high coherent reading during call analysis | TKProf output

Similar Questions

• the trace of tkprof output

  Hello
  
  I need clarification on the costing
  
  I have the following query

  DECLARE
          type array is table of t%ROWTYPE index by binary_integer;
          l_data array;
          l_rec t%rowtype;
  BEGIN
          SELECT
                  a.*
                  ,RPAD('*',4000,'*') AS PADDING1
                  ,RPAD('*',4000,'*') AS PADDING2
          BULK COLLECT INTO
          l_data
          FROM ALL_OBJECTS a;
          DBMS_MONITOR.SESSION_TRACE_ENABLE ( waits=>true );
          FOR rs IN 1 .. l_data.count
          LOOP
                  BEGIN
                          SELECT * INTO l_rec FROM t WHERE object_id = l_data(rs).object_id;
                  EXCEPTION
                    WHEN NO_DATA_FOUND THEN NULL;
                  END;
          END LOOP;
  END;

  tkprof output shows

  SQL ID: 78kxqdhk1ubvq
  Plan Hash: 3995659421
  SELECT * 
  FROM
   T WHERE OBJECT_ID = :B1 
  
  
  call     count       cpu    elapsed       disk      query    current        rows
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Parse        1      0.01       0.00          1         63          0           0
  Execute  72184      0.34       1.03          9         54          0           0
  Fetch    72184      0.46     157.98      81365     368657          0       71726
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  total   144369      0.82     159.02      81375     368774          0       71726
  
  Misses in library cache during parse: 1
  Optimizer mode: ALL_ROWS
  Parsing user id: 93     (recursive depth: 1)
  
  Rows     Row Source Operation
  -------  ---------------------------------------------------
        1  TABLE ACCESS BY INDEX ROWID T (cr=5 pr=11 pw=0 time=0 us cost=4 size=8092 card=1)
        1   INDEX UNIQUE SCAN T_PK (cr=3 pr=6 pw=0 time=0 us cost=2 size=0 card=1)(object id 83085)
  
  
  Elapsed times include waiting on following events:
    Event waited on                             Times   Max. Wait  Total Waited
    ----------------------------------------   Waited  ----------  ------------
    Disk file operations I/O                        3        0.00          0.00
    db file sequential read                     12464        0.07         92.18
    db file scattered read                      14590        0.07         63.10
  ********************************************************************************
  
  Now looking at stat line, does that mean the cost to retrieve one single record via unique index scan is 11 Physical block reads? The loop did fetch 72,726 rows and there were 81,375 physical block reads.
  
  
  *** 2012-01-27 10:18:51.978
  SELECT * FROM T WHERE 
  call     count       cpu    elapsed       disk      query    current        rows
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Parse        0      0.00       0.00          0          0          0           0
  Execute      1      0.00       0.00          0          0          0           0
  Fetch        1      0.00       0.00          0          5          0           1
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  total        2      0.00       0.00          0          5          0           1
  
  Misses in library cache during parse: 0
  Optimizer mode: ALL_ROWS
  Parsing user id: 93     (recursive depth: 1)
  ********************************************************************************
  
  DECLARE
          type array is table of t%ROWTYPE index by binary_integer;
          l_data array;
          l_rec t%rowtype;
  BEGIN
          SELECT
                  a.*
                  ,RPAD('*',4000,'*') AS PADDING1
                  ,RPAD('*',4000,'*') AS PADDING2
          BULK COLLECT INTO
          l_data
          FROM ALL_OBJECTS a;
          DBMS_MONITOR.SESSION_TRACE_ENABLE ( waits=>true );
          FOR rs IN 1 .. l_data.count
          LOOP
                  BEGIN
                          SELECT * INTO l_rec FROM t WHERE object_id = l_data(rs).object_id;
                  EXCEPTION
                    WHEN NO_DATA_FOUND THEN NULL;
                  END;
          END LOOP;
  END;
  
  call     count       cpu    elapsed       disk      query    current        rows
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Parse        0      0.00       0.00          0          0          0           0
  Execute      1      6.77      11.53        318      48684          0           1
  Fetch        0      0.00       0.00          0          0          0           0
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  total        1      6.77      11.53        318      48684          0           1

  The summary statistics above do refers to the execution of the whole of the PL/SQL block? That means that the 318 blocks read above referred to.
  
