Insert with 2 primary passes

Similar Questions

• MySQL Insert with autoincremented primary key

  I did not before MySQL.  I try and hit a roadblock soon enough.

  I would like to insert new records and have the auto-generated primary key / auto-increment.

  So, I have attached a few screenshots.  The first is a screenshot of the MySQL settings for the table that I'm writing.  The second is the Labview code that I threw as well as I am trying to run.

  The complete of the error I get is:

  > Database Connection.viADO error: 0x80004005
  Exception occurred in the Microsoft OLE DB provider for ODBC drivers: [MySQL] [ODBC 3.51 Driver] [mysqld - 5.7.11 - log] field 'techniciansID' didn't is not a default value to create a NI_Database_API.lvlib:Rec - Command.vi-> NI_Database_API.lvlib:Cmd Execute.vi-> NI_Database_API.lvlibData.vi B tools insert-> Connection.vi in the database

  I know that this error indicates that the techniciansID has no default value and he won't write because of it... but since it is an AutoIncrement field, it seems like it should work.

  Any help would be appreciated.  Thank you

  Thad

  Setting to 0 did not work, but I understand it.  For some reason any when I was refreshing my tables in MySQL server and using the "Forward Engineer" feature, the changes were not multiplication.  I had to drop the schema of the database (attached image) and then do an "engineer forward."  I made the changes, but the tables and the columns still had the attributes of origin... guess they cannot be updated by the script during execution.

  After doing this and the original settings I had (autoincremented primary key), the insert works in MySQL and Labview.

  Thanks for all the answers.  They made me think and check some things I didn't have before.

  -Thad

• New Hp laptop comes with 4 primary partitions. How do I creat more than I can duel boot

  New Hp laptop comes with 4 primary partitions. They are system, OS (C drive), recovery and HP tools > how do I create a new partition so that I can duel boot withour causing the entire disk pass the dynamic that would get me no where?

  If you change something, it may invalidate your warranty. If you need to return your laptop to HP, they will just wipe the drive and start over, no questions asked.

  You must remove the HP tools or the recovery partition. I think that removing the partition on an HP tools automatically goes to sleep you out of the recovery partition.

  If you delete the recovery partition, you must make sure that you have done the set HP recovery disk and it is on quality discs and safely set aside.

  If you are planning on dual booting with different versions of Windows, make sure that Windows utility block each other. For example, don't let Windows defrag loose on the other OS partition.

• Nested tables will not align with the primary table

  
  Hi all. Looks like I am facing another obstacle focus on the table. While I was creating one of my pages, I used nested tables to create a column on the left side of the page that will contain my menu secondary, while the other column will hold a flash element and the content of the page.
  
  Although I have inserted tables nested with a spacing of the cell '0' and '0' cell padding and Visual AIDS seem to indicate that the values in the nested table are identical with the primary table who is the holder, the nested table that will contain the film and the page content is not embedded with the table above. It seems to be off by 1-2 pixels or more, but since there will be a right on the image under the menu is quite obvious.
  
  I enclose the code for your information (line 165, 166).
  
  Thank you for your time and your suggestions. I really appreciate it.
  
  

  Saturday, September 16, 2006 15:06:50 + 0000 (UTC), "HTML-Newbie.
  wrote:

  > Discover the link http://www.fastventures.com/dev/test_temp_2col.html and you
  > see the picture under the main menu align with her on the
  > right side.

  Change this:

  
  
  
  

  To do this:

  <> SRC = "img/place_second.jpg" width = "572" height = "200" > "

  
  align = "right" >
  
  <>
  SRC = "img/place_second.jpg" width = "572" height = "200" > "
  

  Gary

• Sam P850 - what it takes with a primary partition 3, if I resize number 2

  The laptop model is P850-131.

  I need to decrease the size of the partition win 7 to create a space to expand and its logical partitions.
  But what to do with partition primary number 3 after resizing is finished.
  What is it. It contains data. Is - this for backup recovery Toshiba or what.
  Contain data, if no backup has not been done.

  Should I organize a new primary number 3 because it is primary end either, it's...
  It seems not to be of type NTFS. If I create another, what it should be.
  All information is valuable.

  Can you please open disk management and make the screenshot. It will be very useful to you understand what you mean exactly.

