How to divide basedon characters of the string

var str:String = "M01L01T01S01".

How to cut based on alphabatics

I need to change the string above as 'M01_L01_T01_S01 '.

Im not an expert in manipulating strings, so it is perhaps not the best way but this one solution

var str:String = "M01L01T01S01"var pattern:RegExp = /[a-zA-Z]\d*/ig;var results:Array = str.match(pattern);var output:String = results.join("_");

Tags: Adobe Animate

Similar Questions

  • How to remove special characters from the string using translate() without typing all special characters?

    Hi all

    I am trying to remove special characters without the help of regular expressions.

    translate (the column name or string,'!@#$ & * (* () _) * "" :} {?}) >? /, «, » ')

    I want to eliminate this manual process to give all special characters using a chr() or ascii() function.

    Please show me the way.

    Thanks in advance

    Similar to the solution of Michael...

    SQL > ed
    A written file afiedt.buf

    1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
    2, i like (select level 1 c from dual connect by level<=>
    3 less
    4 Select + 32 (level-1) double connect by level<=>
    5 less
    6 select + 58 (level-1) double connect by level<=>
    7 less
    8 select + 91 (level-1) double connect by level<=>
    9 less
    10. Select 123 + (level-1) from dual connect by level<=>
    11 less
    12. Select 255 double
    13            )
    14, ts as (select level r, substr (str, level 1) c
    15 t
    16 connect by level<=>
    17             )
    18, tf as (select row_number() (order for r) r
    19                    ,ts.c
    20 TS
    21 I join on (i.c = ascii (ts.c))
    22             )
    23 select replace (sys_connect_by_path(c,'!'),'! ') Str
    24 TF
    25 where connect_by_isleaf = 1
    26 connect r = prior r + 1
    27 * start with r = 1
    SQL > /.

    STR
    -----------------------------------------------------------------------------------------------------------------------
    Thisisthemostamazingtest¸astringcosting5000

    Or something as horrible as this...

    SQL > ed
    A written file afiedt.buf

    1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
    2, I like (select replace (sys_connect_by_path (chr (c), 'A'), 'A') as tr)
    3 of)
    4 select c, rownum r
    5 (select 32 + (level-1) as the double connection by level c<=>
    6                         union
    7 select + 58 (level-1) double connect by level<=>
    8                         union
    9 select + 91 (level-1) double connect by level<=>
    10 the union
    11. Select 123 + (level-1) from dual connect by level<=>
    12 union
    13. Select 255 double
    14 tri 1
    15                        )
    16                  )
    17 where connect_by_isleaf = 1
    18 log r = prior r + 1
    19 start with r = 1
    20            )
    21 select translate (str, 'A' |) TR, 'A') as str
    22 * t, I
    SQL > /.

    STR
    --------------------------------------------------------------------
    Thisisthemostamazingtest¸astringcosting5000

  • How to get individual characters in the string

    Hello

    I have a question how to get the numbers on the back the strings.

    mc_invis_table_1

    mc_invis_table_2

    mc_invis_table_30

    mc_invis_table_100

    mc_invis_table_200

    mc_invis_table_500

    mc_invis_table_264

    My strings have a standard naming mc_invis_table_ followed by numbers from 1 to 1000.

    Can I get the numbers on the back of each channels above? Like 1,2,30,100,200,500,264 and so on...

    Thank you

    Zainuu

    var str:String = "mc_invis_table_200";
    var res: String = str.substr (15, str.length);
    trace (res);

    hope it solves

  • How to avoid special characters in the string box

    Hello

    is it possible that a special character can be avoided in a box of the string, as authorizing only a - z and 0-9 to enter a box in the chain

    Hi all

    Darin Laurette method is simple.

    AnkitG: You must change the code.

    Good learning for me.

    Kind regards

    Leila

    CLD

  • How to get special characters in the oracle column only

    Hi all

    with spec_tab

    as

    (

    Select ',' col1 of double

    Union

    Select ',' col1 of double

    Union

    Select 'something' double

    )

    Select col1

    of spec_tab

    How to get special characters in the oracle column only

    You mean like this?

    -------------

    WITH spec_tab
         AS (SELECT ',,,,' col1 FROM DUAL
             UNION
             SELECT ',' col1 FROM DUAL
             UNION
             SELECT 'some thing' FROM DUAL)
    SELECT col1
      FROM spec_tab
      where translate('~'||col1,'~0123456789abcdefghijklmnopqrstuvwxyz ','~')<>'~'
    

    Output:

    -----

    COL1

    ,

    ,,,,

    See you soon,.

