How to retrieve the name of a table?

I can cite a table so that it includes an index like this value:

This ["myArray" + i] = new Array();

But how I can extract the index value when the tables have a name property?

No, it looks pretty clear. I just didn't read.

You can assign a name to your berries property or really just the index property because that's all you want:

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```
      
        
        
      
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If you find this information useful, please give points to "correct" or "useful".

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Can any body tell how to get the name of the item to a particular array.i have a table within array.i must compare the name of Francesca in particular key.here is the table.
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[0] = object (@43adc19)
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delete = "N".
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Thanks and greetings
Vineet Sharma

Hi Vineet Osho,

You can browse your object using the loop and you can get the name of the table... as below...

for each (var obj:Object in myArray)
{
for (var str:String in obj)
{
If (obj [str] is array)
{
var arrayName:String = str;
}
}
}

Thank you

Jean Claude

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Retrieve the names of columns in a table.

Hi all

I want to retrieve column names of a table "test", whose values are null

For ex:

Select * from test

give the results that

column_1, column_2, column_3, column_4
111

allows to consider the case that the table has only one record.

as a result, we will have to get column_2, column_3, column_4 and more.

I tried dynamic "run immediately" the statement and tried to extract in a single execution of immediate instruction, but I wasn't able to accomplish because of several columns.

is it possible without using a pl/sql function or procedure?

Check this box:

SQL> INSERT INTO my_Test values('ABCD',NULL,NULL);

1 row created.

SQL> COMMIT;

Commit complete.

SQL> select * from my_Test;

COL1       C COL3
---------- - ----------
ABCD

SQL> declare
  2  CURSOR C1 IS SELECT column_name FROM all_tab_cols WHERE table_name = 'MY_TEST';
  3  v_sql VARCHAR2(10000) := NULL;
  4  my_null_col_list VARCHAR2(32767) := NULL;
  5  my_cnt NUMBER := 0;
  6  BEGIN
  7  FOR I in C1 LOOP
  8  v_sql := 'SELECT COUNT(*) FROM my_test WHERE '||I.column_name ||' IS NULL';
  9  execute immediate v_sql INTO my_cnt;
 10  IF (my_cnt > 0) THEN
 11  my_null_col_list := my_null_Col_list||','||I.column_name;
 12  END IF;
 13  END LOOP;
 14  my_null_col_list := SUBSTR(my_null_col_list,2);
 15  dbms_output.put_line('Columns that have null values for table my_Test are:'||my_null_col_list);

 16  END;
 17  /
Columns that have null values for table my_Test are:COL2,COL3

PL/SQL procedure successfully completed.

SQL> desc my_test;
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 COL1                                               VARCHAR2(10)
 COL2                                               VARCHAR2(1)
 COL3                                               VARCHAR2(10)

SQL>

How to get the names of the table columns in the quick dashboard
How to get the names of the table columns in the quick dashboard

Thanks and greetings
------------------------
Kishore P
Make a prompt like:

SELECT case when 1 = 0 then 'D0 time. " "" T02 by month name "other" 'D2 market' '. "" M04 region' ' the end 'Sample Sales' UNION ALL SELECT case when 1 = 0 then 'D0 Time. " "" T02 by month name ' else ' 'Time D0. "" T02 by month name ' ' the end 'Sample Sales.

Put the name of column in single quotes.

Make your rank as a function:
Rank ('F1 income'. "" Recipes 1-01 (after all) "by @{pColumn} {'D0 time'. ({"" T05 annually name '})

It works fine for me

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http://obiee101.blogspot.com

How to retrieve the values of a number of column by column in pl sql

I wanted to know how can I retrieve the values of a column just in number and not the name of the column.

user10989720 wrote:
I need exactly this kind of thing.

I am retrieving the name of the column from all_tab_columns and under this column name can I retrieve values using any kind of query sub.

Select column_name
from all_tab_columns
where table_name = 'QUOTE_HEADERS_EXT' and
column_id = 58

You're still not understanding. You need to do if you want to get the values of the table dynamically.

Either like this:

SQL> create or replace type t_colval is table of varchar2(4000);
  2  /

Type created.

