How to get the previous group on XML element

Similar Questions

• How to get the value of an xml element attributes

  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0
  
  I'm trying to parse an XML document
  
  < response >
  < well uwi = "102112900816W400" > < / well >
  < production >
  < PRODUCING_ENTITY >
  < NUMBER YEAR = '2009' >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < NUMBER YEAR = '2010' >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < NUMBER YEAR = '2011' >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < NUMBER YEAR = '2012' >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < / PRODUCING_ENTITY >
  < / production >
  < / well >
  < well uwi = "100092900816U400" > < / well >
  < production >
  < PRODUCING_ENTITY >
  < NUMBER YEAR = "1999" >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < NUMBER YEAR = '2000' >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < NUMBER YEAR = '2001' >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < NUMBER YEAR = "2003" >
  < NUMBER of MONTHS = LAST_DAY '1' = "31" / >
  < NUMBER of MONTHS = LAST_DAY '2' = "28" / >
  < NUMBER of MONTHS = LAST_DAY "3" = "30" / >
  < / YEAR >
  < / PRODUCING_ENTITY >
  < / production >
  < / well >
  < / answer >
  
  For the purposes of the practice, I have saved this in my table tdw_test_xml_files;
  
  My goal is to get the /WELL/@uwi and /YEAR/@NUMBER
  
  UWI YEAR
  ------ ---------------
  102112900816W400 2009
  102112900816W400 2010
  102112900816W400 2011
  102112900816W400 2012
  100092900816U400 1999
  100092900816U400 2000
  100092900816U400 2001
  100092900816U400 2003
  
  
  I tried this... but I can't get the value of the attribute for the element < YEAR >
  
  Select r.uwi, r.year
  of tdw_test_xml_files.
  XMLTABLE
  (
  "for $WELL in $ response/WELL/good.
  for $DEPT to $UWIIDX in $WELL, Production, PRODUCING_ENTITY, YEAR
  return < RESULT >
  University of the West Indies West <>{fn:data($WELL/@uwi)} < / UWI >}
  {
  $WELL/production/PRODUCING_ENTITY/YEAR [$UWIIDX]-> (I don't know how to extract the value of the attribute here)
  }
  < / RESULT > '
  passing FILECONTENT as 'GOOD '.
  columns
  UWI VARCHAR (50),
  YEAR vARCHAR2 (24)
  ) r
  /
  
  
  If I do this; I get the Cartesian plan result set, which is not my goal
  
  SELECT xtab.*, xtab2.*
  OF tdw_test_xml_files, XMLTable (' for $i in/Response/Well)
  Return $i"
  PASSAGE filecontent
  Uwi varchar2 COLUMNS (50) PATH'@uwi'
  rn for ORDINALITE
  ) xtab
  , XMLTable (' for $i in/Response/Well/Production/PRODUCING_ENTITY/YEAR)
  Return $i"
  PASSAGE filecontent
  COLUMNS year varchar2 (50) PATH'@NUMBER'
  ) xtab2;
  
  Any help will be highly appreciated thanks...

  I'm just curious to know how make the query now in unique XMLTable, not that I am forced by using x number of xmltable; - P, just look more clean...

  Here goes:

  SQL> SELECT x.*
    2  FROM tdw_test_xml_files t
    3     , XMLTable(
    4         'for $i in /Response/Well
    5            , $j in $i/Production/PRODUCING_ENTITY/YEAR
    6            , $k in $j/MONTH
    7          return element r {
    8            $i/@uwi
    9          , element year  {data($j/@NUMBER)}
   10          , element month {data($k/@NUMBER)}
   11          }'
   12         passing t.filecontent
   13         columns uwi   varchar2(50) path '@uwi'
   14               , yr    varchar2(4)  path 'year'
   15               , mon   varchar2(2)  path 'month'
   16       ) x
   17  ;
  
