How to find the number who sent the sms blackBerry smartphones?
Hello
you know when you have several mobile numbers assigned to the same person, and this person sends you an SMS, how do I know what number he used to send the SMS?
Thank you.
Boutros
The SMS message open, click Menu > until the email and in the email you will see FROM: phone number.
Tags: BlackBerry Smartphones
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How to get the default BlackBerry smartphone email address?
Hi all
How can I get the BlackBerry default email address?
Thank you
Sumit
Thanks Pierre.
Here's the post that says abt the same question.
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I start with the second question:
bytes_read = ReadLine (file_handle, line_buffer, maximum_bytes);
the second argument is the buffer to store the characters read, so it's an array of characters; It must be large enough to hold maximum_bytes the value NULL, if char [maximum_butes + 1]
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Hi Member
I have download the LabVIEW Machine https://decibel.ni.com/content/docs/DOC-19328 learning package
I want to run the K average algorithm to group the image in a group of two or three or more
the problem is how to find the result I mean the image of clustred', the image that contain 2 or three threatened value only
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a my vi below
Best regards
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Alex
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If the COA sticker is damaged, you must use the recovery partition to reinstall Windows 7, it will be exempt from the need to use the product key to activate your installation of Windows 7.
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[2014-06-12 15:19:21.493] [I] Snapshot Tree Count: 1 [2014-06-12 15:19:21.493] [I] ==================== [2014-06-12 15:19:21.494] [I] Name: before upgrade to 5.0.1 [2014-06-12 15:19:21.494] [I] Id: 31 [2014-06-12 15:19:21.494] [I] Description: [2014-06-12 15:19:21.495] [I] createTime: Mon Mar 19 2012 13:48:57 GMT-0400 (EDT) [2014-06-12 15:19:21.495] [I] quiesced: false [2014-06-12 15:19:21.495] [I] replaySupported: null [2014-06-12 15:19:21.495] [I] backupManifest: null [2014-06-12 15:19:21.496] [I] snapshot id: snapshot-83 [2014-06-12 15:19:21.496] [I] state: poweredOff [2014-06-12 15:19:21.496] [I] childSnapshotList length: 1 [2014-06-12 15:19:21.496] [I] [2014-06-12 15:19:21.497] [I] ==================== [2014-06-12 15:19:21.497] [I] Name: Before 5.1 upgrade [2014-06-12 15:19:21.497] [I] Id: 36 [2014-06-12 15:19:21.497] [I] Description: [2014-06-12 15:19:21.498] [I] createTime: Fri Sep 21 2012 21:59:58 GMT-0400 (EDT) [2014-06-12 15:19:21.498] [I] quiesced: false [2014-06-12 15:19:21.498] [I] replaySupported: null [2014-06-12 15:19:21.498] [I] backupManifest: null [2014-06-12 15:19:21.499] [I] snapshot id: snapshot-84 [2014-06-12 15:19:21.499] [I] state: poweredOff [2014-06-12 15:19:21.499] [I] childSnapshotList length: 1 [2014-06-12 15:19:21.499] [I] [2014-06-12 15:19:21.500] [I] ==================== [2014-06-12 15:19:21.500] [I] Name: Before Named Instance [2014-06-12 15:19:21.500] [I] Id: 37 [2014-06-12 15:19:21.501] [I] Description: [2014-06-12 15:19:21.501] [I] createTime: Mon Nov 11 2013 13:40:46 GMT-0500 (EST) [2014-06-12 15:19:21.501] [I] quiesced: false [2014-06-12 15:19:21.501] [I] replaySupported: null [2014-06-12 15:19:21.502] [I] backupManifest: null [2014-06-12 15:19:21.502] [I] snapshot id: snapshot-236 [2014-06-12 15:19:21.502] [I] state: poweredOff [2014-06-12 15:19:21.502] [I]
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Hello Oracle experts
I am trying to find number of separators to a text string. But I could find only for the first record. Can you if it doesn't matter who you please let me know how to find the record2.
I use
Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
With partitioning, OLAP, Data Mining and Real Application Testing options
Thank you
with t as
(select 3999 ^ 0077774 ^ Institution ^ Mountwest ^ 1 ^ Lilly ^ Maria ^ [email protected] ^ 555-555-5555 ^ 2 ^ Lilly ^ Maria ^ [email protected] ^ 999-999-9999 ^ 3 ^ Lilly ^ Maria ^ [email protected] ^ 777-888-1234 ^ 1 yyyy xxxxxx Drxxx ^ ^ xxxxxxx ^ AA ^ 99999 ^ MRO ^ U.S. ^ ^ ^ I do not know ^ 2 years ^ Public ^ applicable ^ Urban ^ 1, 000-4, 999 ^ N ^ Conference ^ N ^ 14/04/2009 10:52:51 ^ 24/08/2010 09:26:46 ^ Active ^ ^ I ^ ^' string1 from all the double union)
Select ' ^ ^ ^' double string1
)
Length (STRING1) - length (replace(STRING1,'^','')) SELECT delim_number from TTry:
SELECT length(STRING1)-NVL(length(replace(STRING1,'^','')),0) delim_number from T -
How to find the child level for each table in a relational model?
