How to find Max, Min and Avg generation of redo to a database

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• Max, Min, and Count with Group By

  Hello

  I want the max, min and the meter of a table that is grouped by a column

  I need a combination of these two selects:

  select
       max(COUNTRY_S) MAXVALUE,
       min(COUNTRY_S) MINVALUE
  from
       tab_Country
  
  

  select
       count(*)
  from
       (select COUNTRY_TXT from tab_Country group by COUNTRY_TXT) ;
  
  

  The result should be a line with the maximum and minimum of the table value and the County grouped by table, not the max and min of each group! -J' hope you understand my question?

  Is this possible in a SQL-select?

  Thank you very much

  Best regards

  Heidi

  Hi, Heidi,.

  HeidiWeber wrote:

  Hello

  I want the max, min and the meter of a table that is grouped by a column

  I need a combination of these two selects:

  1. Select
  2. MAXVALUE, Max (COUNTRY_S),
  3. min (COUNTRY_S) MINVALUE
  4. Of
  5. tab_Country
  1. Select
  2. Count (*)
  3. Of
  4. (select the COUNTRY_TXT of the COUNTRY_TXT tab_Country group);

  The result should be a line with the maximum and minimum of the table value and the County grouped by table, not the max and min of each group! -J' hope you understand my question?

  Is this possible in a SQL-select?

  Thank you very much

  Best regards

  Heidi

  It is not clear what you want.  Maybe

  SELECT MAX (country_s) AS max_country_s

  MIN (country_s) AS min_country_s

  COUNT (DISTINCT country_txt) AS count_country_txt

  OF tab_country

  ;

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002

• How to find corrupted files and remove them on mac i

  How to find corrupted files and remove them on i mac?  AM currently using OS x EL capitan 10.11.12 Mac said to run slowly and the recent upload did not work until the 3rd attempt.

  Thank you

  You do not have.

  You can run this program and post the results so that we can see what you have installed that could cause your problems.

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• Find dates MIN and MAX

  Please, advise how correctly find MIN and MAX dates.
  The XML code:

  <DATES>
  <DT>2011-02-24</DT>
  <DT>2011-02-25</DT>
  <DT>2011-02-26</DT>
  <DT>2011-02-27</DT>
  <DT>2011-02-28</DT>
  </DATES>

  Model:

  <?xdoxslt:minimum(DT)?>
  <?xdoxslt:maximum(DT)?>

  The output:

  0
  20110224

  Expected results:

  2011-02-24
  2011-02-28

  Hello

  If your data is:
  
  
  
  

  2008-10-04
  
  1
  
  
  
  2009-10-21
  
  3
  
  
  
  2009-11-05
  
  4
  
  
  
  2008-11-10
  
  2
  
  

  The maximum is given by: / ROWSET/ROW/DT [.. / DT_RANK = count (//ROW)]
  and the minimum is: / ROWSET/ROW/DT [.. / DT_RANK = 1]

  There may be more effective, but it works.

  concerning

  Jorge

• Grouping and then find the min and max

  DROP TABLE purge of y;

  CREATE TABLE y
  (
  ID NUMBER (10),
  START_DATE_TIME NUMBER (15),
  END_DATE_TIME NUMBER (15)
  );

  INSERT INTO y VALUES (1, 20140602164819, 20140606140851);
  INSERT INTO y VALUES (1, 20140827141743, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141744, 20140827141835);
  INSERT INTO y VALUES (1, 20140827141744, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141944, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141944, 20140924142131);
  INSERT INTO y VALUES (1, 20140927141944, 20141027142131);
  INSERT INTO y VALUES (2, 20140602164819, 20140606140851);
  INSERT INTO y VALUES (2, 20140827141743, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141744, 20140827141835);
  INSERT INTO y VALUES (2, 20140827141744, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141944, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141944, 20140924142131);
  INSERT INTO y VALUES (2, 20140927141944, 20141027142131);

  COMMIT;

