How to generate xml with CDATA from a query

Similar Questions

• generate xml with levels data

  Hello
  
  I have a tlable like that
  
  Desription level value
  1 dept
  2 name of the King
  3 salary 3000
  3 something information
  
  So I want to generate xml according to the levels output, the output schould be
  < Dept >-> level 1
  < name > King-> level 2
  < > 3000 salary < / salary >-> Level3
  < Info > something < / info >-> Level3
  < / name >
  < / dept >
  
  I tried to use the XMLELEMENT function... without success, I realize that with Oracle xml functions?
  
  MDK.

  Please always provide your version of the database. It is easier for us to provide an appropriate response.

  Here are some ways that work on 10.2.0.4 (and probably high too):

  (1) implement a recursive function in XQuery
  (2) using the DBMS_XMLGEN.newContextFromHierarchy function

  Connected to Oracle Database 10g Enterprise Edition Release 10.2.0.4.0
  Connected as marc
  
  SQL>
  SQL> create table emp (
    2   lvl number,
    3   descr varchar2(30),
    4   val   varchar2(100)
    5  );
  
  Table created
  
  SQL> insert into emp values(1, 'dept', null);
  
  1 row inserted
  
  SQL> insert into emp values(2, 'name', 'King');
  
  1 row inserted
  
  SQL> insert into emp values(3, 'salary', '3000');
  
  1 row inserted
  
  SQL> insert into emp values(3, 'info', 'something');
  
  1 row inserted
  
  SQL> set long 500
  SQL>
  SQL> select xmlquery(
    2  'declare function local:getHierarchy($start-with as xs:integer)
    3   {
    4     for $i in ora:view("EMP")/ROW[LVL=xs:string($start-with)]
    5     return element {$i/DESCR}
    6     {
    7       $i/VAL/text(),
    8       local:getHierarchy(xs:integer($i/LVL)+1)
    9     }
   10   }; (: :)
   11   local:getHierarchy(1)'
   12   returning content
   13  ) as result
   14  from dual;
  
  RESULT
  --------------------------------------------------------------------------------
  
     King3000something
  
  

  
  SQL> select dbms_xmlgen.getXML(
    2    dbms_xmlgen.newContextFromHierarchy(
    3     'select level, xmlelement(evalname(descr), val) from emp
    4     connect by prior lvl = lvl-1 start with lvl = 1'
    5    )
    6  ) as result
    7  from dual;
  
  RESULT
  --------------------------------------------------------------------------------
  
  
    King
      3000
      something
    
  
   
  

  Published by: odie_63 on Dec 27. 2010 18:27

• How to generate a working executable from the example of writer DataSocket VI file

  I am trying to build an executable file of the example "DS Writer.vi".  The first problem was that the "Control.vi of DataSocket Server" was not distributed with my script compile/install.  I fixed it (thanks Dennis) but now I get the following error message.

  LabVIEW: (Hex 0 x 626) cannot open a VI with compiled code separate in a Run Time Engine that does not have access to the VIObjCache.

  There is a solution to this (http://forums.ni.com/t5/LabVIEW/Getting-LabVIEW-load-error-code-59-using-LabVIEW-2010-with-a-Run/td-...), but it involves change a property of a VI library of DataSocket (if I understand though).  I'm reluctant to make a change to a library OR standard, because it could cause maintenance problems in the future (other developers not having the same change, or updated versions of LabVIEW).

  Has anyone successfully built an executable using DataSocket?  If so, can you offer any advice?  I'm using LabVIEW 2011.

  Thank you, Mark

  Thanks Nathan.  I was able to create and deploy an executable with DataSocket.  The last obstacle was to "uncheck the option"Code is compiled separately from the source file"in the properties of the VI" for the "DataSocket Server Control.vi.  The only problem with this solution is that I now have a custom DataSocket library.  I think that a solution would be to copy as VI or library in my project folder so that the solution is transferable to others in the future.  I would like to hear how other developers LabVIEW with custom libraries, either by strictly avoid that, keeping their own copies, or another solution.  But this is probably a topic for a new thread.

