How to reach school year from a date

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  I have 4 table
  
  1st is EMPLOYEE (E #, ENAME), the primary key is E #.
  
  2nd is DRIVER(E#,L#), the primary key is E # ID EMPLOYEE
  
  3. is TRIP(T#,L#), the primary key is T #, foreign key L # driver
  
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  I try

   
  SELECT DRIVER.L# AS License_No, LONGTPT(TRIP.L#) AS "LONGEST POINT" 
  FROM DRIVER 
     LEFT OUTER JOIN TRIP on DRIVER.L# = TRIP.L#;
  This only query the L# and the LONGEST Point.

  Could someone guide me how to do select on screen the ENAME and with my LONGPT function.
  
  Published by: user4757127 on November 25, 2012 10:11
  
  Published by: user4757127 on November 25, 2012 10:17
  
  Published by: user4757127 on November 25, 2012 10:18

  Hello

  Welcome to the forum!

  user4757127 wrote:
  ... How can I do a select query to view the employee NAME, LONGPT. The name of the driver that perform no trigger point must be in the application as well.

  I don't know what you mean by "the employee, LONGPT.

  My best guess is that you need join the employee table in your current query:

  SELECT  driver.l#          AS License_No
  ,     employee.ename                              -- *****  NEW  *****
  ,     longtpt (trip.l#)      AS "LONGEST POINT"
  FROM           driver
  JOIN          employee     ON   driver.e#     = employee.e#     -- *****  NEW  *****
  LEFT OUTER JOIN trip          ON   driver.l#     = trip.l#
  ;
  

  Again, this is just a guess and guess isn't always the best way to solve problems.

  I hope that answers your question.
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  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

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  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
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• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

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  Steve

  This might work for you...

  I placed your data in a table named "Data."

  Create a second (in this example, titled 'Table 1')

  

  In the table 'Table 1' months are in the first column and the first row (which is a header row) contains the years - add columns to add new year:

  B2 = if (SUMIFS (data: $B, data: $A, "> =" & (B$ 1, $A2, 1), DATE data: $A, "<" & EOMONTH(A1,0) will GET (DATE B$ 1, $A2, 1, 0) "" "") > 0, SUMIFS (data: $B, given: $A, "> =" & (B$ 1, $A2, 1), DATE data: $A, "<" & EOMONTH(A1,0) will GET (DATE B$ 1, $A2, 1, 0) "" ""), "")

  It's abbreviation dethrone select cell B2 and type (or copy and paste it here) the formula:

  = IF (SUMIFS (data: $B, data: $A, "> =" & (B$ 1, $A2, 1), DATE data: $A, "<" & EOMONTH(A1,0) will GET (DATE B$ 1, $A2, 1, 0) "" "") > 0, SUMIFS (data: $B, given: $A, "> =" & (B$ 1, $A2, 1), DATE data: $A, "<" & EOMONTH(A1,0) will GET (DATE B$ 1, $A2, 1, 0) "" ""), "")

  Select copy of cell B2

  Select the cells B2 at the end of F13, dough

  now select cells A2 through F13 and add a graphic (the XY scatter diagram)

  Add new year add one (or more) new columns for "table 1", then add the year to the top:

  

  Now alone, click the chart to activate the chart.  then click on the button 'change data references '.

  now, drag the data reference control handle to the right to add the new year to the table:

  

  You can add several years to the time, so you don't have to it very often

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