  Select
  *
  Of
  There
  order by 2, 3;

  out necessary: when the output of the table are sorted by start_date_time and end_date_time in ascending order.
  and when the value of for a particular id start_date_time is located between the
  another set of values start_date_time and end_date_time for the same id then min (start_date_time) and max (end_date_time) is the desired output.

  and if there is no overlap then (start_date_time) min and max (end_date_time) is the output desired.

  and for each line of the output in ascending order of line number order addd;

  Example output is in the output table named

  drop table output is serving;

  create an output table
  (
  ID NUMBER (10),
  START_DATE_TIME NUMBER (15),
  END_DATE_TIME NUMBER (15),
  ROW_NUMBER NUMBER (10)
  );

  
  Values to INSERT OUTPUT (1, 20140602164819, 20140606140851, 1);
  Values to INSERT OUTPUT (1, 20140827141743, 20140924142131, 2);
  Values to INSERT OUTPUT (1, 20140927141944, 20141027142131, 3);
  Values to INSERT OUTPUT (2, 20140602164819, 20140606140851, 1);
  Values to INSERT OUTPUT (2, 20140827141743, 20140924142131, 2);
  Values to INSERT OUTPUT (2, 20140927141944, 20141027142131, 3);

  COMMIT;

  SELECT
  *
  Of
  output
  ORDER BY 1,2,3,4;

  Thank you

  SQL_Novice

  Hello

  Your postal code.  It is difficult to tell what you're doing wrong without knowing what you are doing.

  user6166680 wrote:

  Hi Frank:

  Max works for ID 3 values only because there is only one group here, as all other values compared, they overlap with max (end_date_time);

  but when I use MAX for ID 1 and 2, the result set is not the same thing as LAG works because there is a GAP...

  Exactly, you have to find the gaps.  If start_date_time is less than or equal to the MAXIMUM of all the end_date_times earlier, then it isn't a gap; Otherwise, there is a gap.

  What is the problem with MAX?

  WITH got_new_group AS

  (

  SELECT id, start_date_time and end_date_time

  CASE

  WHEN start_date_time <= > MAX (end_date_time) OVER (PARTITION BY id )

  ORDER BY start_date_time

  end_date_time

  ROWS BETWEEN UNBOUNDED PRECEDING

  AND 1 PRECEDING

  )

  THEN 0

  1. OTHER

  END AS new_group

  OF y

  )

  got_group_number AS

  (

  SELECT id, start_date_time and end_date_time

  SUM (new_group) OVER (PARTITION BY ID.

  ORDER BY start_date_time

  end_date_time

  ) AS group_number

  OF got_new_group

  )

  SELECT id

  MIN (start_date_time) AS group_start_date_time

  MAX (end_date_time) AS group_end_date_time

  group_number

  OF got_group_number

  GROUP BY id, group_number

  ORDER BY id, group_number

  ;

  You will notice that it is exactly what I posted earlier, in response #5, except that instead of using the OFFSET it uses MAX.

  Output:

  ID GROUP_START_DATE_TIME GROUP_END_DATE_TIME GROUP_NUMBER

  --------------- --------------------- ------------------- ---------------

  1 20140602164819 20140606140851 1

  1 20140827141743 20140924142131 2

  1 20140927141944 20141027142131 3

  2 20140602164819 20140606140851 1

  2 20140827141743 20140924142131 2

  2 20140927141944 20141027142131 3

  3 20140330041350 47121231000000 1

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• How to find the Maxima and Minima for each column of a 2D array?

  Hello

  I have a 2D chart and I would find the maxima and minima of each column of the 2-D table. Even though I know how to get maxima and minima for the whole picture but don't know how columnwise? Any ideas please?

  Thank you

  Rohit

  Hello

  @Smercurio-What you said is true, I should have shown using automatic indexing enabled which is really excellent choice. I just tried to show in a very simple way.

  Anyway, here's the best way

  

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• How to find the lock and more information why the prg conc taking too long

  Oracle Apps R12-Orader management
  
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