• How to generate URLS with several variables of input fields?

  I create an ad with four text fields labels fname, lname, city and province, and I wanted to know how to generate URLS based on the information entered in the fields. The text of the default fields to display "Name," "Last Name", "City" and "State", respectively, but if a user does not enter information in these fields, I want the URL to behave as if those who were empty, if that makes sense. Text fields are in a clip called 'input_text' and the button is titled 'send '. If any of you can provide insight, I would greatly appreciate. Thank you.

  1 use the instructions to see if if the properties your textfields text meets your requirements for the creation of this url.

  2. you can use the properties and methods string flash to create your url.

  p.s. the + sign can be used to concatenate strings.

• How to add xml with existing xml content

  Hello

  I have a requirement where I need to add the xml with the existing xml content.

  For example: this is the entry that I get every time in a loop for

  in loop1:

  < ParentType >

  < a > < /A > abcd

  < B > < /B > abcd

  < / ParentType >

  loop2 once again I get this entry.

  < ParentType2 >

  ABCD < c >/< c >

  ABCD < d >/< d: >

  < / ParentType2 >

  now my requirement is to add this XML in a variable, which is finally at the end of the loop for it should look like this

  < ParentType >

  < a > < /A > abcd

  < B > < /B > abcd

  < / ParentType >

  < ParentType2 >

  ABCD < c >/< c >

  ABCD < d >/< d: >

  < / ParentType2 >

  Thank you

  Solved my problem.

• How to generate XML from database data using a procedure?

  Hello

  I want to generate output as xml to database tables using a procedure. Can anyone suggest me on how to do this?

  Thanks for your time.

  Reel for the XML script

• How to generate XML nested using PL/SQL data?

  I have an XML that looks like this file...
  
  <? XML version = "1.0"? >
  < TDefs >
  < ListItem >
  < TDef >
  < DisplayName > AFP < / DisplayName >
  < enabled > True < / enabled >
  < LISName > AFP < / LISName >
  < LOINC / >
  < PrintName > AFP < / PrintName >
  < CompatibilityCode > 1 < / CompatibilityCode >
  < details >
  < PatientReplicates > 1 < / PatientReplicates >
  < AutoReDilute > false < / AutoReDilute >
  < / details >
  < DilutionList >
  < TDefDilution >
  < dilution > 1 < / Dilution >
  < CalculationFactor > 1 < / CalculationFactor >
  < / TDefDilution >
  < / DilutionList >
  < TDefRange >
  < RangeList >
  < RangeInfo >
  < ID >
  < int > 6509 < / int >
  < /ID >
  < name >
  < string > check Range2 < / string >
  < / name >
  < Name_MessageID >
  < int >-1 < / int >
  < / Name_MessageID >
  < IsNull RepeatedlyReactiveData = "true" / >
  < IsNull RepeatedlyReactiveComments = "true" / >
  < CreatedByIM >
  < Boolean > true < / Boolean >
  < / CreatedByIM >
  < / RangeInfo >
  
  This is data that are from different tables. It is a multilevel nested nodes each other.
  How do I achieve using PL/SQL? What is the best way?
  
  I've only used to date dbms_xmlgen to generate data from a single table.
  Can anyone help?

  How do I achieve using PL/SQL? What is the best way?

  SQL/XML functions.

  For example: {message identifier: = 9670705}

  After a few data structures and table (DDL) samples if you need specific help on the query.

• How to load xml with base64 big element using sqlldr

  Hello
  I'm trying to load xml data into Oracle 10 g 2. I want to use tool standard sqlldr if possible.
  (1) I recorded my schema successfully:
  -Put the 6kbytes schema in a table
  - and
  DECLARE
  schema_txt CLOB.
  BEGIN
  SELECT the text IN schema_txt patterns;
  DBMS_XMLSCHEMA.registerschema ("uddkort.xsd", schema_txt);
  END;
  -Success: I can create table like:
  CREATE TABLE XMLTYPE XmlTest
  XMLSCHEMA 'uddkort.xsd '.
  ELEMENT 'profile '.
  ;
  -USER_XML_TABLES shows:
  XMLSCHEMA, SCHEMA_OWNER, NOM_ELEMENT, TABLE_NAME, STORAGE_TYPE
  "XMLTEST", "uddkort.xsd", "THISE", "profile", "OBJECT-RELATIONAL".
  
