How to find the number of lines in the content of the text?

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• How to find the number of data items in a file written with the ArryToFile function?

  I wrote a table of number in 2 groups of columns in a file using LabWindows/CVI ArrayToFile... Now, if I want to read the file with the FileToArray function so how do I know the number of items in the file. during the time of writing, I know how many elements array to write. But assume that I want the file to be read at a later time, then how to find the number of items in the file, so that I can read the exact number and present it. Thank you all

  Hello

  I start with the second question:

  bytes_read = ReadLine (file_handle, line_buffer, maximum_bytes);

  the second argument is the buffer to store the characters read, so it's an array of characters; It must be large enough to hold maximum_bytes the value NULL, if char [maximum_butes + 1]

  So, obviously the number of lines in your text tiles can be determined in a loop:

  Open the file

  lines = 0;

  While (ReadLine () > 0)

  {

  lines ++;

  }

  Close the file

• How to find the serial number of the processor in the MacBook pro s serial number? I have a dead MacBook that was given for service to a third party. I doubt that they have replaced the original parts. Help, please. Thank you

  How to find the serial number of the processor in the MacBook pro s serial number? I have a dead MacBook that was given for service to a third party. I doubt that they have replaced the original parts. Help, please. Thank you

  As far as I KNOW, the serial number of the MacBook does not have the serial number of the processor.

• A torn my sticker with the serial number. How to find the number of the whole installation?

  Best regards, tore my sticker with the serial number. I don't see the numbers. How to find the number of the whole installation?

  Original title: windows 7 sn

  Option 1:

  If the COA sticker is damaged, you must use the recovery partition to reinstall Windows 7, it will be exempt from the need to use the product key to activate your installation of Windows 7.

  Option 2:

  If your recovery partition is not available or damaged, you must contact the manufacturer of your computer, and request that a defined recovery disk you can use to reinstall Windows 7. They could practice a small shipping and handling. This will exempt the need to also use the product key.

  Option 3:

  If neither options 1 or 2 is possible, then you will need to invest in a new license of full version of detail.

• How to find the serial number adobe Installation section

  How to find the serial number adobe Installation section

  Creative cloud does not use a serial number and creative cloud subscribers for not having any serial number associated with their programs.  Creative cloud subscribers use their adobe ID to activate their programs.

  Download and install the desktop creative cloud application (after signing with your adobe - the same as that used to pay for your creative cloud subscription ID), https://creative.adobe.com/products/creative-cloud

  Open the office application (a shortcut will be on your desktop) > click applications, and then select the programs you want to install.

  the desktop application gives you access to the cs6, cc, cc 2014 and cc 2015 apps.  and probably more in the future.

  If you already have the cc desktop application and you need to update your adobe id, log out and then back to your client application using the adobe id to pay for your subscription in cc: http://helpx.adobe.com/creative-cloud/kb/sign-in-out-creative-cloud-desktop-app.html

• How to find the number of users connected to the database of the level operating system (Linux)

  Hi all
  
  Could someone knows how to find the number of users connected to the database without connection with sql * more
  
  y at - it a command to find?
  
  example, we have 10 databases in a server, how to find the number of users connected to the special data base without connecting to database(v$session)?
  
  the Oracle version:-10g, 11g
  Operating system:-OEL4, OEL5, AIX, Solaris
  
  any help will be appreciated.
  
  Thanks in advance.
  
  Thank you.
  
  Kind regards
  Rajesh.

  but you can say total number of connection with the above given the command? It would also be useful to know.

  See you soon,.
  LKM

• How to find the square root of a number/variable

  I have a number within a variable.

  How to find the square root of the variable?

  for example:

  xxyy var = 57;

  I want to find the square root of 57;

  use:

  trace (Math.sqrt (xxyy));

• average of k: how to find the data clustred; : or how to assign number t0 each data group

  Hi Member

  I have download the LabVIEW Machine https://decibel.ni.com/content/docs/DOC-19328 learning package

  I want to run the K average algorithm to group the image in a group of two or three or more

  the problem is how to find the result I mean the image of clustred', the image that contain 2 or three threatened value only

  or how aasign a 1 value for all the intesity who

  belong to the cluster a and 255 for data that belongs to group 2

  for the look of the image as binary image?

  a my vi below

  Best regards

  my post before shows how to set the threshold manually using the slider of the graph.

  Here is the version k-means automated help .vi box tools

  

  

  Alex

• How to find the age of a child and snapshot number snapshot for a virtual machine.

  Hi all

  How to find the age of a snapshot for a virtual machine child count and snapshot.