SQL> ed
Wrote file afiedt.buf

  1  CREATE OR REPLACE FUNCTION get_column(p_sql IN VARCHAR2, p_column_no NUMBER) RETURN t_colval PIPELINED IS
  2    v_finaltxt  VARCHAR2(4000);
  3    v_v_val     VARCHAR2(4000);
  4    v_n_val     NUMBER;
  5    v_d_val     DATE;
  6    v_ret       NUMBER;
  7    c           NUMBER;
  8    d           NUMBER;
  9    col_cnt     INTEGER;
 10    f           BOOLEAN;
 11    rec_tab     DBMS_SQL.DESC_TAB;
 12    col_num     NUMBER;
 13  BEGIN
 14    c := DBMS_SQL.OPEN_CURSOR;
 15    DBMS_SQL.PARSE(c, p_sql, DBMS_SQL.NATIVE);
 16    d := DBMS_SQL.EXECUTE(c);
 17    DBMS_SQL.DESCRIBE_COLUMNS(c, col_cnt, rec_tab);
 18    FOR j in 1..col_cnt
 19    LOOP
 20      CASE rec_tab(j).col_type
 21        WHEN 1 THEN DBMS_SQL.DEFINE_COLUMN(c,j,v_v_val,2000);
 22        WHEN 2 THEN DBMS_SQL.DEFINE_COLUMN(c,j,v_n_val);
 23        WHEN 12 THEN DBMS_SQL.DEFINE_COLUMN(c,j,v_d_val);
 24      ELSE
 25        DBMS_SQL.DEFINE_COLUMN(c,j,v_v_val,2000);
 26      END CASE;
 27    END LOOP;
 28    LOOP
 29      v_ret := DBMS_SQL.FETCH_ROWS(c);
 30      EXIT WHEN v_ret = 0;
 31      v_finaltxt := NULL;
 32      CASE rec_tab(p_column_no).col_type
 33        WHEN 1 THEN DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_v_val);
 34        WHEN 2 THEN DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_n_val);
 35                    v_v_val := to_char(v_n_val);
 36        WHEN 12 THEN DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_d_val);
 37                    v_v_val := to_char(v_d_val,'DD/MM/YYYY HH24:MI:SS');
 38      ELSE
 39        DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_v_val);
 40      END CASE;
 41      PIPE ROW (v_v_val);
 42    END LOOP;
 43    DBMS_SQL.CLOSE_CURSOR(c);
 44* END;
SQL> /

Function created.

SQL> select * from table(get_column('select * from emp',1));

COLUMN_VALUE
---------------------------------------------------------------------------------------------------------------
7369
7499
7521
7566
7654
7698
7782
7788
7839
7844
7876
7900
7902
7934

14 rows selected.

SQL> select * from table(get_column('select * from emp',2));

COLUMN_VALUE
---------------------------------------------------------------------------------------------------------------
SMITH
ALLEN
WARD
JONES
MARTIN
BLAKE
CLARK
SCOTT
KING
TURNER
ADAMS
JAMES
FORD
MILLER

14 rows selected.

SQL>

Or like this:

SQL> create or replace type t_colval is table of varchar2(4000);
  2  /

Type created.

SQL> ed
Wrote file afiedt.buf

  1  CREATE OR REPLACE FUNCTION get_column(p_table IN VARCHAR2, p_column_no NUMBER) RETURN t_colval PIPELINED IS
  2    v_column_name VARCHAR2(30);
  3    v_rc          SYS_REFCURSOR;
  4    v_val         VARCHAR2(4000);
  5  BEGIN
  6    SELECT column_name
  7    INTO   v_column_name
  8    FROM   user_tab_columns
  9    WHERE  column_id = p_column_no
 10    AND    table_name = UPPER(p_table);
 11    OPEN v_rc FOR ('SELECT '||v_column_name||' FROM '||p_table);
 12    LOOP
 13      FETCH v_rc INTO v_val;
 14      EXIT WHEN v_rc%NOTFOUND;
 15      PIPE ROW(v_val);
 16    END LOOP;
 17    CLOSE v_rc;
 18* END;
SQL> /

Function created.

SQL> select * from table(get_column('EMP',2));

COLUMN_VALUE
----------------------------------------------------------------------------------------------------------------
SMITH
ALLEN
WARD
JONES
MARTIN
BLAKE
CLARK
SCOTT
KING
TURNER
ADAMS
JAMES
FORD
MILLER

14 rows selected.

SQL>

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How to retrieve forgotten names of users and passwords for windows mail?

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How to retrieve the values of character without using single quotes

Hi all
How to retrieve the values of character without the use of single quotes. Its Possible in Oracle SQL
Please answer me...
For example
Is actual query-> Select * from employees where name like in("SCOTT", "JAMES", "ALBERT",...);
I want to--> Select * from employees where name like(SCOTT, JAMES, ALBERT...); -without the use of single quotes.
Why I need this application, I need to retrieve the records more than 200 employees in a select statement by using name in where clause.

shagarmahabubjan wrote:

Hi all

How to retrieve the values of character without the use of single quotes. Its Possible in Oracle SQL

Please answer me...

For example

Actual query is---> Select * from employees where name like in("SCOTT", "JAMES", "ALBERT",...);

I want to---> Select * from employees where name like(SCOTT, JAMES, ALBERT...); -without the use of single quotes.

Why I need this application, I need to retrieve the records more than 200 employees in a select statement by using name in where clause.

In short... you can't. The channels are channels, and SQL and PL languages dictate that the string literals are provided within single quotes.

I don't see how trying to retrieve more than 200 records of employees in the select statement means that you must get rid of the quotes.

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Hello
I installed ODI 11 g on windows. and load the multiple file. as you can see that this procedure (script) is used to get the name of the files. using technology "Operating System"
cmd /c dir D:\test\*.*/b /a:-d > D:\\Filesname.txt. It works well on windows. Now, I want to load these files names that are on the Linux server.
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In Linux.

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Concerning
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/Home/user_name/ScriptFile.sh

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I would like to retrieve the name of the region (hideShowHeader) when I click on the hide/show icon. I know how to catch the event but some OAWebBeanConstants I always check null... any idea?

Thank you very much, Pier Paolo.
Hello

Try to print below in LIC...

System.out.println ("name of the event:" + pageContext.getParameter (OAWebBeanConstants.EVENT_PARAM));
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