    Manik.

  • REGEXP_REPLACE to add characters in the string

    Hi all

    How to add characters between the sctring?

    I have a string "1A24B67IO" and you want to convert to "1a 2 - 4B - 67IO.

    I tried to use the REGEXP_REPLACE function, but not able to do.

    Hello

    As you have not given the logic behind it... I guess you must insert - so much that even the example you provided.

    With T as
    (
    select '1A24B67IO' col_val from dual
    )
    --
    --End of sample data
    --
    select regexp_replace(col_val,'([[:alnum:]]{3})([[:alnum:]]{2})([[:alnum:]]{4})','\1-\2-\3') from t
    /
    PRAZY@11gR2> /
    
    REGEXP_REPL
    -----------
    1A2-4B-67IO
    
    Elapsed: 00:00:00.20
    

    Kind regards
    Prazy

  • Select tool and exhaust of the characters in the string

    I would like to choose a directory path using the selection functions. The string ends to the position of the backslash,

    Example "C:\Program Files\Microsoft Games" will become "c:".

    How to do this

    Thank you

    JIm

    Thanks for the help, it's the indicator that was truncating the line.

    Sorry for the questions but I'm very new to labview, it is very different from the CVI

    Jim

  • replace characters in the string

    Hi all

    Is it possible to index the characters in a string as if it were a table and remove them from the second position and now. I just want with the first letter or number so that I can later concatenate strings to it.

    Thanks for any help!

    -Michael

    Hi Michael,

    Yes. Use the function "Sring subset. At the beginning the value 0 (default value) and the length of 1.

    This will give you the first character in the string.

    Steve

  • How to enter special characters with the Run statement (@).

    Hello

    Oracle10g (R1)

    NLS_CHARACTERSET = "AL32UTF8.

    When I insert record with special characters like "hastened" with the customer tool insert it works fine, but I run the same INSERT statement execution i.e. statement "SQL > @/ path/Script_File_Name.sql ' special characters has not inserted correctly and it become something like 'h¿ta'.»»

    How to enter special characters correctly race (@) statement?

    Thank you

    If you create a file in Notepad, select the ANSI or the encoding UTF-8 in the dialog box save as.  Copy the Linux file in binary mode. Set the variable NLS_LANG ".» WE8MSWIN1252 ", if the file was saved with the ANSI coding or to. AL32UTF8", if the file was saved with UTF-8 encoding. Be sure to export the variable.  Then, start SQL * more and run the script.  I guess that you are on a U.S. or Western Europe of Windows version.

    Thank you

    Sergiusz

  • How to find special characters in a string of give/sentance

    Hi all

    I have a task to complete with the time to give. Because I'm not very good in PL/SQL, I need you're help.
    Condition is:

    I must come with the SQL or PL/SQL code which should return and find the hidden or special character in the name of the data files in a database. There are nearly 400 + database are present in almost any flavor of UNIX, and I need to check the database each.

    As you know, the name of the data file will be like this:
     /u02/instance_name\oradata\datafile_01.dbf 
    So, it should avoid these things and only discover the special characters in the name of the data file.
     
    a-z , A-Z , 0-9 and \ 
    Please keep in mind that... I'll be pulled the script Oracle the Oracle 9i client that will access all the databases of Oracle 9i to 11g in a short and give me the result.

    Please help me to solve this problem and let me know if you need more information.

    Hello

    Mukesh says:
    Hi Frank,.

    It is an excellent service. Thanks for you response.
    I want to change the query that... I should get only the name of these data files that are special characters of detention. I don't know how to put it in that condition. :(

    Here's one way:

    SELECT  file_name
    ,       ...     -- other expressions, if you want any
    FROM    dba_data_files
    WHERE   TRANSLATE ( file_name
                      , '?0123456789.ABCDEFGHIJKLMNOPQRSTUVWXYZ\_/abcdefghijklmnopqrstuvwxyz'
                      , '?'
                      ) IS NOT NULL
    

    Among other expressions, you can put in the SELECT clause (if you wish) is a copy of the TRANSLATE function, you had in your message. That would underline exactly what characters rendering invalid file name.

  • REGEXP_REPLACE problem with special characters in the string

    Hi guys,.

