Internal sorting/replacing characters

Similar Questions

• Formula to replace characters in a string

  Hi all

  Is it possible to replace characters in a string somewhere if the string has no specific pattern for these characters? I use the replacestr function to replace characters in a string (i.e. ABC), but the chain is in the ABC format * where * are two random characters. The result I'm looking for is to replace ABC * with the NodeID.

  ReplaceStr (propvalue (Core.Abbrev), ABC, ID (), T),) This formula works, but is either two additional characters in the end, after ABC. How can I cut that?

  Thank you

  If)

  Not (Equals (Integer, length (PropValue (Core.ABBREV)), length (ReplaceStr (PropValue (Core.ABBREV), ABC, T))),

  ReplaceStr (PropValue (Core.Abbrev), PropValue (Core.Abbrev), ID (), T),

  PropValue (Core.Abbrev)

  )

• Internal battery replacement for a 2000-361NR

  Good evening

  I'm a replacing the internal battery for my HP 2000-361NR. The external battery does not recognize that it is plugged. Does this mean I have to replace externally. I did diagnostics on it and it wont let me update the BIOS.

  Thanks in advance!

  Ah, so you get a battery error internal 601 at startup then tested battery Diagnostics UEFI which does not.

  These errors are related and mean the same external battery of the device. Tests you have given show that he does not and must be replaced.

  Make sure the internal battery 601 it's portable external battery turn off, remove the battery from the camera, then goot. The error should not appear.

  Do you know if your laptop is still under warranty? If so, then you can contact the HP Support to get it replaced under warranty.

  If not, a replacement battery may be purchased one a small shop, an online retailer like Amazon or HP.com directly.

• replace characters

  I need where any occurrence of 'BOM fo' should be replaced with "BOM -"
  We are on oracle 9i.
  
  I gave a few examples here, like having special characters, spaces, dashes that are all deleted.

  'Bill of Materials -BOOK1'      = 'BOM-BOOK1'
  'Bill of Materials- CASE2'      = 'BOM-CASE2'
  'Bill of Materials - PEN'       = 'BOM-PEN'
  'Bill of Materials CAL'         = 'BOM-CAL'
  'NEW Bill of Materials # TEXT'  = 'NEW BOM#TEXT'
  'DROPPED Bill of Materials ANymore'  = 'DROPPED BOM ANymore'

  Thank you
  Sandy

  Hi, Sandy.

  with a as (
              select 'Bill of Materials -BOOK1' product from dual union all
              select 'Bill of Materials- CASE2' product from dual union all
              select 'Bill of Materials - PEN' product from dual union all
              select 'Bill of Materials CAL' product from dual union all
              select 'NEW Bill of Materials # TEXT' product from dual union all
              select 'OLD Bill of Materials # TEXT & Image' product from dual union all
              select 'DROPPED Bill of Materials ANymore' product from dual
            )
  select    a.product         product
          , regexp_replace  (
                              a.product
                            , 'Bill of Materials([[:space:]]*)([[:space:]]{1}|[[:punct:]]{1})([[:space:]]*)'
                            , 'BOM\2'
                            ) product_replaced
  from      a                 a
  ;
  

  I used [[: space:]] {1} | for cases without special characters.

• Find and replace characters GREP

  Hello

  Is it possible to find and change a word (or a character style) at the end of each line of a text paragraph.

  Is it possible to do it with a script?

  
  My Script

  app.findGrepPreferences.appliedCharacterStyle = "italic";

  myFind = myDoc.findGrep ();

  for (i = 0; i < myFind.length; i ++) {}

  myIndex = myFind [i] .paragraphs [-1].parentStory.characters [myFind [i] .index-1];
  myIndex.contents = SpecialCharacters.EM_SPACE;
  }
  But its finding all the italic styles and insert em space.
  I need to change only the ending of the character of the line Style ("Italic")

  Any help would be great.

  Hurix

  Hi Hurriz

  To search for a font and style replace the following line

      app.findTextPreferences.appliedCharacterStyle = "Italic";

  with

  app.findTextPreferences.appliedFont = "Times New Roman\tItalic";
  

  Separate the name of the font "Times New Roman" and the name "Italic" style and only with "\t".

  Make sure that you spell and capitalize the names of police and style with precision

  We could also use 2 lines instead of 1 if you're afraid of things like \t!

  app.findTextPreferences.appliedFont = "Times New Roman";
  app.findTextPreferences.fontStyle = "Italic";
  

  If you wanted to could put on the text cursor with the font type and style you are looking for and use

  app.findTextPreferences.appliedFont = app.selection[0].appliedFont;
  

  Which can be useful if you for some reason a problem getting the details of the correct font.

  Hope that helps.

  Trevor

• Replace characters in large tables

  Hello
  
  I have a lot of large tables to change:
  replace 'AB' to 'C '.
  and 'FROM' to 'F'
  ...
  words to replace 10
  
  I can do:
  Update test set name = replace(nom,'AB','C');
  
  In order to avoid to analyze the 10 times tables
  I think that to use some sort of mapping table
  'AB' = > 'C '.
  'FROM' = > 'F'
  ...
  
