I'd like to find all lines line keys

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• extract all lines if condition is met

  Hi all, consider the following data.
  

  WITH table1 AS 
  (
    SELECT 1 amt, 'dummy' txt, 'R' txt2 , '1X' pid FROM dual UNION ALL
    SELECT 123 amt, 'CATS' txt, 'P' txt2, '1X' pid FROM dual UNION all
    SELECT 145 amt, 'CAR' txt, 'PR' txt2, '1X' pid FROM dual UNION all
    SELECT 165 amt, 'NAME' txt, 'P' txt2, '1X' pid FROM dual UNION ALL
    SELECT 166 amt, 'NAME' txt, 'PK' txt2, '1X' pid FROM dual UNION all
  
  
    SELECT 100 amt, 'dummy' txt, 'R' txt2, '2X' pid FROM dual UNION ALL
    SELECT 13 amt, 'CATS2' txt, 'P' txt2, '2X' pid FROM dual UNION all
    SELECT 15 amt, 'CAR2' txt, 'PR' txt2, '2X' pid FROM dual UNION all
    SELECT 15 amt, 'NAME2' txt, 'P' txt2, '2X' pid FROM dual 
  
  )

  I want to display the following result

  AMT  TXT    TXT2  PID
  ========================
  1    DUMMY  R     1X
  123  CATS   NO    1X
  145  CAR    NO    1X
  165  NAME   NO    1X
  166  NAME   PK    1X
  
  
  100 DUMMY   R     2X
  13  CATS2   P     2X
  15  CAR2    PR    2X
  15  NAME2   P     2X

  the logic behind this output is as follows:
  When I find a line whose amount is 1 or - 1 and txt = dummy, I want to take the pid of this line value and find all lines with this pid where txt2 (p, PR) and set the txt2.
  If txt2 is not in P or PR, and then set the column to the current value
  
  for example. the first line of data above has amt = 1 and txt = model. I'll take the pid of this line, which is 1 X and find all the other lines with this value of pid and txt2 in P, PR
  in this case I found the line with amt = 123, 145, 165. I display the rows in output but txt2 change no.
  
  If you notice, line with amt = 166 wasn't the change as txt2 = PK. in the second series of data, I view the data, as is since I couldn't find a line with amt in(1,-1) and txt = model
  
  
  can someone help me write a query to display the above output?

  Hello

  Here's one way: use the function SUMMARY, with a CASE expression:

  SELECT       amt
  ,       txt
  ,       CASE
            WHEN  txt2  IN ('P', 'PR')
            AND   0 < COUNT ( CASE
                                     WHEN  amt     IN (1, -1)
                            AND   txt     = 'dummy'
                            THEN  1
                                 END
                               ) OVER (PARTITION BY pid)
            THEN  'NO'
            ELSE  txt2
         END     AS txt2
  ,       pid
  FROM       table1
  ;
  

• HP 15-p238tx: How can I find all my drivers.

  I install windows 7 on my 15-p238tx. I'd like to find all my drivers.

  Hello:

  You should be able to use all the W7 x 64 drivers and software (do not use the BIOS and firmware files) on your model.

  http://h22207.www2.HP.com/us-en/drivers/selfservice/HP-Pavilion-15-P000-notebook-PC-series/6936226/model/7174371

  To install the graphics on your model, you must:

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• How to find all photos in Lightroom where the original file is not found?

  Greetings

  I know there are a lot of pictures in my library in Lightroom where the original file is not found. How can I find all the photos for which this is the case? In other words, I see the exclamation point error in the upper right part of some photos and I would like to find all photos that have this condition so that I can link them to the originals.

  Thank you

  John

  In the library Module, chose the menu library/search all missing Photos

  

• I need to find all of the XML elements and add a line break for the text of each of them

  I need to find all XML elements and to add a line break the text of each of them.

  Is it possible with a script?

  Try this piece of code as it is. I hope that's what you want...

  var myDoc = app.activeDocument;
  var inddRooElement = myDoc.xmlElements.item(0);
  var xPathElements = inddRooElement.evaluateXPathExpression("//*");
  var elementCount = xPathElements.length;
  for(var eId=0; eId
  ----------------
  Green4ever
  		   

• Find all the lines from the previous column value difference lines

  I have an interesting requirement. There is a DATE column and a user in one table and I have to find all the lines for all users for which the previous and the current line has lagged in lets say more than 30 minutes. The rows are already sorted in time.
  
  For example in the following table, we need to ID 4 and 6 for user 1.
  
  
  Date of the user ID
  1 1 today 1 hr. 0 Min. 0 sec.
  today 2 1 1 hour 1 min 0 sec
  Today 3 1 1 hour 29 min 0 s
  * 4-1 today 1 hour 59 min 3s *.
  5 1 today 2 hours 10 min 2 sec
  * 6 1 today 2 hours 50 min 7 s *.
  
