importing into a partitioned table of interval 11g

Similar Questions

• import a table that is partitioned into non partitioned table?

  Hello
  
  RDBMS 10 g
  
  It's my scenario:
  I took an export datapump of a schema containing partitioned tables.
  
  Now, I'm supposed to import this schema in another data base were partitioning option is not installed, so it must be converted to a table somehow unique bunch.
  
  What are my options to achieve this without having to install partitioning... ?
  
  Thank you!

  Extract the ddl, create the tables (not cut) at the front, and then import data only (or table_exists_action = add).

  Nicolas.

• Try to convert the partitioned Table of interval in the range... Swap partition...

  Requirement:
  
  Interval of replacement partitioned Table by range partitioned Table
  

  DROP TABLE A;
  
  CREATE TABLE A
  (
     a              NUMBER,
     CreationDate   DATE
  )
  PARTITION BY RANGE (CreationDate)
     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
     (PARTITION P_FIRST
         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  
  INSERT INTO A
       VALUES (1, SYSDATE);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 30);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 60);

  I need to change this partitioned Table apart to a partitioned range Table. I can do using the EXCHANGE PARTITION. Like if I use the classic method to create another table range partitioned, then:
  
  

  DROP TABLE A_Range
  CREATE TABLE A_Range
  (
  a NUMBER,
  CreationDate DATE
  )
  PARTITION BY RANGE (CreationDate)
     (partition MAX values less than (MAXVALUE));
  
  Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.

  Problems:
  
  I can't do
  

   ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A
    WITHOUT VALIDATION;
   

  ORA-14095: ALTER TABLE CHANGE requires a not partitioned table nonclustered
  This is because the tables are partitioned. So it does not allow me.
  
  If I instead:
  
  
  Create a table that is not partitioned for exchanging data by partition.
  

    Create Table A_Temp as Select * from A;
    
     ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A_TEMP
    WITHOUT VALIDATION;
     
    select count(*) from A_Range partition(MAX);
   

  -The problem is that all the data is in MAX Partition.
  Even after the creation of a large number of partitions by walls of separation, the data is still in MAX Partition only.
  
  So:
  
  -What we cannot replace a partitioned Table to the Table partitioned using the EXCHANGE PARTITION range interval. that is, we have to insert in...
  -We can do it, but I'm missing something here.
  -If all the data is in MAX Partition due to "WITHOUT VALIDATION", can say us be redistributed in the right type of range partitions.

  You must pre-create the partitions in a_range and then swap one for one for a tmp, and then to arange. With the help of your sample (thanks to proviing code, incidentally).

  SQL> CREATE TABLE A
    2  (
    3     a              NUMBER,
    4     CreationDate   DATE
    5  )
    6  PARTITION BY RANGE (CreationDate)
    7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
    8     (PARTITION P_FIRST
    9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  Table created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 30);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 60);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  

  You can find the form of existing partitions assistance:

  SQL> select table_name, partition_name, high_value
    2  from user_tab_partitions
    3  where table_name = 'A';
  
  TABLE_NAME PARTITION_NAME HIGH_VALUE
  ---------- -------------- --------------------------------------------------------------------------------
  A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  

  You can then create the table a_range with apporopriate partitions. Note that you may need to create additional in a_range partitions because the partitioning interval does not create the partitions has no data for, even if that leaves 'holes' in the partitioning scheme. So, on that basis:

  SQL> CREATE TABLE A_Range (
    2     a NUMBER,
    3     CreationDate DATE)
    4  PARTITION BY RANGE (CreationDate)
    5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
    6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
    7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
    8      partition MAX values less than (MAXVALUE));
  
  Table created.
  