  How can I do?
  Thanks in advance
  11 GR 2

  Hello

  John Spencer wrote:
  Deal is good for that sort of thing. something like:

  update test
  set nom = case when instr(nom, 'AB') != 0
  then replace(nom, 'AB', 'C')
  when instr(nom, 'DE') != 0
  then replace(nom, 'DE', 'F') end;
  

  John

  But be careful; If the same line may contain two or more, or chains under source, CASE will replace one of them. Example of FAIR, if name = "DEXYAB", the increased above it change to "DEXYC", "FXYC". To change all or part of 10 hooks under source, you can use
  

  
  
  • 10 expressions nested replace, as suggested, of Etbin
    
  • MODEL (see Query SQL
    
  • a WITH recursive (available in Oracle 11.2) clause or
    
  • a user-defined function. That's what I generally use.
    

• "REPLACE CHARACTERS FOR 'U' if the value is not a 'F' or me"

  Hi all
  
  I need a function to replace all characters to U if its not F or M
  
  The function should be similar below. But donno to form a regular expressiion above that can be placed in the second parameter.
  REGEXP_REPLACE('R','[^FM]','U')
  
  
  Entry
  F
  R
  M
  
  M
  A
  B
  
  Output
  F
  U
  M
  U
  M
  U
  U
  
  
  Thank you
  CDPrasad
  
  Published by: cdprasad on January 23, 2011 07:28

  Why would you use a regular expression (cpu-crushing) here?
  Looks like you can do it easily with the CASE:

  SQL> create table t as
    2  select 'F' col from dual union all
    3  select 'R' from dual union all
    4  select 'M' from dual union all
    5  select  null from dual union all
    6  select 'M' from dual union all
    7  select 'A' from dual union all
    8  select 'B' from dual;
  
  Table created.
  
  SQL>
  SQL> select col
    2  ,      case
    3           when col not in ('F', 'M')
    4           or col is null
    5           then 'U'
    6           else col
    7         end
    8  from   t; 
  
  C C
  - -
  F F
  R U
  M M
    U
  M M
  A U
  B U
  
  7 rows selected.
  

• How to replace characters in the Recordset?

  Hello
  
  I need to replace some special characters, the has and o, in a recordset with & aring; & licence; and & ouml;
  
  How is that done?
  
  Thnaks!

  Thank you, Julian, which works very well now.
  Thanks again!

• replace characters in the string

  Hi all

  Is it possible to index the characters in a string as if it were a table and remove them from the second position and now. I just want with the first letter or number so that I can later concatenate strings to it.

  Thanks for any help!

  -Michael

  Hi Michael,

  Yes. Use the function "Sring subset. At the beginning the value 0 (default value) and the length of 1.

  This will give you the first character in the string.

  Steve

• Replace characters does not?

  Hi, I'm fairly new to APEX and think I'm stuck on a relatively minor issue, but does not operate.
  I have a page that prints a PDF document, and in the header of the PDF, it's variable printing is provided by the application, which is
  Name - & P3_NAME.
  
  Is it possible to either make a replacement or topping on it, i.e. something like
  Name - replace (& P3_NAME., ' A 'B')
  
  I tried different things and it either blocks the page, or print the statement above and does not run so that the variable is not displayed.
  On the page, it goes 'attributes print' - 'header of the page.
  
  Can anyone help, or have any ideas?

  That is obviously not treat the string as a command from PL/SQL. So I suggest you to create an auxiliary element, for example:, a static assignment based on a PL/SQL Expression or a function that returns to REPLACE it ('& P3_NAME', 'A', 'B').

  Then in the header, instead, you can refer to &.

• Replace characters in a text field

  Hello

  I have a script to replace a carriage return in a text box.

  The script does not work when run from the console.

  Can any advise please how the script can be revised to find/replace a carriage return in a multi-line text box?

  var t = this.getField("ActionAgenda").value;
  t = t.replace("\r","") / / remove carriage return

  Any help would be most appreciated.

  Get the value of the field as a string

  var t = getField("ActionAgenda").valueAsString;

  Replace with nothing carriage returns

  t = t.replace(/\r/g,""); "

  The value of the field value string changed

  getField("ActionAgenda").value = t;

• Sort of characters

  Hi friends,
  There is a column to store the job numbers.
  Now I want to sort this task numbers
  
  For ex: suppose that the column contains the following values
  10
  10.1
  10.2
  10.1.1
  10.3
  10.12
  
  These values should be classified as follows:
  
  10
  10.1
  10.1.1
  10.2
  10.3
  10.12
  
  
  Functionally, we can describe these values as
  10 is the parent task
  10.1 is the first task of child 10
  10.1.1 is the task of the child of 10.1
  10.2 is the second child task of 10.
  10.3 is the third child task of 10.
  10.12 responsibility 12th child 10.