  UWI                            YR   MON
  ------------------------------ ---- ---
  102112900816W400               2009 1
  102112900816W400               2009 2
  102112900816W400               2009 3
  102112900816W400               2010 1
  102112900816W400               2010 2
  102112900816W400               2010 3
  102112900816W400               2011 1
  102112900816W400               2011 2
  102112900816W400               2011 3
  102112900816W400               2012 1
  102112900816W400               2012 2
  102112900816W400               2012 3
  100092900816U400               1999 1
  100092900816U400               1999 2
  100092900816U400               1999 3
  100092900816U400               2000 1
  100092900816U400               2000 2
  100092900816U400               2000 3
  100092900816U400               2001 1
  100092900816U400               2001 2
  100092900816U400               2001 3
  100092900816U400               2003 1
  100092900816U400               2003 2
  100092900816U400               2003 3
  
  24 rows selected
   
  

• I'm new in indesign scripting, please tell me how to write a script to get the contents of an XML element and then sort all the content

  I'm new in indesign scripting, please tell me how to write a script to get the contents of an XML element and then sort all the content

  Hello

  Can the code below is useful for you, but I do not know how to sort.

  Change the tag based on your employment application.

• How to pass the content of an xml element in the text frame in inDesign Script

  var XMLFile = File.openDialog ("select XML Files... ») ;

  var doc = app.activeDocument;

  If (!) App.Documents.Length)

  {alert ("ERROR: Document not opened");}

  return;

  }

  doc.importXML (XMLFile);

  var firstFigureNode = doc.xmlElements [0] .xmlElements [1] .xmlElements [0];

  var lableNode = firstFigureNode.xmlElements [0];

  var lableNodeText = lableNode.contents;

  myFrame var = doc.textFrames.add ({geometricBounds: [-13, 13, 3, -3]});

  lableNodeText.move (LocationOptions.AFTER, myFrame.texts [0]);

  ========================================================

  My requirement is: == > > move the content of an xml element in the text by inDesign Script block, but XML InDesign file Structure should not be change & data in the XML Structure should remain as it was before...

  I tried to code above, but it does not work...

  Please can someone help me in solving this problem...

  It does not work correctly...

  It moves firstFigureNode in myFrame...

  firstFigureNode.placeXML (myFrame);

  ===>> For Apple Script try below Code ===>>

  myFrame markup using firstFigureNode

• How to get the previous motnh

  Hi Experts,
  
  Can someone tell me to get the previos months beginning and end date...
  
  If m 20-dec-2012 then output should be 1 November 2012 and November 30, 2012...
  
  Thnx in advance...

  977490 wrote:
  Hi Experts,

  Can someone tell me to get the previos months beginning and end date...

  If m 20-dec-2012 then output should be 1 November 2012 and November 30, 2012...

  Thnx in advance...

  Use

  select trunc(trunc(sysdate,'MM')-1,'MM') "First Day of Last Month",
  trunc(sysdate,'MM')-1
  "Last Day of Last Month" from dual
  

  20-dec-2012

  Select TRUNC (trunc (to_date (20-dec-2012', 'mon-dd-yyyy'), "LUN")-1, 'MY')
  "First day of the month pr."
  trunc (to_date (20-dec-2012', 'mon-dd-yyyy'), "LUN")-1
  "Last day of the previous month.
  of the double

  Published by: Rahul India on January 24, 2013 14:37

• How to get the previous month and year accordingly

  Hi friends,
  I wanted to select the month as a number like 4 and the new year 2011
  but I want to choose the previous month from sysdate
  as if the sysdate is June 10, 2011
  It should give me 5 months and
  in the year, it should give as 2011
  If the sysdate is January 1, 2012
  the month should be like 12 and year should be in 2011
  
  Thank you

  Hello

  776317 wrote:
  Thank you very much I just the 0 being the prefix... can you pls how to avoid that too well pls

  TO_CHAR ( ADD_MONTHS (SYSDATE, -1)
          , 'FMmm yyyy'
         )
  

  For more information on the FM, wee manual SQL language modifier works:
  http://download.Oracle.com/docs/CD/B28359_01/server.111/b28286/sql_elements004.htm#sthref456

• How to get the previous record that meets a criterion?

  Hello!
  