  Now, create a regular table to use in the constituencies:

  SQL> CREATE TABLE A_tmp (
    2     a              NUMBER,
    3     CreationDate   DATE);
  
  Table created.
  

  and all partitions in Exchange:

  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p44
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION jan_2013
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p45
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION dec_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p46
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION nov_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> select * from a;
  
  no rows selected
  
  SQL> select * from a_range;
  
           A CREATIOND
  ---------- ---------
           1 23-NOV-12
           1 23-DEC-12
           1 22-JAN-13
  

  John

• 11g auto States meet on partitioned tables

  Ive looked at notes

  Collecting statistics on partitioned Table 10g and 11g (Doc ID 1417133.1()

  and
  

  Database RAC DataGaurd and APPS: DBMS_STATS enhancements in Oracle Database 11g

  11.2.0.2

  Ive just noticed that automatic statistics maintenance night window collect works at the level of the table, but not on the scores of partitioned tables (stats white poster) still a global stats meet at the end of week doesn't work.   If someone looked before can you specify

  I need set at the database level so that a change will result in that all my partitioned tables get analyses during the race every night.  IM guess incremental = true.

  Or a level table, it looks like additional dbms_stats.set_prefs = true will work according to the above.  ID rather self-employment prepare tho so I did not do it at the table level.

  How can I change nightly differential work = true if that's what is necessary?

  Thank you.

  ignore this.  We had a bug that disabled our auto stats every night gather running works now.

  I opened a call, asides stats collection not... the real answer to my question (which Im sure some of you knew anyway) is that the incremental stats every night together stats if (score > 10% Rassi) and overall stats are collected if (total variations in all partitions stale > 10%)...

  If the stats are gathered first at the partition level and based on these changes that the overall statistics are developed.

• Create no partition Table partitioning

  Dear all,

  I have a table that is not partition, and it has about 20 G data... If I want that table with say DATE_M partition column

  Please can anyone suggest the best way to do it.

  Thank you

  To create a partitioned table

  (1) you must make a backup of the existing one you can take expdp or DEC

  (2) remove the table and create the same table now with partitions (a minimum score is required)

  you want a range of ex-based partition if you use a date column

  (3) loading data from the previous table into the new partitioned table, either by DEC or impdp, the inserts will be automatically in their respective partitions and you don't mention explicitly.

  Their is no other possible way to partition a non partitioned table, you can do than workarounds to minimize the downtime of the table trying different ways to load data into the partitioned table.

  You can use the enable row movement clause of create table and also use local indexes for easy maintenance partition.

• Delay in a partitioned table index population

  Hello
  
  We have a 3 TB database, which earns about 5 GB per day. Fat is partitioned by date (a partition for each day), as well as their local indexes. The population of data is made by IBM DataStage and assume that it uses a bulk loading. I have 2 questions:
  
  1. is the index updated immediately for cargo in bulk, or Oracle wait until the load has finished updating indexes on table?
  2. is there a way to tell Oracle to have an index for a table, but not for a partition of this table? What I want to do is fill partition today the table with data today, but be able to build the index for this partition at a later date. Deletion and re-creation of the index for the entire table are not an option.
  
  Thank you.

  What you would normally do here is to load the data into a separate intermediate table, build indexes on this staging of the table, and then create a swap partition to load the data into the partitioned table. Exchange partition is a way to exchange very quickly a partition of a partitioned with a separate table and unpartitioned table. This happens almost instantly.

  Justin

• Size of partition on interval range partitioned Table happens when SYSDATE is used in a Where Clause

  We have tables interval range partitioned on a DATE, with a partition for each day column - very standard and straight out of doc Oracle.

  A 3rd party application queries the tables to find the number of rows based on the date range that is located on the column used for the partition key.

  This application uses the date range specified from the current date - i.e. for last two days would be «...» StartDate > SYSDATE-2 "- but the partition size is irrelevant and the explain command plan shows that each partition is included."

  In presenting the request uses the date in a variable partition size location and query table is obviously much better.

  DB is 11.2.0.3 on RHEL6, and default settings - i.e. nothing that could influence the behavior of the optimizer to something unusual.

  I can't work on why this would be the case. It is very easy to reproduce with cases of simple test below.

  I would be very interested to hear any views on why it's that way and if anything can be done to allow the size of the partition to work with a query including SYSDATE because it would be difficult to get the application code has changed.

  In addition to make a case to change the code, I need an explanation of why query using SYSDATE is not advisable and I know this information.

