How do for lines double in the outbuildings of columns
Hello
I have a table like this:
ID customer date_01 date_02 date_03 date_04
-----------------------------------------------------------------------------------------------------
1 Smith, Peter 01/01/2000 03/28/2001 12/01/2002 09/13/2004
2 Miller, John 09/12/2004
3 Brown, Steve 03/11/2009-12/12/2010
4 Hanson, Pete
I need a query that returns a set of results as follows:
id date
---------------------------------------------------------------------------
1 Smith, Peter 01/01/2000
1 Smith, Peter 28/03/2001
1 Smith, Peter 01/12/2002
1 Smith, Peter 13/09/2004
2 Miller, John 09/12/2004
3 Brown, Steve 11/03/2009
3 Brown, Steve 12/12/2010
If all columns date (date_01 to date_04) have the value NULL, then the line should appear not at all. The lines should get duplicated in the dependence of the amount of filled DATE columns
(date_01 to date_04).
I use Oracle 10 g - any help will be appreciated.
Rgds
J.
In 10g...
WITH qry1 AS
(SELECT 1 id, 'Smith, Peter' customer, TO_DATE('01/01/2000','MM/DD/YYYY') date_01, TO_DATE('03/28/2001','MM/DD/YYYY') date_02, TO_DATE('12/01/2002','MM/DD/YYYY') date_03, TO_DATE('09/13/2004','MM/DD/YYYY') date_04 OF DOUBLE UNION ALL)
SELECT 2, 'Miller, John', TO_DATE (December 9, 2004 "," MM/DD/YYYY ""), NULL, NULL, NULL FROM DUAL UNION ALL
SELECT 3, 'Brown, Steve', TO_DATE (March 11, 2009 "," MM/DD/YYYY ""), TO_DATE (12 December 2010 "," MM/DD/YYYY"), NULL, NULL FROM DUAL UNION ALL
SELECT 4, "Hanson, Pete", NULL, NULL, NULL, NULL FROM THE DOUBLE)
SELECT *.
Of
(SELECT id,
customer,
CASE WHEN lvl = 1 THEN date_01
ONCE lvl = 2 THEN date_02
ONCE lvl = 3 THEN date_03
ONCE lvl = 4 THEN date_04
END dates
OF qry1, (SELECT LEVEL lvl
OF the double
CONNECT BY LEVEL<>
)
WHERE the dates IS NOT NULL
ORDER BY 1;
OUTPUT:-
=======
Smith, Peter 1 January 1 00
1 Smith, Peter 28 March 01
1 Smith, Peter 1 December 02
1 Smith, Peter SEPT. 13.-04
2 Miller, John December 9 04
3 Brown, Steve 12 December 10
3 Brown, Steve 11 March 09
Thank you
Ann
Tags: Database
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