you want to

  ID ORG DF DRY SUB_SEC

  --      ---     --      ---     -------

  1234 CQ DPRK DPRK HD

  and is not

  1234 IS CQ ASIC, ASIC

  or

  TS 1234 IT IT SW

  or

  1234 CQ ASIC ASIC HD

  )
  If you change the query at all, post your modified version.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002

• Need help with the condition join in SQL

  Hi all -
  
  I need to ask for help with this query:
  
  Create table user_tab_col_test (varchar2 (30) from table_name, column_name varchar2 (30), data_type varchar2 (30));
  
  Insert into user_tab_col_test (table_name, column_name, data_type) values ('table1', 'column1', 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ('Column2', 'table1', 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ("Column3", 'table1', 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ('column4', 'table1', 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ("column1", "table2", 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ('table2', 'column2', 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ('table2', "Column3", 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ('table2', 'column4', 'varchar2')
  Commit;
  
  Create table all_cons_columns_test (varchar2 (30) from table_name, column_name varchar2 (30), constraint_name varchar2 (30))
  
  Insert into all_cons_columns_test (table_name, column_name, constraint_name) values ("table1", "column1", "primary")
  Insert into all_cons_columns_test (table_name, column_name, constraint_name) values ("table1", "column1", "secondary")
  Commit;
  
  This is my query and the current result:
  
  Select u.table_name, u.column_name, c.constraint_name
  Of user_tab_col_test u
  Outer join all_cons_columns_test c left
  On (u.table_name = c.table_name
  AND U.COLUMN_NAME = C.COLUMN_NAME
  AND C.CONSTRAINT_NAME IN ('main'))
  order of U.table_name, U.COLUMN_NAME;
  
  TABLE_NAME COLUMN_NAME, CONSTRAINT_NAME
  ------------------ --------------------- ----------------------------
  Table1 primary Column1
  Table1 Column2
  Table 1 Column3
  Table2 Column1
  Table2 Column2
  
  
  Three questions:
  (1) I don't want to return results where table_name = "table1". I can't get this to work.
  (2) is my proper request and this is the best way to return my desired results? For example, I want all of the columns of user_tab_col_test and I want to only display the constraint_name from all_cons_columns_test argument if the argument constraint_name = 'primary '.
  (3) will be the synatx be the same if I need to join a third table to all_cons_columns_test?
  
  Any advice/suggestions are appreciated-
  John
  
  Published by: user703358 on January 11, 2013 20:57
  
  Published by: user703358 on January 11, 2013 21:48

  Hi, John,.

  user703358 wrote:
  Hi all -

  I need to ask for help with this query:

  Create table user_tab_col_test (varchar2 (30) from table_name, column_name varchar2 (30), data_type varchar2 (30));

  Insert into user_tab_col_test (table_name, column_name, data_type) values ('table1', 'column1', 'varchar2')
  Insert into user_tab_col_test (table_name, column_name, data_type) values ('Column2', 'table1', 'varchar2')...

  Thanks for posting the CREATE TABLE and INSERT.
  It is more useful if you post the code that can be run without modification. You did not semicolons after INSERTION instructions.

  Three questions:
  (1) I don't want to return results where table_name = "table1". I can't get this to work.

  What have you tried? Post your best attempt.
  Here's one way:

  SELECT    u.table_name
  ,        u.column_name
  ,        c.constraint_name
  FROM             user_tab_col_test      u
  LEFT OUTER JOIN  all_cons_columns_test  c
                          ON    u.table_name     = c.table_name
                 AND   u.column_name     = c.column_name
                 AND   c.constraint_name IN ('primary')
  WHERE       u.table_name     = 'table1'          --  *****  NEW  *****
  ORDER BY  u.table_name
  ,            u.column_name
  ;
  

  You would not put this condition in the clause; who controls what is considered as a match between the tables, and "u LEFT OUTER JOIN c" means show all lines of u, even if they do not have a match in the c.

