identify the most recent candidate

First I'm sorry for the creation of a long term position, just trying to understand.
Please help me make my efficient query.

Example followed with a logic behind the scenes.

create table finalcand (ptsequence number,version number,candidate varchar2(10),date_submitted date,
file_valid varchar(2))

insert into finalcand values(101,1,'VJ',TRUNC(SYSDATE),'Y');
insert into finalcand values(102,1,'RD',TRUNC(SYSDATE),'Y');
insert into finalcand values(103,1,'GD,TRUNC(SYSDATE),'Y');
insert into finalcand values(104,1,'GD',TRUNC(SYSDATE),'N');
insert into finalcand values(105,2,'GD,TRUNC(SYSDATE),'Y');
insert into finalcand values(107,2,'GVR',TRUNC(SYSDATE),'N');
insert into finalcand values(106,1,'GD',TRUNC(SYSDATE+1),'Y');
insert into finalcand values(108,1,'GD',TRUNC(SYSDATE),'Y');
insert into finalcand values(109,2,'GVR',TRUNC(SYSDATE+1),'Y');

o/p required

   PTSEQUENCE    VERSION    PATIENT DATE_SUBMITTED FILE_VALID   RNK
     105     2     GD     7/23/2009           Y             2
     108     1     GD     7/23/2009           Y             3
     103     1     GD     7/23/2009           Y             4
     104     1     GD     7/23/2009           N             4
     107     2     GVR     7/23/2009           N             2

IM using this query that works perfectly, but I'm still trying to see if I can do it effectively.

SELECT z.*
  FROM (SELECT r.*,
               RANK() OVER(
               PARTITION BY r.candidate 
               ORDER BY R.DATE_SUBMITTED DESC,
                        R.VERSION DESC, 
                        R.PTSEQUENCE desc) rnk
          FROM finalcand r
          where file_valid='Y') z
 WHERE RNK >1
union all
SELECT z.*
  FROM (SELECT r.*,
               RANK() OVER(
               PARTITION BY r.candidate  
               ORDER BY R.DATE_SUBMITTED DESC,
                        R.VERSION DESC, 
                        R.PTSEQUENCE desc) rnk
          FROM finalcand r
          ) z
 WHERE RNK >1
 and z.file_valid='N'

Logic behind it all

This is to identify all records that are no more final candidate

-> candidate is identified by the name of the candidate.
-> version and date_submitted is used to identify the most recent entry of this candidate.
-> if same candidate has several entries with the same version and also date_submitted even then use max (ptsequence) to identify the most recent.

Problem here is
-> if we see a candidate with File_valid input = ' don't this means that the earlier version of this candidate should be the most recent.
An other problem is
-> if we see a candidate with File_valid input = ' don't and no not all old records, then the current should be the last.

Thanks for reading this post.

Published by: user5495111 on July 23, 2009 13:37

OK then, this query matches your output (with the exception of the rank column)

select * from (
select r.*
     , row_number() over (partition by r.candidate
                              order by r.file_valid desc
                                  , r.date_submitted desc
                                  , r.version desc
                                  , r.ptsequence desc) rn
  from finalcand r)
  where rn!=1
  order by candidate, rn

PTSEQUENCE  VERSION  CANDIDATE  DATE_SUBMITTED    FILE_VALID RN
----------- -------- ---------- ----------------- ---------- ----
105         2        GD         23-JUL-2009       Y          2
108         1        GD         23-JUL-2009       Y          3
103         1        GD         23-JUL-2009       Y          4
104         1        GD         23-JUL-2009       N          5
107         2        GVR        23-JUL-2009       N          2   

5 rows selected

Tags: Database

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