How do you return a group expression of REGEXP_SUBSTR?

I have the string USERSbthompsonDESKTOP, and I want to return to "bthompson.

Something equivalent to this Perl code:
my ($user) = $string = ~ /USERS(.+?) OFFICE;
Print "$user\n";
The output is "bthompson.

-It does not work...
Select regex_substr ('USERSbthompsonDESKTOP ',' USERS(.+?)) OFFICE ') twice;
Returns: USERSbthompsonDESKTOP

I tried to add a backreference, but do not know how it works.

Select regexp_substr ('USERSbthompsonDESKTOP ',' USERS(.+?)) OFFICE ', '\1') twice; -Returns the first expression?
Returns:
ORA-01722: invalid number
01722 00000 - "invalid number."
* Cause:
* Action:

Select regexp_substr ('USERSbthompsonDESKTOP ',' USERS(.+?)) DESKTOP\1') twice;
Returns null.

Is there a way to return only "bthompson' of this string?

You were close.
Using REGEXP_REPLACE instead of REGEXP_SUBSTR and your query will work.

Tags: Database

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