How to write a SQL for this condition?
I have a table with columns v_sub, v_visit, and T_DATE and the structure is like thisv_sub v_visit T_DATE
1 visit-1 01 - mar - 09
1 visit-2 05 - mar - 09
1 visit-3 17 - mar - 09
2-visit-1-4 February 09
2 visit-2 12 - mar - 09
2 visit-3 20 - mar - 09
I want to write a query that control weather it is in chronological order or not. (for v_sub, v_visit and T_DATE must be in chronological order as above)
and I want to check the condition as below:
v_sub v_visit T_DATE
1 visit-1 01 - mar - 09
1 visit-2 5 February 09
1 visit-3 17 - mar - 09
2-visit-1-4 February 09
2 visit-2 12 January 09
2 visit-3 20 - mar - 09
Thanks in advance
Use the LAG function to get previous date
SQL> -- sample data
SQL> with t
2 as
3 (
4 select 1 v_sub, 'visit-1' v_visit, to_date('01-mar-09','dd-mon-yy') v_date from dual union all
5 select 1, 'visit-2', to_date('05-mar-09','dd-mon-yy') from dual union all
6 select 1, 'visit-3', to_date('17-mar-09','dd-mon-yy') from dual union all
7 select 2, 'visit-1', to_date('04-feb-09','dd-mon-yy') from dual union all
8 select 2, 'visit-2', to_date('12-mar-09','dd-mon-yy') from dual union all
9 select 2, 'visit-3', to_date('20-mar-09','dd-mon-yy') from dual
10 )
11 -- end of sample data
12 select v_sub, v_visit, v_date, lag(v_date) over(partition by v_sub order by v_visit, v_date) v_previous_date
13 from t
14 /
V_SUB V_VISIT V_DATE V_PREVIOU
---------- ------- --------- ---------
1 visit-1 01-MAR-09
1 visit-2 05-MAR-09 01-MAR-09
1 visit-3 17-MAR-09 05-MAR-09
2 visit-1 04-FEB-09
2 visit-2 12-MAR-09 04-FEB-09
2 visit-3 20-MAR-09 12-MAR-09
6 rows selected.
Now you can check if the previous_date is less than T_DATE
Tags: Database
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