How to use a repository in a new report

Hello

I'm starting to learn OBIEE and installed in my home. I installed OBIEE and used the RCU to install a deposit in an Oracle database.
Then I used the tool of Administration of BI to do a "repository" that connects to my data (also in an Oracle database).
In the Administration of BI tool, I now have a physical layer, a business model and mapping and a presentation layer. I saved it as a file on my HDD DPR.
Then, in the Oracle BIEE home I choose 'new report '. But I can not find how do I choose my 'repository' with my data. I also tried to make a new datamodel, but here I am also not able to choose my deposit.

How can I connect to my data in a report? How does it work?

Many thanks in advance,
Best regards
André.

You are totally getting confused...

Have these figure everything out.

You have installed DB.
You will create the schema (two users) in DB with the remote control (repository creation utility: basically stores the metadata required for OBIEE).
You install OBIEE and use these schema here.
Above installation install weblogic and then deploy on weblogic BI files so that they work. To remember the password weblogic.

Now when you open Admin tool - password repository must be "Admin123" (capital A) and username is weblogic and password must be the password weblogic.

You will be able to open to the top of the RPD in online mode.

I suggest you go first by the OBIEE Architecture then the installation and start the exercises.

Mark correct or useful if it helps. Also let me know if you were able to open the RPD and answers.

Kind regards
Rayan Vieira

Tags: Business Intelligence

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    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (2, 'Scott', 2000, 'Analyst', to_date (October 22, 1985 "," DD-MON-RRRR'), 1, to_date (May 2, 2012 13:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (2, 'Scott', 2000, 'Analyst', to_date (October 22, 1985 "," DD-MON-RRRR'), 2, to_date (May 2, 2012 14:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (2, 'Scott', 3000, 'Lead', to_date (October 22, 1985 "," DD-MON-RRRR'), 3, to_date (May 2, 2012 15:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (3, 'Smith', 4000, 'Lead', to_date (22 October 1981 "," DD-MON-RRRR'), 1, to_date (June 2, 2012 13:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (3, 'Smith', 5000, 'Lead', to_date (22 October 1981 "," DD-MON-RRRR'), 2, to_date (June 2, 2012 14:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (3, 'Smith', 5500, 'Lead', to_date (22 October 1981 "," DD-MON-RRRR'), 3, to_date (June 2, 2012 15:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (3, 'Smith', 8000, 'CTO', to_date (22 October 1981 "," DD-MON-RRRR'), 5, to_date (June 2, 2012 17:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (4, 'Tom', 4000, 'Lead', to_date (22 October 1981 "," DD-MON-RRRR'), 1, to_date (July 2, 2012 13:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (4, 'Tom', 5000, 'Lead', to_date (22 October 1981 "," DD-MON-RRRR'), 2, to_date (2 July 2012 14:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (4, 'Tom', 5500, 'Lead', to_date (22 October 1981 "," DD-MON-RRRR'), 3, to_date (July 2, 2012 15:00 ',' DD-MON-RRRR hh24:mm'));

    Insert into EMP_HIST (ENO, ENAME, SAL, JOB, DOB, VERSION)

    values (4, 'Tom', 8000, 'CTO', to_date (22 October 1981 "," DD-MON-RRRR'), 4, to_date (July 2, 2012 16:00 ',' DD-MON-RRRR hh24:mm'));

    I want to display changes (current value and previous value)

    for each column as below.

    PK_Value Column_Name Previous_value Current_Value

    -------------- -------------------------- --------------------  --------------------

    1         ENo                1                        1

    1 Ename Sanjiv Sanjeev

    1 1000 1900 sal

    1 committed post clerk

    1 DATE OF BIRTH 12/10/89-12/10/89

    2         ENo                2                        2

    2 Ename Scott Scott

    2 sal 2000 3000

    2 senior analyst job

    2 DATE OF BIRTH 12/10/89-12/10/89

    3         ENo                3                        3

    3 Ename Smith Smith

    3 5500 8000 sal

    3         Job                         Lead                  CTO

    3 DATE OF BIRTH 12/10/89-12/10/89

    Solution for above requirement is query below.

