How read information calculate the number of bytes in a megabyte?

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• How to calculate the number of bytes

  There is a general algorithm that calculates the total number of bytes in a pl/sql record?

  And dates may take up to 7 or 8 bytes (for data) with the data if they are a column on a table or not in function (this is to with internal C code date types)...

  SQL> select dt, dump(dt) from xx;
  
  DT
  --------------------
  DUMP(DT)
  ----------------------------------------------
  18-FEB-2011 15:00:35
  Typ=12 Len=7: 120,111,2,18,16,1,36
  
  SQL> select sysdate, dump(sysdate) from dual;
  
  SYSDATE
  --------------------
  DUMP(SYSDATE)
  ----------------------------------------------
  18-FEB-2011 15:01:04
  Typ=13 Len=8: 219,7,2,18,15,1,4,0
  
  SQL>
  

• VISA read where you don't know the number of bytes?

  I work with a VISA resource via the USB port that reads in the results of printf (% lu % TSP %d)) of a microcontroller. These results are as ASCII numbers, their length in bytes is unknown. Numbers * should * be not more than 3 digits, but I can't know that for sure. Reading VISA won't let me the number of bytes unwired, so should I join just a high constant let him? Or is there a better way?

  1. do you have the microcontroller send a character to end of line (0xA on the ASCII table) at the end of the printf.

  2. turn the stop of the session VISA character and the value it is 0xA.  You may need to perform this task via the VISA property node.

  3. playback VISA to read more bytes than you tell never expect to get.  VISA playback will stop reading when it detects the termination character (End Of Line).

• How to calculate the number of days/weeks/months between 2 dates?

  Hello
  
  I would like to know how to calculate the number of days/weeks/months between 2 dates in OBIEE 11 g, for example, I have 26/05/2013 and 19/05/2013, then I want to get 7 days.
  
  Thank you!
  Jamie

  Hi Jamie,

  Through this links...

  http://www.bravesoft.com/blog/?p=682
  http://twobiee.blogspot.in/2012/01/working-with-date-differences.html

  Mark as correct it allows u...
  Thank you...

• How to calculate the number of days between dates

  How can I determine the number of days between 2 dates? Say today and 10/07/46
  
  Thanks Bob

  You could do it like this:

  Photoperiod var = 1000 * 60 * 60 24; number of ms in a day

  var today: Date = new Date();

  var every time that: Date = new Date (1946,6,10);

  var diff = Math.floor((today.getTime()-whenever.getTime())/dayLength);

  trace (diff)

• Calculate the number of fringes

  Is anyone know the feasibility of the use of the Machine Vision or LabView to calculate the number of fringes in each region? (Attached image). I want to count how many white line on each region. For example, on the attached picture, there are about 6 regions and each region will display the number of the white line in their own region. For information, I have V8.5 of LabView and NI Vision Assistant V8.5. Please, give me some ideas on how to solve it.

  Thank you.

  Farid

  Check this box

• The number of bytes is the data type of "pixel"?

  I'm relatively new to use Pixel Bender to process audio data, so I'm sorry for my lack of understanding of what follows.

  I had a question about the data types 'pixel' and 'image' Pixel Bender.

  I'm trying to understand code Kevin Goldsmith has written for his mixer 2 channels of audio and there seems to be a gap between the amount of data sent to the shader of PB, and the amount received when the buffer is sent to her for treatment.

  Here is the link to the code:

  http://blogs.Adobe.com/Kevin.Goldsmith/2009/08/pixel_bender_au.html

  At the top of the code, it says a "BUFFER" of 2048 constant:

  private public static var Buffer_size : uint = 0 x 800;

  Then, in the processSound() function, he implemented an byteArray with a size of 16 384 bytes:

  shaderBuffer. length = BUFFER_SIZE * 2 * 4;     <---(échantillons stéréo 2048 * 2 * 4 octets/échantillon)

  However, I am confused about the part where it defines a hypothetical image and sends the data to the shader:

  effectShader. data ["source"] . width = BUFFER_SIZE / 1024;     <---(2048 / 1024 = 2)

  effectShader. data ["source"] . height = 512 ;

  From the code above, one can easily see that the size of the image is only 1024 "pixel" (2 * 512), and on the receiving end there is a "image.4" of variable entry expected to receive.  So far, I was under the assumption that a data type "image4" consists of a variable amount of pixels (determined by the size of the image that is food inside), each composed of 4 layers of color of 1 byte.  In this logic, each pixel in a data type "image4" should consist of 4 bytes.  Now, let's do the math: 4 bytes * 1024 pixels = 4096.

  4096 is not equal to 16 384!

  How can feed you a 16 384 'byteArray' bytes in a variable "image4" of 4096 bytes?

