How to reference the substitution model in State of PL/SQL string
Hello - I need display conditionally an article based on the value of #TITLE #. I'm trying a function body pl/sql expression returning a BooleanDECLARE
PAGE_TYPE VARCHAR2 (1000);
BEGIN
PAGE_TYPE: = lower (substr (:TITLE,instr(:TITLE,'Query')));
If (page_type = "query") then
Return TRUE;
on the other
return FALSE;.
end if;
END;
There are no errors, but the condition is not met, whereas it should be.
I tried to adjust some elements of the application to the value of #TITLE # and I'm obviously not reference properly. they are all null:
: Test_value: = & TITLE. ;
: TEST_VALUE2: =: TITLE;
: TEST_VALUE3: = V ('TITLE');
Help?
Thank you
Carol
Hello
Your can use the page title attribute in the metadata as...
SELECT page_title
INTO my_var
FROM apex_application_pages
WHERE application_id = :APP_ID
AND page_id = :APP_PAGE_ID
???
See you soon
Ben
Tags: Database
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