  (1) create a simple partitioned table

  CREATETABLE part_test
     (id                      NUMBER NOT NULL,
      starttime               DATE NOT NULL,
      CONSTRAINT pk_part_test PRIMARY KEY (id)) 
  PARTITION BY RANGE (starttime) INTERVAL (NUMTODSINTERVAL(1,'day')) (PARTITION p0 VALUES LESS THAN (TO_DATE('01-01-2013','DD-MM-YYYY')));
  

  (2) fill in the rows of the table 1 million distributed among 10 partitions

  BEGIN
      FOR i IN 1..1000000
      LOOP
          INSERT INTO part_test (id, starttime) VALUES (i, SYSDATE - DBMS_RANDOM.value(low => 1, high => 10));
      END LOOP;
  END;
  /
  EXEC dbms_stats.gather_table_stats('SUPER_CONF','PART_TEST');
  

  (3) to query the Table of data from the last 2 days using SYSDATE in paragraph

  EXPLAIN PLAN FOR 
  SELECT  count(*) 
  FROM    part_test
  WHERE   starttime >= SYSDATE - 2;
  

  -------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     3 ×  7895 (1) | 00:00:01 |       |       |

  |   1.  GLOBAL TRI |           |     1.     3 ×            |          |       |       |

  |   2.   RANGE OF PARTITION ITERATOR.           |   111K |   867K |  7895 (1) | 00:00:01 |   KEY | 1048575.

  |*  3 |    TABLE ACCESS FULL | PART_TEST |   111K |   867K |  7895 (1) | 00:00:01 |   KEY | 1048575.

  -------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter("STARTTIME">=SYSDATE@!-2)

  (4) now do the same query, but with SYSDATE - 2 presented as a literal value.

  This query returns the same response but very different cost.

  EXPLAIN PLAN FOR
  SELECT count(*) 
  FROM part_test
  WHERE starttime >= (to_date('23122013:0950','DDMMYYYY:HH24MI'))-2;
  

  -------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     8.   131 (0) | 00:00:01 |       |       |

  |   1.  GLOBAL TRI |           |     1.     8.            |          |       |       |

  |   2.   RANGE OF PARTITION ITERATOR.           |   111K |   867K |   131 (0) | 00:00:01 |   356 . 1048575.

  |*  3 |    TABLE ACCESS FULL | PART_TEST |   111K |   867K |   131 (0) | 00:00:01 |   356 | 1048575.

  -------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 filter ("STARTTIME" > = TO_DATE (' 2013-12-21 09:50 ',' syyyy-mm-dd hh24:mi:ss'))))

  Thank you in anticipation

  Jim

  sysdate is not constant and its value may change from time optimization of execution; but the optimizer can deduce that he will be a known running value and then produce a plan that will make the size of partition running.  This is the meaning of 'KEY' in the column pstart – the partition of departure will be known at run time and the size of partition will take place in order to eliminate the previous partitions.

  Concerning

  Jonathan Lewis

• Can we import data from partition to a partition not table table?

  Hello
  
  I have partition table export dump.i want to import the table into the table to partition not... is it possible?
  
  
  
  Thank you
  Yusuf

  Yes. Just pre-create the table partitions WITHOUT in the system that you want to import. Then start the import operation with ignores = (ignore existing objects). To import the rows in the table, and since it is not defined with partitions there is no partitions.

• Disable LOGGING for partition table based on the automatic INTERVAL

  Hello
  
  I created a database table of paritioned range interval with NOLOGGING as the default attribute for the table as well as the tablespace definition.
  
  When ORACLE automatically creates a new partition for this table, it activates the LOGGING for this automatic partition even if the table definition says anything else.
  
  How can I go about changing this behavior? Is it still possible?
  
  FYI my platform is 11 GR 1 (11.1.0.7) material on SUN SOLARIS 10 SPARC.
  
  Any help will be appreciated.

