How to handle the list manager correctly?

Hello

I am a student and I had to make a simple request to APEX.
It is a part of modelling on the project:

apex_ask.jpg

As you can see, I have two relationship 'n - n' and a '1-n ".
I want to create a user page in order to allow him to add a 'work' (work) but this "object" should be linked with the "n" type (type), "n" person and "n" copy.

I am currently working on this page:

scrennshot_apex.JPG
As you can see, I have two list manager.

I try a simple test:

If I click on "region with dynamic action button" called click me! a short javascript code to show me the content of the second list manager

id_personne = $v("P13_PERSONNE");
alert(id_personne);

the result looks like "40:30:4:6".

I want to in PL/SQL, but I don't know how to do this:

  • Get the value of the Manager of the list (like javascript)
  • Get every issue of '40:30:4:6' in a LOOP

Currently my PL/SQL looks like:

DECLARE
    v_personne VARCHAR2(40) := '3:42:22:4:1:5';
    v_cptr NUMBER;
    LN$I pls_integer := 0;
BEGIN
    v_cptr := regexp_count( v_personne, ':' );
    LOOP
        LN$I := LN$I + 1 ;
        dbms_output.put_line( to_char( LN$I) ) ;
        exit when LN$I >= v_cptr ;
    END LOOP;
END;
/


I'm only counting the number of ': ' for loop.

Kind regard

Hello

2909908 wrote:

Please update your profile name with an explicit name, check out this video: https://www.youtube.com/watch?v=_FD80PU41k8

Hello

I am currently working on this page:


As you can see, I have two list manager.

I try a simple test:

If I click on "region with dynamic action button" called click me! a short javascript code to show me the content of the second list manager

  1. id_personne = $v ("P13_PERSONNE");
  2. Alert (id_personne);

the result looks like "40:30:4:6".

I want to in PL/SQL, but I don't know how to do this:

  • Get the value of the Manager of the list (like javascript)
  • Get every issue of '40:30:4:6' in a LOOP

Currently my PL/SQL looks like:

  1. DECLARE
  2. v_personne VARCHAR2 (40): = "3:42:22:4:1:5";
  3. v_cptr NUMBER;
  4. LN$ I pls_integer: = 0;
  5. BEGIN
  6. v_cptr: = regexp_count (v_personne, ' :');)
  7. LOOP
  8. $ LN I: = LN$ I + 1;
  9. dbms_output.put_line (to_char (LN$ I));
  10. When out LN$ I > = v_cptr;
  11. END LOOP;
  12. END;
  13. /

I'm only counting the number of ': ' for loop.

Kind regard

You can use STRING_TO_TABLE to process the values of list manager.

see the example given below

DECLARE
  l_vc_arr2 APEX_APPLICATION_GLOBAL.VC_ARR2;
BEGIN
  l_vc_arr2 := APEX_UTIL.STRING_TO_TABLE(:P13_PERSONNE);
  FOR z IN 1..l_vc_arr2.count LOOP
    htp.p(l_vc_arr2(z));
  END LOOP;
END;

Visit this link for reference: http://docs.oracle.com/cd/E11882_01/appdev.112/e12510/apex_util.htm#AEAPI186

Hope this helps you,

Kind regards

Jitendra

Tags: Database

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