    I have had problems using the REGEXP_REPLACE function and I'm trying to find a solution.

    The closest I can get is this thread:

    Re: How to replace the first occurrence of a substring

    and that's only because the solution, I'm trying to achieve is the one suggested. I did ppost my problem there, but because it is answered, I don't have an answer.

    I'm doing the following:
    select 
      regexp_replace('A*|A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31|A1|A||_|EX|8HI01|H11|A1|A||_|OCR|H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|EP|||_|AA|2151|G31|A|||_|',
      '^(\w|-)*\|{1}',null)
    from dual
    Basically, replace it does not work, because the first part of the string contains an asterisk. If you delete the Asterix, then replace it won't work.

    How can I get around this? I can't use a regular REPLACEMENT as I want to remove the first instance of A * and not all instances of the A.

    Help, please! I don't know what to do... probably, I mustn't start a loop through the string?

    Thanks in advance guys!

    Robin

    User_resU wrote:
    I want to remove the first instance of A * and not all instances of the A.

    To decode your regular expression, it seems that you want to remove A * | and not just A *.

    SQL> select   regexp_replace('A*|A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31
    |A1|A||_|EX|8HI01|H11|A1|A||_|OCR|H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|
    EP|||_|AA|2151|G31|A|||_|',
      2    '^(\w|-)\*\|{1}',null) reg
      3  from dual;
    
    REG
    --------------------------------------------------------------------------------
    
    A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31|A1|A||_|EX|8HI01|H11|A1|A||_|OCR
    
    |H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|EP|||_|AA|2151|G31|A|||_|
    
  • How to handle special characters in the Apex

    Hello

    In my application, I have two regions - region report (interactive report) and other is region HTML with text elements two - Empno and name

    My report has two columns Empno (varchar2) and Ename (varchar2).

    When I click on the link change in the column of the report, the empno should be a read-only value EMPNO and ename is a text with the value of the ENAME field.

    When I run my application, I have encountered the following problems:
    1. If my empno has special characters such as "#", the characters after that is not posting
    2. If my empno has special characters such as "," characters after the decimal point is considered to be a value of next texitem

    Here is my authentication information,

    CTSAN_ORACLE_DB workspace
    Username [email protected]
    Password lakshmi321
    URL: http://apex.oracle.com/pls/apex/f?p=9444:19:4292839314890159:


    Please, I beg you. suggest me how to fix these problems.

    Thank you
    David...

    Published by: David on August 13, 2010 03:05

    Do not pass the data values in the URL. If it is possible to escape values to make URL - and APEX parameter-safe, it is much better to avoid the problem completely.

    Create a primary key of the substitution on the table which is an immutable discreet digital identifier and use it only as a URL parameter. In pages/target areas, use this value of PK to extract the data from the table.

  • How can I make characters follow the mouse?

    Hello, I am designing a new game. I wanted to add the feature to have the character be controlled mouse. I tried different ways, but none of them does not seem to work. How can I do for where the character following the mouse at a constant speed?

    package

    {

    import flash.display.Stage;

    import flash.events. *.

    import flash.ui.Keyboard;

    import flash.display.MovieClip;

    SerializableAttribute public class extends MovieClip Hero

    {

    public var stageRef:Stage;

    public var health: Number = 6;

    public var speed: number = 2;

    public var leftPressed:Boolean = false;

    public var rightPressed:Boolean = false;

    public var upPressed:Boolean = false;

    public var downPressed:Boolean = false;

    public void Hero()

    {

    stage.addEventListener (KeyboardEvent.KEY_DOWN, keyPressed);

    stage.addEventListener (Event.ENTER_FRAME, loop, false, 0, true);

    stage.addEventListener (KeyboardEvent.KEY_UP, keyReleased);

    }

    public void loop(e:Event):void

    {

    {if (leftPressed)}

    x = speed;

    } else {if (rightPressed)

    Speed x +=;

    }

    {if (upPressed)}

    y = speed;

    } else {if (downPressed)

    y += speed;

    }

    }

    public void keyPressed(event:KeyboardEvent):void

    {

    Switch (Event.keycode)

    {

    case Keyboard.LEFT:

    leftPressed = true;

    break;

    case Keyboard.RIGHT:

    rightPressed = true;

    break;

    case Keyboard.UP:

    upPressed = true;

    break;

    case Keyboard.DOWN:

    downPressed = true;

    break;