    WITH

    got_r_num AS

    (

    SELECT

    Eno,

    Ename,

    To_char (sal) AS sal,

    employment,

    To_char (dob, 'DD-MON-YYYY') AS date of birth,

    ROW_NUMBER () OVER (PARTITION BY eno ORDER BY version DESC) AS r_num

    Of

    emp_hist

    )

    SELECT

    *

    Of

    (got_r_num) PIVOT UNPIVOT (str FOR column_name IN (ename, sal, job, birth date))

    MIN (str) FOR r_num IN (2 AS previous_val, 1 AS)

    current_val))

    ORDER BY

    Eno,

    Column;

    But there are a few changes to the rquirement as below

    There is a table that maintains the version the most recent/maximum for each employee.

    Table EMP_AUD_LOOKUP have structure below

    CREATE

    TABLE emp_aud_lookup

    (

    ENo NUMBER,

    Version NUMBER

    );

    Insert into emp_aud_lookup (ENO, VERSION) values (1.3);

    Insert into emp_aud_lookup (ENO, VERSION) values (2,3);

    Insert into emp_aud_lookup (ENO, VERSION) values (3.6);

    Insert into emp_aud_lookup (ENO, VERSION) values (4.6);

    version of Eno

    ------  -----------

    1 3

    2 3

    3 6

    4 6

    maximum/later in the EMP_AUD_LOOKUP table.

    For emp = 1, version the most recent/maximum is 3

    For emp = 2, version the most recent/maximum is 3

    For emp = 3, version the most recent/maximum is 6, if it's 5 emp_hist table but the matching record in

    Table 6 (since it can be changed in other tables to load of the EMP_AUD_LOOKUP

    that is the case has changed in child table thats why he is 6)

    For emp = 4, version the most recent/maximum is 6, if it is 4 emp_hist table but the matching record in

    Table 6 (since it can be changed in other tables to load of the EMP_AUD_LOOKUP

    that is the case has changed in child table thats why he is 6)

    Updated the result will be like

    PK_Value Column_Name Previous_value Current_Value

    -------------- -------------------------- --------------------  --------------------

    1         ENo                1                        1

    1 Ename Sanjiv Sanjeev

    1 1000 1900 sal

    1 committed post clerk

    1 DATE OF BIRTH 12/10/89-12/10/89

    2         ENo                2                        2

    2 Ename Scott Scott

    2 sal 2000 3000

    2 senior analyst job

    2 DATE OF BIRTH 12/10/89-12/10/89

    3         ENo                3                        3

    3 Ename Smith Smith

    3 8000 8000 sal

    3         Job                         CTO                   CTO

    3 DATE OF BIRTH 12/10/89-12/10/89

    4         ENo                4                        4

    4 Tom Tom Ename

    4 8000 8000 sal

    4         Job                         CTO                   CTO

    4 DATE OF BIRTH 12/10/89-12/10/89

    In the case of ENo = 1, will be later

    SELECT version in v_latest OF EMP_AUD_LOOKUP where Eno = 1;

    v_latest = 3

    Latest = > max (version) of emp_hist < = v_latest or 3 < = 3 so 3

    Previous = > max (version) of emp_hist < v_latest-1 or 2 < = 2 so 2

    In the case of ENo = 2, will be later

    SELECT version in v_latest OF EMP_AUD_LOOKUP where Eno = 2;

    v_latest = 3

    Latest = > max (version) of emp_hist < = v_latest or 3 < = 3 so 3

    Previous = > max (version) of emp_hist < v_latest-1 or 2 < = 2 so 2

    In the case of ENo = 3, will be later

    SELECT version in v_latest OF EMP_AUD_LOOKUP where Eno = 3;

    v_latest = 6

    Latest = > max (version) of emp_hist < = v_latest or 5 < = 6 so 5

    Previous = > max (version) of emp_hist < v_latest-1 is 5 < = 5 so 5

    In the case of ENo = 4, will be later

    SELECT version in v_latest OF EMP_AUD_LOOKUP where Eno = 4;

    v_latest = 6

    Latest = > max (version) of emp_hist < = v_latest or 4 < = 6 so 4

    Previous = > max (version) of emp_hist < v_latest - 1 = 4 < = 5 so 4

    Can we make changes above with a modified respect logic based on the id of the most recent version of the other table.

    either we can manipulate in row_number() function.