  This code snippet should help... Assuming that you have the following entries:

  VM (VC:VirtualMachine)

  snapshot (VC:VirtualMachineSnapshot)

  System.log("====== Snapshot details for VM: "+snapshot.config.name+" ======");
  var snapshotTrees = vm.snapshot.rootSnapshotList;
  System.log("Snapshot Tree Count: "+snapshotTrees.length);
  for each (snapshotTree in snapshotTrees){
      showSnapshotInfo(snapshotTree, snapshot);
  }
  
  function showSnapshotInfo(snapshotTree, selectedSnapshot){
      if(selectedSnapshot == snapshotTree.snapshot){
          System.log("====================");
          System.log("Name: "+snapshotTree.name);
          System.log("Id: "+snapshotTree.id);
          System.log("Description: "+snapshotTree.description);
          System.log("createTime: "+snapshotTree.createTime);
          System.log("quiesced: "+snapshotTree.quiesced);
          System.log("replaySupported: "+snapshotTree.replaySupported);
          System.log("backupManifest: "+snapshotTree.backupManifest);
          System.log("snapshot id: "+snapshotTree.snapshot.id);
          System.log("state: "+snapshotTree.state.value);
          var childSnapshotList = snapshotTree.childSnapshotList;
          if(childSnapshotList != null){
              System.log("childSnapshotList length: "+snapshotTree.childSnapshotList.length);
          }
          System.log("");
      }
      if(snapshotTree.childSnapshotList != null){
          System.log("Children found: "+snapshotTree.childSnapshotList.length);
          for each (childSnapshotTree in snapshotTree.childSnapshotList){
              showSnapshotInfo(childSnapshotTree, selectedSnapshot);
          }
      }
  }
  

  During the passage of one of my virtual machines, here is an example of output I get:

  [2014-06-12 15:19:21.493] [I] Snapshot Tree Count: 1
  [2014-06-12 15:19:21.493] [I] ====================
  [2014-06-12 15:19:21.494] [I] Name: before upgrade to 5.0.1
  [2014-06-12 15:19:21.494] [I] Id: 31
  [2014-06-12 15:19:21.494] [I] Description:
  [2014-06-12 15:19:21.495] [I] createTime: Mon Mar 19 2012 13:48:57 GMT-0400 (EDT)
  [2014-06-12 15:19:21.495] [I] quiesced: false
  [2014-06-12 15:19:21.495] [I] replaySupported: null
  [2014-06-12 15:19:21.495] [I] backupManifest: null
  [2014-06-12 15:19:21.496] [I] snapshot id: snapshot-83
  [2014-06-12 15:19:21.496] [I] state: poweredOff
  [2014-06-12 15:19:21.496] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.496] [I]
  [2014-06-12 15:19:21.497] [I] ====================
  [2014-06-12 15:19:21.497] [I] Name: Before 5.1 upgrade
  [2014-06-12 15:19:21.497] [I] Id: 36
  [2014-06-12 15:19:21.497] [I] Description:
  [2014-06-12 15:19:21.498] [I] createTime: Fri Sep 21 2012 21:59:58 GMT-0400 (EDT)
  [2014-06-12 15:19:21.498] [I] quiesced: false
  [2014-06-12 15:19:21.498] [I] replaySupported: null
  [2014-06-12 15:19:21.498] [I] backupManifest: null
  [2014-06-12 15:19:21.499] [I] snapshot id: snapshot-84
  [2014-06-12 15:19:21.499] [I] state: poweredOff
  [2014-06-12 15:19:21.499] [I] childSnapshotList length: 1
  [2014-06-12 15:19:21.499] [I]
  [2014-06-12 15:19:21.500] [I] ====================
  [2014-06-12 15:19:21.500] [I] Name: Before Named Instance
  [2014-06-12 15:19:21.500] [I] Id: 37
  [2014-06-12 15:19:21.501] [I] Description:
  [2014-06-12 15:19:21.501] [I] createTime: Mon Nov 11 2013 13:40:46 GMT-0500 (EST)
  [2014-06-12 15:19:21.501] [I] quiesced: false
  [2014-06-12 15:19:21.501] [I] replaySupported: null
  [2014-06-12 15:19:21.502] [I] backupManifest: null
  [2014-06-12 15:19:21.502] [I] snapshot id: snapshot-236
  [2014-06-12 15:19:21.502] [I] state: poweredOff
  [2014-06-12 15:19:21.502] [I]
  

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How to find the ANGLE b/w two edges in Oracle Spatial

  How to find the ANGLE b/w two edges on Oracle Spatial. I have two edge connected on the same node. I wanted to know the angle betwwn them. Can someone help me?