Earthlings,
I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
So: How to find the child level for each table in a relational model?
I have a database of relacional (9.2), all right?
Tips:. O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */ /↑\ Fks O"O O" <-- level 2 for first table (circle) /↑\ Fks "o"o"o" <-- level 1 for middle table (circle) ↑ Fk "º"
-Each circle represents a table;
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I started to think about the following:
First of all, I need to know how to take the kids:
Thought...select distinct child.table_name child from all_cons_columns father join all_cons_columns child using (owner, position) join (select child.owner, child.constraint_name fk, child.table_name child, child.r_constraint_name pk, father.table_name father from all_constraints father, all_constraints child where child.r_owner = father.owner and child.r_constraint_name = father.constraint_name and father.constraint_type in ('P', 'U') and child.constraint_type = 'R' and child.owner = 'OWNER') aux using (owner) where child.constraint_name = aux.fk and child.table_name = aux.child and father.constraint_name = aux.pk and father.table_name = aux.father;
We will share!
Thanks in advance,
Philips
Published by: BluShadow on April 1st, 2011 15:08
formatting of code and hierarchy for readbilityHave you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?
SQL> create table my_emp ( 2 emp_id number primary key, 3 emp_name varchar2(10), 4 manager_id number 5 ); Table created. SQL> ed Wrote file afiedt.buf 1 create table my_mgr ( 2 manager_id number primary key, 3 employee_id number references my_emp( emp_id ), 4 purchasing_authority number 5* ) SQL> / Table created. SQL> alter table my_emp 2 add constraint fk_emp_mgr foreign key( manager_id ) 3 references my_mgr( manager_id ); Table altered. SQL> ed Wrote file afiedt.buf 1 select level lvl, 2 child_table_name, 3 sys_connect_by_path( child_table_name, '/' ) path 4 from (select parent.table_name parent_table_name, 5 parent.constraint_name parent_constraint_name, 6 child.table_name child_table_name, 7 child.constraint_name child_constraint_name 8 from user_constraints parent, 9 user_constraints child 10 where child.constraint_type = 'R' 11 and parent.constraint_type = 'P' 12 and child.r_constraint_name = parent.constraint_name 13 union all 14 select null, 15 null, 16 table_name, 17 constraint_name 18 from user_constraints 19 where constraint_type = 'P') 20 start with child_table_name = 'MY_EMP' 21* connect by prior child_table_name = parent_table_name SQL> / ERROR: ORA-01436: CONNECT BY loop in user dataIf you have a cycle, you have some problems.
(1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on
SQL> ed Wrote file afiedt.buf 1 select level lvl, 2 child_table_name, 3 sys_connect_by_path( child_table_name, '/' ) path 4 from (select parent.table_name parent_table_name, 5 parent.constraint_name parent_constraint_name, 6 child.table_name child_table_name, 7 child.constraint_name child_constraint_name 8 from user_constraints parent, 9 user_constraints child 10 where child.constraint_type = 'R' 11 and parent.constraint_type = 'P' 12 and child.r_constraint_name = parent.constraint_name 13 union all 14 select null, 15 null, 16 table_name, 17 constraint_name 18 from user_constraints 19 where constraint_type = 'P') 20 start with child_table_name = 'MY_EMP' 21* connect by nocycle prior child_table_name = parent_table_name SQL> / LVL CHILD_TABLE_NAME PATH ---------- ------------------------------ -------------------- 1 MY_EMP /MY_EMP 2 MY_MGR /MY_EMP/MY_MGR 1 MY_EMP /MY_EMP 2 MY_MGR /MY_EMP/MY_MGR(2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.
-Generate the DDL for all tables without constraint
-Can generate the DDL for all primary key constraints
-Can generate the DDL for all unique key constraints
-Can generate the DDL for all foreign key constraintsThis is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.
Justin
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How to find the snid? If it is removed or deleted from this sticker on the back?
How to find the snid and sn & id of the laptop if it is removed or deleted this sticker on the back?
My laptop is acer ferrari 1000
Tools Information as SIW system reports the product name and serial number IF this information is stored somewhere in the computer.
I don't know what you mean by 'id', but for example, all the following values are reported by SIW:
Manufacturer
Name of the product
Version
Serial number
Type of machine
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DMI system UUID
UUID
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