Identify the Session parameters

Dear Experts,

How can a DBA, I identify the session level settings. For example, a session changes the initialization of the settings at a session level such as below:

Session 1_

ALTER session set cursor_sharing = force;

Select * from emp where empno = 123;



and the session preceding is always connected.

Is there a view to watch for the updated initialization settings the?

Thanks for the work on my question.

Concerning

Oracle Lover3 wrote:
Dear Experts,

How can a DBA, I identify the session level settings. For example, a session changes the initialization of the settings at a session level such as below:

Session 1_

ALTER session set cursor_sharing = force;

Select * from emp where empno = 123;

and the session preceding is always connected.

Is there a view to watch for the updated initialization settings the?

As he has already contributed by others to in the session, you can use V$ PARAMETER to find corrupted session parameter values.

For settings that apply to the optimizer, there are two new modes in Oracle 10 g and later: V$ SYS_OPTIMIZER_ENV and V$ SES_OPTIMIZER_ENV.

V$ SYS_OPTIMIZER_ENV represents the default values inherited by each session defined by the parameters of the instance.

V$ SES_OPTIMIZER_ENV displays the current values for each session, including all parameters changed in the session by ALTER SESSION. If this practical perspective can be used to check from outside the session if all relevant parameters for the optimizer have been modified or not.

Kind regards
Randolf

Oracle related blog stuff:
http://Oracle-Randolf.blogspot.com/

SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676 /.
http://sourceforge.NET/projects/SQLT-pp/

Tags: Database

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Execution Plan
----------------------------------------------------------
Plan hash value: 1171456783

---------------------------------------------------------------------------------------------------------------------
| Id  | Operation                          | Name           | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
---------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT                   |                |     1 |    49 |     4   (0)| 00:00:01 |       |       |
|   1 |  PARTITION RANGE ALL               |                |     1 |    49 |     4   (0)| 00:00:01 |     1 |     3 |
|*  2 |   TABLE ACCESS BY LOCAL INDEX ROWID| ONS            |     1 |    49 |     4   (0)| 00:00:01 |     1 |     3 |
|*  3 |    INDEX RANGE SCAN                | IDX_COD        |     1 |       |     4   (0)| 00:00:01 |     1 |     3 |
---------------------------------------------------------------------------------------------------------------------

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---------------------------------------------------

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SQL> alter session set nls_comp=LINGUISTIC;

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PARAMETER                                          VALUE
-------------------------------------------------- ------------------------------------------------------------
NLS_LANGUAGE                                       AMERICAN
NLS_TERRITORY                                      AMERICA
NLS_CURRENCY                                       $
NLS_ISO_CURRENCY                                   AMERICA
NLS_NUMERIC_CHARACTERS                             .,
NLS_CALENDAR                                       GREGORIAN
NLS_DATE_FORMAT                                    DD-MON-RR
NLS_DATE_LANGUAGE                                  AMERICAN
NLS_SORT                                           BINARY_CI
NLS_TIME_FORMAT                                    HH.MI.SSXFF AM
NLS_TIMESTAMP_FORMAT                               DD-MON-RR HH.MI.SSXFF AM
NLS_TIME_TZ_FORMAT                                 HH.MI.SSXFF AM TZR
NLS_TIMESTAMP_TZ_FORMAT                            DD-MON-RR HH.MI.SSXFF AM TZR
NLS_DUAL_CURRENCY                                  $
NLS_COMP                                           LINGUISTIC
NLS_LENGTH_SEMANTICS                               CHAR
NLS_NCHAR_CONV_EXCP                                FALSE

17 rows selected.


SQL> select id,is_active from ons where domicile = 'US' and id = 440 and name = 'AMERICAN COMPANY';

Execution Plan
----------------------------------------------------------
Plan hash value: 270874147

------------------------------------------------------------------------------------------------------------------------------
| Id  | Operation                          | Name                    | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
------------------------------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT                   |                         |     1 |    49 |     2   (0)| 00:00:01 |       |       |
|   1 |  TABLE ACCESS BY GLOBAL INDEX ROWID| ONS                     |     1 |    49 |     2   (0)| 00:00:01 | ROWID | ROWID |
|*  2 |   INDEX RANGE SCAN                 | UX_NAME_BR              |     1 |       |     2   (0)| 00:00:01 |       |       |
------------------------------------------------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

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    Since you have a session variable as part of the report, and this variable initialization failed, you get this error.

  • need help to identify the responsible application of integration...

    Hello

    I'm a guy MSSQL and Oracle is still a little mysterious to me.  I'm looking for assistance tracking the application in an environment that is responsible for special inserts.

    For example, I have 10 different programs running and inserting values to a DB.  I need to know which of them inserts a '0' in a particular column.

    I found a trigger that will tell me the user, unfortunately these programs use a credential that is shared so that it does not help me... here is what I have:

    CREATE OR REPLACE TRIGGER check_for_zero_insert

    AFTER INSERTION

    ON DATA_TABLE_0001

    FOR EACH LINE

    DECLARE

    v_username varchar2 (10);

    BEGIN

    -Find user name of the person making the INSERTION in the table

    SELECT user INTO v_username

    DOUBLE;

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    INSERT INTO audit_table

    (instance.

    seems,.

    user name ( )

    VALUES

    (: seems,)

    : instance.

    v_username);

    END;

    But even once, user name will not help me, I need the originating instance if possible (a name of the executable, PID or something to identify the specific application of the other side.)