  Published by: user733179 on March 5, 2009 12:00

  Hello

  To obtain a separate calculation for each value of the usr, start the analytical clause with "BY usr PARTITION":

  WITH     got_dif     AS
  (
       SELECT     id,     dt,     usr
       ,     (dt - LAG (dt)
                  OVER ( PARTITION BY  usr
                            ORDER BY          dt
                          )
            )             -- difference in days
                * 24 * 60  AS minutes_dif
       FROM     table_x
  --     WHERE     ...     -- if needed
  )
  SELECT     id,     dt,     usr
  FROM     got_dif
  WHERE     minutes_dif     > 30
  ;
  

• How to find a line number in excel

  Hello

  I need help to find line number in excel.

  Actually what I try to do is, I use the scanner to read the barcode (string) then I need to search for the same string in the excel file (my datas are recorded as like this for ex: in line 5, column 1 I have to chain column 2 column 10 (West) I have certain values). Now when my string corresponds to the West his will display values from column 2 to 10, so I have to find which line matched the West channel number.

  Thank you

  The search through the forums helps a lot. Here is a discussion where I've solved your problem.

  http://forums.NI.com/NI/board/message?board.ID=170&message.ID=200494&jump=true

  For more information and some samples VI and tool kits, you can go to the excel Council

• 114 the desire doesn't print all lines of text

  When you print an email (TEXT), my desire 114 printer prints all lines of text with the same quality.  Some of the lines are darker than others, some lines are barely readable or white, while some lines print only half the size of the font.  When I print a report of State printer, a few lines (like the lines 3, 6, 9 for example) do not print.

  I cleaned up, second level cleaned and aligned the printer several times without success.  Because it's consistent printing for printing when PRINTING TEXT, it almost seems like the printer receives no signal for some lines or print on paper areas.  If a JPG or image is printed, it prints in full.

  Any ideas?

  Thanks for your answer, but after all my attempts to clean the printer heads and firmly reinstall the black cartridge has solved my problem.  I think that the resettlement is actually what solved my problem because like I said in my previous post, it appeared that the printer would not print a few lines compared to others.

  Thanks again for your response.

• How to divide a single line (all lines) for the use of a few sql

  I have table

  Select * from une_table;

  name_a	date_a	name_b	Date_B
  Sunday	01.01.2015	Monday	02.01.2015
  Tuesday	03.01.2015	Wednesday	04.01.2015

  How to divide this table in all lines after using sql:

  name	Date
  Sunday	01.01.2015
  Monday	02.01.2015
  Tuesday	03.01.2015
  Wednesday	04.01.2015

  Thanks for the replies.

  Trajon,

  You don't have a table. You have a store of garbage. There is a repeating group in your 'table' and column name_a etc is unnecessary, because you can derive the day of the week from your date by a to_char function.

  You can find it in your documentation online.

  Knowing that you can get the ordinal number of a date using to_char, what have you tried to do it yourself?

  Your answer is probably: NOTHING.

  First try to solve it yourself and if you post something here, make sure that this forum is not to throw up, because your code that is terribly bad.

  ------------

  Sybrand Bakker

  Senior Oracle DBA

• $ GREP is now finding forced line break. How to disable.

  Somehow, my location indicator GREP $, which has always found just the end of a paragraph (Enter), is now suddenly find the end of a line ending with a forced line break (SHIFT + ENTER).

  So, if in GREP I seek

  Tiger$

  ... it is now to find all occurrences of the word Tiger that appear at the end of a paragraph and also who appear just before a forced line break.

  How to turn off this behavior?

  Could this be something to do with the 8.1 update?

  Thank you

  Ariel

  Win 7, 8.1 InDesign ME

  I think what he used to do... Try with an explicit negative lookahead:

  Tiger (?. \n)$)

• Adjust the height of the line in an interactive report for all lines

  Hello
  I have an interactive report with lots of data in certain cells. The height of the heights of lines varies, so that all data is visible in the cells.
  I want to correct or to limit the row height to a specific value, so that all lines are displayed with the same height.
  Do anyone knows how to win this? Thanks in advance.
  
  Published by: kps204020 on 26.12.2012 20:27

  kps204020 wrote:
  Thanks a lot for your answer.
  I tried your proposal, but it has no effect. The cells in the report show all their content using as many lines as you need for this.

  This is the default behavior for the HTML table data (tables and cells grow to fit their content).

  So I have always with lots of lines, lines and lines with only a few mixed lines in my IR dependant on the contents of the cell. Because some lines almost filling the whole screen, it is difficult to get an overview with regard to adjacent lines.
  I use the Application Express 4.1.1.00.23. with the theme 21. Scarlet and Firefox 17.0.1.