  (2) is my proper request and this is the best way to return my desired results? For example, I want all of the columns of user_tab_col_test and I want to only display the constraint_name from all_cons_columns_test argument if the argument constraint_name = 'primary '.

  Basically, this application is very well.
  It displays all the columns of user_tab_col_test; missing data_type. Just add u.data_type to the SELECT clause, or change the SELECT clause

  SELECT    u.*
  ,         c.constraint_name
  

  (3) will be the synatx be the same if I need to join a third table to all_cons_columns_test?

  Do you mean "" * add * one-third * column * to all_cons_columns_test '? "
  It depends on what results you want. Post new CREATE TABLE and INSERT and instructions the results you want new data.
  Most likely, the basic structure of what you've written will remain exactly the same.

• Need help with the data storage store, local array and network connections

  Need help with my ESXi 4.1 installation

  My hardware:

  I built a server with an Asus P6T whitebox, i7 920, 12 Gig RAM, NIC, Intel Pro1000 PT Quad, 3ware 9650SE-12ML with 8 1.5 TB SATA green in a raid 6 array gives me about 8 + TB with a spare drive all housed within a NORCO RPC-4220 4U Rackmount Server chassis.  I also have a 500 GB SATA drive which will hold the ESXi and virtual machines.

  The network includes a firewall, Netgear Prosafe FVS336G, GS724Tv of Netgear ProSafe 24 port Gigabit Managed Switch on a dhcp cable modem internet service provider.

  I also have 2 old NetGear SC101T NAS disks (4to) I want to connect to the system how some - at a later date have... data on them and want to transfer to the new storage array. I always looking into the question of whether they will work with ESXi 4.1, or I might have to only access it through Windows XP.

  My Situation:

  I have already installed ESXi 4.1 and vsphere client with no problems and it is connected to a dhcp cable internet service.  I've set up host via a dynamic DNS service name give me a static hostname on the internet.  I installed three machines to virtual OS successfully at the moment and now want to first start by creating a multimedia storage server which will use some of this new 8 TB array, then separate data storage for use with a web server small overhead storage and a backup.  It is a domestic installation.

  Help with the data store and network:

  I was doing some reading, because I'm new to this, and it looks like I'll probably want to set up my table via ESXi as a nfs disk format.  Now, the data store is usually in another physical box from what I understand, but I put my readers and ESXi all in the same box.  I'm not sure that the best way to put in place with grouped network cards, but I want to make this work.

  I understand that in ESXi 4.1 using iSCSi LUN must be less than 2 TB, but nfs - I should be able to add a bigger partition then 2 TB (for my multimedia) in nfs, right? or should I still add it separately as a separate 2 TB drives and then extend them to get the biggest space.

  Any suggestions or direct resources showing examples on how to actually add some parts of the table as data warehouses separate nfs.  I know that to go to the configuration tab, and then select Add to storage, and then select nfs. I have not my picture, but it's here that I don't know what to do because ESXi 4.1 system already has an address, should I put the same thing to the new data store array also (will it work?), and what should I use for the name of the folder and the store of data... just do something to the top.  I thought to later install Openfiler (for a multimedia storage using this table server) as a virtual machine, use the table with esxi so that I can access the same storage space with widows and linux-based systems.

  I also know I have to find a way to better use my quad nic card... put in place of virtual switches, grouping, etc HELP?

  Any direction, assistance, similar facilities to sample, suggestions or resources that would help would be great. I did a lot of hunting, but still a little confused on how to best to put in place.

  You must think of VMDK files of large databases with records of random size guest go read some data (a DLL or an INI file), maybe write some data back, then go read other data. Some files are tiny, but certain DLLs are several megabytes. It's random i/o all and heavy on the search time. IO Opsys is small random operations that are often sequential (go read data, write data, go read other data,...) so that deadlines are critical to the overall performance. That's why people say OPS are / s of reference and forget the MBs flow. The only time where you bulk transfers are when you read media (ISO files).

  Well, now forget all this. Actually the disk activity will depend on the specific applications (database? mail server? machines compiler?), but the above is true for boots, and whenever applications are idle. You should see the profile to know.