    Hello.. Try the below...

    WITH qry1 AS (SELECT eno,

    Ename,

    SAL,

    employment,

    Date of birth

    Version

    Max (version) OVER (PARTITION BY eno) mx_ver

    Of emp_hist).

    qry2 AS

    (SELECT eno1,

    To_char (Eno) eno,

    Ename,

    To_char (SAL) sal,

    employment,

    Date of birth to_char(DOB,'DD-mon-YYYY'),

    To_char (ld_eno) ld_eno,

    ld_ename,

    To_char (ld_sal) ld_sal,

    ld_job,

    To_char(DOB,'DD-mon-YYYY') ld_dob

    FROM (SELECT q1.eno, eno1,

    Q1. Nwe eno,

    Ename,

    SAL,

    employment,

    Date of birth

    INF. ROW_NUMBER() over (PARTITION BY q1.eno ORDER BY q1.version),

    Lead (Q1. Eno, 1, Q1. ENO) OVER (PARTITION BY q1.eno ORDER BY q1.version) ld_eno,.

    Lead(Ename,1,Ename) OVER (PARTITION BY q1.eno ORDER BY q1.version) ld_ename,

    Lead(SAL,1,SAL) OVER (PARTITION BY q1.eno ORDER BY q1.version) ld_sal,

    Lead(Job,1,Job) OVER (PARTITION BY q1.eno ORDER BY q1.version) ld_job,

    Lead(DOB,1,DOB) OVER (PARTITION BY q1.eno ORDER BY q1.version) ld_dob,

    version Q1.version

    OF qry1 q1 emp_aud_lookup eal

    WHERE q1.eno = eal.eno

    AND (q1.mx_ver = eal.version AND (q1.version = q1.mx_ver OR q1.version = q1.mx_ver - 1))

    OR(Q1.mx_ver <> EAL.version and Q1.version = Q1.mx_ver)))

    WHERE rn = 1)

    SELECT eno1 eno,

    CASE WHEN lvl = 1 THEN 'ENO '.

    ONCE lvl = 2 THEN 'ENAME '.

    ONCE lvl = 3 THEN 'SAL '.

    ONCE lvl = 4 THEN "JOB."

    ONCE lvl = 5 THEN 'DOB '.

    ELSE 'N/A '.

    END as col_name,

    CASE WHEN lvl = 1 THEN eno

    ONCE lvl = 2 THEN ename

    ONCE lvl = 3 sal THEN

    ONCE lvl = 4 THEN employment

    ONCE lvl = 5 THEN dob

    END as previous_value,

    CASE WHEN lvl = 1 THEN ld_eno

    ONCE lvl = 2 THEN ld_ename

    ONCE lvl = 3 THEN ld_sal

    ONCE lvl = 4 THEN ld_job

    ONCE lvl = 5 THEN ld_dob

    END AS current_value

    OF qry2, (lvl SELECT LEVEL FROM dual CONNECT BY LEVEL<=>

    ORDER BY eno, lvl;

    OUTPUT:-

    -------

    ENO COL_N PREVIOUS_VALUE CURRENT_VALUE

    ---- ----- --------------- ---------------

    1 1 1 ENO

    1 ENAME Sanjiv Sanjeev

    1 1000 1900 SAL

    1 committed POST clerk

    1 DOB DECEMBER 10, 1989 10 DECEMBER 1989

    2 2 2 ENO

    2 ENAME Scott Scott

    2 SAL 2000 3000

    2 senior analyst JOB

    2 DATE OF BIRTH 22 OCTOBER 1985 OCTOBER 22, 1985

    3 3 3 ENO

    3 ENAME Smith Smith

    3 8000 8000 SAL

    3 USE CTO CTO

    3 DATE OF BIRTH 22 OCTOBER 1981 OCTOBER 22, 1981

    ENO 4 4 4

    4 Tom Tom ENAME

    4 8000 8000 SAL

    4 JOB CTO CTO

    4 DATE OF BIRTH 22 OCTOBER 1981 OCTOBER 22, 1981

    20 selected lines.

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