How to display the image of wamp if data type I use is blob?

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  I need to display the image based on the values retrieved from the base.
  
  For example, if the value of a column is 1, then I need to be to display an image within a table. Help, please. Thank you.
  
  Published by: 853213 on April 18, 2011 21:50

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  If you want to add custom images
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  I was New in aid of BB.Plz.

  I am facing the problem is, I go get web Image.

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  import java. IO;
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  Take a look at these classes:

  import net.rim.device.api.system.Bitmap;
  import net.rim.device.api.system.EncodedImage;
  import net.rim.device.api.ui.image.Image;
  import net.rim.device.api.ui.component.BitmapField;
  

  This code should do you need:

          EncodedImage image = EncodedImage.createEncodedImage(data, offset, length);
          BitmapField bitmapField = new BitmapField();
          bitmapField.setImage(image);
          add(bitmapField);
  

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• How to retrieve and display the image on screen stored in pim...

  Hello world

  Can anyone tell how to recover the image store in pim and then display it on the screen

  See the code below. I just copied it from PIM API doc

   import java.io.IOException;
   import javax.microedition.pim.Contact;
   import javax.microedition.pim.ContactList;
   import javax.microedition.pim.PIM;
   import javax.microedition.pim.PIMException;
   import javax.microedition.pim.PIMItem;
   import net.rim.device.api.io.Base64InputStream;
   import net.rim.device.api.io.Base64OutputStream;
  
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       public void setPhoto() throws IOException
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           byte[] photoEncoded = Base64OutputStream.encode( photo, 0,
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       public byte[] getPhoto() throws IOException
       {
           if( _contact.countValues( Contact.PHOTO ) > 0 ) {
               byte[] photoEncoded = _contact.getBinary( Contact.PHOTO, 0 );
               return Base64InputStream.decode( photoEncoded, 0,
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           } else {
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       private static byte[] getSamplePhoto()
       {
           // return the raw bytes of the photo to use
       }
  
       public static void main( String[] args ) throws Throwable
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   }
  

  .

• How to display an image from the file in the database

  I want to be able to display an image from the file that I have stored in a database. In the database, the image is store as a file with numbers. When I go to display only the sign of an image appears. I want to be able to display the image not the symbol for numbers of the image or file. I know I'm close I just can't understand what I'm messing, to get the image to display.

  Here is the code:

  <? PHP require Connections/Connections.php"?" >

  <? PHP

  session_start();

  {if (isset($_SESSION["fname"]))}

  }

  else {}

  Header('Location:NewRequest.php');

  }

  ? >

  <? PHP

  $User = $_SESSION ['Pnom"];

  $result = $con-> query ("SELECT ALL * from newrequest where Fname ="$User"" ");

  ? >

  <! doctype html >

  < html >

  < head >

  < link href = "CSS/Master.css" rel = "stylesheet" type = "text/css" / > "

  < link href = "CSS/Menu.css" rel = "stylesheet" type = "text/css" / > "

  < meta charset = 'utf-8 '.

  ReviewRequest < title > < / title >

  < / head >

  < body >

  < div class = "Container" >

  < div class = "Header" > < / div >

  < div class = "Menu" >

  < div id = 'Menu' >

  < nav >

  < ul class = "cssmenu" >

  < li > < a href = "Account.php" > account < /a > < /li > ""

  < li > < a href = "UpdateAccount.php" > update account < /a > < /li > ""

  < li > < a href = "NewRequest.php" > new request < /a > < /li > ""

  < li > < a href = "ReviewRequest.php" > Review Request < /a > < /li > ""

  < li > < a href = "LogOut.php" > sign out < /a > < /li > ""

  < /ul >

  < / nav >

  < / div >

  < / div >

  < div class = "LeftBody" > < / div >

  < div class = "RightBody" >

  < name of the form = "form1" method = "post" action = "" >

  < table border = "1" >

  < b >

  < td = '26' height > name < table >

  Location < td > < table >

  Description < td > < table >

  Image of < td > < table >

  < Td > status < table >

  < /tr >

  <? PHP while ($row = $result-> fetch_assoc()) {? >}

  < b >

  < class td = "GFied" > <? PHP echo $row ["Fname"];? > < table >

  < class td = "GFied" > <? PHP echo $row ['Location'];? > < table >

  < class td = "GFied" > <? PHP echo $row ['Description'];? > < table >

  < class td = "GFied" > < img src = "<?" PHP echo $row ["numero_imagenom_image"];? > "alt =" "> < table >"

  < class td = "GFied" > <? PHP echo $row ['Status'];? > < table >

  <? PHP}? >

  < /tr >

  < /table >

  < / make >

  < / div >

  < div class = "Footer" > < / div >

  < / div >

  < / body >

  < / html >

  This is what it looks like when it displays:

  

  How can I actually picture to display?

  emrenilo32520834 wrote:

  I added the .jpg but the image still does not display, the images are saved in a jpg file.

  If the images in the database to follow this format - 1234567.jpg, 9897654.jpg

  Then your original code must have worked:

  

  Are the images in their own folder, if so you need to add this folder for code name:

  

• How to display multiple images at the same time in CS6?

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  Hello

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• How to display an image on the screen

  I am currently using the following code

  InputStream imageStream = app.getClass().getResourceAsStream("/resources/map.png");
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  EncodedImage image = EncodedImage.createEncodedImage(data, 0, data.length);
  BitmapField bmpField = new BitmapField();
  bmpField.setImage(image);
  divisionScreen.add(bmpField);
  

  But it does nothing on the divisionScreen. The same screen has some listechamps as items that normally appear. I want to display the image above the items in this list.

  Thanks in advance

  Hello

  Try this way adding image if it works then something is wrong with the wqay you do

  Bitmap objHeaderImage = Bitmap.getBitmapResource ("88Header.png");

  BitmapField = objHeader = new BitmapField (objHeaderImage);

  Note Add the image to your project by right-clicking on your project and selecting Add files.

  This is perhaps the reason why your original way did not work.

  I would like to know if it works or not.