    There are other columns of information in session $ v - you might find program, machine or a process (PID process) useful.

    declare

    v_user varchar2 (30); v_program varchar2 (64); v_machine varchar2 (64); v_process varchar2 (24);

    Start

    Select the process, machine, program, osuser

    in v_user, v_program, v_machine, v_process

    session $ v where sid = sys_context ('userenv', 'SID');

    end;

    /

  • identify the tables that are affected by a transaction

    Hi guys,.

    I am running version:

    Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
    PL/SQL Release 11.2.0.3.0 - Production
    CORE Production 11.2.0.3.0
    AMT for Linux: Version 11.2.0.3.0 - Production
    NLSRTL Version 11.2.0.3.0 - Production



    Is it possible to identify the SQL code or the tables involved in a transaction by looking at the transaction$ v?

    Just wrote a small application, but can't test it in my DB... Just check it...
    Basically CREATE all the views will provide some information.

    SELECT t.ses_addr,
       s.sid,
       p.object_id,
       D.OBJECT_NAME,s.command
  FROM v$transaction t,
       v$session s,
       V$locked_object p,
       dba_objects d
 WHERE     t.ses_addr = s.saddr
       AND p.session_id = s.sid
       AND d.object_id = p.object_id;

    The command column is a code displays what kind of operation is being currently... the explanation of the code can be mentioned in the documentation:

    http://docs.Oracle.com/CD/B19306_01/server.102/b14237/dynviews_2088.htm

    See you soon,.
    Manik.

  • the current user of the session & current schema

    Hi all


    ACC to a url
    "
    o CURRENT_USER: the name of the user whose privilege the session is running
    in the framework.

    o SESSION_USER: the name of the user who originally created this session? who is online
    in. It is constant for a session.

    o CURRENT_SCHEMA: the name of the default schema that will be used to resolve references
    for objects not qualified.
    "

    Session user is clearly making the distinction. My question is that is there any situation when the CURRENT_USER and CURRENT_SCHEMA is different? My understanding is that when we have a program of sup with authid define, then the user of the session I (if another user not the define called)
    is different and the current_schema is different. The current_schema is definers schema while the user of the session is the Summoner of the program overtime. I guess that this is a good understanding.


    Is EQUIVALENT to current_user, current_schema? If this is not the case, if someone can cite a small program to show the difference?

    As others have said, current_schema contols which schema for unqualified names are resolved in. It can be changed using:

    alter session set current_schema =

    or in a stored procedure liike authid clause:

    SQL> Create Procedure test_definer as
  2     l_user           VARCHAR2(30);
  3     l_current_user   VARCHAR2(30);
  4     l_session_user   VARCHAR2(30);
  5     l_current_schema VARCHAR2(30);
  6  begin
  7     select user into l_user from dual;
  8
  9     select Sys_Context('USERENV', 'CURRENT_USER')
 10     into l_current_user
 11     from dual;
 12
 13     select Sys_Context('USERENV', 'SESSION_USER')
 14     into l_session_user
 15     from dual;
 16
 17     select Sys_Context('USERENV', 'CURRENT_SCHEMA')
 18     into l_current_schema
 19     from dual;
 20
 21     Dbms_Output.Put_Line ('User is: '||l_user);
 22     Dbms_Output.Put_Line ('Current User is: '||l_current_user);
 23     Dbms_Output.Put_Line ('Session User is: '||l_session_user);
 24     Dbms_Output.Put_Line ('Current_schema is: '||l_current_schema);
 25  end;
 26  /

Procedure created.

SQL> Create Procedure test_current
  2     authid Current_user as
  3     l_user           VARCHAR2(30);
  4     l_current_user   VARCHAR2(30);
  5     l_session_user   VARCHAR2(30);
  6     l_current_schema VARCHAR2(30);
  7  begin
  8     select user into l_user from dual;
  9
 10     select Sys_Context('USERENV', 'CURRENT_USER')
 11     into l_current_user
 12     from dual;
 13
 14     select Sys_Context('USERENV', 'SESSION_USER')
 15     into l_session_user
 16     from dual;
 17
 18     select Sys_Context('USERENV', 'CURRENT_SCHEMA')
 19     into l_current_schema
 20     from dual;
 21
 22     Dbms_Output.Put_Line ('User is: '||l_user);
 23     Dbms_Output.Put_Line ('Current User is: '||l_current_user);
 24     Dbms_Output.Put_Line ('Session User is: '||l_session_user);
 25     Dbms_Output.Put_Line ('Current_schema is: '||l_current_schema);
 26  end;
 27  /

Procedure created.