  What I can say is follow: before do you anything create recovery disk. It may happen that after changing the structure of the partitions you will not be able to install the OS using F8 and repair my computer option.

• Another user changed the row with a primary key oracle.jbo.Key]

  I see many discussions about this error, but still cannot understand the difficulty that I need in my scenario.

  I am an Oracle Developer and completely new to ADF, please bear with me.

  I use JDeveloper 11.1.1.9.0

  My scenario:

  Creates an object editable view (UVO) with sub selects in the query, which is from several db tables.

  Creating a table using the UVO

  When I try to update a field in the table, and then click the validate, I get the error message:

  Another user changed the row with a primary key oracle.jbo.Key]

  Can someone explain in what scenarios I see this error and how do I solve this problem?
  

  Try the viewObject execution after validation and reQueryOnCommit set to true

  For details see - binary: a reason more for "Houston-25014: another user has modified the line containing oracle.jbo.Key primary key '

  Ashish

• Parallel insert with noappend hint

  Hello

  I have a question about parallel to insert with the noappend indicator. Oracle Documentation says that:

  Append mode is the default for a parallel insert operation: data are always inserted in a new block, which is allocated to the table. Therefore, the APPEND is optional. You must use Add method to increase the speed of INSERT operations, but not when the use of space must be optimized. You can use NOAPPEND to void append mode.

  
  

  When I delete (all) and insert (parallel use noappend) and I see the number of blocks used by my table always increases. The blocks must not be reused due to remove it before insert?

  
  

  Version; Oracle Database 11g Enterprise Edition Release 11.2.0.4.0

  
  

  Here is the script I used:
  

  
  

  drop table all_objs;

  create the table all_objs in select * from object where rownum < 10000;

  Start

  DBMS_STATS.gather_table_stats (User, 'ALL_OBJS');

  end;

  Select the blocks of all_tables where table_name = 'ALL_OBJS ';

  ALTER session enable parallel dml.

  Start

  I'm in 1.5

  loop

  delete from all_objs;

  Insert / * + NOAPPEND PARALLEL (8 O) * /.

  in all_objs O

  Select * from object where rownum < 10000;

  end loop;

  end;

  commit;

  Start

  DBMS_STATS.gather_table_stats (User, 'ALL_OBJS');

  end;

  Select blocks of all_tables

  where table_name = 'ALL_OBJS ';

  Output:

  Deleted table.

  Table created.

  PL/SQL procedure successfully completed.

  BLOCKS

  ----------

  142

  1 selected line.

  Modified session.

  PL/SQL procedure successfully completed.

  Validation complete.

  PL/SQL procedure successfully completed.

  BLOCKS

  ----------

  634

  1 selected line.

  
  

  
  

  Why block increase of 142 to 634 even with the noappend trick?

  
  

  Thank you.
  

  Well, looks like the expected result:

  Repeated insertions PARALLELS - a lot of direct path writes, table size increases as the lines are added above the HWM, final size after ten iterations = 10 x original size

  NOAPPEND PARALLEL repeated inserts - no direct path did not write, size of the table increases do not significantly, lines inserted under the HWM

  The NOAPPEND PARALLEL insert clearly is re-use of space released by the deletion. However, I wonder why there is an overload of 3,000 blocks? It would be interesting to see how the overhead varies according to the degree of parallelism.

• Update line programmatically with Composite primary keys

  Hi all

  I use JDeveloper 11.1.2.4.0,I want to update the program with two primary keys PK1_ID and PK2_ID line

  When I have a primary key I can do it by:

  /////////////////////////////////////////////////////

  Key = new key (new Object() {empid});

  Employees1ViewImpl vo = (Employees1ViewImpl) this.getEmployees1View1 ();

  Locate the line using key reference in the View object.

  Line k = vo.getRow (key);

  using this method, we can set the new FirstName

  k.setAttribute ("FirstName", "Vero");

  this.getDBTransaction () .commit ();

  ///////////////////////////////

  Is it possible to use the same code with more of primary key?

  
  

  
  

  
  

  Kind regards

  The key class contains an array of attributes that identify the line you're looking for. In your case, the key has two attributes

  Key = new key (new Object() {pkId1, pkId2});

  the rest of the method works as what.