    }

    }

    public void keyReleased(event:KeyboardEvent):void

    {

    if(Event.keycode == Keyboard.Left)

    {

    leftPressed = false;

    }

    If (event.keyCode is Keyboard.RIGHT)

    {

    rightPressed = false;

    }

    If (event.keyCode is Keyboard.UP)

    {

    upPressed = false;

    }

    If (event.keyCode is Keyboard.DOWN)

    {

    downPressed = false;

    }

    }

    }

    }

    :

    package

    {

    import flash.display.Stage;

    import flash.events. *.

    import flash.display.MovieClip;

    SerializableAttribute public class extends MovieClip Hero

    {

    public var stageRef:Stage;

    public var health: Number = 6;

    public var speed: number = 2;

    private var angle: Number;

    public void Hero()

    {

    stage.addEventListener (Event.ENTER_FRAME, loop, false, 0, true);

    }

    public void loop(e:Event):void

    {

    angle = Math.atan2 (x-MouseX, MouseY-y);

    x = speed * Math.cos (angle);

    y = speed * Math.sin (angle);

    If (Math.ABS (x-MouseX) + Math.ABS (y-MouseY)<>

    x = mouseX;

    y = mouseY;

    }

    }

    }

    }

  • How to avoid special characters in a string

    Hai.

    I want only Alphabets & numbers to appear on my channel. No other special characters except spaces. How can I do this?

    Hi Alice,.

    See the attached example.

    It will be useful.

    Mike

  • How to use wildcard characters in the filter REMAINS for subscription items

    I've followed this documentation:

    String columns filters

    Support the % operator (started by).

    Support * operator (contains).

    Can't stand (trimmed) operator.

    Examples:

    Name = service *.

    Name = * g *.

    Name = * g - unauthorized

    URL OF THE REST:

    http:// /RequestCenter/nsapi/serviceitems/serviceitemsubscription /=

    I can get the filters to work without wildcards, but have had no success in using ' *' or '%' characters  Please provide an example encoded URL appropriate for

    ServiceItemTypeName starting with "virtual".  I was not able to get all the data returned when using wildcard characters in a filter.

    Here is what I tried:

    ServiceItemTypeName = instant virtual server

    http://10.8.0.46:8080/RequestCenter/NSAPI/serviceitems/serviceitemsubscription/ServiceItemTypeName=virtual%20Server%20Snapshot

    answer: 200

    literal works as expected

    ServiceItemTypeName = virtual %

    http://10.8.0.46:8080/RequestCenter/NSAPI/serviceitems/serviceitemsubscription/ServiceItemTypeName=virtual%25

    Request-Type = application/xml

    answer: 200

    expected result not returned

    ServiceItemTypeName = virtual *.

    http://10.8.0.46:8080 / RequestCenter/nsapi/serviceitems/serviceitemsubscription/ServiceItemTypeName virtual = *.

    Request-Type = application/xml

    500

    Internal error: invalid parameter values specified or an unexpected error.

    fails with the error response

    Hi Dan,.

    I don't think you can use wildcards here.

    Please see the integration Guide to 9.4. Section: "REST API-> Quick Reference.

    You will find a table of what features are supported for resources exposed by the API. There you will find a line for "All Service elements", and you will see that: get all the, sorting, paging and all filters are supported; Search for names of wildcards are not...

    When I came across this situation, I guess I'm trying to do a generic name search here... and it is not supported. This, however, works for the other columns (Designer if created), which is what, in my view, that documentation is trying to describe. (Although, personally, I feel that it is a bug).

Maybe you are looking for

  • System to disable the key: [98515117]

    So I turned on my laptop today and he came and asked an admin password after three attempts (98515117) code appears. Heeeelllpp.

  • ArcSoft Scan-n-Stich is available for MAC?

    I think that Best Buy sold me a scanner that I can't use - I'm a graphic designer and try to 'sting' 2 images does NOT work!

  • backup does not

    My computer backup system does not work.  Whenever I put in a new disk, format and the program starts, I get the message "the disc in the drive is a previous backup disk.  However, this is incorrect.

  • Thanks, I found what I needed to do.

    Thank you all, I found I had to do to solve the problem.

  • This plsql function is considered ok?

    This plsql function is considered ok?  The reason that I ask is that the results are different when called within a packet vs appeal during a procedure.  I don't know if this is a bug or if it is illegal. CREATE OR REPLACE package body test as functi