  I am trying to create a query that adds information which finally fixed an element for a given 'pause'.
  
  I have a table, let's call it actionHistory, which looks like:
  
  ID | timestamp | action | author
  ------------------------------------------------
  101477 | 2010-05-10 09:10:20 | Difficulty | Tim
  101477 | 2010-05-10 09:10:30 | change | John
  101477 | 2010-05-10 09:10:40 | breaking | Maggie
  101477 | 2010-05-10 09:10:50 | Difficulty | Rick
  222222 | 2010-05-10 09:10:30 | change | Lewis
  222222 | 2010-05-11 09:10:40 | breaking | Maggie
  222222 | 2010-05-11 09:10:50 | Difficulty | Tim
  222222 | 2010-05-12 09:10:40 | Difficulty | Maggie
  222222 | 2010-05-13 09:10:40 | breaking | Albert
  
  I'm looking for is the following result:
  
  ID | timestamp | action | author | lastFixBy
  -----------------------------------------------------------
  101477 | 2010-05-10 09:10:20 | Difficulty | Tim |
  101477 | 2010-05-10 09:10:30 | change | John |
  101477 | 2010-05-10 09:10:40 | breaking | Maggie | Tim
  101477 | 2010-05-10 09:10:50 | Difficulty | Rick |
  222222 | 2010-05-10 09:10:30 | change | Lewis |
  222222 | 2010-05-11 09:10:40 | breaking | Maggie |
  222222 | 2010-05-11 09:10:50 | Difficulty | Tim |
  222222 | 2010-05-12 09:10:40 | Difficulty | Maggie |
  222222 | 2010-05-13 09:10:40 | breaking | Albert | Maggie
  
  Can you tell me how I can make?
  I tried many ways but no return to what I'm looking for.
  
  Thanks in advance.
  
  Published by: user8910765 on June 5, 2010 13:51
  
  Published by: user8910765 on June 5, 2010 14:00

  Hello

  That's what you asked for in Oracle 10:

  SELECT       a.*
  ,       CASE
             WHEN  action = 'break'
             THEN  LAST_VALUE ( CASE
                                  WHEN  action = 'fix'
                                  THEN  author
                                 END
                                 IGNORE NULLS
                             ) OVER ( PARTITION BY  id
                                             ORDER BY      tmstmp
                                  )
         END        AS lastfixby
  FROM       actionhistory         a
  ORDER BY  id
  ,            tmstmp
  ;
  

  Like all of the built-in functions, LAST_VALUE is documented in the manual of the SQL language:
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions073.htm#sthref1508

  user8910765 wrote:
  ... just in case where it might be useful, one of the queries I've tried myself a left subquery joined that Oracle has no right ("a column may be outside not attached to a subquery').

  Much more, it would help if you posted the request.
  It looks like you were using the old outer join notation (+). You can get the desired results by using an outer join with ANSI rating, but I think it would be more complicated and slower than with a LAST_VALUE.

• How to obtain the page to an XML element?

  Hi all

  I am fairly new to InDesign scripting (and scripts in general) and have lots of fun :-)

  I have an InDesign document containing several frames (texts, graphics, etc.) and I tagged using the InDesign tags window.

  After much struggle, I managed to get the name of the XML element tag first in my document using this simple code:

  app.activeDocument.xmlElements[0].xmlElements[0].markupTag.name
  

  I know that it worked because I got the right answer in the Javascript console. (By the way, can someone explain to me why I write xmlElements [0] twice?) And what is the difference between xmlElements and xmlItems? Any help is appreciated).

  Then I'll probably use a loop for for each markupTag of each xmlElement. But I have a lot of trouble to obtain the page associated xmlElement :-/

  After a lot of searching on Google, I came across this article which is supposed to answer my question exactly. I tried to understand this code, copy and paste in ExtendScript, but I must admit it's a bit too complex for me...

  Can someone tell me how to get a graphic or a text linked to my XML tags block? Any help is greatly appreciated!

  Nevermind, I found an easier way to achieve what I was trying to do. Actually, I wanted to be able to handle different images in my document, so why I wanted to use the XML markup.

