How to get the empty values for common data for a column?

Hello
I have a table whose data is like this:
DEPT_ID     STATUS     USER_ID     ART_ID

7     R     1234     0000001
7     P     2411     0000002
7     Q     1231     0000003
7     S     7676     0000004
3     R     6776     0000005
3     S     7869     0000006
6     Q     787     0000007
6     W     5656     0000008
.......more data like this
How can we get this are data in this format:
7     R     1234     0000001
     P     2411     0000002
     Q     1231     0000003
     S     7676     0000004
3     R     6776     0000005
     S     7869     0000006
6     Q     787     0000007
     W     5656     0000008

In SQL * Plus, you can use the PAUSE command

SQL> break on deptno;
SQL> ed
Wrote file afiedt.buf

  1  select deptno, ename
  2    from emp
  3*  order by deptno
SQL> /

    DEPTNO ENAME
---------- ----------
        10 CLARK
           MILLER
           KING
        20 FORD
           smith
           ADAMS
           SCOTT
           JONES
        30 SM0
           TURNER
           BLAKE
           MARTIN
           ALLEN
           WARD
           PAV
           BAR

16 rows selected.

In SQL, you must use an analytic function

SQL> ed
Wrote file afiedt.buf

  1  select (case when deptno = prior_deptno
  2               then null
  3               else deptno
  4            end) deptno,
  5         ename
  6    from (select deptno,
  7                 lag(deptno) over (order by deptno, ename) prior_deptno,
  8                 ename
  9            from emp
 10*          order by deptno, ename)
SQL> /

    DEPTNO ENAME
---------- ----------
        10 CLARK
           KING
           MILLER
        20 ADAMS
           FORD
           JONES
           SCOTT
           smith
        30 ALLEN
           BLAKE
           MARTIN
           SM0
           TURNER
           WARD
           BAR
           PAV

16 rows selected.

Justin

Tags: Database

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