How to get 30 days trail vision?

Hi support them.

I am a new user, I wonder know how I can get the vision of 30-day track?

Please advise,

Thank you

Bing

You can download 30 days free trial of Acrobat Pro DC using this link Download Adobe Acrobat products. Standard, Pro | DC, XI, X.

Kind regards
Nicos

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Similar Questions

How to get the 'DAY' based on the territory of current account held a number between

Hi all

Looks like I'm at the end of my intelligence here but how to get the 'DAY' based on the territory of current account with a number between 1 and 7? Oracle has functions to extract the day of the week, but I can't find the other way around.

SQL> select * from v$version;

BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
CORE    11.2.0.3.0      Production
TNS for Linux: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production

SQL> alter session set nls_territory=AMERICA;

Session altered.

SQL> select to_char (sysdate, 'D') from dual;

T
-
3

SQL> alter session set nls_territory=GERMANY;

Session altered.

SQL> select to_char (sysdate, 'D') from dual;

T
-
2

I need a way to know that the number '3' on the database with NLS_TERRITORY = AMERICA means a 'Tuesday' or the number '2' on a database with NLS_TERRITORY = GERMANY means "Tuesday" as well.

Hope I am clear enough.

And wish you all a happy new year :)

Kind regards
Smail

Use the format "IW" to get the date of Monday and the format "DAY" to get the "first day of the week. Then compare dates to see if they are identical.

ALTER SESSION SET NLS_TERRITORY = 'AMERICA';

SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday",
TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week",
MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON"
FROM DUAL CONNECT BY LEVEL <= 7;

Monday    NLS First day of week 1 if day 1 = SUN, 0 if MON
--------- --------------------- --------------------------
31-DEC-12 30-DEC-12                                      1
24-DEC-12 30-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1
24-DEC-12 23-DEC-12                                      1

alter session set nls_territory = 'FRANCE';

SELECT TRUNC(SYSDATE-LEVEL, 'IW') "Monday",
TRUNC(SYSDATE-LEVEL, 'DAY') "NLS First day of week",
MOD(TRUNC(SYSDATE-LEVEL, 'IW') - TRUNC(SYSDATE-LEVEL, 'DAY') + 7, 7) "1 if day 1 = SUN, 0 if MON"
FROM DUAL CONNECT BY LEVEL <= 7;

Monday   NLS First day of week 1 if day 1 = SUN, 0 if MON
-------- --------------------- --------------------------
31/12/12 31/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0
24/12/12 24/12/12                                       0

Or it could be simpler:

ALTER SESSION SET NLS_TERRITORY = 'AMERICA';

WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
SELECT INPUT_DAY,
TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
from data;

INPUT_DAY Day label
--------- ------------------------------------
        1 SUNDAY
        2 MONDAY
        3 TUESDAY
        4 WEDNESDAY
        5 THURSDAY
        6 FRIDAY
        7 SATURDAY

alter session set nls_territory = 'FRANCE';

WITH DATA AS (SELECT LEVEL INPUT_DAY FROM DUAL CONNECT BY LEVEL <= 7)
SELECT INPUT_DAY,
TO_CHAR(TRUNC(SYSDATE, 'Day')+INPUT_DAY-1, 'DAY') "Day label"
from data;

INPUT_DAY Day label
--------- ------------------------------------
        1 MONDAY
        2 TUESDAY
        3 WEDNESDAY
        4 THURSDAY
        5 FRIDAY
        6 SATURDAY
        7 SUNDAY

How to get the day as a numeric value without the date in shape?
Hello
to reduce the costs of a sql statement, I need to get the day of a date under the number (to compare to a numerical value) value without formatting. Each formatting causes a complete table of the table scan and the date field. Is there a function for this problem?

Version of Oracle's 11g.

Thank you Carsten
You can use EXTRACT...
```
SQL> select extract(day from sysdate) from dual;

EXTRACT(DAYFROMSYSDATE)
-----------------------
                      7

SQL>
```

How to get the days and months when two dates are given
Hi all

I have a requirement where I need to return the number of months and days between two given dates.
I have no need to take account of the year as the difference in dates is always less than a year

I have 28 June 2012 and January 31, 2013, as dates.

I'm working on 10g

When I select the double months_between(:a,:b) and provide the dates he gives me 7.09677
I want to give only 7 months and 9 days, or what ever the exact days are.

