How to group them by for a single column of OBIEE 11 g

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  user12204556 wrote:
  (I use 10.2.0.5 but I think that this applies to any version)

  After reading lots of documentation on Oracle I started to think how often Oracle 'written' for a single update statement.

  The following is correct?

  For an update statement:
  (1) the original data are written in tables UNDO space

  Yes

  (2) this is protected by a write first to REDO log

  Yes

  (3) the new data is written to the table space

  No, your data still haven't write (immediately) to datafiles (your tablespaces logically). When point of control (when manually to CHANGE the point of VERIFICATION SYSTEM, SWITCH of NEWSPAPER, when the buffer cache is full, STOP IMMEDIATELY in backup database tablespace mode) then your blocks of data will apply to data files.

  (4) this is also protected by an entry first in the redo log

  Yes

  (5) after that fills in the redo log, it is copied to an archived log

  YesIn ARCHIVELOG mode()

  (6) at the time of the backup that Archives archiving log is also best once more

  YES.

  So for a single update, I count at least six entries of the same data?

  These are not same data! This is the mechanism of oracle database. Cancel the information generated immediately and ensure uniformity reading (to restore). Redo information just, contain no information. It comes to redo change agent who used methods of recovery (media and instance) and finally your data updates do not immediately write data by DBWR because files there is reason of performance.

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• How the group using SQL for the desired output.

  Hi all
  
  I am currently using oracle 10.2.0.4.0
  
  Create a table script:

  CREATE TABLE FORTEST
  ( gpno VARCHAR2(10 BYTE),
    classnumber  VARCHAR2(10 byte),
    age_min NUMBER,
    age_max NUMBER,
    amount NUMBER)

  INSERT statement:

  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 01,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 01,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 01,36,40,3) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 02,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 02,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 02,36,40,5) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 03,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 03,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G123' , 03,36,40,3) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G124' , 01,0,29,1) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G124' , 01,30,35,2) 
  insert into fortest  (GPNO,classnumber,age_min,age_max,amount) values
  ('G124' , 01,36,40,3) 

  power required:

  gpno    classnumber    age_min    age_max    amount
  G123    1,3                0        29        1
  G123    1,3                30       35        2
  G123    1,3                36       40        3
  G123    2                  0        29        1
  G123    2                  30       35        2
  G123    2                  36       40        5
  G124    1                  0        29        1
  G124    1                  30       35        2
  G124    1                  36       40        3

  as for gpno g123, classnumber 1 and 3, the rates are the same in all the age_min and age_max they need to be grouped.
  even if gpno 123 classnumber 2 has the same rates as the classesnumber 1 and 3 for the age groups 0 to 29 and 30 to 35,
  rates are different for ages 36 to 40. so it should not be placed together. How can I do this in SQL
  
  any help is appreciated.
  
  Thanks in advance.

  Hello

  Thorny problem!

  Unfortunately, LISTAGG was created to the Oracle 11.2. About half of the complexity here is the aggregation of chain, i.e. forming the list of the classnumbers, as '1.3', using only functions available in Oracle 10.2.

  Here's a solution:

  WITH     got_gpno_classnumber_cnt   AS
  (
       SELECT     gpno, classnumber, age_min, age_max, amount
       ,     COUNT (*) OVER ( PARTITION BY  gpno
                                    ,            classnumber
                        )   AS gpno_classnumber_cnt
       FROM    fortest
  --     WHERE     ...     -- If you need any filtering, this is where it goes
  )
  ,     pairs          AS
  (
       SELECT    a.gpno
       ,       a.classnumber
       ,       MIN (b.classnumber)
                  OVER ( PARTITION BY  a.gpno
                            ,                    a.classnumber
                    )     AS super_classnumber
       FROM       got_gpno_classnumber_cnt  a
       JOIN       got_gpno_classnumber_cnt  b  ON   a.gpno     = b.gpno
                                    AND  a.age_min     = b.age_min
                                  AND  a.age_max     = b.age_max
                                  AND  a.amount     = b.amount
                                  AND  a.gpno_classnumber_cnt
                                          = b.gpno_classnumber_cnt
       GROUP BY  a.gpno
       ,            a.classnumber
       ,       b.classnumber
       HAVING       COUNT (*)     = MIN (a.gpno_classnumber_cnt)
  )
  ,     got_rnk          AS
  (
       SELECT DISTINCT
               gpno, classnumber, super_classnumber
       ,     DENSE_RANK () OVER ( PARTITION BY  gpno
                                 ,                    super_classnumber
                                 ORDER BY          classnumber
                         )         AS rnk
       FROM    pairs
  )
  ,     got_classnumbers     AS
  (
       SELECT     gpno, classnumber, super_classnumber
       ,      SUBSTR ( SYS_CONNECT_BY_PATH (classnumber, ',')
                     , 2
                   )     AS classnumbers
       FROM     got_rnk
       WHERE     CONNECT_BY_ISLEAF = 1
       START WITH     rnk             = 1
       CONNECT BY     rnk             = PRIOR rnk + 1
            AND     gpno             = PRIOR gpno
            AND     super_classnumber  = PRIOR super_classnumber
  )
  SELECT DISTINCT
         g.gpno
  ,       c.classnumbers
  ,       g.age_min
  ,       g.age_max
  ,       g.amount
  FROM       got_gpno_classnumber_cnt  g
  JOIN       got_classnumbers         c  ON   c.gpno        = g.gpno
                               AND  c.classnumber  = g.classnumber
  ORDER BY  g.gpno
  ,            c.classnumbers
  ;
  

  Out (just as you requested):

  GPNO       CLASSNUMBERS       AGE_MIN    AGE_MAX     AMOUNT
  ---------- --------------- ---------- ---------- ----------
  G123       1,3                      0         29          1
  G123       1,3                     30         35          2
  G123       1,3                     36         40          3
  G123       2                        0         29          1
  G123       2                       30         35          2
  G123       2                       36         40          5
  G124       1                        0         29          1
  G124       1                       30         35          2
  G124       1                       36         40          3
  

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