  For those of you who have the same problem, who knows from InDesign CS5, there is an itemByName method that allows you to select an image by its name in the layers panel. So much easier to use :-)

  Thread closed!

• How to bind the form to an XML element with a specific attrib/value?

  Is it possible to link a form in Designer to an XML element using an attribute as a criterion value?  This is a very basic construction of XPath and I can't believe that the form designer cannot do this.  For example:

  < library >

  < book lang = "fr" >
  Harry Potter < title > < /title >
  < price > 29.99 < / price >
  < / book >

  < book lang = "MS" >
  < title > Learning XML < /title >
  < price > 39.95 < / price >
  < / book >

  < / book >

  I would bind only the knot book with an attribute lang of "eng".

  [The simple xpath reference would be: bookstore/book[@lang='eng']

  Thanks for any help that anyone can provide.  I am new to LiveCycle Designer

  Jordon

  You must use the below expression in data binding, property to get the title of the book whose language is English

  .book $. (lang.value == "eng") .title

  Thank you

  Srini

• How to get the ripple working, config.xml is not found

  Here a load of resources for getting started, but I just can't get anything to work as stated in the documentation, or the youtube video shows.

  I have various things installed, NodeJS, JVM, BlackBerry WebWorks 2.0.0.71, ripple in Chrome.

  To begin with when you use 'create cordova' layer of the project is different, cordova 3.4.0 I get:

  hooks /...

  mergers /...

  config. XML

  www/js /...

  www/img /...

  www/css /...

  www/index.html

  But information to addresses such as https://developer.blackberry.com/bbos/html5/documentation/creating_hello_world.html don't show this provision.

  I'm supprised when I open the config.xml file in Chrome that it does not detect the XML XSD and ripple offers to launch itself.  If I navigate to file:///C:/Users/Username/RippleSites/myproject/ www/index.html can activate ripple but she complains the file config.xml in lack.  Services of ripple Start' provides no clue as to any error and no TCP server listening on port 9910.

  I guess BB10 doesn't work with a specific version of cordova, which uses a different type of layout of project that one 3.4.x uses.  How can I fix the environment to use the correct versions and also automatically prevent the upgrade within this environment?  Because I want to obviously NPM allows management version of the future module updates.

  How C:\Users\Username\WebWorks Project\project interacts with the ripple need to use a specific home project directory as well?

  See the Option #1 here for more information about enabling access to the local files for Chrome/ripple:
  http://supportforums.BlackBerry.com/T5/Web-and-WebWorks-development/solution-ripple-launch-is-INTERR...

  That being said, the that training has been designed to be an emulator for the WebWorks 1.0 SDK, it relies on the features that have changed in WebWorks 2.0. For example, we leverage is no longer webworks.js, but cordova.js and webworksready changed to deviceready. In the end, there may be still some differences in the APIs, if efforts have been made to minimize any impact as he.

  BlackBerry 10 works with Cordova 3.1.0 and above (it may have been a few versions ago, but I don't remember exactly). Stay up to date with Cordova and use the latest version through the Museum is my personal recommendation.

  Note that if you use Cordova, you also need to install the NDK BlackBerry properly configure your environment variables.

  Note that the link to the above documentation referred BBOS, which is the platform of the inheritance (BBOS 5, 6, 7). BlackBerry 10 documentation can be found here:
  http://developer.BlackBerry.com/HTML5/documentation/V2_0/

  The www folder is root of your project that will contain all the files of HTML5. The other files are related to Cordoba and used for packing and manage your application is built.

• How to get the number of a xml file in flash?

  Hello

  It comes to my XML file

  <? XML version = "1.0"? >

  < ArrayHolder >

  < level1 > '1', '1', '1' < / level1 >

  < level2 > 2,2,1,2,2 < / level2 >

  < level3 > 1,3,3,3,1 < / level3 >

  < / ArrayHolder >

  I want to store level1 not in 'levelArray '.

  Thank you

  JaxNa

  you always have a quote but once it is fixed, divide each value of the node on the commas and then loop in the table pouring each element to a number.