  RAID 10 is faster (and often more reliable) than RAID 5 or RAID-6 except in certain specific cases. In General RAID 10 is ideal for many random writes, since the calculation of parity for RAID-5 and - 6 adds to the overall latency between command and response - latency is cumulative if a little slow here and a little slow it adds up to a lot of overall slow synchronous especially with e/s on a network. OTOH RAID-5 and -6 can produce faster readings due to the number of heads, so you can use it for virtual machines that transfer bulk. Test. You may find that you need several different types subdashboards for best results.

  You said 3ware, they have some good grades on their site, but don't believe it. With my 9650 that I found myself with only a couple of their recommendations-, I put the (simple) table for allocation size 256 k, nr_requests at 2 x the queue_depth and use the planner date limit. I had the habit for the Ext4 file system formatted with stride and stripe-width synced to the table and used the options large_files with fewer inodes (do not use the huge_files option unless you plan to have single VMDK files in the terabyte range). Use a cache of great reading in advance.

  Virtual machines use VMDK files in all cases except raw iSCSI LUN that they treat native disks. VMDK is easier to manage - you can make a backup by copying the file, you can move it to a PC and load it into another flavour of VMware, etc. There could be some features iSCSI to your San as a transparent migration but nothing for me. NFS has less chatter of Protocol if latency lower times to complete an operation. NFS is good to read and write a block of data, that's all it boils down to.

  UPS is good, but it won't help if something inside the machine explodes (UPS does nothing if the PC power supply goes down). If the RAID card has an option for a battery backup module, so it can contain some writings in memory and may end up the disk i/o after replacing the power supply. 3ware also limits the types of caching available if help is not installed, and you get just the right numbers with the module.

• help with the alignment of the e-mail

  Hi guys, looking for help with the alignment of an email Center.

  Sound centre lining up properly in the preview of dreamweaver and preview of mail chimp, but when I sent it to Gmail, it has left-aligned.

  Any ideas why this is?

  Keep in mind im a recruit in coding and Dreamweaver.

  I hope that the code below allows...

  Thank you!

  

  I don't know about you but display: inline-table; is not necessary.

• Help with the session variable PHP CS5.5 - Please

  Hi all

  I am needing a little help with the help of a session variable, and I hope someone can point me in the right direction.

  I created a PHP page that uses the Dreamweaver 'User authentication' feature and the basics of this works very well, to direct a user to the correct page depending on whether they are or are not a valid user. I want to customize the page 'user valid' with people, user name entered in the authentication of the user table... a seemingly simple task using a session variable, but I just seem not to be able to make it work!

  The generated code for the AU on page 1 is the following:

  <? PHP

  Validate request to connect to this site.

  If (! isset {})

  session_start();

  }

  $loginFormAction = $_SERVER ['PHP_SELF'];

  If (isset($_GET['accesscheck'])) {}

  $_SESSION ['PrevUrl'] = $_GET ['accesscheck"];

  }

  If (isset($_POST['txtfirst_name'])) {}

  $loginUsername = $_POST ['txtfirst_name'];

  $password = $_POST ['txtsurname'];

  $MM_fldUserAuthorization = "";

  $MM_redirectLoginSuccess = "member_update.php";

  $MM_redirectLoginFailed = 'login.php ';

  $MM_redirecttoReferrer = false;

  @mysql_select_db ($database_panto, $panto);

  $LoginRS__query = sprintf ("SELECT firstname, name OF web_access WHERE firstname = %s AND family name = %s",

  GetSQLValueString ($loginUsername, "text"), GetSQLValueString ($password, "text"));

  $LoginRS = mysql_query ($LoginRS__query, $panto) or die (mysql_error ());

  $loginFoundUser = mysql_num_rows ($LoginRS);

  If {($loginFoundUser)

  $loginStrGroup = "";

  If (via PHP_VERSION > = 5.1) {session_regenerate_id (true) ;} else {session_regenerate_id() ;}

  Declare two session variables and assign them

  $_SESSION ['MM_Username'] = $loginUsername;

  $_SESSION ["MM_UserGroup"] = $loginStrGroup;

  If (isset($_SESSION['PrevUrl']) & & false) {}

  $MM_redirectLoginSuccess = $_SESSION ["PrevUrl"];

  }

  Header ("Location:".) $MM_redirectLoginSuccess);

  }

  else {}

  Header ("Location:".) $MM_redirectLoginFailed);

  }

  }

  ? >

  First of all, the text highlighted in red above seems to be setting the session variable that I need. Is this correct?