    Copyright being the default, test_definer procedure works with the privileges and in the schema of the user Thatcreated in this oracle of $ case ops. The test_current procedure operates in the schema of the user calling him and privileges. So if we call both in the scheme of the owner that they are actually the same:

    SQL> exec test_definer;
User is: OPS$ORACLE
Current User is: OPS$ORACLE
Session User is: OPS$ORACLE
Current_schema is: OPS$ORACLE

PL/SQL procedure successfully completed.

SQL> exec test_current;
User is: OPS$ORACLE
Current User is: OPS$ORACLE
Session User is: OPS$ORACLE
Current_schema is: OPS$ORACLE

PL/SQL procedure successfully completed.

    However, if we create a new user and give that run them both, we'll see a feel:

    SQL> create user a identified by a;

User created.

SQL> grant create session to a;

Grant succeeded.

SQL> grant execute on test_definer to a;

Grant succeeded.

SQL> grant execute on test_current to a;

Grant succeeded.

SQL> connect a/a
Connected.
SQL> exec ops$oracle.test_definer;
User is: A
Current User is: OPS$ORACLE
Session User is: A
Current_schema is: OPS$ORACLE

PL/SQL procedure successfully completed.

SQL> exec ops$oracle.test_current;
User is: A
Current User is: A
Session User is: A
Current_schema is: A

PL/SQL procedure successfully completed.

    John

  • Query Builder session parameters as a resolve to ORA-01843 (not a month valid)

    Hi all! I am new to Oracle and RDBMS, sorry for a fake question.
    I'm doing a few queries to a tutorial (10 g XE) database with Query request Builder Express 2.1000039.
    I ask the column with id, order date and order status. in a column of the date as a condition command 'where' I've wrote:
     >= to_date('23-JUN-2006', 'DD-MON-RRRR')
    and got an error "ORA-01843: not one month valid."

    Then I edited the line filter condition:
     >= to_date('23-JUN-2006', 'DD-MON-RRRR', 'NLS_DATE_LANGUAGE = american')
    and got a decent result, BUT resulting table date format DD-MM-RR.

    So, here are a few questions:
    1. can I change settings of session (for example
    alter session set NLS_DATE_FORMAT = 'DD-MON-RRRR'
    ) so, to use it in the query designer, before you generate a request itself and do not write "NLS_DATE_LANGUAGE = american' whenever I am inserting data to a field of date data type?"
    2. I wonder why resulting table date format is "DD-MM-RRRR. How can I get a data exactly in a date format 'DD-MON-RRRR', how I am specifying in a query?

    My operating system is Windows 7 Home Basic Edition, NLS_DATE_FORMAT is DD-MON-YYYY in 2 cases, the register and, respectively, in the environment variable.

    SQL * Plus displays all tables in query mentionted correctly, corresponding to an "ALTER SESSION...". PARAMETERS.

    Hope for your help, guys. Thanks for the replies!

    >
    Can I change "Application Builder-> Application-> change security attributes" without creating applications?
    >

    No you need to create an application, and as I said application-level settings determine the application only, is not a solution. Furthermore, I'm not sure that this property is available in your version of the Apex.

    I tried to change the session using SQL commandsand then I went back to the Query Builder, but it doesn't change anything, it seems different sessions are used to connect to the database.

    Yes, I'm sorry, but I have no solution for you, maybe there is a way to change this somewhere in the admin part, but I have no rights admin here and I can't test anything.

    I hope that a few experts hops on the thread ;)

  • "CFADMIN", "there was an error while checking the token. The session has expired or UN-bel

    People - I am really stumped on this one and need help.  I train a new employee on our CF 9.0.2 EA environment and I wanted him to run some of our scheduled tasks.  I had to open a session in the production with the admin site and password (one-time password using only the id of cfadmin "generics") without incident.

    He sailed to the scheduled tasks without incident, clicked the button "Run the scheduled task" and upward jumped a message to open a session in Administrator CF.  Never, ever have I seen this happen before.  I checked, and no one else was recorded in the CF administrator at the time.

    The application log contained the following warning: "CFADMIN", "there was an error while checking the token. The session has expired or unauthenticated access is suspected. »

    I have google, Yahooed and anything else in the meantime and can only end of references to CF10 and single account sessions.  Yet once we checked it was the on using only the administrator see  (I know because I am just another one who knows the admin password).  We are all both in the same group of security for the server (Windows 2003 R2) administration have the same level of security to the database - read-only (MS SQL Server 2005), but none of this is important since we are through THE and by using the IUSER or IWAM permissions.  Doesn't seem to matter if the integrated Windows authentication check or not in IE options either.

    I tried to separate application ID and password security - but I got the same error message.

    All ideas are most appreciated.

    Libby

    Charlie - thank you very much for your help.  Although you have identified the real problem, unfortunately I have always a solution.  But I kept in the back of my mind...

    But just recently, I was hit with this same problem myself.  As a last resort, I clean my cookies and all my temporary Internet files.  For me, that did the trick.

    My store is running the most vanilla of CF9 environments possible, Web site instance unique, the only database MS SQL Server, IIS 7 on a Windows 2008 R2 server.  Absolutely not the bells and whistles.

    Again, thank you for taking the time to read my post and you offer thoughts and support.  Without the help of specialists like you - well - I don't know where I'd be.

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