How to search the folder hierarchy by the parties of a folder name. Is there a library similar to library bookmark folder to facilitate the Organization of record?
How can I search by folder for the email account names and names of folder of bookmarks by keywords or parts of the name of the folder? Is there a way to enter and to associate keywords to send/benchmark folder names?
We put all our transactions in messaging and bookmarks in a reversed under the account name and appropriate ISP user tree structure, but often end up with double taxonomic entries under multiple ISP accounts such as Roadrunner or Google-mail address for the same Windows user account and the name. Sometimes I create a same folder in both accounts. Be able to search by folder_name in all e-mail accounts in the same Windows user name would be wonderful to correct the bifurcations in taxonomy of folder name.
What I do not right - please?
Please - Chris
I use the add-on for quick folder move - it has a MRU list and a box of text in which you can type a folder name, with an incremental search phase.
https://addons.Mozilla.org/en-us/Thunderbird/addon/quick-folder-move/?src=API
You my also find the QuickFolders useful add-on.
I also wonder if your deposit under the ISP account is the best way to go. I would look of combining messages from accounts under local folders into an independent style of the account.
Tags: Thunderbird
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Hello
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Can someone help me with a sentece SQL to do?
Thanks in advance.You can certainly do it:
SELECT movimento, dt_movimento, cd_material, cd_tp_operacao, nf, serie, quantidade, pr_unitario FROM itemfat i WHERE cd_material IN ('722136', '759177', '810725', '818848') AND cd_tp_operacao IN ('1102C', '2102C') AND dt_movimento = (SELECT MAX (dt_movimento) FROM itemfat d WHERE d.cd_material = i.cd_material AND d.cd_material IN ('722136', '759177', '810725', '818848') AND d.cd_tp_operacao IN ('1102C', '2102C')) ORDER BY cd_material, dt_movimento
: p
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In this case put himIND DTE STAT --------------------------------------- 5 6/13/2011 1 5 6/10/2011 1 5 6/9/2011 1 5 6/8/2011 1 5 6/7/2011 1 5 6/6/2011 0 5 6/3/2011 0 5 6/2/2011 1 5 6/1/2011 1 6 6/13/2011 1 6 6/10/2011 1 6 6/9/2011 1 6 6/8/2011 0 6 6/7/2011 0 6 6/6/2011 0 6 6/3/2011 1 6 6/2/2011 1 6 6/1/2011 0
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Hello
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Sorry, I don't understand how you get the columns ind and cnt. I can guess what you want for ind, but I can't do it even for NTC. Are you sure that the results you've posted are really what you want from the data you've posted?
My best guess is:
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Output:
IND CNT MIN_DT MAX_DT ---------- ---------- --------- --------- 1 5 07-JUN-11 13-JUN-11 2 3 09-JUN-11 13-JUN-11
The column of the cnt is not what said you you wanted:
user11290011 wrote:
... In this case put himIND CNT MIN_DT MAX_DT -------------------------------------- 1 3 6/7/2011 6/13/2011 2 2 6/9/2011 6/13/2011
If the results I posted are not the results you want, and then tap where the output I posted does not, after the good results and to explain exactly how you calculate the correct results of the sample data.
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Right now, our materialized views to produce something like the following:
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ChrisThere is probably a way simpler than that, but it's early in the morning and I don't wake even...
SQL> ed Wrote file afiedt.buf 1 with t as (select 'REC01' as record_key, to_date('01-JAN-2010','DD-MON-YYYY') as date_created, 'A' as column1, 'B' as column2, null as column3 from dual union all 2 select 'REC01', to_date('04-JAN-2010','DD-MON-YYYY'), null, 'C', 'D' from dual union all 3 select 'REC02', to_date('06-JAN-2010','DD-MON-YYYY'), 'X', null, 'Z' from dual) 4 -- end of test data 5 select record_key, date_created, column1, column2, column3 6 from ( 7 select record_key 8 ,last_value(date_created) over (partition by record_key order by date_created) as date_created 9 ,last_value(column1 ignore nulls) over (partition by record_key order by date_created) as column1 10 ,last_value(column2 ignore nulls) over (partition by record_key order by date_created) as column2 11 ,last_value(column3 ignore nulls) over (partition by record_key order by date_created) as column3 12 ,row_number() over (partition by record_key order by date_created desc) as rn 13 from t 14 ) 15* where rn = 1 SQL> / RECOR DATE_CREATED C C C ----- ------------------- - - - REC01 04/01/2010 00:00:00 A C D REC02 06/01/2010 00:00:00 X Z SQL>
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I create the content of the Organization in BPM studio 10g. When I deploy the .exp file # BPM standalone 10g, new roles can be mapped to standalone BPM. However, the information of the participants cannot be imported. How to import information on the participants?
SincerelyHey you,.
To import the Participant information you entered Studio in company:
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(2) in the Studio, right click on "Organization" in project-> 'Export' browser-> don't forget when you export the file .xdml
(3) in the tool click business process administrator 'Body'-> click on the tab 'Import'-> 'Organization'-> click on 'Browse' and select the .xdml file you exported in step 2-> click on "import".
Hope this helps,
Dan
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