How to find the Unique universal disc identifier?

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• How to find the unique index to break the record?

  Hello

  When I do an UPDATE on a table how can I accumulate documents violates a unique index on the table? Is there something like "EXCEPTIONS IN" when using ALTER TABLE MODIFY CONSTRAINT... ENABLE VALIDATE EXCEPTIONS IN...?

  Oracle DB 10g

  Look in the logging of DML errors

  ORACLE-BASE - DML Oracle 10 g Release 2 of the database connection error

• I make new the old id must paasward wen apple id I go passward, says your id or passward not at even I have received emails but get no email how to find the solution, I, m stuck wat to do

  I make new the old id must paasward wen apple id I go passward, says your id or passward not at even I have received emails but get no email how to find the solution, I, m stuck wat to do

  Have you tried to reset it in security issues? If you are not able to do so, contact Apple support so a security identifier Apple Advisor can help you. 800-275-2273.

• How to find the velocity of an incremental encoder

  I use the RE22I encoder which can give up to 8192 pulses per revolution, I have A, B, Z reports that I use an fpga as a controller Please help me.

  How to find the speed of the encoder using these signals I'm going to have a clock in the fpga sysytem will help.

  Start by looking at the information on Wikipedia on the rotary encoders and a book on encoders OR white.  These articles will give you a basic understanding of the encoder and the signals it produces.

  With proper decoding, you can get the direction and momentum of each of the points on your encoder 8192.  If the tree can reverse (same vibration on one point unique all-in-mnearly stationary), full decoding must be used.  If data are only of interest while the tree turns in a direction and speed will not close to zero, a simple decoding can be used.  Decoding of a quadrature encoder is a good way to learn to use a state machine.  Signals A and B can exist in only four possible combinations, but the possible transitions to do interesting things.

  Define DECODING is a purely logical exercise and it is a simple coding in LabVIEW, such as a state machine.  There are examples, Desing Patterns, or project templates (depending on your version of LV) that come with LV to help you get started.

  By using the channels A and B you can update your calculation of velocity 8192 times per turn.  With the help of Z you get only an update by the revolution. You use depends on your application.  The pulse of Z is also useful to define a reference position for the measurement of phase angle.

  Lynn

• How to find the position of the VI icon currently run on the block diagram of the appellant

  Dear forum,

  I am currently trying to use a LabVIEV VI as a simple sequencer: several (very slow) actions must run one after the other. Each action is represented by a Sub - VI, some actions are executed several times. My task is to view the Subvi somehow executing.

  My first intention (just manipulate the icon of the VI running with 'Icon.Get VI as Image data' / 'Icon.Set VI of Image data' invoke nodes) has failed, because it changes all instances of the VI icon. If you use the same VI several times, all these VI icons are changed (see here: http://forums.ni.com/t5/LabVIEW/How-to-change-animate-icon-of-currently-running-VI/m-p/3120754/highl... )

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  Kind regards

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• How to find the size of the virtual server?

  Hello

  We intend to pass our applications 4 virtual servers has 2 physical servers. In this process, we need to identify the size of the current virtual servers to use as a starting point to configure or add the size in physical server. can anyone provide information on whats stats to be noticed and how to find the size of the current virtual servers?

  Thank you

  Hi Sekhar, there.

  in general, it is a fairly complex task if you want to size the new platform correctly, i.e. not to oversize it and have very low use below, i.e. spend too much on equipment.

  In fact, it's the first thing to consider the level of use of the new platform. Most likely your organization (HW and infrastructure) has targets to a minimum. optimal and maximum usage levels.

  In the case where you do not have this as a starting point, and then you continue with load average and the current peak (CPU, RAM, NW). To these basic lines, you can use the statistics of WLS Admin Console, where the use of CPU and memory statistics are presented since the server was last started. For more detailed statistics, you can use WLDF to capture measures key at regular intervals, and then base your analysis of these data.

  Finally and above all, the size of FS, but I've seen some comments above related to the size of the FS.

  HTH,

  A.

• How to find the OS ppid in v$ session and V$ process

  Hello
  
  Oracle 11gDB
  
  I have this suspiscious process in my session of $ v which is always running and connected to a 'HR' scheme, even if the 'HR' application is also stopped and other HR related batch process.
  And he also told me that it came from the UNIX sun-server1. My problem is that I can not locate the PPID OS for this process when I login to the operating system to the Sun-server1.
  I tried to kill this session, but he maintains the connection. Even if I bounce the database, it come back.
  
  How to find the source of this process to the Sun-server1?
  
  I tried this script:
  

  SELECT     p.program, p.spid
  FROM v$session s, v$process p
  WHERE s.paddr = p.addr
  AND s.sid IN (39)

  Program                                                 Spid
  ============    ====
  ORACLE.EXE (SHAD)     6404

  But if I have a ps - ef | grep 6404 there is no existing process OS. No matter what other script that can identify the process id of the operating system?
  