• How to get the previous week from Monday to Sunday from sysdate

  for example, sysdate is 15-SEP-07 We must retrieve the data from SEPT. 01.-15-06 - SEP - 2015, although 31 August 15 is Monday our application must ignore since the current month is September

  SQL> with t
    2  as
    3  (
    4  select to_date('07-SEP-15', 'dd-mon-rr') my_sysdate
    5    from dual
    6  )
    7  select greatest(trunc(my_sysdate, 'iw') - 7, trunc(my_sysdate, 'month')) start_date
    8       , trunc(my_sysdate, 'iw') - 1 end_date
    9    from t;
  
  START_DAT END_DATE
  --------- ---------
  01-SEP-15 06-SEP-15
  

• Get the first instance of XML elements

  Hi all

  My XML tag looks like this:

  < Xref RID = Ref "id001' type = 'Test' >

  < Xref RID = ref "id002' type = 'Test' >

  < Xref RID = ref "id003' type = 'Test' >

  < Xref RID = ref 'id004' type = 'Test' >

  Code:

  var root = app.activeDocument.xmlElements [0];

  (var xrefRid = root.evaluateXPathExpression('//xref[@rid]');

  (var xrefType = root.evaluateXPathExpression('//xref[@ref-type]');

  for (i = 0; i < xrefRid.length; i ++)

  {

  var refTypeValue is xrefRid [j].xmlAttributes.itemByName ("ref-type") .value;.

  var ridValue is xrefType [j].xmlAttributes.itemByName ("rid") .value;.

  If (refTypeValue is "Test")

  {

  Alert (ridValue);

  }

  }

  In my multiple number same document 'RID' is here, but I want the first occurrence of the xref tag.

  By example, if < Xref RID = Ref "id001' type = 'Test' > occur on different pages of a book, but I need the first occurrence of the elements.

  Hope someone can help me...

  Vandy

  If your structure is constructed in the same manner as above , XPath works very well:

  _root var = app.activeDocument.xmlElements.firstItem ();

  var _firstXrefID001andID002 = _root.evaluateXPathExpression ("//p [position () = 1] / xref [@ RID ="id001"] |") [/ / p [position () = 2] / xre f[@rid='id002'] ");"

  App.Select (_firstXrefID001andID002);

  If further stations of

  are possible, for example

        1

        Title

        Example text sample text sample text sample text sample text sample text

       

  Sample text sample text sample sample text sample text sample

       

  Sample text sample text sample sample text sample text sample

       

  Sample text sample text sample sample text sample text sample

       

  Example of example text text Sample text sample text Sample Text sample text

       

  Example of example text text Sample text sample text Sample Text sample text

       

  Example of example text text Sample text sample text Sample Text sample text

       

  Example of example text text Sample text sample text Sample Text sample text

       

  Example of example text text Sample text sample text Sample Text sample text

       

  Example of example text text Sample text sample text Sample Text sample text

       

  Example of example text text Sample text sample text Sample Text sample text

       

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  Example of example text text Sample text sample text Sample Text sample text

  You can try these XPathsExpressions and take the first element of tables resulting:

  _root var = app.activeDocument.xmlElements.firstItem ();

  [var _firstXrefID001 = _root.evaluateXPathExpression("//p/xref[@rid='id001']"); "

  App.Select(_firstXrefID001[0]);

  [var _firstXrefID002 = _root.evaluateXPathExpression("//p/xref[@rid='id002']"); "

  App.Select(_firstXrefID002[0]);

  Roland

• How to get the value of a literal XML node content in BPEL 2.0?

  Hello!

  I have a problem creating A Expression in the distribution of the XML literal one activity, I would like to help me...

  Well, I have the same activity in the 1.0 version of BPEL and is now different is BPEL 2.0,.

  I have a Web Service < WSEjecutaComandos > when having a function of controls remote that connects,

  Entries of my Web Service: "int numEquipo, String [] comandos, int numCta, int publicar, int, String date version"

  The second argument is an array of string type...

