How to find the third element table pl/sql ina

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  Error from the 1 in the command line:
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  madala03 wrote:

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  SUM(BYTES/1024/1024)

  --------------------

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• How to find the size of the partitioned tables?

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  Hello
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• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
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  .
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  Thought...
  We will share!
  
  Thanks in advance,
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  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How to find the second largest in a pl/sql table

  Hello friends,
  
  I want to find the first and second maximum items in a pl/sql table.
  
  Here's the code...
  
  DECLARE
  Max_earnings_type TYPE TABLE IS NUMBER;
  max_earnings_tab max_earnings_type: = max_earnings_type();
  number of v_count: = 0;
  number of v_max_earnings;
  
  
  Can someone give me how to find the maximum first max and second in the type of the given table.
  
  appreciate your help.
  
  Thank you/kumar
  
  Published by: kumar73 on October 21, 2010 09:42

  kumar73 wrote:

  When I tried to implement your logic in my application, I get the following error...

  PL/SQL: digital or value error: NULL index key value table

  What happens if the PL/SQL table has NULL values. Question is how you want to handle NULL values. You want to ignore nulls as GROUP BY do? If you want to consider NULL values, you can say if you want to order the NULLS FIRST or NULLS LAST. I guess that logical GROUP BY:

  DECLARE
      TYPE max_earnings_type IS TABLE OF NUMBER;
      TYPE max_earnings_sorted_type IS TABLE OF NUMBER
        INDEX BY BINARY_INTEGER;
      max_earnings_tab        max_earnings_type;
      max_earnings_tab_sorted max_earnings_sorted_type;
  BEGIN
      SELECT  sal + comm
        BULK COLLECT
        INTO  max_earnings_tab
        FROM  emp;
      FOR v_i in 1..max_earnings_tab.count LOOP
        IF max_earnings_tab(v_i) IS NOT NULL
          THEN
            max_earnings_tab_sorted(max_earnings_tab(v_i)) := 1;
        END IF;
      END LOOP;
      DBMS_OUTPUT.PUT_LINE('MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.last),'NULL'));
      DBMS_OUTPUT.PUT_LINE('Second MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.prior(max_earnings_tab_sorted.last)),'NULL'));
  END;
  /
  MAX value in PL/SQL table is 2650
  Second MAX value in PL/SQL table is 1900
  
  PL/SQL procedure successfully completed.
  
  SQL> SELECT  sal + comm
    2    FROM  emp;
  
    SAL+COMM
  ----------
  
        1900
        1750
  
        2650
  
        1500
  
    SAL+COMM
  ----------
  
  14 rows selected.
  
  SQL>
  

  SY.