How does Firefox read-ahead?

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• Oracle Read-Ahead: not the same as looking forward, Yes?

  Hello
  
  I tried to understand the systems Oracle Read-Ahead, and I think I understand how it works, but I would like to say that I'm not mistaken.
  
  
  What I managed to understand in the Oracle documentation, the Oracle read-ahead mechanism is especially used for sequential access to data blocks. For example, to perform operations such as table scans.
  
  In this case, Oracle will for example use a physical operation called scattered read.
  Read the straggling, in turn, is configured in the ini. ORA parameter a name like db_multiblock_read_count. A multiblock read count of 60, will make the scattered read read operation 60 blocks of sequential data from the drive, starting with the data block that was requested in the operation.
  
  From what I understand, this is the basis of the read-ahead mechanism. It is use mult block transactions reading data rather than the simple operations of bock.
  
  If what I've said so far is correct. There are two things I'd like to know:
  
  1.
  These 60 blocks read by the read sctarred. They go directly into the database buffer cache? Or are they loaded everything first in to a lower level cache, as a scattered read cache?
  
  For example, if the table scan requested page 1. And the read operation recovered scattered pages from database 1 to 60. I guess that this single page 1 would be transferred to the buffer cache. More later when the requested table to page 2 scan, the cache buffers would recover the scattered read cache this page in the buffer cache. Or is it completely wrong? And when scattered reading gets 1 to 60 pages. It automatically transforms the data pages in the buffer cache in random positions of the main buffer?
  
  
  2.
  With Oracle read-ahead, table scans and other such physical operations always incur straggling expected read periodically. For example, every 60 pages, scanning table facing in another scattered read wait OK?
  
  3.
  Read-ahead in oracle anticipates a physical operator database page needs a specific point in time, Yes? The following does not occur:
  While the analysis of the table is currently on page 50, with another 10 pages more left in the database buffer, background processes decides it's a good idea ask to get another 50 pages of data yet. So that the thread of forground treatment table scan never has a stop in reading e/s.
  
  It is of to future research, and it is not a function of Oracle, is it?
  
  Thank you for your understanding.
  
  -------------------
  
  I did a few tests where, although the size of the table to a data transformations are still the same (1 GB) but the time I take to make my exit from the source table varies. The processing time for each record has increased considerably from one test to the next. But I noticed that the time-out of the transformation of data remains constant, although the time cpu increases considerably. The increase in time CPU means that the extraction of time until that next buffer was reduced, which would give more time for the system to look forward. Eventally I could have done the time so much CPU, if read IO was executed in anticipation, that it would be possible for PLAYBACK of theortically waiting time at 0. I know is not going to happen. So I had just be certain of how early reading works.
  
  
  My best regards.

  sono99 wrote:
  Hello

  I tried to understand the systems Oracle Read-Ahead, and I think I understand how it works, but I would like to say that I'm not mistaken.

  What I managed to understand in the Oracle documentation, the Oracle read-ahead mechanism is especially used for sequential access to data blocks. For example, to perform operations such as table scans.

  In this case, Oracle will for example use a physical operation called scattered read.

  
  Read the straggling, in turn, is configured in the ini. ORA parameter a name like db_multiblock_read_count. A multiblock read count of 60, will make the scattered read read operation 60 blocks of sequential data from the drive, starting with the data block that was requested in the operation.

  From what I understand, this is the basis of the read-ahead mechanism. It is use mult block transactions reading data rather than the simple operations of bock.

  Don't know if you wanted to read several blocks at the same time or the features of the cache before reading provided by some storage devices. But it seems to me you speak CRBM (Multiblock read County) and no cache of early reading provided by storage vendors.

  If what I've said so far is correct. There are two things I'd like to know:

  1.

  
  These 60 blocks read by the read sctarred. They go directly into the database buffer cache? Or are they loaded everything first in to a lower level cache, as a scattered read cache?

  For example, if the table scan requested page 1. And the read operation recovered scattered pages from database 1 to 60. I guess that this single page 1 would be transferred to the buffer cache. More later when the requested table to page 2 scan, the cache buffers would recover the scattered read cache this page in the buffer cache. Or is it completely wrong? And when scattered reading gets 1 to 60 pages. It automatically transforms the data pages in the buffer cache in random positions of the main buffer?

  If my MBRC is 60 and none of the blocks are in a buffer and size of the table is more than 60 blocks then together 60 blocks would be transferred to the buffer cache. There was nothing called scattered read cache in the architecture of Oracle.

  2.
  With Oracle read-ahead, table scans and other such physical operations always incur straggling expected read periodically. For example, every 60 pages, scanning table facing in another scattered read wait OK?

  Yes file db scattered read wait event would mean that an another physical i/o was instituted for the extraction of blocks next records.

  3.
  Read-ahead in oracle anticipates a physical operator database page needs a specific point in time, Yes? The following does not occur:
  While the analysis of the table is currently on page 50, with another 10 pages more left in the database buffer, background processes decides it's a good idea ask to get another 50 pages of data yet. So that the thread of forground treatment table scan never has a stop in reading e/s.

  It is of to future research, and it is not a function of Oracle, is it?

  Yes, I don't think so it is a feature of Oracle, but provides some storage provider. It is also known as Read ahead.

  Thank you for your understanding.

  -------------------

  I did a few tests where, although the size of the table to a data transformations are still the same (1 GB) but the time I take to make my exit from the source table varies. The processing time for each record has increased considerably from one test to the next. But I noticed that the time-out of the transformation of data remains constant, although the time cpu increases considerably. The increase in time CPU means that the extraction of time until that next buffer was reduced, which would give more time for the system to look forward. Eventally I could have done the time so much CPU, if read IO was executed in anticipation, that it would be possible for PLAYBACK of theortically waiting time at 0. I know is not going to happen. So I had just be certain of how early reading works.

  My best regards.

  I don't understand your last paragraph.

  Concerning
  Anurag

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  Hi Karine,.

  I was absent for the whole of last week, so I only read your answer today.

  The Wavelet Transform Daubechies4.vi you mentioned is indeed already included in LabVIEW (minimum full version, which is what offers Student Edition). From what I see, it's a very simple implementation of the transformation that the VI I mentioned in my post above. To better understand how it works, read first to the top of its help file (use ctrl + h), then open the VI by double-clicking on it to see the block diagram. From there, you will see that this VI essentially multiplication of matrix of coefficients db4 to the signal. That being said, we can go back to your questions:

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  I hope this helps.

  Kind regards

  Yodha

  OR Singapore

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  Rob Brown - Microsoft MVP<- profile="" -="" windows="" expert="" -="" consumer="" :="" bicycle=""><- mark="" twain="" said="" it="">

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