  Now in my BPEL process, I do is the following assignment:

  ************************************************************

  < assign the name = "AssignCreaPath" >

  < copy >

  < from >

  < literal >

  " < fnCRexecElement xmlns =" http://Servicios/ ">

  < numEquipo > 2 < / numEquipo >

  < comandos >mkdir etl/entries/mmkis /< / comandos >

  < numCuenta > 1 < / numCuenta >

  < publicar > 0 < / publicar >

  < / fnCRexecElement >

  < / literal >

  < / from >

  < to > $InvokeClear_fnCRexec_InputVariable.parameters < /pour >

  < / copy >

  < copy >

  (< a >concat(ora:getContentAsString($InvokeClear_fnCRexec_InputVariable.parameters/comandos),$inputVariable.payload/client:fecha)< / from >

  < to >$InvokeClear_fnCRexec_InputVariable.parameters/comandos< /pour >

  < / copy >

  < copy >

  < a > $InvokeVersion_fnGetVersionProcesoByFecha_OutputVariable.parameters/version < / from >

  < to > $InvokeClear_fnCRexec_InputVariable.parameters/version < /pour >

  < / copy >

  < copy >

  < a > $inputVariable.payload / client: date < / from >

  < to > $InvokeClear_fnCRexec_InputVariable.parameters/date < /pour >

  < / copy >

  < / assign >

  ***************************************************

  Well the conflict I have is as follows,

  previously defined an entitlement with the XML Fragment copied on the payload to the Web Service (WSEjecutaComandos), input variable

  and the XML code is copied to each of the variables,

  Then him concatenating input values (I noted in red) < comandos > with the value of 'farm' (String), and once again copy Variable < comandos > and has not had any problems

  but now with the new BPEL 2.0, I do the same thing now using literal XML (this good!) but the option to concatenate (that I've noticed in red) and copied to the same variable ( I noticed blue ), I mark the following error message:

  

  I should know, I am doing wrong, or you need to to XPath function as the value that they already have the variable < comandos > will concatenate date,

  and is the final value of my entry, my Web Service.

  must be defined as table of values of type < comandos [i] >

  define the following activities before $InvokeClear_fnCRexec_InputVariable.parameters/comandos [1],

  but it seems that this BPEL 2.0 does not respect me in the form of hooks index.

  Thank you...

  See you soon,.

  I found the solution to get the value of an xml element and it concatenated with another variable within a beneficiary.

  is:

  ORA: getNodeValue (ora:getChildElement($InvokeCreaPath_fnCRexec_InputVariable.parameters,2))

  first get the desire here in my tree xml element is position 2 < comandos=""> and then get the value of this node.

  See you soon,.

• How to get the name of the previous tag of an xml in java

  Hai

  I need to get the name of the previous tag from an xml in java.

  I got the current tagname, I need to get the previous tagname attribute

  NodeList parentactionList = lParentRule.getElementsByTagName)

  "parentactiondetails" );

  I use this way to get the the current tag name, I need to get the name of the previous tag IE... before 'parentactiondetails'

  for the sample

  < / parentruledetails >
  < / Parentrule >
  < / SingleParentRule >
  < parentactiondetails ACTION_FLAG = "RulePass" PARENT_RULE_CODE = "PR626" / >
  < ParentCompliance >

  I have xml like this I'm getting the "parentactiondetails"... now I need to get the name of the previous tag < / SingleParentRule > Java

  Can someone help me,

  The following code retrieves the tag replacing "parentactiondetails."

  NodeList children = doc.getElementsByTagName("parentactiondetails");
  for (int i = 1; i < children.getLength(); i = i + 2) {
       // Alternate child ( tag).
       Node nd = children.item(i);
       // Print node name
       System.out.println(nd.getNodeName());
       //Get attributes
       NamedNodeMap attributes = nd.getAttributes();
       for (int j = 0; j < attributes.getLength(); j++) {
            Node attr = attributes.item(j);
            //Print the attribute key and value
            System.out.println("\t" + attr.getNodeName() + " -- "
                      + attr.getNodeValue());
       }
  }