  Thank you very much

  In addition to the excellent response of Rene, you will want to note that

  SELECT *
  FROM
   T WHERE OBJECT_ID = :B1 
  
  call     count       cpu    elapsed       disk      query    current        rows
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Parse        1      0.01       0.00          1         63          0           0
  Execute  72184      0.34       1.03          9         54          0           0
  Fetch    72184      0.46     157.98      81365     368657          0       71726
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  total   144369      0.82     159.02      81375     368774          0       71726
  
  Misses in library cache during parse: 1
  Optimizer mode: ALL_ROWS
  Parsing user id: 93     (recursive depth: 1)
  
  Rows     Row Source Operation
  -------  ---------------------------------------------------
        1  TABLE ACCESS BY INDEX ROWID T (cr=5 pr=11 pw=0 time=0 us cost=4 size=8092 card=1)
        1   INDEX UNIQUE SCAN T_PK (cr=3 pr=6 pw=0 time=0 us cost=2 size=0 card=1)(object id 83085)
  

  This means that the cost to retrieve a record by making table T scan limited unique index is 11 physical blocks that includes 6 from the unique index of object_id. The execution plan has a hierarchical structure, and parents I/O, cost, schedule, etc. is a sum of measures for all of its children and the parameters of the operation itself. In the light of the foregoing, "ACCESS BY ROWID TABLE INDEX" operation is the operation of parent and the "INDEX UNIQUE SCAN" is the operation of the child. Statistics of the child are rolled in the statistics of the parent. This calculation of rail costs to retrieve a line are the same for each 71726 rows. So if you look at your original trace file (it's a good idea to understand the functioning of the trace file) you will see a stat to retrieve this record as noted in the report of tkprof.

  To retrieve the 71726 lines it cost 0.82 s CPU and time elapsed 159,02 dry. There was 368774 logical block IO 81375 were block physical readings.
  Note the CPU and wait for the temporal offsets.

   Elapsed times include waiting on following events:
    Event waited on                             Times   Max. Wait  Total Waited
    ----------------------------------------   Waited  ----------  ------------
    Disk file operations I/O                        3        0.00          0.00
    db file sequential read                     12464        0.07         92.18
    db file scattered read                      14590        0.07         63.10
  ********************************************************************************
  

  Thus to retrieve these files altogether, they were physical i/o 12 464 'db file sequential read' taking 92,18 dry (note e/s physical does NOT block!) and e/s in physics 14 590 'file db scattered read' taking 63,10 sec, each contributing to the wait time. "the db file sequential read" is usually a single e/s block, it's index reading. 'db file scattered read' is an e/s multiple blocks read and in this case, it represents the blocks read from table to retrieve a line. It seems that every row of the table t occupies more than one block.

  HTH,

  Mich

  Published by: Mich Talebzadeh on January 27, 2012 06:01

• ID package already in use, an error has occurred during the recording of output ' 1.1.0"to the database.

  Hello

  I currently have an application called "Apa Doanya' (id 33020976) for BB 7 and below. Now, I created another version of it for BB10. To publish this version BB10, I created a new application named also "Apa Doanya' (id 46317888), download the file bar, but not yet to introduce the new application for review. Later, I changed my mind, I want to release this BB10 version under the name of my current application so that I can keep the sides and the current download figures. So in my application, I added a new version, download the folder bar and increment the version 1.1.0. But I got an error when recording on step 5, he said:

  Package already in use ID
  An error has occurred during the recording of output ' 1.1.0"to the database.

  I tried several times but no luck. What has caused this? Is - it because I already download the bar file to another application (id 46317888)? Just to be sure, I remove bar app 46317888 file and download a dummy cod file (so that the application can be saved). Then repeat the previous step (add a new version and so on) but I still have the same error.

  Really appreciate any help.

  -Hammemi - D

  Hi erik,
  Thanks for reminding me

  Yes, the problem is now RESOLVED. It was, I think, a bug/error on their part (support of the seller) so they erased the package id (I quote: "the package ID has been deleted.").

  Thank you very much :-)

• Keyboard of blackBerry Smartphone accessing during calls that I do

  I just got my Blackberry Storm yesterday because my Palm LifeDrive (which I liked) has a cracked screen and I wanted to migrate to an integrated phone/PDA solution.  My previous phone was a LG Dare I loved also.  It's just for the context.  Problem: when I call I want the pad to display by default.  It is heavy to go button options and then try to press the option "Show keyboard" during a call.  One of the default options that displays for "Speaker" when I make a call is annoying more useful because I accidentally turned on the speakerphone during a call several times.  Is there a way to change these options?  I searched these forums and the web, but couldn't find any doubt even closer, if I used probably just the wrong search terms.  Thanks for any help in this sense - I don't really like most of the things on this phone and read these forums helped me already.

  When phone mode, there is a small keyboard at the bottom left icon - you can press that instead of having to hit BBmenu > keyboard.  But apart from that, I don't think there is a way to have the keyboard default upward.

  As speaker, you should study an application similar to TalkLock or StormSlider they lock the screen during calls preventing the presses of the screen.

• BlackBerry Storm 9530 smartphones stops during calls

  Hello

  My first Blackberry, it's a Storm 9530, and everything seems as it should be-except that it will completely die during calls. Not all the time, but most of the time. (about 4 to 5 times)

  Sometimes I hear a noise from the Bzzz electronic, then the red light comes on, I think I can see an error screen (briefly - not backlit)-then a white screen, then a small clock-face, then the start of Blackberry screen and the loading bar. Takes a few minutes to load, then it's as if nothing happened - until I make the next call.