  I'm sorry to seem presumptuous to the explanation above, but I can not understand what is happening here!

  The number of bytes is a 'pixel' in PB?  He holds float or integer values or both?

  I've scoured the web to find these answers, but nothing helps!  Maybe I'm off the mark with my current understanding of the pixels and images in PB, but I need to understand this before I can move with the application that I do.

  I am very grateful of any advice or information that someone can give.

  Thank you

  Matt

  This is the Pixel Bender Language Reference:

  "pixel1: represents the value of a single channel of an image." The name distinguishes this
  single element pixel of a pixel which contains several channels. The pixel values are
  considered as 32-bit floating-point numbers. »

  32 bits = 4 bytes

  If a channel is four bytes rather than that you have accessed. If this should explain the difference.

• I need my files to open in the monitor # 2 I usually have some important information about the number of monitor 1. I need the files to alternate when they are open. One in 2, then one 1.

  I need my files to open in the monitor # 2 I usually have some important information about the number of monitor 1. I need the files to alternate when they are open. One in 2, then one 1.

  Kind regards

  How it works is usually the application (explorer.exe is an application) in question is open about everything that monitor his last (final) session was closed the.  Not all applications have this built-in memory, but most do.

  I don't think that even something TO manage multiple monitors (this is what it was built for) will do what you are wanting.  ;-)  I see no way of programming of this type of automation.  ;-)

  https://www.DisplayFusion.com/

• Calculate the number of days remaining until the next anniversary. Help, please!

  Hi guys,.

  I'm new to the forum and to the development of BB. So please do not judge harshly if the answer to my question seems obvious.

  I need to calculate the number of days until the next birthday (taking into account any valid birth date)

  After looking at the API and the forum search, I realized that I could

  calculate the difference between two dates in milliseconds and then divide the delta of the value of a day in milliseconds. That is to say:

  birthdayCalendar.set (Calendar.YEAR, those);

  Date1 = birthdayCalendar.getTime () .getTime ();

  date2 = System.currentTimeMillis ();

  Delta = date1 - date2

  numOfDays = delta\DateTimeUtilities.ONEDAY

  Here's my question. How do I create a valid date1 what about leap years?

  Maybe there's a better way to solve this problem?

  Any help is greatly appreciated.

  I agree that the determination of the number of days between today and Feb. 29 could be a little difficult, if it is not a leap year.  I suspect that the calendar has a certain built-in mechanism to compensate for this, but your solution to choose a date is better.

  DST has a role to play, and Yes, the calendar makes up for it.  Let us take two dates, for example (before DST) March 1 and June 1 (after the DST).  If you take a calendar and set the same hour, minute, etc., they are all the same except for dates, then subtract one from the other, and then divide by the number of milliseconds in 1 hour, you calculate the number of hours between the same time on two different days.  You will find that it is not a multiple of 24 hours - because there is actually an hour less than the number of days since the clocks move forward (in the northern hemisphere anyway...),

  In your case, you are not calculating the number of hours, you calculate the number of days.  But you will be dividing by [24 * (time in an hour)].  If you take [23 * (time in an hour)] and divide it by [24 * (time in an hour)], using arithmetic on integers, you will end up 0.  The easiest to get around this, who also works for the end of the DST too, is to simply add one hour to the date before the division.

  Hope that makes sense...

• How can I know the number of columns in a TYPE?

  Hello

  If we have a guy like below

  type vc_arr2 is table of the varchar2 (32767) index directory.

  How can I get the number of columns?

  Minoo.TK wrote:

  Hello

  If we have a guy like below

  type vc_arr2 is table of the varchar2 (32767) index directory.

  How can I get the number of columns?

  It is a type of associative array definition. A table has no columns. It is a collection of elements (variables or values). An array location is usually called a cell.

  The standard method Count() exist in Oracle for all table types.

  As for the definition of the table, as in structures, variables make the table contain - associative array is defined in the PL/SQL code and does not exist in the layer of metadata to the database as a new user-defined type. For the definition, you must read the declaration of PL/SQL defining the table.

  Note that there is very rarely the need for associative tables in PL/SQL - 99% of the time they are used without any idea as to what as a table associative is also.

• REQ: script to calculate the number of months

  Looking for a script that will calculate the number of months between 2 dates (to 2 decimal points)

  or if there is a way to make a calculation of the number of months

  for example: if I go to google and say 75 days - months, it returns a value of 2.46

  That's what I'm looking for

  If anyone can help?

  with a calculation of date or number calculation?

  I tried # days / 365 x 12 but there is no decimal places.  right guard rounded up/down

  As mentioned in a month, the days are not constant throughout the year and change formula 28-31 days. How are you calculating the decimal value of the month?

  A year has 365 days, if she did then there would be no need for leap years and centuries jump.