  If so, what is the code that I need to put on page 2 to use this session variable? or

  I have to do something else on the page 1 to correctly assign the session variable?

  Would be very grateful for your expertise

  Mark

  It seems that you put the columns incorrectly in the user authentication server behavior. This is the SQL query that checks the credentials of the user:

  $LoginRS__query = sprintf ("SELECT firstname, name OF web_access WHERE firstname = %s AND family name = %s",

  GetSQLValueString ($loginUsername, "text"), GetSQLValueString ($password, "text"));

  You are looking for first name and last name, while you should look for the user name and password of the user.

  $_SESSION ['MM_Username"] is a session variable that stores the login name of the user. To use it in a page, all that is needed is the page start with session_start(). You can then echo the value to display.

  If you want to display the person's true name, you must create a recordset in the second page, use of $_SESSION ['MM_Username'] to search for the first name and the patronymic. Alternatively, you can change the code like this (I copied only part of it):

  $LoginRS__query = sprintf ("SELECT firstname, surname OF web_access WHERE firstname = %s AND password is %s",

  GetSQLValueString ($loginUsername, "text"), GetSQLValueString ($password, "text"));

  $LoginRS = mysql_query ($LoginRS__query, $panto) or die (mysql_error ());

  $loginFoundUser = mysql_num_rows ($LoginRS);

  If {($loginFoundUser)

  $loginStrGroup = "";

  $row = mysql_fetch_assoc ($LoginRS);

  $_SESSION ['full_name'] = $row ["FirstName"]. ' ' . $row ['name'];

  If (via PHP_VERSION > = 5.1) {session_regenerate_id (true) ;} else {session_regenerate_id() ;}

  Declare two session variables and assign them

  $_SESSION ['MM_Username"] = $loginUsername;

  $_SESSION ["MM_UserGroup"] = $loginStrGroup;

  You can then use $_SESSION ['full_name'] in a page which begins with session_start().

• need help with the Update statement

  Hello
  I received a question in a course and I tried my best to respond, and now my brain is giving. I would really appreciate help with the update statement. I don't mind if you do not validate a solution, a little nudge in the right direction would be really useful. I'll post that I got.
  
  THE QUESTION
  / * For these agents disabled on more than seven missions, change their date of deactivation of the first date of deactivation of all the agents that have been activated in the same year as the agent that you update currently.
  */
  
  I have it divided into parts, here is my select statement to agents disabled on more than 7 missions, which produces the deactivation_dates in the agents table that I want to update...

  SELECT
  s.deactivation_date
  FROM
  (
  SELECT
  a.deactivation_date,
  count(m.mission_id) as nomissions
  FROM
  agents a
  INNER JOIN
  missions_agents m
  on
  a.agent_id=m.agent_id
  GROUP BY
  a.deactivation_date
  ) s
  WHERE
  s.nomissions>7 AND s.deactivation_date IS NOT NULL

  .. .and the code for the first date of deactivation for each year of activation agent

  select 
  a2.deactivation_date
  from
  agents a2
  where a2.deactivation_date= 
  (
  select min(a.deactivation_date)
  from 
  agents a
  where to_number(to_char(a.activation_date,'YYYY'))=to_number(to_char(a2.activation_date,'YYYY'))
  )

  ..... I am not real to marry these two statements together in the Update statement. I can't extract each date of deactivation produced in the first select statement and their match against the first date of deactivation in the year they have been activated for the second select statement.
  
