How to reach only 1 record (based on order by) has another request?

Hello

I have a table of orders. Each order can have multiple notes stored in another table. I want to join the last note inserted to my query that selects all orders...

I know I have to use an outer join to ensure that orders that have NO notes are always included. But with my query below all notes are selected, I want just one record for each order with just the last inserted note (based on entry_date).

If anyone can help? Thank you!
  ORDERS [ORDERID number, ORDERNUMBER varchar]
  NOTES  [NOTEID number, ORDERID number, NOTE varchar, ENTRY_DATE date]
select
  O.ORDERID,
  O.ORDERNUMBER
from
  ORDERS O
  left outer join NOTES N on O.ORDERID = N.ORDERID

Hello
Here's one way:

select
  O.ORDERID,
  O.ORDERNUMBER
from
  ORDERS O
  left outer join (
SELECT ORDERID
   FROM (
  (SELECT ORDERID,
              ROW_NUMBER() OVER (PARTITION BY ORDERID ORDER BY ENTRY_DATE DESC) row_num
      FROM NOTES)
     WHERE row_num = 1) N
ON (O.ORDERID = N.ORDERID)

Tags: Database

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 res13.display = display.noPrint;
 res14.display = display.noPrint;
 res15.display = display.noPrint;
 res16.display = display.noPrint;
 res17.display = display.noPrint;
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 res16.display = display.hidden;
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SQL>

    David Fitzjarrell

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