  
  Thank you very much

  KinsaKaUy? wrote:
  Thanks Sb, what is your new name :)

  Who do you think is the culprit?

  root@sun-server1 # ps -ef|grep "May 16"
  v231sys  7065  7051   0   May 16 pts/1      11:16 /usr/jdk/jdk1.5.0_13/bin/sparcv9/java -server -Xms1024m -Xmx1024m -XX:MaxPermSi
  v231sys  7051     1   0   May 16 pts/1       0:00 /bin/sh startWebLogic.sh V231_ABDC
  root 13117 11928   0 12:56:30 pts/3       0:00 grep May 16
  v231sys  7229  7065   0   May 16 pts/1       1:17 /opt/SPLcobAS51/bin/cobjrun64 -Dcom.microfocus.cobol.cobjvm=sun_150_64 -DSPLCJV
  v231sys  6257  8518   0   May 16 pts/1       0:00 bash
  v231sys  7211  7065   0   May 16 pts/1       1:17 /opt/SPLcobAS51/bin/cobjrun64 -Dcom.microfocus.cobol.cobjvm=sun_150_64 -DSPLCJV
  

  When the process lasts more than 24 hours, you can get is no longer hours or minutes.
  You can use the utility "netstat" to connect the source & destination?

  If this isn't the case, random randomly start put to death via kill - 9 until you success!

• How to find the SCP to a java card

  Hello
  
  How will I know if a java card uses SCP01 and SCP02?
  Because I read the respose data returned by the Init setting command suite updated map, but it comes to send back more info back to entity of off - map:
  Main data of diversification 10 bytes
  2-byte key information
  Challenge map 8 bytes
  Cryptogram of card 8 bytes
  
  And in the same GP2.2 E.1.2.1 , it is written that
  This cryptogram of the card as well as the meter of the sequence, the challenge of the card, the secure channel protocol identifier,
  and other data are sent to the entity of off - map.
  I want to know how to find the SCP protocol identifier?
  
  In addition, it is written that:
  As the entity of off - map should now have the same information as the card used to generate the cipher of the card.
  It should be capable of generating the same session key and the cipher card even and performing a comparison.
  It is able to authenticate the card.
  
  Can someone explain please how to generate these keys and check the card?
  
  Thank you

  Umer says:
  I also found that the SCP is found in the Init-setting control response to date.

  It's also a good way to get the PCs?

  Yes. That's what I use. It does not give you the value of i (current hit is I = 15), but this is not a very big deal in practice (in my code anyway).

  See you soon,.
  Shane

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How to find the drive assigned to ASM diskgroup

  Hi all
  I created some ASM disks and do not know if I attributed to a diskgroup. Please may I know how to find the disc by ASM diskgroup or free on the disk that can be used.
  
  
  Thank you.

  Hello

  You must make reference to:
  http://download.Oracle.com/docs/CD/B28359_01/server.111/b31107/asmdiskgrps.htm#CHDIBGGH
  If you scroll down a bit you'll find: "groups example 4-3 look at a disk with associated disks.

  You can also check more specifically:
  http://www.Stanford.edu/dept/ITSS/docs/Oracle/10G/server.101/b10755/dynviews_1019.htm

  HTH,
  Thierry

• How to find the employee is rehired

  Hello
  
  How to find the employee is rehired?
  
  through Front End and back End
  
  Thank you.

  You're looking to identify if an employee was re-employed, or looking to find all employees who were rehired?

  To determine if an employee was re-employed:
  (1) place you * HRMS Manager > people > enter & maintain
  (2) look at the employee's most recent Start Date field
  (3) compare this to their first Date field engaged in the Services tab

  If the two are different, it means that the employee was re-employed.

  Technically, each period of employment is linked to their period of Service. They will be on the per_periods_of_service table. So, there are 3 rows in per_periods_of_service if an employee was re-employed twice (that is to say, initially engaged and then reembauche twice).

  I hope this helps.

• How to find the user Apex table

  Hello
  
  Please let me know, how to find the user apex table. I need validate the unique user based on the same, for which I use below function.
  
  DECLARE
  VAL A BOOLEAN;
  BEGIN
  VAL: = APEX_UTIL.IS_USERNAME_UNIQUE (p_username =
  (: P6_USERNAME);
  END;
  
  However, in this case, he always comes back "FALSE," saying new user exists.
  
  Kindly help me in fixing this problem.

  There is a view called apex_workspace_apex_users.

  Details under Home > utilities > Application Express views

  André

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  In bookmarks menu select organize bookmarks to open the bookmarks library. In the bookmarks library, click views, and then display the columns and then added. This will display a column showing when a bookmark has been added.