  Right, so refer to a new feature of Oracle 11 g partitioning called 'partitioning interval. "

  +"+
  + The interval partitioning: A new strategy of partitioning in Oracle Database 11g, +.
  + Interval partitioning extends the functionality of the method range to define equipartitioned +.
  + ranges using a definition of the interval. Rather than specify individual +.
  + going to explicitly, Oracle will create any partition automatically as needed.
  + every time the data of a partition are inserted for the first time. Interval +.
  + a lot of partitioning improves maneuverability of a partitioned table. For +.
  example, + a partitioned table interval could be set so that Oracle creates a +.
  + new partition for each month in a calendar year; a partition is then automatically +.
  + created for "September 2007" as soon as the first record in this month is inserted.
  + in the database. +
  + The techniques available for a partitioned table interval are interval, interval-+.
  + List, range-Hash, and interval range. +
  +"+

  In order to disable interval partitioning on the transactions table, use:
  
  ALTER TABLE transactions SET INTERVAL ();
  

  http://download.Oracle.com/docs/CD/B28359_01/server.111/b32024/part_admin.htm

  Disable partitioning interval on this table, create a procedure to run every day we'll say, to create a new partition and chop the old partition of the appropriate table. I presume that the automatic partitioning interval creates the partition with the logging by default option without checking the parameters in the table. I have seen no information on this in the Oracle documentation.

  Hope that helps.

  Ogan

• import of partitioned table

  Hello world
  
  We have a partitioned table that has 18 recording. I exported the table partitioned into an image file. Now, we import only 6 partitions of the partitioned table.
  
  I want to clarify that we need create the table in advance and import only those paritiones by specifying like this:
  
  IMP xyz/nnn@orcl tables = (tablename:partitionname, tablename:partitionname, etc...) ignore = y
  
  I'm doing it correctly?
  
  Thanks in advance

  Hello
  You are right that you don't need to create the table before import. Import command will create the required table and table and partitions for you. It will create all the partitions but will import the data of only the partition that you MENTION, and you must then manually remove the partitions that are not necessary.
  I suggest you to make export of partitions only you want rather than export the full table and import only a few partitions.

  Salman

• Possible to move data in a partitioned into another tablespace table without indexes becoming UNUSABLE?

  Hello

  We use oracle 11.2.0.3 and know that if move us data into partitions to a different tablespace indexes get marked as UNUSABLE.

  It is the range of composite date hash partitioned table.

  As a result, to rebuild the global and local bitmap index.

  Is it possible to transfer data to one another without the index tablespace becomes UNUSABLE?

  Thank you

  Hello

  If you want to update the index (so that it becomes invalid) while you perform the move partition, you can use the index update clause.

  Details are mentioned in the Oracle documentation. Glue one of the page here for quick reference.

  Maintenance of Partitions

  Note: It has an impact on the duration of this sql statement which may increase or decrease depending on the amount of data to move.

  Concerning

  Anurag

• Creating a partitioned table to an existing table interval.

  Hello

  Is there a way I can create a partitioned table interval of an existing table using DEC? I know how to create a partitioned table in range.

  create the table range_partitioned_table

  partition by range (date_column)

  (

  partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),

  lower partition p2 values (to_date (' 09/01/2012 ',' mm/dd/yyyy')),

  PN VALUES LESS THAN (MAXVALUE) PARTITION

  )

  AS SELECT * from existing_table;

  Is there a similar way to the Interval partition an existing table?

  create the table interval_partitioned_table

  partition by range (date_column)

  interval (provide the interval)

  (

  partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),

  partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),

  -PN SCORE VALUES LESS THAN (MAXVALUE)

  )

  AS SELECT * from existing_table;

  For example:

  SQL > create table interval_partitioned_table
  2 partition by range (hiredate)
  interval of 3 (numtoyminterval(1,'YEAR'))
  (4)
  5 score below p1 ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),
  6 partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),
  7 - PARTITION pN VALUES LESS THAN (MAXVALUE)
  8)
  9 AS SELECT * FROM emp;

  Table created.

  SQL >

  SY.

• Links of images imported from a CSV file into a SQL table using phpMyAdmin

  I have .csv with five areas, the first is images.

  images150/9310VSony02.jpg.

  This imported into a sql database using phpMyAdmin (first time user) table called rsIMAGESTEST.

  Using Dreamweaver is applying insert for php objects/dynamic Table/Recordset XXX pages

  The table is at - he saw in explores the image url is displayed rather than the jpeg format. image.

  The rest of the data in other areas is fine stright txt. Please can someone explain what I am doing wrong.

  Flowing is the sql I can to get what we need to change?