  I have the Blackberry Desktop Manager on my Macbook. Tells me that newer software is available - but never successfully downloading it, often crashing out of it during the relief phase. The same software on my Windows PC won't even find my phone (even if it appears in the my computer window).

  I read in some messages in the forum, but did not find any problems.

  Here's the bad news: Yes, I bought it on ebay!  Unused and unlocked. I accept full responsibility for my actions! Oh!

  I'm in the United Kingdom using a Virgin SIM card. I realize this will give me limited use BB facilities - but, quite frankly, at this point even end a call would be a joy!

  It comes with a 12 month warranty, but before I send again, I thought I'd post on the forum in case it was a problem with an easy solution. Or any patch.

  Thanks in advance, L

  Storm 9530

  IMEI: 352110.03.209148.1

  PIN: 306ECC5F

  Carrier: unlocked (originally from T-Mobile) now on a SIM of Virgin UK

  OS: v5.0.0.154 (Platform 4.2.0.21)

  Well, I'm not really a superstitious person - but I hesitate to hit the solved button in case I have any jinx.

  But it seems that the software update has resolved the problem. So far, so good, anyway. Phone has not stopped since the update.

  Think I'll wait one more day, do a little more of screams and then click resolve.

  On a different note, which can be of interest for all Virgin UK customers: Virgin were to launch their friendly service of BB on January 4 this year, but it has been delayed. Currently, they only provide service BB for the curve and the torch (that they provide on contract). The new service would be welcome all BB phones which users on their own and use the Virgin fare. This year, the latest schedule come into force this service is end of February / beginning of March.

  I cross my fingers. So far, I have a smartphone that can be used for phone calls and texts! Tried to go back to my old Sony Ericsson - at least I could send and receive MMS.

  Enjoy, L

  Storm 9530

  IMEI: XXX

  PIN: XXX

  Carrier: unlocked (originally from T-Mobile) now on a SIM of Virgin UK

  OS: v5.0.0.328 (Platform 4.2.0.128)

  EDIT: Personal information such as PIN & IMEI for your safety are prohibited. Please see the guidelines of the user   under article ""be sure to." "

• read a call to API WS

  Friends of HELO, me and API to your screen once more

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  Dim wsCall As New ServiceManagerClient ("BasicHttpBinding_IServiceManager")
  Dim wsCallRetrieveReq As New CallRetrieveRequest
  Dim wsCallRetrieve As New CallRetrieveResponse

  wsCallRetrieveReq.sDatabase = "unitronics.
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  wsCallRetrieveReq.sLoginUserID = "ialvarez".
  wsCallRetrieveReq.sLoginPassword = "ialvarez".
  wsCallRetrieveReq.lEntityRef = "400145".

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  txtCallNumber.Text = wsCallRetrieve.ToString

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  mmmmm, I think I'm wrong

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  and how he can fix this problem if it affects database performance?

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  Aman...

• How to activate Adobe Reader software call Webserices

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• Do UPDATE statement in line for coherent reading?

  Hi all
  I have a question for the update statement, do UPDATE statement 17Etat for coherent reading? As a statement of pure update: update t set col1 = col1 * 20;
  
  I'll check with the following steps:
  ######################################
  Preparation: Tables Create1:
  ######################################
  t_update_old (col1 int, col2, col3 float int primary key (2000));
  
  ######################################
  Preparations: generate data for two tables:
  ######################################
  insert into t_update_old
  Select seq_1.nextval, seq_1.nextval, chr (seq_1.nextval) of double;
  for x in 1.17 loop
  insert into t_update_old
  Select seq_1.nextval, seq_1.nextval, chr (seq_1.nextval) of t_update_old;
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  ######################################
  Description of the run
  ######################################
  Create 2 sessions: S1 & S2
  Session S1 updates t_update_old using the following statement:
  Update t_update_old set col2 = col2 * 20;
  
  S2 session will update t_update_old for a specific line.
  Update t_update_old set col2 is + 1 col2 where col1 = 100000;.
  
  The two session are performed in the following order:
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  Point in time 3: Action update the 100000th ranks in t_update_old by S2 is finished, validation of the transaction in S2 and S2 is finished.
  Point of time 4: update t_update_old of S1 with the 100000th line in t_update_old.
  Point 5 of time: S1 is finished.
  
  ######################################
  The Question is:
  ######################################
  What is the result of the following statement:
  Select col2 where col1 = 100000;
  
  100 000 * 20 = 2 000 000
  or
  (100 000 + 1) * 20 = 2 000 020

  By default in Oracle, each SQL statement see data if it exists when begins the execution of SQL statements and the READ COMMITTED isolation level, the effects of each committed transaction are taken into account by statements that start other transactions or validated. The answer is therefore 2 because I understand that the transaction in S2 is committed before start of query in S1.

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