  Calculation of a variable with the result of a calculation method is set to decimal.

  cDateFormat = "d-mmm-yyyy";
  var cStartDate = "January 1, 2000;
  var oStartDate = util.scand (cDateFormat, cStartDate);
  oStartDate.setHours (0, 0, 0, 000);
  var cEndDate = "January 15, 2000;
  var oEndDate = util.scand (cDateFormat, cEndDate);
  oEndDate.setHours (0, 0, 0, 000);
  nDiff var = oEndDate.getTime () - oStartDate.getTime ();
  Console.println ("end date:" + cEndDate);
  Console.println ("start date:"+ cStartDate ");
  Console.println ("difference in milliseconds:" + nDiff);
  Console.println ("difference in seconds:" + nDiff/1000);
  Console.println ("difference in minutes:" + nDiff / (1000 * 60));
  Console.println ("difference in hours:" + nDiff / (1000 * 60 * 60));
  Console.println ("difference in days:" + nDiff / (1000 * 60 * 60 * 24));
  Console.println ("difference in weeks:" + nDiff / (1000 * 60 * 60 * 24 * 7));
  Console.println ("difference over the years:" + nDiff / (1000 * 60 * 60 * 24 * 365.2524));
  Console.println ("difference in months:" + nDiff / ((1000 * 60 * 60 * 24 * 365.2524) / 12));  12 months in a year;

  End date: January 15, 2000
  Start date: January 1, 2000
  Difference in milliseconds: 1209600000
  Difference in seconds: 1209600
  Difference in minutes: 20160
  Difference in hours: 336
  Difference in days: 14
  Difference of weeks: 2
  Difference in years: 0.0383296591617194
  Difference in months: 0.45995590994063273

  Several turncate the decimal values scirpts because keeping them may not meet the need of specific calculation. You know that there are methods to roud until the next iniger, round.5 to the top and turnacate to the lower intiger.

  According to the date of departure, the values may be different:

  For a start date of February 1, 2000, 75 days would be 1,810 months but for a start date of 1 February 2001 75 days becomes 1,838 since the number of days of changes of February 29 to 28 and the number of days for the month of fractions varies from 26 to 27.

• calculate the number of minutes

  Hello citizens of oracle,
  
  I have a situation where I have to calculate the number of minutes took to run the package. I've seen proc_log that will give me proc_name (give me the name of the proc), START_DT (which gives the time when the process began exactly) and EXEC_TIME (gives having plenty of time each process taken in minutes and seconds). So I need to make the sum of the column EXEC_TIME. Please help me how to do this.
  
  Thanks for the help.
  
  Sam

  So, how do you intend to group on a varchar2 column? Can you change the view to the EXEC_TIME in an interval instead? Is even more logical design-wise.

  Please post some examples of data so I can get an idea of the format for the varchar2 column.  Want to most likely to convert it to an interval to summarize time exec, or converting varchar2 int to exec_time in a few seconds, then convert minutes to maintain granularity.

  NM, I see here the format, you are def going to need to set this view if you want to match the runtime.

  You are with your format makes it incredibly hard perform such an easy task. Change this EXEC_TIME column in the view to an int of total of seconds or milliseconds of delay of performance or do this column, an INTERVAL DAY TO SECOND data type. Once you do this, you can do a 'SELECT sum (exec_time) FROM WHERE XX... »

  Published by: TheDudeNJ on November 12, 2009 13:48

  Published by: TheDudeNJ on November 12, 2009 13:49

  Published by: TheDudeNJ on November 12, 2009 13:51

• How can I determine the number of contacts that I have

  How can I determine the number of contacts that I currently have on my iphone

  I don't know of a way on the iPhone, but if you have a Mac, you can go to the Contacts (platform) app and scroll to the bottom where you will find the total.

  Same for iCloud.com on your browser, go to the app, scroll down.

• How can I find the number of pixels is in my photos of the ipad? I sell on ebay and they have new requirements for the photos. 500 pixels on the longest side. Is it possible to increase the pixels on already took pictures?

  How can I find the number of pixels is in my photos of the ipad? I sell on ebay and they have new requirements for the photos. 500 pixels on the longest side. Is it possible to increase the pixels on already took pictures?

  See if this application works for you > https://itunes.apple.com/us/app/image-size/id670766542?mt=8

• I have an iPhone 6 and use Verizon as my server. How can I increase the number of rings until it goes to voicemail?

  I have an iPhone 6 and use Verizon as my server. How can I increase the number of rings until it go to voicemail?

  You can not. There is no adjustment to make on a phone. In fact, it is not based on the number of rings, it is a problem of synchronization based on the parameters of the call. You can contact Verizon to see if they can increase at that time here, but even if they can, it won't be much, only a few seconds if they do at all.