  (2) how can I load XML data into that?
  -An element of the schema is < xs: element name = "billede" type = "xs: base64Binary" minOccurs = "0" / >
  -This data field may be 10kbytes or more
  
  I tried many control files - search the net but no luck so far.
  Any suggestions?
  / Christmas, DK

  I regret - it seems, Miss me some basic understanding here (XBD is new to me...):

  Reread this part of the documentation on the XML to mappings of SQL types:
  http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14259/xdb05sto.htm#sthref831

  When you save the relational storage schema object, Oracle creates SQL object types to support the underlying structure.
  In particular (see table 5-6 in the link), XS: base64Binary is mapped to a compatible SQL binary data type: RAW (default), or BLOB (if we use the annotation).

  In my example, the generated object type is:

  SQL> desc "image888_T"
   Nom                                       NULL ?   Type
   ----------------------------------------- -------- ----------------------------
   SYS_XDBPD$                                         XDB.XDB$RAW_LIST_T
   name                                               VARCHAR2(4000 CHAR)
   content                                            BLOB
  

  I don't understand how this can be (is) done automatically?

  When you load an XML instance in the table, the contents of the string encoded in base64 is automatically converted into format binary original and stored as a BLOB (that's works the mapping).
  Then, when you run:

  select extractvalue(t.object_value, '/image/content') from images_table t;
  

  It follows a BLOB column containing the original image, not the string base64, so you won't need a converter.

• How to integrate Xml with OFA Editor?

  How the report to integrate Xml Publisher with the OA Framework?
  
  Thank you
  Kumar

  Hello

  Refer

  http://apps2fusion.com/at/51-PS/260-integrating-XML-Publisher-and-OA-framework

  http://oraclearea51.com/articles/64-OAF-Beginners-Guide/236-integration-of-XML-Publisher-with-OAF-generating-output-in-PDF-MSWord-MSExcel-and-HTML-format.html

  -Anand

• How the XML element used in RTF PUBLIC/PRIVATE? I know how to hide columns in RTF, but do not know how to generate xml below way. Help, please.

  Hello

  I'm following link below to show/hide my columns dynamically. See "formatting of column.

  http://docs.Oracle.com/CD/E12844_01/doc/BIP.1013/e12187.PDF

  According to the doc element can be made in private/public.

  <items type="PUBLIC">
   <item>
    <name>Plasma TV</name>
    <quantity>10</quantity>
    <price>4000</price>
   </item>
   <item>
  

  And even can be used to hide the column with the help of State

  <?if@column:/items/@type="PUBLIC"?>
  

  MY QUESTION IS HOW TO DO THIS IN MY XML BELOW?

  Here's the part of my XML code that I use in the definition of the data to RTF.

  <group name="GH3" source="QH3">
  <element name="COLUMN_HEAD3" value="COLUMN_NAME" /> 
  </group>
  <group name="GH4" source="QH4">
  <element name="COLUMN_HEAD4" value="COLUMN_NAME" /> 
  </group>
  

  I'm out like that.

  <LIST_GH3>
  <GH3>
  <COLUMN_HEAD3>REBILL_TO_OTHER_BUSINESS_UNIT</COLUMN_HEAD3>
  </GH3>
  </LIST_GH3>
  <LIST_GH4>
  <GH4>
  <COLUMN_HEAD4>XYZ</COLUMN_HEAD4>
  </GH4>
  </LIST_GH4>
  

  In order to use the logic according to the oracle document I want output like this.