  Any help greatly appreciated... :))

  I began to wonder how things would :)

  user8695469 wrote:
  First of all why he chooses the date the earliest of all agents

  UPDATE  AGENTS_COPY AC /* (1) */
  SET     DEACTIVATION_DATE = (
  SELECT  MIN(AGS.DEACTIVATION_DATE)
  FROM    AGENTS_COPY  AGS
  ,       AGENTS_COPY AC /* (2) */
  WHERE   TRUNC(AGS.ACTIVATION_DATE,'YEAR') = TRUNC(AC.ACTIVATION_DATE,'YEAR') /* (3) */
  )
  

  He recovers as soon as the subquery has not been correctly set in the SET clause. It seems you are trying to update a correlated, but we are still having a conceptual shift. I have added a few comments to your code above and below will explain.

  (1): when you do a correlated update it is useful to the table alias that you did right here.

  (2): this table statement is not necessary and is the reason why the FIRST deactivation date is selected. The alias that you use (3) refers to THIS table, not the one defined in the update statement. Remove the line indicated by (2) in the FROM clause and a correlated update will happen.

  and secondly why is it to update each row, when I thought that I'm just the lines where the agents are disabled and missions > 7? Pointers on where I'm wrong would be very appreciated. (SQL = stupid query language!) :)

  user8695469 wrote: then why is it to update each row, when I thought that I'm just the lines where the agents are disabled and missions > 7? Pointers on where I'm wrong would be very appreciated. (SQL = stupid query language!) :)

  
  WHERE EXISTS
  (
  SELECT
  a.agent_id,
  count(m.mission_id)
  FROM
  agents a
  /* INNER JOIN AC ON AC.AGENT_ID = A.AGENT_ID */
  INNER JOIN
  missions_agents m
  ON
  a.agent_id=m.agent_id
  GROUP BY
  a.agent_id,
  a.deactivation_date
  HAVING
  count(m.mission_id)>7 AND a.deactivation_date IS NOT NULL
  )
  

  Once again this problem is similar to the question above that a correlation update doesn't work. Test existence of lines in an EXISTS subquery. Since your subquery is not related to the table that you are trying to update, it will be always return a line and, therefore, it returns true for EACH LINE in the AGENTS table. To limit the game to only agents > 7 missions results, you need to add a join condition that references the table in your update statement. I added one above (with comments) as a sample.

  I recommend you look over all material that you have associated with correlated subqueries, including documents that I posted above. This seems to be what you're having the problem more with. If you need me to explain the concept of correlated queries any better please let me know.

  Thank you!

• Need help with the ANSI Join syntax

  Version: 11.1.0.7
  
  I have my select statement that returns 3000 lines and looks like
  

  select ..
  from tab1 a,tab2 b,tab3 c
  where a.c1=b.c1 and
  b.c2 = c.c2(+)
  and ...
  group by
  ..

  I want to convert it to ANSI SQL, because it must be able to Hibernate, and the developer says that Hibernate include only ANSI SQL. I tried something like
  

  select ..
  from tab1 a INNER JOIN tab2 b
  ON a.c1=b.c1 
  LEFT OUTER JOIN tab3 c
  ON b.c2=c.c2
  where ...
  group by
  ..

  I felt bad and it turned out to be the same. It returns no rows. Please help with the correct syntax.

  I'm not sure, sorry, because it's certainly the ANSI equivalent to the non-ANSI.

  Would you have examples of queries and data that you can reproduce the problem with, and that we could analyze?

  Published by: Seanmacgc on July 15, 2009 12:48

  If there is no Clause WHERE conditions in the original that are included in the ANSI version of the query in the WHERE Clause for the EXTERNAL table itself joined, then that could transform the JOIN JOIN internally, that is, all the filters on the EXTERNAL joined table should be included in the JOIN predicate - IT (b.c2 = c.2 AND c.c3 = 'X').

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  Thank you in advance,

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  Hi, I'm fighting to open same mine, making a new software update