  All users using Firefox?

  In fact, I'm working on my first APEX Solution for use in my business and demanding customers a solution for this topic. So I'm very keen to find a solution.
  I am very looking forward to your reply.

  I have been involved in similar questions in the past. My first reaction is simple: these data must be included in the report? The offending column can be removed from the primary report? They will always be visible in the display of the row and the detail view when it exists.

  The second option is to create a detailed view of the report with a structure that is better suited to the data concerned and make it the default view. (For an example, see the treatment of the PRODUCT_DESCRIPTION column in the detail view of the report in the sample database Application: click the show details on the product page.)

  The third possibility is some sort of customization of the presentation of the data. It will be using a combination of HTML/CSS/dynamic of the Actions/Plug-ins/JavaScript that you may not be familiar with: do you have any experience of these? To go this route, you must describe in detail how you want to present data, or what behavior is required when the data is too long and share a sample of the report on the apex.oracle.com we can work with.

• Justify all lines option questions?

  I want to create a captive text box and all the lines of text to the top on the left and the right, so I use the option justify the option lines.

  1. After you have done that, is it possible to adjust the spacing of the headline? I tried to adjust tracking, even if this does not work. Is the only way to use a separate area or Type Point Type for the title not so is not affected by the option justify all lines option?

  2. is there another way to achieve what I want?

  Thank you.

  Fred,

  I would like to have a single line, such as the title, centered (or other), you can only select this line with text (Path) (on ClickDragging) and paragraph tool > focus (or other).

• The query results: extract all lines?

  I was looking for a feature that will allow me to choose to return "all records" in the query results window. The current behavior is fetching 50 files at a time (for example fetch 50 records when you scroll the results = s-l-o-w). What I would do, that is 'Recover all lines' and then use for the scroll bar to scroll "smoothly" to the last record. For example, the 8.0.6 Query Builder version has this feature and SQL Developer 3.0, if I right click on the results. I choose 'Count lines... ". ", looks like it would be a perfect place to put an option"retrieve all rows.

  If your application is to be able to quickly reach the last record in a query you can press Ctrl + Page Down (with emphasis in the grid of results) and you will automatically position your view to the last record in the query automatically go get all the results in the process.

  You have no need to do anything with the mouse scroll is actually the fastest way to reach the desired line.

• Can we find the lines twice in a table

  Hi all
  Just curious, is it possible, we can find all the lines twice in a table without comparing the individual columns?
  
  for example if we have a table emp (without any unique constraint defined) with the emp_id, emp_name and dept columns
  and entire duplicate as lines below:
  < pre >
  emp_id, emp_name dept
  1 ABC 20
  1 ABC 20
  2 30 DEF
  DEF 2 30 < / pre >
  
  Here, there are duplicate lines. Do we have all these criteria where we can search all duplicate line without comparison emp_id, emp_name and dept?
  
  Thank you
  Deepak

  I'm not sure what you mean by "Comparing the individual columns", but there are several ways to identify duplicates.

  And here's one:

  SELECT  EMP_ID
  ,       EMP_NAME
  ,       DEPT
  FROM    EMP
  GROUP BY EMP_ID
  ,       EMP_NAME
  ,       DEPT
  HAVING COUNT(*) > 1
  

  Here's another:

  SELECT  DISTINCT
          EMP_ID
  ,       EMP_NAME
  ,       DEPT
  FROM
  (
          SELECT  EMP_ID
          ,       EMP_NAME
          ,       DEPT
          ,       ROW_NUMBER() OVER (PARTITION BY EMP_ID, EMP_NAME, DEPT ORDER BY EMP_ID, EMP_NAME, DEPT) RN
          FROM    EMP
  )
  WHERE   RN > 1
  

• Find the line in the 2d array

  Help, please...

  I have a 2d double table and I want to find a specific line, an extract to new table 2d.

  My 2d array is:

  100	31.3	25.3	32.1	25.6
  100	31.3	25.3	32.1	25.6
  160	32.4	25.5	33.5	26
  170	33.2	25.8	34.3	26.2
  100	33.9	26	35.2	26.4
  160	32.4	25.5	33.5	26
  160	32.4	25.5	33.5	26
  100	31.3	25.3	32.1	25.6
  170	33.2	25.8	34.3	26.2

  and I want to find the line with the numbers 100,160,170 and build new table 2d

  100	31.3	25.3	32.1	25.6
  160	32.4	25.5	33.5	26
  170	33.2	25.8	34.3	26.2

  Please help... tnx, tnx

  I guess you should be more specific about your question. If you have decided to find values that are present in the 1st column, you can use search table 1 d and pass the index to the 2D array index so you will get a table 1 d of line then build the table by searching for the element.

  

  

  That's what explains Yamaeda