  <LIST_GH3 type="PUBLIC">
  <GH3>
  <COLUMN_HEAD3>REBILL_TO_OTHER_BUSINESS_UNIT</COLUMN_HEAD3>
  </GH3>
  </LIST_GH3>
  <LIST_GH4 type="PRIVATE">
  <GH4>
  <COLUMN_HEAD4>BLANK</COLUMN_HEAD4>
  </GH4>
  </LIST_GH4>
  

  Should what changes I make in my XML to get the result of the execution as above? Help, please. Where should I make changes in the XML above? Name of the Group? Name of the element?

  I intend to use it under condition in RTF model to hide the column, but do not know how to set the column as PRIVATE/PUBLIC type in the XML output that is used to populate the data in the RTF while running.

  <?if@column:/BTSPIEXP/LIST_GH3/@type=”PUBLIC”?>COLUMN_HEAD3<?end if?>
  

  Kind regards

  Patricia K.

  Hello

  Problem has been resolved. I used the value of the item to determine whether to show it.

  Kind regards

  Patricia K.

• How to extract xml with namespaces

  Hi all
  
  Here's the XML I:
  
  <? XML version = "1.0" encoding = "UTF-8"? >
  -< transaction xmlns: xsi = "http://www.w3.org/2001/XMLSchema-instance" xmlns = "http://schemas.test.com/Support/Services/test1/2012" xsi: schemaLocation = "http://schemas.test.com/Support/Services/test1/2012 Support.test1.v1.xsd" >
  -< application >
  < > 10 Sam < / Sam >
  < > 32 Actid < / Actid >
  < Pax > 3 < / Pax >
  < > 10 - DEC - 2012 Flt < / Flt >
  < user name > WebUserNameTest < / name >
  < / request >
  < application >
  < Sam > 1 < / Sam >
  < Actid > 3 < / Actid >
  < > 2 Pax < / Pax >
  < Flt > 2012 - dec - 12 < / Flt >
  < user name > WebUserNameTest < / name >
  < / request >
  < / transaction >
  
  I need to extract the item values:
  
  The code below will help me when I have no namespace, what needs to be done in order to work with the value of the element namespace and etract
  
  v_string_xml: =.
  ' / / Query [' |] To_char (counter_xml) | '] / Sam / text () ';
  v_ssp_table (v_ssp_table. COUNTY) .memid: =.
  p_xml_in. EXTRACT (v_string_xml) .getnumberval ();
  
  v_string_xml: =.
  ' / / Query [' |] To_char (counter_xml) | '] / Actid / text () ';
  v_ssp_table (v_ssp_table. COUNTY) .actid: =.
  p_xml_in. EXTRACT (v_string_xml) .getnumberval ();
  
  v_string_xml: =.
  ' / / Query [']
  || To_char (counter_xml)
  || '] / Pax / text () ';
  v_ssp_table (v_ssp_table..) Pax COUNT): =.
  p_xml_in. EXTRACT (v_string_xml) .getnumberval ();
  
  v_string_xml: =.
  ' / / Query [' |] To_char (counter_xml) | '] / Flt / text () ';
  v_ssp_table (v_ssp_table..) Flt COUNT): =.
  p_xml_in. EXTRACT (v_string_xml) .getstringval ();
  
  v_string_xml: =.
  ' / / Query [']
  || To_char (counter_xml)
  || '] / Username / text () ';
  v_ssp_table (v_ssp_table. COUNTY) .username: =.
  p_xml_in. EXTRACT (v_string_xml) .getstringval ();
  
  Published by: akm006 on March 19, 2013 11:11

  Try

  SQL> declare
    2  x xmltype := xmltype('
    3  
    4  
    5  10
    6  32
    7  3
    8  2012-DEC-10
    9  WebUserNameTest
   10  
   11  
   12  1
   13  3
   14  2
   15  2012-DEC-12
   16  WebUserNameTest
   17  
   18  ') ;
   19
   20  v_string_xml varchar2(100);
   21  v_string_xml_ns varchar2(500);
   22  v_ssp number;
   23  counter_xml number := 1;
   24  begin
   25
   26  v_string_xml := 'Transaction/Request[' || TO_CHAR (counter_xml) || ']/Memid/text()';
   27
   28  v_string_xml_ns :='xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.test.com/Support/Services/test1/2012"';
   29
   30  v_ssp := x.EXTRACT(v_string_xml,v_string_xml_ns).getnumberval();
   31
   32  dbms_output.put_line(v_ssp);
   33
   34  end;
   35  /
  