  Timo

• Need help writing an update / insert with linked tables

  I am new to ColdFusion. I am learning to write querys and creates a small application to collect information from visitors to my web site. (It's also a good way for me to learn this language) I'm having a problem and it is not only the way to use an update / insert with related tables. I don't know if I'm still gather the appropriate variables to compare them to existing DB records until his execution is the update or insert some querys. Can someone help me, show me how can I update / insert related tables and maybe tell me if I create the varibales good to the compairison? This is my code, I commented out.

  <! - creating a variable to compare with the db table - >
  < cfset userIP = ('#CGI.) REMOTE_ADDR #') >

  <! - run the query and compare the cfset cell remote_addr - >
  < name cfquery = 'userTracking' datasource = "" #APPLICATION.dataSource # "dbtype ="ODBC">"
  SELECT REMOTE_ADDR
  Of user_track
  WHERE REMOTE_ADDR = #userIP #.
  < / cfquery >

  <!-if the record exists, then run this update-->
  < cfif userTracking EQ userIP >
  < cfquery datasource = "#APPLICATION.dataSource #" >
  UPDATED user_track, trackDetail
  SET user_track. REMOTE_ADDR = < cfqueryparam value = '#Trim (CGI.' ' REMOTE_ADDR) # "cfsqltype ="CF_SQL_VARCHAR">.
  user_track. Browser = < cfqueryparam value = '#Trim (CGI.' "HTTP_USER_AGENT) #" cfsqltype = "CF_SQL_VARCHAR" >.
  user_track.visits = visits + 1,
  trackDetail.date = < cfqueryparam value = "#Now ()" # "cfsqltype ="CF_SQL_TIMESTAMP">,"
  trackDetail.path = < cfqueryparam value = "#Trim (PATH_INFO)" # "cfsqltype ="CF_SQL_LONGVARCHAR">"
  WHERE REMOTE_ADDR = < cfqueryparam value = '#Trim (CGI.' ' REMOTE_ADDR) # "cfsqltype ="CF_SQL_VARCHAR">
  < / cfquery >
  < cfelse >

  <! - if it isn't, then insert a new record-->
  < datasource = "" #APPLICATION.dataSource # cfquery "dbtype ="ODBC">"
  INSERT INTO user_track, trackDetail
  (user_track. REMOTE_ADDR, user_track.browser, user_track.visits, trackDetail.userID, trackDetail.date, trackDetail.path)
  VALUES)
  < cfqueryparam value = '#Trim (CGI.' ' REMOTE_ADDR) # "cfsqltype ="CF_SQL_VARCHAR">.
  < Len (Trim (HTTP_USER_AGENT)) GT 1 cfif >
  < cfqueryparam value = '#Trim (CGI.' "HTTP_USER_AGENT) #" cfsqltype = "CF_SQL_VARCHAR" >.
  < / cfif >
  visits + 1,
  < cfqueryparam value = '#Trim (CGI.' "HTTP_USER_AGENT) #" cfsqltype = "CF_SQL_VARCHAR" >.
  < cfqueryparam value = "" #user_track.userID # "cfsqltype ="CF_SQL_VARCHAR">,"
  < cfqueryparam value = "#Now ()" # "cfsqltype ="CF_SQL_TIMESTAMP">,"
  < cfqueryparam value = "#Trim (PATH_INFO)" # "cfsqltype ="CF_SQL_LONGVARCHAR">"
  )
  < / cfquery >
  < / cfif >

  
  I'm close on this? This throws any errors, but it is not no longer works. It is so obviously wrong. I get a cfdump the end of my query of compairison, but once it hits the stated case, it is lost.
  
  Thanks for your time no matter who.

  Newbie

  You must define the variable before you can use it.  You try to use it on line 1 of your model.

• Prevent the Insert with Error Message

  Hello
  
  I have a req where a user cannot insert two rows of the same kind.
  
  To achieve this I write a process to compare the line that is inserted with the existing lines.
  
  I don't know where and what to include in the code while once create button an error message pops up and the insertion of the line is not processed or the line is not processed.
  
  How to display an error message?
  How to prevent you insert this line?
  
  Please suggest.
  Thank you.

