How to find the connection line

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  I'm trying to connect my iphone to my internet TV. On my phone, it asks me a password to connect to my network TV (different from the wifi network that I connected my TV) and I have no idea how to find the password.

  Hello Pam,.

  Welcome to the community of Sony.

  What is the model # of the TV?

  You can locate the model # of the TV from this link.

  The password has been entered in the iPhone is the WPA password.

  See the following article in the knowledge base to use the Wi - Fi Direct feature with your iPhone.

  https://us.en.KB.Sony.com/app/answers/detail/A_ID/34416

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  Kind regards

  Colby

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  Hi all
  
  Could someone knows how to find the number of users connected to the database without connection with sql * more
  
  y at - it a command to find?
  
  example, we have 10 databases in a server, how to find the number of users connected to the special data base without connecting to database(v$session)?
  
  the Oracle version:-10g, 11g
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  Kind regards
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  but you can say total number of connection with the above given the command? It would also be useful to know.

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  I am using the Forum to get a new code to the printer and the printer shows homepage that's on, but now I don't know how to find the e-mail address for my computer.

  Hello

  In the front of the printer, go to configuration. Locate and enter the Web Services. Aprove any step to activate the service... leave the system a few minutes to complete your registration, a page will be printed automatically with the code printer and directions to select the email address of hpeprint.com.

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• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How to find the ANGLE b/w two edges in Oracle Spatial

  How to find the ANGLE b/w two edges on Oracle Spatial. I have two edge connected on the same node. I wanted to know the angle betwwn them. Can someone help me?

  Ok. My first example is an approximation. Further you get North or South of the Ecuador, gets the more vague.
  This one should do the trick with some degree of precision.

  declare
    PI constant number := 3.14159265358979;
    g1 sdo_geometry;
    g2 sdo_geometry;
    g3 sdo_geometry;
  
    angle1 number;
    angle2 number;
  
    FUNCTION POINT(P_LAT  IN number
                  ,P_LONG IN number)
      RETURN MDSYS.SDO_GEOMETRY IS
    BEGIN
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      -- it is not important for this example, just something to be aware of
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                                                    ,mdsys.sdo_elem_info_array(1,2,1)
                                                    ,mdsys.sdo_ordinate_array(p_long,p_lat)));
    END;
  
  begin
  
    -- For the example, project in WGS84
    -- g1,g2,g3 could also come straight out of the database as sdo_geometry
    g1 := point(50, 7);          -- Point A
    g2 := point(51, 7);          -- Point B
    g3 := point(50,10);          -- Point C
  
    angle1 := atan2(g2.sdo_point.x - g1.sdo_point.x,
                    g2.sdo_point.y - g1.sdo_point.y);
    angle2 := atan2(g3.sdo_point.x - g1.sdo_point.x,
                    g3.sdo_point.y - g1.sdo_point.y);
  
    -- depending on rotation and where we are on the planet, adjustments may be needed
    if angle1 < 0      then angle1 := angle1 + 2 * PI; end if;
    if angle2 < 0      then angle2 := angle2 + 2 * PI; end if;
    if angle2 < angle1 then angle2 := angle2 + 2 * PI; end if;
  
    dbms_output.put_line('Angle between the lines A-B and A-C: '||
                         round(sdo_util.convert_unit(angle2-angle1,'Radian','Degree'),1));
  end;
  

  Angle between the lines A-B and A-C: 90
  

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  Hello

  I start with the second question:

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  Hello

  How to find the properties of Thin Client, PC.

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  Hi Yogi,

  Thanks for posting your query in Microsoft Community.

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  TechNet Forum

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  in general, it is a fairly complex task if you want to size the new platform correctly, i.e. not to oversize it and have very low use below, i.e. spend too much on equipment.

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• How to find the size of the table?

  Hi all

  Can anyone suggest how to find the size of the table? I had a few (15272 selected lines) on the name of "CMPT_" How can I check only 'CMPT_' size tables?

  
  

  
  

  
  

  
  

  Please someone help give the SQL query to run.

  
  

  Thanks in advance.

  
  

  Vincent
  

  madala03 wrote:

  Hi thanks for the reply

  I'm out like below

  SUM(BYTES/1024/1024)

  --------------------

  25383.25

  But how to check all the name of tables CMPT and their sizes?

  Select nom_segment, dba_Segments sum(bytes/1024/1024) where nom_segment like ' % CMPT GROUP BY nom_segment;

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  User, please tell us our jdev version!

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