Your contributions are appreciated
Try this:
```
WITH t AS
(SELECT TO_DATE('28-JUN-2012', 'DD-MON-YYYY') date1, TO_DATE('31-JAN-2013', 'DD-MON-YYYY') date2 FROM dual)
SELECT TRUNC(MONTHS_BETWEEN(date2, date1)) months,
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FROM   t
```

How to get which day is the first Monday of that day
I need to know what day is the first Monday of sysdate. Is it possible to know?
Hello

Use [NEXT_DAY | http://download.oracle.com/docs/cd/B12037_01/server.101/b10759/functions083.htm].
```
SQL> SELECT NEXT_DAY(SYSDATE,'MONDAY') FROM DUAL;

NEXT_DAY(
---------
02-NOV-09
```
Arun-

How to get the date in the exact day in the field when another?
Hello

Please help me how to get the day of the week using another date field.

In fact, a field (week_day) has 1,2,3,4,5,6,7 here 1-, 2 - KILL like this.
another field has the date. After this date, go to this particular week and need to pick up the date of the Etiquettemois above. It should be this week there himself.

Thanks in advance!

Kind regards
Florian...

Published by: Florian on October 29, 2010 03:07
Maybe it's
```
select trunc(date_field,'D') + week_field - 1 from table
```

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In addition, I used "IMAQ rake 3 VI", it can get every edge (from terminal to search for lines). However, it may not show these points gave rise to on the image, so I can't easily confirm or right side points.

Could someone help me on this issue: how to get all edge points coordination and watch them on the image. Think.

I found that the process could solve my problem: "Rake 3 vi (find first tacks)" and "overlay points (results)."

However, it seems a bit complex. Are there simple methods to achieve the same results? Could 'IMAQ find Edge' show all edges?

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How to get the last date of 3 days for the current month?
MY OUTPUT WOULD LOOK LIKE THIS
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JANUARY 31, 2016

GUYS HELP ME / / /...

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LAST_DAY)

---------

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The description of the problem seems a little unclear and I wish I had a better understanding before you start working on it. I would be grateful if you could help me with more information.
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- When was the last time it was working fine?
If you encounter problems with Windows Mail app, try the following steps.

Step 1:

Please go to the link below, download the file and run it.

Run applications troubleshooting

Download and run the troubleshooter modern UI App.

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I downloaded Acrobat Pro and paying by monthly subscription, but when I open a document I always get a window with a message 27 days remaining in your trial period. How to get rid of this message?

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How to get the last day of a month for every 2 months for a given period?

Hello
Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?
Thanks in advance.

Try the below

SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

END as lastweekday,

BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

-(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

END as lastweekendday,

BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

END AS lastmonday

FROM (SELECT SYSDATE startdate,

SYSDATE + 300 enddate

THE DOUBLE)

CONNECT BY LEVEL<=>

I canceled my account same day and join as convert PDF word has not converted correctly how to get credit for membership cancellation

I canceled my account same day and join as convert PDF word has not converted correctly how to get credit for membership cancellation

You need to contact Adobe customer service:

They will check and help you. (Live chat)

Contact the customer service

How to get the date - 7 days (week)
Hi all

I am beginner in Java and JSP

I'm JSP search form (VO) where I need to set a default value for the start_date - 7 days

OK I get this display today date but how to get that displays a date-7 days?

< %
DateFormat df = new SimpleDateFormat ("JJ. MM.yyyy");
Date date = new Date();
String default = 'StartDate =' + df.format (new Date());
% >

ID
Thank you
Simple approach if you're not worried about leap years: -.
```
Date todayMinus7 = new Date(System.currentTimeMillis() - 7 * 24 * 60 * 60 * 1000);
```
Alternatively take a look at the GregorianCalendar class and the add() method.

How to get the difference in dates in days
Hi friends,

How to get the date difference between two dates exactly

date2-date1 days exactly... shouyld rounded to the nearest value of...

and one entire display i mean positive integer
Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

This gives negative also result
Hello

776317 wrote:
Hi friends,

How to get the date difference between two dates exactly

date2-date1 days exactly... shouyld rounded to the nearest value of...

Date1 - date2 is the exact number of days is after date2 date1. (It is as accurate as possible, given that the DATEs do not have fractions of a second).

and one entire display i mean positive integer
Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

You want to probably get the exact number of days first, then ROUND this number:
```
SELECT  ROUND (SYSDATE - TO_DATE (date_start, ...))   AS days
FROM    per_periods_of_service; 
```
Always pass arguments at least 2 to TO_DATE:
(1) the string to be converted, and
(2) a saying string how (1) is formatted

This gives negative also result

Right; If date1 is before date2 then date1 - date2 returns a negative number.
If you want to never get a negative value, use ABS (date2 - date1). If it returns 4, then you know that one of the DATEs was 4 days before the other, but you won't know who was earlier.

I hope that answers your question.
If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
Explain, using specific examples, how you get these results from these data.
Always tell what version of Oracle you are using.

How to get 30 days trail vision?

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