  @mysql_select_db ($database_pauls, $pauls);

  $query_Recordset3 = SELECT * FROM rsIMAGESTEST;

  $Recordset3 = mysql_query ($query_Recordset3, $pauls) or die (mysql_error ());

  $row_Recordset3 = mysql_fetch_assoc ($Recordset3);

  $totalRows_Recordset3 = mysql_num_rows ($Recordset3);

  To view the image, you must pass the value of the recordset to the src attribute of the tag. Assuming that the domain name is 'image ':

  You can also use Insert a picture. In the dialog box select the Source Image, the value of "Select file name of" to "Data Sources." You can then select the domain name correct of your recordset.

• A slower loading into partitioned table as the non partitioned table - why?

  Hello
  
  Using oracle 11.2.0.3.
  
  Have a large fact table and do some comparative tests on the loading of large amounts of data histroical (several hundred GB) in fact range partitioned to date table.
  
  Although I understand if use exhange partition loading may be faster to load a partitioned table, trying to figure out why a standard sql insert takes 3 x long to load a table partitioned compared to an identical table but not partitioned. Identical EVERYHING in terms of columsn and the sql that the insert and second partitioned sql execution to
  ensure caching with no impact.
  
  Local partitioned table a partitioned bitmap index as compared to the non-partitioned table that has standardnon-partioned bitmap indexes.
  
  Any ideas/thoughts?
  
  Thank you

  One would expect that the queries that cannot no partition pruning may be slowed down, Yes.

  An easy way to see this is to imagine that you have a partitioned local index b-tree and a query that needs to scan all partitions of the index to find a handful of lines that interest you (of course, this is not likely to be exactly what you see probably but we hope informative of the source of the problem). Let's say that each partition of the index has a height of 3, so for each partition, Oracle has read 3 blocks to reach the correct terminal node. So to analyze each of the N index partitions, you need block index 3 * N bed. If the index is not partitioned, perhaps the height of the index would go up to 4 or 5 If, in that case not partitioned, you must read 4 or 5 blocks. If you have hundreds or thousands of partitions, it can easily be hundreds of times more work to analyze all the index partitions individual he would to analyze one unpartitioned index.

  Partitioning is not a magical option "go faster". It is a compromise - you optimize certain operations (such as those that can partition pruning) at the expense of operations that do not partition size.

  Justin

• Unusable index Partitioned table

  Oracle Version: 11.2.0.2
  OS: Linux RHEL 5
  
  I'm having a problem with the index on a partitioned table interval. This is the scenario:
  
  There are 3 indices (A, B, C) on a table. A is created on two columns (1,2), B is on the column (2), C is the column (3). Table is partitioned on column 2 apart. A and B are partitioned indexes. When I drop a partition without a clause to update index, Index C will unusable. After seeing this, I gave up the C rating and create it as a local partitioned index, then all indexes are in condition of use after the drop partition statement. Is - this mandatory on a range partitioned table all indexes on the table must be locally partitioned inorder to have indexes in usable state after the drop statement of partition (without the update index clause)? Also there will be a negative impact for all indexes on the table like locally partitioned indexes?

  >
  Is - this mandatory on a range partitioned table all indexes on the table must be locally partitioned inorder to have indexes in usable state after the drop statement of partition (without the update index clause)?
  >
  Yes - it should be obvious by looking at a simple example.

  You have an OVERALL index and drop a partition but say Oracle are NOT updating the overall index.

  How this index may be usable for anything? It is not accurate. There was GARBAGE everywhere that gets in the way of Oracle find the entries of the "good". There are the index keys in the branch blocks that belong to the partition that has been deleted. Oracle cannot use these keys to determine how the blocks of branch, he needs to find.
  >
  Also there will be a negative impact for all indexes on the table like locally partitioned indexes?
  >
  Who knows? There are maybe or maybe not.

  As with many things Oracle "it depends."

  It depends on what types of queries that you ran.

  It depends on the filter predicates used for query.

  It depends on if the maintenance simple score (add/drop/split) are important to you.

  For the maintenance of the partition only all index LOCAL is the best.

  For full table scan, an index is not intended to be used.

  For a query that needs all THE records for a COMPANY_ID given in a table partitioned by DATE an OVERALL index could be better. Oracle also use 100 index LOCAL (if there are 100 partitions) to get the same data.

  It depends on.