  10
  
  PL/SQL procedure successfully completed
  
  SQL>
  

• How can you livechat with someone from Apple

  HOOOWWWWWW. _.   GRR

  See this link: https://www.apple.com/support/

  Depending on the question and your cat location are not available. -AJ

• How to generate an xml file?

  I just starting to learn how to generate xml data with the actionscript here is what I have so far:

  var xml =
  < ErikPhotos >
  < / ErikPhotos >;
  
  so that {(xml.photo.length (< 20))
  var point: XML = < photo / >;
  DevBlog var = xml.photo.length () + 10001;
  Item.@name = photoIndex.toString () .substr (1);
  xml.appendChild (item);
  }

  trace (XML);

  If I followed what I get:

  < ErikPhotos >
  < name photo = "0001" / >
  < name photo = "0002" / >
  < name photo = "0003" / >
  < name photo = "0004" / >
  < name photo = "0005" / >
  < name photo = "0006" / >
  < name photo = "0007" / >
  < name photo = "0008" / >
  < name photo = "0009" / >
  < name photo = "0010" / >
  < name photo = "0011" / >
  < name photo = "0012" / >
  < name photo '0013' = / >
  < name photo = "0014" / >
  < name photo = "0015" / >
  < name photo = "0016" / >
  < name photo = "0017" / >
  < name photo = "0018" / >
  < name photo = "0019" / >
  < name photo = "0020" / >
  < / ErikPhotos >

  that is what I wanted... So far so good.  Now I want to do is make the script write a real xml file which will be in my directory after you run the script.

  If this isn't a web-based application, you can use adobe air.

• How to generate an xml document with a BLOB on the inside?

  Hello

  Using the Oracle 11 g Release 11.2.0.4.0 database, I actually use dbms_xmldom to generate xml data.

  When generated, it is sent using utl_http.

  All right, except that I have to include a child that contains a BLOB (stored in the database) in the exact way that it is stored in the XML structure.

  (Field value contains an encoded 64 base pdf file). Length of the file can be up to 2 MB

  My nearest solution was to Convert Oracle XML BLOB to type even if I'm really stuck with LPX-00210 error.

  Is there another way than dbms_xmldom do?

  In fact, I'm totally lost.

  Can you give me a hand on this or show me an example of work?

  Kind regards

  Stone

  Here goes...

  SQL> create table images (
    2    id       integer
    3  , name     varchar2(256)
    4  , content  blob
    5  );
  
  Table created
  
  SQL>
  SQL> declare
    2
    3    bf          bfile := bfilename('XML_DIR','base64.bin');
    4    lob_ptr     blob;
    5    dest_offs   integer := 1;
    6    src_offs    integer := 1;
    7
    8  begin
    9
  10    insert into images (id, name, content)
  11    values (1, 'Koala.jpg', empty_blob())
  12    returning content into lob_ptr;
  13
  14    dbms_lob.open(bf, dbms_lob.lob_readonly);
  15    dbms_lob.loadblobfromfile(lob_ptr, bf, dbms_lob.getlength(bf), dest_offs, src_offs);
  16    dbms_lob.close(bf);
  17
  18  end;
  19  /
  
  PL/SQL procedure successfully completed
  
  SQL> commit;
  
  Commit complete
  
  SQL>
  SQL> select id
    2       , name
    3       , utl_raw.cast_to_varchar2(dbms_lob.substr(content, 30)) as first_bytes
    4       , dbms_lob.getlength(content) as lob_size
    5  from images
    6  /
  