  If I add a row to a table and use all THE columns duplicate values, but the id column (which should be unique [system-generated]), I would still have some duplicate data in all the other columns, correct?

  If the OP wants to ensure without duplicating the data are entered, he would have the better to try and produce a checksum for all data entered in the line and determine if any other input line generates a corresponding checksum, if so, then an error message should / could be displayed showing the possibility of a double row of data...

  Thank you

  Tony Miller
  Webster, TX

• LOBs and how to retrieve the record inserted with EMPTY_BLOb()

  Hi guys
  
  
  How to retrieve the records inserted with EMPTY_BLOb() instead of NULL value.
  
  
  Best greetings
  A.G.

  There must be a better way, but these work:

  SELECT... from tableX where length (lob_column) = 0;
  SELECT... from tableX where dbms_lob.getlength (lob_column) = 0;

  Concerning
  Jonathan Lewis
  http://jonathanlewis.WordPress.com
  http://www.jlcomp.demon.co.UK

  "All experts it is a equal and opposite expert."
  Clarke

• insertion of a line of db from a form with a value passed in another page

  We have a report (P1) on a table (T1). P1 has a link column (C), and C is the PK on T1. By clicking on a link (that is, a line) in the P1 report takes you to the form (P2). P2 is used to allow the user to insert a new row in T1, with the constraint that one of the columns (X) of T1 must have the same value as X was in the line connected on P1. In addition, the X is a NOT NULL attribute.
  
  What we do is:
  First of all, by the way C P2 by defining the name of the link = P2_X_C and the value of link = # c#
  Second, P2, we establish the form P2_C via a SQL element:
  
  SELECT X
  FROM T1
  WHERE C =: P2_X_C
  
  P2 shows well. We put P2_C to display only and allow the user to enter the values for the other columns. The value for X is not NULL and properly to match the value of P1. However, when we hit the button CREATE on P2, we get error: ORA-01400: cannot insert NULL into "T1". » X ». Cannot process the row in the table T1.
  
  APEX seems to have a 'problem' with having a value in a form 'set' and sent to the DB on the INSERT.
  
  Any help would be greatly appreciated.

  Hello

  You must use a calculation that runs before the header to set the value of P2_C - you can use the SQL of the to do. A calculation in this way ensures that the value is stored in the session.

  When you set the value as the source of a display only element, the value is not actually subject with the page. Alternatively, if you use 4 Apex, you can set the item save the Session Yes State setting. This creates a version hidden element that is submitted with the page.

  Andy

• Problems with the primary key of the query string

  Moving from asp to php, to work with David Power's book: The Essential Guide to Dreamweaver CS4 with CSS, AJAX, and PHP.  Recycling of my brain, so starting from scratch in the learning process.

  Everything was going perfectly until I tried to add the primary key of a record in a query string.  I compared my code with the example code for the book, and everything matches.  When previewing the page in my browser and hover over the link which must pass the main code on the next page, the query string does not appear correctly.  It shows user_id = but no figure shows, as it is supposed to.  www.webpage.com/update_user.php?user_id=

  Here is my code: (Please note, <>have been removed, as I was unable to find a way view the code in the correct way here (copy/paste was doesn't work do not, nor insert syntax))

  ? PHP {?}

  ? PHP echo $row_listUser ['family_name'];? PHP echo $row_listUser ["FirstName"];?

  ? PHP echo $row_listUser ['username'];?       ? PHP echo $row_listUser ["admin_priv"];?

  a href = "update_user.php? user_id =? php echo $row_listUser ['user_id'];?" "Edit / has

  a href = "delete_user.php? user_id =? php echo $row_listUser ['user_id'];?" ' Delete / has

  ? PHP} while ($row_listUser = mysql_fetch_assoc ($listUser));?

  Any ideas that could help me understand why this part does not in particular would be greatly appreciated.  Writing to the database worked perfectly, I see that there are numbers in the database as user_id, and it is defined as my primary key in the configuration database.  Such a simple process that is causing me headaches!

