Hierarchical Oracle or MS SQL data

This query to MSSQL

SELECT  AreaID ,  
        AreaName ,  
        AreaSeq ,  
        ISNULL(( SELECT TOP 1  
                        t1.AreaName  
                 FROM   dbo.Area t1  
                 WHERE  t1.AreaSeq > dbo.Area.AreaSeq  
                 ORDER BY t1.AreaSeq  
               ), '') AS AppearBeforeArea ,  
        ISNULL(( SELECT TOP 1  
                        t2.AreaSeq  
                 FROM   dbo.Area t2  
                 WHERE  t2.AreaSeq > dbo.Area.AreaSeq  
                 ORDER BY t2.AreaSeq  
               ), -1) AS AppearBeforeSeq  
FROM    dbo.Area  
ORDER BY Area.AreaSeq; 

Gives this result

sqlseqnoqry.PNG

In Oracle 12 c


Create a Table Script:

create table Area(  
AreaID Number(5,0),  
AreaName Varchar2(50 char) ,  
AreaSeq Number(5,0)  
);

Insert data:

Insert Into Area Values(1,'Shastri Nagar', 0);  
Insert Into Area Values(3,'Saraswati Nagar', 1);  
Insert Into Area Values(2,'Sardar Pura', 2);  
Insert Into Area Values(5,'Sojati Gate', 3);  
Insert Into Area Values(4,'Polo Ground', 4); 

I tried with this hierarchical query but have no idea how to extract columns of rows child/Leaf;

SELECT    AREAID    , AREANAME    , AREASEQ    
FROM Area
START WITH AREASEQ  = 0    
CONNECT BY PRIOR AREASEQ  < AREASEQ    
ORDER SIBLINGS BY AREASEQ ;   

I use Oracle 12 c;

My Question is can I how ResultSet even return with Oracle query without using the service?

No need for the recursive query... just use an analytic function:

WITH box (AreaID, AreaName, AreaSeq)

(SELECT 1, 'Shastri Nagar', 0 double UNION ALL)

SELECT 3, 'Saraswati Nagar', 1 FROM dual UNION ALL

SELECT 2, "Sardar Pura", 2 FROM dual UNION ALL

SELECT 5, "Door of Sojati", 3 FROM dual UNION ALL

Select the OPTION 4, 'Polo Ground', 4 DOUBLE)

SELECT areaId, name of the area, AreaSeq

, lead (areaName) OVER (ORDER BY AreaSeq ASC) AS beforeAreaName

, lead (areaSeq, 1, -1) OVER (ORDER BY AreaSeq ASC) AS beforeAreaSeq

area

/

HTH

Tags: Database

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    Count (case when tech_type = 'B' then 1 end) tech_b,.

    Count (case when tech_type = "C" then 1 end) tech_c

    of (connect_by_root select link_id link_id,)

    the connect_by_root ID, tech_type

    of sample_data

    Start with parent_group_id = 0

    connect prior group_id = parent_group_id)

    Link_id group, id

    order by link_id, id;

    Same results, using SELECT... PIVOT

    WITH got_roots AS

    (

    SELECT CONNECT_BY_ROOT link_id AS link_id

    Id CONNECT_BY_ROOT ID

    tech_type

    OF sample_data

    START WITH parent_group_id = 0

    CONNECT BY PRIOR group_id = parent_group_id

    )

    SELECT link_id, tech_a, tech_b, tech_c

    OF got_roots

    PIVOT (COUNT (*)

    FOR tech_type IN ('A' AS tech_a

    'B' AS tech_b

    'C' AS tech_c

    )

    )

    Id ORDER BY link_id

    ;

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