  In the 10g version (and more), you can use regular expressions 'format' of these strings, like this:

  WITH t AS (SELECT '10' col1
               FROM dual
              UNION
             SELECT '10.1'
               FROM dual
              UNION
             SELECT '10.2'
               FROM dual
              UNION
             SELECT '10.1.1'
               FROM dual
              UNION
             SELECT '10.3'
               FROM dual
              UNION
             SELECT '10.12'
               FROM dual
           )
  SELECT t.col1
    FROM t
   ORDER BY REGEXP_REPLACE(REGEXP_REPLACE(t.col1, '([[:digit:]]+(\.|$))', '00\1'), '([[:digit:]]{3}(\.|$))|.', '\1')
  ;               
  
  COL1
  ------
  10
  10.1
  10.1.1
  10.2
  10.3
  10.12
  

  If you want to know how regular expressions work, just take each function call and put it in the SELECT clause.

  C.

• Is SQL * Loader capable of replacing characters during load?

  Hello
  
  I have a table that is loaded into a DB Oracle with sql loader. Is it somehow possible to write a SPACE character instead of all the empty strings with the charger? I can illustrate what I need with this SQL code:
  

  update my_table 
  set first_column = ' ' 
  where first_column is null;

  Any suggestions?
  
  Thank you!

  my recommendation is to stop using SQL * LOADER and use of external tables, instead, it will give much better flexibility during the ETL and you do exactly what you ask

• sort characters in a varchar2

  Hello
  
  I have two tables of data I want to align. The two paintings have names of places. The format of the names in the two tables is similar, but slightly different.
  
  for example.
  
  Table 1: The Museum of life
  Table2: Life, Museum of
  
  My idea was to sort all characters in the string of two (while dropping whatever it is not alphanumeric and case sensitive) to harmonize the two.
  
  for example.
  
  The Museum of life-> EEEFFILMMOSUU
  Life, the Museum of the-> EEEFFILMMOSUU
  
  Only, I can't figure out a way to do it in Oracle. I imagine it would be possible to write a PL/SQL script, but before going into this, I thought I'd see if there is a built-in way to do what I'm trying to do, or maybe someone else has a better idea to do what I'm trying to accomplish?
  
  Thanks for any help and advice.

  Strange, you cannot use my suggestion. Anyway, you don't need two functions. Just take advantage of associative arrays and eliminate the need for sorting:

  SQL> CREATE OR REPLACE
    2    FUNCTION ordered_characters(
    3                                p_str VARCHAR2
    4                               )
    5    RETURN VARCHAR2
    6    IS
    7        TYPE char_tbl_type IS TABLE of VARCHAR2(1)
    8          INDEX BY VARCHAR2(10);
    9        v_char_tbl char_tbl_type;
   10        v_char     VARCHAR2(1);
   11        v_result   VARCHAR2(4000);
   12        v_idx      VARCHAR2(10);
   13    BEGIN
   14        FOR i IN 1..nvl(length(p_str),0) LOOP
   15          v_char := substr(p_str,i,1);
   16          v_char_tbl(v_char || to_char(i,'0000')) := v_char;
   17        END LOOP;
   18        v_idx := v_char_tbl.FIRST;
   19        FOR i IN 1..nvl(length(p_str),0) LOOP
   20          v_result := v_result || v_char_tbl(v_idx);
   21          v_idx    := v_char_tbl.NEXT(v_idx);
   22        END LOOP;
   23        RETURN v_result;
   24  END;
   25  /
  
  Function created.
  
  SQL> COLUMN ordered_characters FORMAT A10
  SQL> SELECT  ename,
    2          ordered_characters(ename) ordered_characters
    3    FROM  emp
    4  /
  
  ENAME      ORDERED_CH
  ---------- ----------
  SMITH      HIMST
  ALLEN      AELLN
  WARD       ADRW
  JONES      EJNOS
  MARTIN     AIMNRT
  BLAKE      ABEKL
  CLARK      ACKLR
  SCOTT      COSTT
  KING       GIKN
  TURNER     ENRRTU
  ADAMS      AADMS
  
  ENAME      ORDERED_CH
  ---------- ----------
  JAMES      AEJMS
  FORD       DFOR
  MILLER     EILLMR
  
  14 rows selected.
  
  SQL> 
  

  SY.

• Internal brand of hard drive to replace a default

  

  What brand of HDD internal to replace the former absence of a compaq presario CQ5320F 64-bit AY03011-ABL. Want to get even an or better without too much cost.

  It is a desktop computer, law is not a laptop? Yes, you chose a bad time in history looking for a hard drive. I think that the industry is milking this thing "floods in Thailand" as an excuse for us keep gouging for too long. Where are you located? Personally, I like Seagate hard drives but Western Digital makes a good. Try one of these:

  http://www.Newegg.com/product/product.aspx?item=N82E16822148840