     ID NAME         FIRST_BYTES                      LOB_SIZE
  ----- ------------ -------------------------------- ----------
      1 Koala.jpg    /9j/4AAQSkZJRgABAgEAYABgAAD/7g      1068504
  
  SQL>
  SQL> declare
    2
    3    x_doc       xmltype;
    4    domdoc      dbms_xmldom.DOMDocument;
    5    domnode     dbms_xmldom.DOMNode;
    6    domtext     dbms_xmldom.DOMText;
    7    ostream     sys.utl_BinaryOutputStream;
    8    chunksize   pls_integer;
    9    offset      pls_integer := 1;
  10    buf         raw(32767);
  11    image       blob;
  12
  13  begin
  14
  15    select xmlelement("image",
  16             xmlelement("id", t.id)
  17           , xmlelement("name", t.name)
  18           , xmlelement("content")
  19           )
  20         , t.content
  21    into x_doc
  22       , image
  23    from images t
  24    where t.id = 1 ;
  25
  26    domdoc := dbms_xmldom.newDOMDocument(x_doc);
  27
  28    -- get /image/content node so that we can append a text node and stream the BLOB to it :
  29    domnode := dbms_xslprocessor.selectSingleNode(dbms_xmldom.makeNode(domdoc), '/image/content');
  30    domtext := dbms_xmldom.createTextNode(domdoc, null);
  31    domnode := dbms_xmldom.appendChild(domnode, dbms_xmldom.makeNode(domtext));
  32
  33    ostream := DBMS_XMLDOM.setNodeValueAsBinaryStream(domnode);
  34    chunksize := dbms_lob.getchunksize(image);
  35
  36    loop
  37      begin
  38        -- read BLOB in chunk of  :
  39        dbms_lob.read(image, chunksize, offset, buf);
  40      exception
  41        when no_data_found then
  42          exit;
  43      end;
  44      -- write chunk to DOM node :
  45      ostream.write(buf, chunksize);
  46      offset := offset + chunksize;
  47    end loop;
  48
  49    ostream.flush();
  50    ostream.close();
  51
  52    dbms_xmldom.writeToFile(domdoc, 'XML_DIR/image.xml');
  53    dbms_xmldom.freeDocument(domdoc);
  54
  55  end;
  56  /
  
  PL/SQL procedure successfully completed
  

  Image.xml release:

  
    1
    Koala.jpg
    /9j/4AAQSkZJRgABAgEAYABgAAD/7gAOQWRvYmUAZAAAAAAB/+EUI0V4aWYAAE1NACoAAAAIAAcB
  MgACAAAAFAAAAGIBOwACAAAABwAAAHZHRgADAAAAAQAEAABHSQADAAAAAQA/AACcnQABAAAADgAA
  AADqHAAHAAAH9AAAAACHaQAEAAAAAQAAAH0AAADnMjAwOTowMzoxMiAxMzo0ODoyOABDb3JiaXMA
  ...
  aWpkRY6dqaJY42qFjs8ZZ5nlkjZpmJUiJ1+ijn3dVeTtb4B1R5NJVaEkn/V8+u4Xijpp6SFlimp6
  qNHgjlVIgrtLCyxll1NpaT6An6W92mA8HwkyadMeEZJjEDmvE/t/1f5uv//Z
  
  

• I have a large collection of big slideshows in iPhoto, created over the years with captions from the titles of the photos. How can I keep these slide shows subtitled in Photos?

  I have a large collection of big slideshows in iPhoto, created over the years with captions from the titles of the photos. How can I keep these slide shows subtitled in Photos?

  You can't keep slideshows as captioned photos.  Slide shows get migrated in the form of albums for the Group of photos is maintained.  But Photos don't have the ability to add descriptions to the slide show so that they would have to be manually added to each slide automatically.

  However, a possible solution would be to export every slide show in iPhoto as a Quicktime movie file. Which will keep the titles and descriptions on each slide.  The resulting QT files can be imported into the iPhoto library before migration or photo library after.