  Ok. My first example is an approximation. Further you get North or South of the Ecuador, gets the more vague.
  This one should do the trick with some degree of precision.

  declare
    PI constant number := 3.14159265358979;
    g1 sdo_geometry;
    g2 sdo_geometry;
    g3 sdo_geometry;
  
    angle1 number;
    angle2 number;
  
    FUNCTION POINT(P_LAT  IN number
                  ,P_LONG IN number)
      RETURN MDSYS.SDO_GEOMETRY IS
    BEGIN
      -- we load both the ordinate array and the point type because some spatial functions show inconsistent behavior
      -- it is not important for this example, just something to be aware of
      return(mdsys.sdo_geometry(2001,8307 -- WGS84
                               ,mdsys.sdo_point_type(p_long,p_lat,null)
                                                    ,mdsys.sdo_elem_info_array(1,2,1)
                                                    ,mdsys.sdo_ordinate_array(p_long,p_lat)));
    END;
  
  begin
  
    -- For the example, project in WGS84
    -- g1,g2,g3 could also come straight out of the database as sdo_geometry
    g1 := point(50, 7);          -- Point A
    g2 := point(51, 7);          -- Point B
    g3 := point(50,10);          -- Point C
  
    angle1 := atan2(g2.sdo_point.x - g1.sdo_point.x,
                    g2.sdo_point.y - g1.sdo_point.y);
    angle2 := atan2(g3.sdo_point.x - g1.sdo_point.x,
                    g3.sdo_point.y - g1.sdo_point.y);
  
    -- depending on rotation and where we are on the planet, adjustments may be needed
    if angle1 < 0      then angle1 := angle1 + 2 * PI; end if;
    if angle2 < 0      then angle2 := angle2 + 2 * PI; end if;
    if angle2 < angle1 then angle2 := angle2 + 2 * PI; end if;
  
    dbms_output.put_line('Angle between the lines A-B and A-C: '||
                         round(sdo_util.convert_unit(angle2-angle1,'Radian','Degree'),1));
  end;
  

  Angle between the lines A-B and A-C: 90
  

• How to find the snid? If it is removed or deleted from this sticker on the back?

  How to find the snid and sn & id of the laptop if it is removed or deleted this sticker on the back?

  My laptop is acer ferrari 1000

  Tools Information as SIW system reports the product name and serial number IF this information is stored somewhere in the computer.

  I don't know what you mean by 'id', but for example, all the following values are reported by SIW:

  Manufacturer
  Name of the product
  Version
  Serial number
  Type of machine
  Infrared (IR) supported
  DMI system UUID
  UUID

• How to find the size of the virtual server?

  Hello

  We intend to pass our applications 4 virtual servers has 2 physical servers. In this process, we need to identify the size of the current virtual servers to use as a starting point to configure or add the size in physical server. can anyone provide information on whats stats to be noticed and how to find the size of the current virtual servers?

  Thank you

  Hi Sekhar, there.

  in general, it is a fairly complex task if you want to size the new platform correctly, i.e. not to oversize it and have very low use below, i.e. spend too much on equipment.

  In fact, it's the first thing to consider the level of use of the new platform. Most likely your organization (HW and infrastructure) has targets to a minimum. optimal and maximum usage levels.

  In the case where you do not have this as a starting point, and then you continue with load average and the current peak (CPU, RAM, NW). To these basic lines, you can use the statistics of WLS Admin Console, where the use of CPU and memory statistics are presented since the server was last started. For more detailed statistics, you can use WLDF to capture measures key at regular intervals, and then base your analysis of these data.

  Finally and above all, the size of FS, but I've seen some comments above related to the size of the FS.

  HTH,

  A.

• How to find missing number of collection

  DECLARE

  Num_tab_ty TYPE TABLE IS NUMBER;

  num_tab num_tab_ty: = num_tab_ty (5,9,11,2,7);

  BEGIN

  -How to find the missing number of collection

  END;

  2831953 wrote:

  DECLARE

  Num_tab_ty TYPE TABLE IS NUMBER;

  num_tab num_tab_ty: = num_tab_ty (5,9,11,2,7);

  BEGIN

  -How to find the missing number of collection

  END;

  How do return you an infinite number of values that are missing?

  How can I ask a question in the forums?

  https://community.Oracle.com/thread/865295

• How to find the largest

  DECLARE

  Num_tab_ty TYPE TABLE IS NUMBER;

  num_tab num_tab_ty: = num_tab_ty (6,4,8,7);

  BEGIN

  -How to find the largest and the lowest number in a collection

  END;

  DECLARE

  Num_tab_ty TYPE TABLE IS NUMBER;

  num_tab num_tab_ty: = num_tab_ty (6,4,8,7);

  number of l_greatest_value;

  BEGIN

  Select max (column_value)

  in l_greatest_value

  table (num_tab);

  END;

  /

  HTH

• How to find the size of the table?

  Hi all

  Can anyone suggest how to find the size of the table? I had a few (15272 selected lines) on the name of "CMPT_" How can I check only 'CMPT_' size tables?

  
  

  
  

  
  

  
  

  Please someone help give the SQL query to run.

  
  

  Thanks in advance.

  
  

  Vincent
  

  madala03 wrote:

  Hi thanks for the reply

  I'm out like below

  SUM(BYTES/1024/1024)

  --------------------

  25383.25

  But how to check all the name of tables CMPT and their sizes?

  Select nom_segment, dba_Segments sum(bytes/1024/1024) where nom_segment like ' % CMPT GROUP BY nom_segment;