  Thank you

  You have the code to request a copy in your folder:

  $query_listUser = 'SELECT user_id, username, first_name, family_name, admin_priv from users ORDER BY family_name ASC';

  $listUser = mysql_query ($query_listUser, $connSCFDIR) or die (mysql_error ());

  $row_listUser = mysql_fetch_assoc ($listUser);

  $totalRows_listUser = mysql_num_rows ($listUser);

  $query_listUser = 'SELECT username, first_name, family_name, admin_priv from users ORDER BY family_name ASC';

  $listUser = mysql_query ($query_listUser, $connSCFDIR) or die (mysql_error ());

  $row_listUser = mysql_fetch_assoc ($listUser);

  The $listUser table will contain the results of the second query, which does not include the field user_id. delete the redundant code.

• Limit the records inserted with FUSION

  I created a procedure for updating a table date of termination when the user enters a date of term.  Username and ID (PK) comes from t_users and the endings are in t_terms with t_terms.user_id = t_users.id as key.  There are about 2,500 users and curently nothing in the picture of the word.

  This procedure lights are part of a dynamic of action when the page is sent on an Apex application:

  create or replace Procedure "TERM_UPDATE"

  ()p_user_id IN NUMBER

  p_term_eff_date IN DATE )

  is

  Start

  fusion en t_terms t

      using t_users u

      on (t.user_id=u.id)

  when matched then

  to update the value TERM_EFF_DATE=p_term_eff_date where useridentifier=p_user_id

  when not equal then

  integration ()user_id term_eff_date) values ()p_user_id p_term_eff_date)

  end ;

  I tried just the merge statement in SQL Workshop.  The result is an insertion of 2500 all records user to the table of endings each time that it fires.  If I run again, I get 5000 inserts.  If I understand this process, t.users_id = u.id must return nothing, triggering the insert without match.  Even when there is a match, I always get the insert.  What the hell is happening?

  The p_user_id and the p_term_eff_date are power from bind on page variables.  I put those to be bind variables when I tested the query.

  I'm under apex 4.2 on 11g.

  Thank you!

  Hello

  Thanks for posting the instructions CREATE TABLE.

  Don't forget to display instructions INSERT for you samples, a few calls to the procedure (with specific values for the arguments) and content of t_term after each call.

  What t_users role in this problem?  You get all the information to t_users; you already know the user_id to the time wherever you call the procedure.  I guess the only reason why you have to t_users to this problem is to guard against inserting a user_id not valid in t_term.  (The foreign key constraint would guard against that, too, but it would trigger an error.  You might find a little more elegant to just merge 0 line when an invalid user_id is passed to the procedure.)

  Here's a way to do it:

  create or replace procedure 'TERM_UPDATE '.

  (p_user_id in NUMBERS

  p_term_eff_date IN DATE

  )

  is

  Start

  merge into dst t_terms

  a_l'_aide_de)

  Select id as user_id

  of t_users

  where id = p_user_id

  )              src

  on (dst.user_id = src.user_id)

  When matched then

  update set TERM_EFF_DATE = p_term_eff_date

  where DECODE (TERM_EFF_DATE - if wanted

  p_term_eff_date, 1

  0

  ) = 0

  When not matched then

  Insert (dst.id, dst.user_id, dst.term_eff_date)

  values (term_id_seq. NEXTVAL, src.user_id, p_term_eff_date);

  end;

  /

  DISPLAY ERRORS

  Because t_terms.id is forced to be NON NULL, you must provide a value for the id before you can insert a new line in t_terms.  In the above procedure, I guess you have a sequence called term_id_seq for this purpose.

• Insert into a primary database of Eve Active Data Guard

  I use Oracle EE 11.2.0.3.8 on Solaris 10.

  I read that it is possible to do an insert in my database for the standby Active Data Guard by redirecting the insert to get on the primary via DB link.  I GLOBAL_NAMES set to TRUE and he needs to stay that way.  This means that I can't create a DB link pointing to my first as such:

  CREATE DATABASE LINK PROD. WORLD WITH THE HELP OF "PROD_PRIM";

  How can I get around this in order to insert data in my standby ADG primary?

  Hello;

  There is an article about it here by Uwe Hesse:

  http://uhesse.files.WordPress.com/2012/03/realtimequery.PDF

  I understand that if GLOBAL_NAMES is true, then, the database link must have the same name as the database in which it connects.

  Best regards

  mseberg